Multiples of 20 in java [closed] - java

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I done a coding to get the output 20,40,60,80 and 100.
Multiple.java:
public class Multiple {
static int n=20;
static int m;
public static void main(String[] args) {
for(int i=1;i<=5;i++){
m=n*i;
System.out.println(m);
}
}
}
Output:
20
40
60
80
100
I didn't have any issue in this coding.I got an output successfully.But loop running 5 times.Let me know is there any other way to get these output(20,40,60,80 and 100) in simplest way.

very interesting. if you know the output result (it's fixed), why don't you write them out directly:
System.out.println(20);
System.out.println(40);
System.out.println(60);
System.out.println(80);
System.out.println(100);`
oh i see, you think that's too long. Then probably you can use the below:
int a = 0;
while(a<100){ a += 20; System.out.println(a);}
Enjoy it!

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How to rught a loop that delete elents of collection,which creat arifmetick progression [closed]

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How to write a loop that will delete those elements of the collection whose numbers form an arithmetic progression, by type if the number 246 deletes, but the second 245 does not, since it does not oblige the progression
import java.util.ArrayList;
public class n {
public static void main(String[] args) {
ArrayList nums = new ArrayList<>();
nums.add(24);
nums.add(223);
nums.add(2424);
nums.add(135);
nums.add(258);
nums.add(246);
for (int i = 0; i < nums.size();i++){
if
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How do I break the infinite loop? - Java [closed]

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This chunk of my Java code keeps returning an infinite loop. How do I change the code to break the infinite loop?
public void setResult(int result) {
this.result = result;
equasion(result);
}
public void equasion(int number) {
setResult(number * number);
}

JAVA: How to print out 5 , 5.5 , 6.5 , ++ [closed]

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I want to make a list of 5 , 5.5 , 6.5 , ++
Can someone show me how to fix it
Here is my code:
package com.bowl.Bowling;
public static void main(String[] args) {
for (double i = 5; i <= 12; i+=0.5) {
System.out.println(i);
i++;
}
}
Output:
5.0
6.5
8.0
9.5
11.0
just delete i++ like here:
public static void main(String[] args) {
for (double i = 5; i <= 12; i+=0.5)
System.out.println(i);
}
in your code, you have two part for update your loop counter which one is i+=0.5 and another one is i++ and you should delete one of them

How to convert to "filter" from for loop [closed]

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I have a simple for loop
and I want to change it into a statement using filter
for (int lotto_num: lottos) {
if (lotto_num == 0) {
unknown_count++;
}
for (int win_num : win_nums) {
if (lotto_num == win_num) {
count ++;
}
}
}
is it possible? I dont't really know how to use filter and stream.
In order to use Java's Stram API you should firstly convert your int[] arrays win_nums and lottos to List<Integer>.
It can be done this way:
List<Integer> win_nums_list = IntStream.of(win_nums).boxed().collect(Collectors.toList());
List<Integer> lottos_list= IntStream.of(lottos).boxed().collect(Collectors.toList());
Now we can use Stream API to get the desired result.
int count = win_nums_list.stream().filter(win_num -> lottos_list.contains(win_num)).count();
int unknown_count = lottos_list.stream().filter(lotto -> lotto== 0).count();
with adding imports to the beginning of your code:
import java.util.*;

Using electron in a formula in java [closed]

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I'm trying to write a Java program that can take values and put them into a formula involving electron. How can I calculate e^x in Java?
you can use java.lang.Math.exp() method to calculate e^x.
here is an example
`
public static void main(String[] args)
{
double a = 2.0;
System.out.println(Math.exp(a));
}
//output = 7.38905609893065
`
you can read more about this using this link.
https://www.javatpoint.com/java-math-exp-method
You could use Math.exp().
Example:
import java.lang.Math;
// inside main
Math.exp(1.0); // e^1
Math.exp(1.6); // e^1.6
import java.lang.Math;
class Answer {
// driver code
public static void main(String args[])
{
double a = 30;
double b = 2;
System.out.println(Math.pow(a, b));
a = 3;
b = 4;
System.out.println(Math.pow(a, b));
a = 2;
b = 6;
System.out.println(Math.pow(a, b));
}
//you can use Math.pow(e,x);

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