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JAVA POST Request MultiFormData with File and Parameters

I am trying to make a POST request using "multipart/form-data" , i need to post a file (Code Below) and 4 parameters(Name,category ...) all Strings.
I can already send the File using code below but never with parameters.
// open a URL connection to the Servlet
FileInputStream fileInputStream = new FileInputStream(sourceFile);
URL url = new URL(upLoadServerUri);
// Open a HTTP connection to the URL
conn = (HttpURLConnection) url.openConnection();
conn.setDoInput(true); // Allow Inputs
conn.setDoOutput(true); // Allow Outputs
conn.setUseCaches(false); // Don't use a Cached Copy
conn.setRequestMethod("POST");
conn.setRequestProperty("Connection", "Keep-Alive");
conn.setRequestProperty("ENCTYPE", "multipart/form-data");
conn.setRequestProperty("Content-Type", "multipart/form-data;boundary=" + boundary);
conn.setRequestProperty("fileToUpload", fileName);
dos = new DataOutputStream(conn.getOutputStream());
dos.writeBytes(twoHyphens + boundary + lineEnd);
dos.writeBytes("Content-Disposition: form-data; name=\"fileToUpload\";filename=" + fileName + "" + lineEnd);
dos.writeBytes(lineEnd);
// create a buffer of maximum size
bytesAvailable = fileInputStream.available();
bufferSize = Math.min(bytesAvailable, maxBufferSize);
buffer = new byte[bufferSize];
// read file and write it into form...
bytesRead = fileInputStream.read(buffer, 0, bufferSize);
while (bytesRead > 0) {
dos.write(buffer, 0, bufferSize);
bytesAvailable = fileInputStream.available();
bufferSize = Math.min(bytesAvailable, maxBufferSize);
bytesRead = fileInputStream.read(buffer, 0, bufferSize);
}
// send multipart form data necesssary after file data...
dos.writeBytes(lineEnd);
dos.writeBytes(twoHyphens + boundary + twoHyphens + lineEnd);
// Responses from the server (code and message)
serverResponseCode = conn.getResponseCode();
String serverResponseMessage = conn.getResponseMessage();
Log.i("uploadFile", "HTTP Response is : " + serverResponseMessage + ": " + serverResponseCode);
if (serverResponseCode == 200) {
runOnUiThread(new Runnable() {
public void run() {
Toast.makeText(PerdidosEAchados.this, "File Upload Complete.",
Toast.LENGTH_SHORT).show();
}
});
}
//close the streams //
fileInputStream.close();
dos.flush();
dos.close();
The server Code
<?php
echo $_POST["Name"]) ;
echo $_POST["category "]) ;
?>
I have tryed adding
dos.writeBytes("Content-Disposition: form-data; name=\"Name\";" + lineEnd);
dos.writeBytes(lineEnd);
dos.writeBytes(Variable);
But the server never registers the parameters, how can i solve this?

Maybe you shuold build the POST request like the forrowing demo code? Hope it helps.
### Send a form with the text and file fields
POST https://httpbin.org/post
Content-Type: multipart/form-data; boundary=WebAppBoundary
--WebAppBoundary
Content-Disposition: form-data; name="Name"
myName
--WebAppBoundary
Content-Disposition: form-data; name="category"
myCategory
--WebAppBoundary
Content-Disposition: form-data; name="data"; filename=".gitignore"
Content-Type: application/json
< ./.gitignore
--WebAppBoundary--
<> 2019-09-23T045805.200.json
###

Error in moving variables from android class to php side [closed]

