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How to make #autowire work in spring when creating instance manually

I have a java interface say ITest implemented by two classes Class1 and Class2. Now I have a factory class which I use to decide which implementation to return. like
if(something)
return new Class1()
else
return new Class2()
Problem is that I have autowired field in Class1 which doesn't get instantiated,, but the same autowiring works in other classes which were instantiated via autowiring.
Here is code for Class1
#Componene
public Class1 implements ITest{
#Autowired
private SomeClass obj;
}
Not sure how to get around this problem. As autowiring for SomeClass works fine in Other classes.

Inject applicationContext in your factory class and use it for bean creation:
#Autowired private ApplicationContext applicationContext;
......
......
if(something){
return applicationContext.getBean("com.xyz.Class1");
}
......
......
OR you can use #Configurable on top of Class1 and Class2. This needs AspectJ weaving to be enabled. Spring will then magically create beans when you use new.

It strongly depends of what exactly do you need, but you can:
Define the object returned by factory as prototype-scope and inject it to singleton, for more details look at: https://docs.spring.io/spring/docs/current/spring-framework-reference/core.html#beans-factory-scopes-sing-prot-interaction
Then whole magic is done by Spring
If you just want to switch between two different stateless implementations you can inject both of them to factory and return an existing bean
#Compoment class Factory {
#Autowired
Class1 class1Instance;
#Autowired
Class2 classInstance;
...
if(something)
return class1Instance;
else
return class2Instance;
...
}
}
But please make sure that both injected classes have no state.
Make factory managed by Spring, both classes not-managed by Spring and inject dependencies manually:
public Class1 implements ITest{
private SomeClass obj;
public Class1(SomeClass obj) {
this.obj=obj;}
}
and in factory:
#Autowired
private SomeClass obj;
...
if(something)
return new Class1(obj);
else
return new Class2(obj);
At first glance looks strange, by that way you can e.g. separate domain and application/infrastructure parts.

You could use your Main Configuration class which is annotated with #SpringBootApplication or #Configuration.
Example:
#SpringBootApplication
public class YourApp {
public static void main(String[] args) {
SpringApplication.run(YourApp.class, args);
}
#Autowired
private CsvBeanRepository repo;
#Bean
public InterfaceSome some() {
if(something) {
return new Some(repo);
} else {
return new Some2(repo);
}
}
}
inside a #SpringBootApplication class or a #Configuration class you can #Autowire your classes normally and use them as parameters for your factory.

I would suggest to use #value annotation for this scenario.
Example
MyClass{
Object getObjectFromFactory()
{
if(something)
return new Class1()
else
return new Class2()
}
}
then you can use it like below
#Value("#{MyClass.getObjectFromFactory}")
private Object myObject;

Spring: Choosing constructor while Autowiring a Component

I've a Component as follows:
#Component
class A(){
private s;
public A(){}
public A(String s){this.s=s;}
}
Here is the other class Where I'm auto wiring the above class:
#Component
class B(){
#Autowire
private A a;
}
In the above autowiring, I need to use the parameterized constructor. How can I pass the constructor args?

You can't, at least not via #Autowired in B but there are other ways to do it:
Wire the parameter into A's constructor:
One constructor is annotated with #Autowired because:
As of Spring Framework 4.3, the #Autowired constructor is no longer
necessary if the target bean only defines one constructor. If several
constructors are available, at least one must be annotated to teach
the container which one it has to use.
#Component
class A(){
private s;
public A(){}
#Autowired
public A(#Value("${myval}") String s){this.s=s;}
}
Expose A as a #Bean
Straight from the docs:
#Configuration
public class AppConfig {
#Bean
public A a(#Value("${myval}") String s) {
return new A(s);
}
}
Construct A in B using an initialization callback
Docs
#Component
class B(){
private A a;
#Value("${myval}")
private String myval;
#PostConstruct
private void init()
{
a = new A(myval);
}
}

There is a concept of prototype bean which I think you require in your case. #Component will create a singleton bean and changing it in one place will change in all parent classes where this was injected.
You need to understand how to inject a prototype bean in singleton bean.
Follow this example
https://stackoverflow.com/a/25165971/949912

Just use setters instead of constructor.
If you want to create object by yourself with new keyword then this object will not be managed by container.

Inject spring bean dynamically

In a java-spring web-app I would like to be able to dynamically inject beans.
For example I have an interface with 2 different implementations:
In my app I'm using some properties file to configure injections:
#Determines the interface type the app uses. Possible values: implA, implB
myinterface.type=implA
My injections actually loaded conditionally relaying on the properties values in the properties file. For example in this case myinterface.type=implA wherever I inject MyInterface the implementation that will be injected will be ImplA (I accomplished that by extending the Conditional annotation).
I would like that during runtime - once the properties are changed the following will happen (without server restart):
The right implementation will be injected. For example when setting myinterface.type=implB ImplB will be injected where-ever MyInterface is used
Spring Environment should be refreshed with the new values and re-injected as well to beans.
I thought of refreshing my context but that creates problems.
I thought maybe to use setters for injection and re-use those setters once properties are re-configured. Is there a working practice for such a requirement?
Any ideas?
UPDATE
As some suggested I can use a factory/registry that holds both implementations (ImplA and ImplB) and returns the right one by querying the relevant property.
If I do that I still have the second challenge - the environment. for example if my registry looks like this:
#Service
public class MyRegistry {
private String configurationValue;
private final MyInterface implA;
private final MyInterface implB;
#Inject
public MyRegistry(Environmant env, MyInterface implA, MyInterface ImplB) {
this.implA = implA;
this.implB = implB;
this.configurationValue = env.getProperty("myinterface.type");
}
public MyInterface getMyInterface() {
switch(configurationValue) {
case "implA":
return implA;
case "implB":
return implB;
}
}
}
Once property has changed I should re-inject my environment. any suggestions for that?
I know I can query that env inside the method instead of constructor but this is a performance reduction and also I would like to think of an ider for re-injecting environment (again, maybe using a setter injection?).

I would keep this task as simple as possible. Instead of conditionally load one implementation of the MyInterface interface at startup and then fire an event that triggers dynamic loading of another implementation of the same interface, I would tackle this problem in a different way, that is much simpler to implement and maintain.
First of all, I'd just load all possible implementations:
#Component
public class MyInterfaceImplementationsHolder {
#Autowired
private Map<String, MyInterface> implementations;
public MyInterface get(String impl) {
return this.implementations.get(impl);
}
}
This bean is just a holder for all implementations of the MyInterface interface. Nothing magic here, just common Spring autowiring behavior.
Now, wherever you need to inject a specific implementation of MyInterface, you could do it with the help of an interface:
public interface MyInterfaceReloader {
void changeImplementation(MyInterface impl);
}
Then, for every class that needs to be notified of a change of the implementation, just make it implement the MyInterfaceReloader interface. For instance:
#Component
public class SomeBean implements MyInterfaceReloader {
// Do not autowire
private MyInterface myInterface;
#Override
public void changeImplementation(MyInterface impl) {
this.myInterface = impl;
}
}
Finally, you need a bean that actually changes the implementation in every bean that has MyInterface as an attribute:
#Component
public class MyInterfaceImplementationUpdater {
#Autowired
private Map<String, MyInterfaceReloader> reloaders;
#Autowired
private MyInterfaceImplementationsHolder holder;
public void updateImplementations(String implBeanName) {
this.reloaders.forEach((k, v) ->
v.changeImplementation(this.holder.get(implBeanName)));
}
}
This simply autowires all beans that implement the MyInterfaceReloader interface and updates each one of them with the new implementation, which is retrieved from the holder and passed as an argument. Again, common Spring autowiring rules.
Whenever you want the implementation to be changed, you should just invoke the updateImplementations method with the name of the bean of the new implementation, which is the lower camel case simple name of the class, i.e. myImplA or myImplB for classes MyImplA and MyImplB.
You should also invoke this method at startup, so that an initial implementation is set on every bean that implements the MyInterfaceReloader interface.