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I am currently developing an app and i have a problem in transferring the variables from android to the php script. However the connection is established. Any help will be appreciated.
Here is my Java code.
// open a URL connection to the Servlet
FileInputStream fileInputStream = new FileInputStream(sourceFile);
URL url = new URL(upLoadServerUri);
// Open a HTTP connection to the URL
conn = (HttpURLConnection) url.openConnection();
conn.setDoInput(true); // Allow Inputs
conn.setDoOutput(true); // Allow Outputs
conn.setUseCaches(false); // Don't use a Cached Copy
conn.setRequestMethod("POST");
conn.setRequestProperty("Connection", "Keep-Alive");
conn.setRequestProperty("ENCTYPE", "multipart/form-data");
conn.setRequestProperty("Content-Type", "multipart/form-data;boundary=" + boundary);
conn.setRequestProperty("uploaded_file", fileName);
dos = new DataOutputStream(conn.getOutputStream());
dos.writeBytes(twoHyphens + boundary + lineEnd);
dos.writeBytes("Content-Disposition: form-data; name=\"uploaded_file\";filename=\""
+ fileName + "\"" + lineEnd);
dos.writeBytes(lineEnd);
dos.writeBytes(twoHyphens + boundary + lineEnd);
dos.writeBytes("Content-Disposition: form-data; name=\"uploaded_file\";name=\""
+ username + "\"" + lineEnd);
dos.writeBytes(lineEnd);
// create a buffer of maximum size
bytesAvailable = fileInputStream.available();
bufferSize = Math.min(bytesAvailable, maxBufferSize);
buffer = new byte[bufferSize];
// read file and write it into form...
bytesRead = fileInputStream.read(buffer, 0, bufferSize);
while (bytesRead > 0) {
dos.write(buffer, 0, bufferSize);
bytesAvailable = fileInputStream.available();
bufferSize = Math.min(bytesAvailable, maxBufferSize);
bytesRead = fileInputStream.read(buffer, 0, bufferSize);
}
// send multipart form data necesssary after file data...
dos.writeBytes(lineEnd);
dos.writeBytes(twoHyphens + boundary + twoHyphens + lineEnd);
And this is my php script
<?php
require("config.inc.php");
$file_path = "uploads/";
$file_path = $file_path . basename( $_FILES['uploaded_file']['filename']);
$user = $_FILES['username'];
if(move_uploaded_file($_FILES['uploaded_file']['tmp_name'], $file_path)) {
$query = "INSERT INTO users ( username, password, picture ) VALUES ( '1234567', $user, $file_path ) ";
$stmt = $db->prepare($query);
$stmt->execute();
echo "success";
} else{
echo "fail";
}
?>
The problem is in the section of setting the values and the variables are moved empty. In the database nothing is being added.

The reason why it fails is because you did not prepare your query properly:
$query = "INSERT INTO users ( username, password, picture ) VALUES ( ?, ?, ? ) ";
$stmt = $db->prepare($query);
$stmt->execute(array('1234567', $user, $file_path));