I solved a similar issue by using org.apache.commons.configuration.PropertiesConfiguration and org.springframework.beans.factory.config.ServiceLocatorFactoryBean:
Let VehicleRepairService be an interface:
public interface VehicleRepairService {
void repair();
}
and CarRepairService and TruckRepairService two classes that implements it:
public class CarRepairService implements VehicleRepairService {
#Override
public void repair() {
System.out.println("repair a car");
}
}
public class TruckRepairService implements VehicleRepairService {
#Override
public void repair() {
System.out.println("repair a truck");
}
}
I create an interface for a service factory:
public interface VehicleRepairServiceFactory {
VehicleRepairService getRepairService(String serviceType);
}
Let use Config as configuration class:
#Configuration()
#ComponentScan(basePackages = "config.test")
public class Config {
#Bean
public PropertiesConfiguration configuration(){
try {
PropertiesConfiguration configuration = new PropertiesConfiguration("example.properties");
configuration
.setReloadingStrategy(new FileChangedReloadingStrategy());
return configuration;
} catch (ConfigurationException e) {
throw new IllegalStateException(e);
}
}
#Bean
public ServiceLocatorFactoryBean serviceLocatorFactoryBean() {
ServiceLocatorFactoryBean serviceLocatorFactoryBean = new ServiceLocatorFactoryBean();
serviceLocatorFactoryBean
.setServiceLocatorInterface(VehicleRepairServiceFactory.class);
return serviceLocatorFactoryBean;
}
#Bean
public CarRepairService carRepairService() {
return new CarRepairService();
}
#Bean
public TruckRepairService truckRepairService() {
return new TruckRepairService();
}
#Bean
public SomeService someService(){
return new SomeService();
}
}
By using FileChangedReloadingStrategy your configuration be reload when you change the property file.
service=truckRepairService
#service=carRepairService
Having the configuration and the factory in your service, let you can get the appropriate service from the factory using the current value of the property.
#Service
public class SomeService {
#Autowired
private VehicleRepairServiceFactory factory;
#Autowired
private PropertiesConfiguration configuration;
public void doSomething() {
String service = configuration.getString("service");
VehicleRepairService vehicleRepairService = factory.getRepairService(service);
vehicleRepairService.repair();
}
}
Hope it helps.

If I understand you correctly then the goal is not to replace injected object instances but to use different implementations during interface method call depends on some condition at run time.
If it is so then you can try to look at the Sring TargetSource mechanism in combination with ProxyFactoryBean. The point is that proxy objects will be injected to beans that uses your interface, and all the interface method calls will be sent to TargetSource target.
Let's call this "Polymorphic Proxy".
Have a look at example below:
ConditionalTargetSource.java
#Component
public class ConditionalTargetSource implements TargetSource {
#Autowired
private MyRegistry registry;
#Override
public Class<?> getTargetClass() {
return MyInterface.class;
}
#Override
public boolean isStatic() {
return false;
}
#Override
public Object getTarget() throws Exception {
return registry.getMyInterface();
}
#Override
public void releaseTarget(Object target) throws Exception {
//Do some staff here if you want to release something related to interface instances that was created with MyRegistry.
}
}
applicationContext.xml
<bean id="myInterfaceFactoryBean" class="org.springframework.aop.framework.ProxyFactoryBean">
<property name="proxyInterfaces" value="MyInterface"/>
<property name="targetSource" ref="conditionalTargetSource"/>
</bean>
<bean name="conditionalTargetSource" class="ConditionalTargetSource"/>
SomeService.java
#Service
public class SomeService {
#Autowired
private MyInterface myInterfaceBean;
public void foo(){
//Here we have `myInterfaceBean` proxy that will do `conditionalTargetSource.getTarget().bar()`
myInterfaceBean.bar();
}
}
Also if you want to have both MyInterface implementations to be Spring beans, and the Spring context could not contains both instances at the same time then you can try to use ServiceLocatorFactoryBean with prototype target beans scope and Conditional annotation on target implementation classes. This approach can be used instead of MyRegistry.
P.S.
Probably Application Context refresh operation also can do what you want but it can cause other problems such as performance overheads.

This may be a duplicate question or at least very similar, anyway I answered this sort of question here: Spring bean partial autowire prototype constructor
Pretty much when you want a different beans for a dependency at run-time you need to use a prototype scope. Then you can use a configuration to return different implementations of the prototype bean. You will need to handle the logic on which implementation to return yourself, (they could even be returning 2 different singleton beans it doesn't matter) But say you want new beans, and the logic for returning the implementation is in a bean called SomeBeanWithLogic.isSomeBooleanExpression(), then you can make a configuration:
#Configuration
public class SpringConfiguration
{
#Bean
#Autowired
#Scope("prototype")
public MyInterface createBean(SomeBeanWithLogic someBeanWithLogic )
{
if (someBeanWithLogic .isSomeBooleanExpression())
{
return new ImplA(); // I could be a singleton bean
}
else
{
return new ImplB(); // I could also be a singleton bean
}
}
}
There should never be a need to reload the context. If for instance, you want the implementation of a bean to change at run-time, use the above. If you really need to reload your application, because this bean was used in constructors of a singleton bean or something weird, then you need to re-think your design, and if these beans are really singleton beans. You shouldn't be reloading the context to re-create singleton beans to achieve different run-time behavior, that is not needed.
Edit The first part of this answer answered the question about dynamically injecting beans. As asked, but I think the question is more of one: 'how can I change the implementation of a singleton bean at run-time'. This could be done with a proxy design pattern.
interface MyInterface
{
public String doStuff();
}
#Component
public class Bean implements MyInterface
{
boolean todo = false; // change me as needed
// autowire implementations or create instances within this class as needed
#Qualifier("implA")
#Autowired
MyInterface implA;
#Qualifier("implB")
#Autowired
MyInterface implB;
public String doStuff()
{
if (todo)
{
return implA.doStuff();
}
else
{
return implB.doStuff();
}
}
}

You can use #Resource annotation for injection as originally answered here
e.g.
#Component("implA")
public class ImplA implements MyInterface {
...
}
#Component("implB")
public class ImplB implements MyInterface {
...
}
#Component
public class DependentClass {
#Resource(name = "\${myinterface.type}")
private MyInterface impl;
}
and then set the implementation type in properties file as -
myinterface.type=implA

Be aware that - if interesting to know about - FileChangedReloadingStrategy makes your project highly dependent on the deployment conditions: the WAR/EAR should be exploded by container and your should have direct access to the file system, conditions that are not always met in all situations and environments.

You can use Spring #Conditional on a property value. Give both Beans the same name and it should work as only one Instance will be created.
Have a look here on how to use #Conditional on Services and Components:
http://blog.codeleak.pl/2015/11/how-to-register-components-using.html

public abstract class SystemService {
}
public class FooSystemService extends FileSystemService {
}
public class GoSystemService extends FileSystemService {
}
#Configuration
public class SystemServiceConf {
#Bean
#Conditional(SystemServiceCondition.class)
public SystemService systemService(#Value("${value.key}") value) {
switch (value) {
case A:
return new FooSystemService();
case B:
return new GoSystemService();
default:
throw new RuntimeException("unknown value ");
}
}
}
public class SystemServiceCondition implements Condition {
#Override
public boolean matches(ConditionContext conditionContext, AnnotatedTypeMetadata annotatedTypeMetadata) {
return true;
}
}

How to specify which subclass Spring should use

In my spring-based project I have a core module ('core') with a class
#Component
public class Superclass {
// stuff
}
instances of which are injected by type throughout the code like this:
public class AService {
#Autowired
private Superclass superclass;
// service stuff
}
I also have two other modules that depend on the core module and one of which (let's call it 'module1') extends Superclass:
#component
public class Subclass extends Superclass {
// overridden stuff
}
The other module ('module2') uses Superclass as is.
Now I want that when I compile and run 'child1' an instance of Subclass is used everywhere an instance of Superclass is expected. So I write a configuration class:
#Configuration
public class Module2Configuration {
#Bean
public Superclass superclass(){
return new Subclass();
}
}
When I run this I see both Superclass and Subclass instantiated which is definitely not what I want. How do specify in 'module1' which type Spring should instantiate?

You can use #Qualifier("some name") annotation.
There is more information about that: http://blogs.sourceallies.com/2011/08/spring-injection-with-resource-and-autowired/

Spring eagerly instantiates singleton beans as stated in the documentation:
By default, ApplicationContext implementations eagerly create and configure all singleton beans as part of the initialization process.
which might explain why both #Components are created.
To specifiy which implementation is provided as a dependency you might want to check on Qualifiers that enable to choose between different implementations. In combination with lazy loading this should do the trick.
Depending on your personal taste you could also use delegation instead of inheritance using a separated interface:
public interface MyService {
public String foobar(int baz);
}
public static class CommonBehavior {
// whatever is used by Superclass and Subclass
}
#Component #Lazy
public class FormerSuperClass implements MyService {
private final CommonBehavior ...;
...
}
#Component #Lazy
public class FormerSubClass implements MyService {
private final CommonBehavior ...;
...
}
Good luck!

There are 2 methods: Use #Qualifier("SubclassName") Or Mark your subclass as #Component and declare the subclass when #Autowired
In your case:
Use #Qualifier("SubclassName")
#Component
public class Superclass {
// stuff
}
#component
public class Subclass extends Superclass {
// overridden stuff
}
public class AService {
#Autowired
#Qualifier("Subclass")
private Superclass superclass;
// service stuff
}
2.Mark your subclass as #Component and declare the subclass when #Autowired
public class Superclass {
// stuff
}
#component
public class Subclass extends Superclass {
// overridden stuff
}
public class AService {
#Autowired
private Subclass subclass;
// service stuff
}

How to provide different beans depending on runtime parameter using #Bean method

I am trying create a #Configuration factory bean that should create other (prototype) beans depending on a runtime parameter. I want to use spring java-based configuration but somehow I could not make it work.
Here is an example:
enum PetType{CAT,DOG;}
abstract class Pet {
}
#Component
#Scope("prototype")
class Cat extends Pet{
}
#Component
#Scope("prototype")
class dog extends Pet{
}
#Configuration
public class PetFactory{
#Bean
#Scope("prototype")
public Pet pet(PetType type){
if(type == CAT){
return new Cat();
}else
return new Dog();
}
}
petFactory.animal(PetType.CAT);
I checked spring docs and all related questions asked here but I end up in the case of supplying runtime parameters to the created bean. And I need to supply runtime parameters to the factory that must use them to create different beans.
EDIT:
Seems (currently) there is no way to define a parameter to a #Bean annotated method as
"runtime". Spring assumes method parameters will be used as constructor args for the new bean and so it tries to satisfy this dependency with container-managed beans.

This seems like it could be a good use of the Spring Profiles feature. Here you can read about Java configurations, and here about XML Profiles.
Your profile would define a Pet bean. Your factory could then wire that bean in.
To modify which profile you use, simply add: -Dspring.profiles.active=dog or -Dspring.profiles.active=cat (or whatever you name them).

Try using #Configurable:
class Factory {
Pet newPetOfType(PetType type) {
switch (type) {
case CAT: return new Cat();
...
}
}
#Configurable
private static class Cat extends Pet {
#Autowired private Prop prop;
...
}
}

You can just #Autowire your PetFactory bean into required bean and call animal() method with required type in runtime, like in the following approach:
#Configuration
public class AppConfiguration {
#Bean
#Scope("prototype")
public Pet getPet(PetType type) {
if(type == CAT){
return new Cat();
} else
return new Dog();
}
}
//...
// Then in required class
#Service
public class PetService {
#Autowired
private AppConfiguration configuration;
//.....
public Pet getPetByType(PetType type) {
return configuration.getPet(type);
}
}