HttpURLConnection and writing file WITH DATA

I'm trying to post a file and data to my server from an Android java script (to my php), it seems I'm pretty much there, but someone PLEASE help me, as I can't seem to format the name/value part (the FILE uploads perfect, but it doesn't send the name value :( )
JAVA:
try{
int serverResponseCode = 0;
final String upLoadServerUri = "http://myUrl/upload_file_functions.php";
String fileName = "/mnt/sdcard/myFile.dat";
HttpURLConnection conn = null;
DataOutputStream dos = null;
String lineEnd = "\r\n";
String twoHyphens = "--";
String boundary = "*****";
int bytesRead, bytesAvailable, bufferSize;
byte[] buffer;
int maxBufferSize = 1 * 1024 * 1024;
File sourceFile = new File("/mnt/sdcard/myFile.dat");
// open a URL connection to the Servlet
FileInputStream fileInputStream = new FileInputStream(sourceFile);
URL url = new URL(upLoadServerUri);
// Open a HTTP connection to the URL
conn = (HttpURLConnection) url.openConnection();
conn.setDoInput(true); // Allow Inputs
conn.setDoOutput(true); // Allow Outputs
conn.setUseCaches(false); // Don't use a Cached Copy
conn.setRequestMethod("POST");
conn.setRequestProperty("Connection", "Keep-Alive");
conn.setRequestProperty("ENCTYPE", "multipart/form-data");
conn.setRequestProperty("Content-Type", "multipart/form-data;boundary=" + boundary);
conn.setRequestProperty("file", fileName);
conn.setRequestProperty("gmail", names[0]);
conn.setRequestProperty("phn", phn);
dos = new DataOutputStream(conn.getOutputStream());
dos.writeBytes(twoHyphens + boundary + lineEnd);
dos.writeBytes("Content-Disposition: form-data; name=\"file\";filename=\""
+ fileName + "\"" + lineEnd);
dos.writeBytes(twoHyphens + boundary + lineEnd);
String data = URLEncoder.encode("gmail", "UTF-8") + "=" + URLEncoder.encode(names[0], "UTF-8");
dos.writeBytes(data);
dos.writeBytes(lineEnd);
// create a buffer of maximum size
bytesAvailable = fileInputStream.available();
bufferSize = Math.min(bytesAvailable, maxBufferSize);
buffer = new byte[bufferSize];
// read file and write it into form...
bytesRead = fileInputStream.read(buffer, 0, bufferSize);
while (bytesRead > 0) {
dos.write(buffer, 0, bufferSize);
bytesAvailable = fileInputStream.available();
bufferSize = Math.min(bytesAvailable, maxBufferSize);
bytesRead = fileInputStream.read(buffer, 0, bufferSize);
}
// send multipart form data necesssary after file data...
dos.writeBytes(lineEnd);
dos.writeBytes(twoHyphens + boundary + twoHyphens + lineEnd);
dos.writeBytes("Content-Disposition: form-data; name=\"" + names[0] + "\"" + lineEnd);
dos.writeBytes("Content-Type: text/plain"+lineEnd);
dos.writeBytes(lineEnd);
dos.writeBytes(names[0]);
dos.writeBytes(lineEnd);
dos.writeBytes(twoHyphens + boundary + twoHyphens + lineEnd);
//*************************
// Responses from the server (code and message)
serverResponseCode = conn.getResponseCode();
String serverResponseMessage = conn.getResponseMessage();
Log.i("uploadFile", "HTTP Response is : "
+ serverResponseMessage + ": " + serverResponseCode);
if(serverResponseCode == 200){
// it worked !
}
//close the streams //
fileInputStream.close();
dos.flush();
dos.close();
}catch (Exception e){
}
It doesn't work, the FILE sends fine, but I can't get a freaking key/name to send ("gmail:"names[0]) I've also tried:
// Open a HTTP connection to the URL
conn = (HttpURLConnection) url.openConnection();
conn.setDoInput(true); // Allow Inputs
conn.setDoOutput(true); // Allow Outputs
conn.setUseCaches(false); // Don't use a Cached Copy
conn.setRequestMethod("POST");
conn.setRequestProperty("Content-Type", "multipart/form-data;boundary=" + boundary);
conn.setRequestProperty("gmail", names[0]);
dos.writeBytes(twoHyphens + boundary + lineEnd);
dos = new DataOutputStream(conn.getOutputStream());
dos.writeBytes(twoHyphens + boundary + lineEnd);
dos.writeBytes("Content-Disposition: form-data; name=\"file\";filename=\""
+ fileName + "\"" + lineEnd);
dos.writeBytes(twoHyphens + boundary + lineEnd);
DOESN'T WORK. I've tried:
dos.writeBytes("Content-Disposition: form-data; name=\"gmail\";filename=\""+ names[0] + "\"" + lineEnd);
Doesn't WORK! WTF! I've programmed for years in C++ and python, it's a simple thing! But I can't figure this out I need help, if you know how to do it PLEASE DO TELL because I've spent two days banging my head against the wall. I'm not lazy I spent 32+ f'n hours on this please I beg you..
What I WANT to happen: send the file for upload, along with the value (name=gmail value=names[0]; name=phn value=phn), so that the email is associated to the file on my server.
What IS happening: file is uploading fine, but data is not passed (the name/value pairs are not sent)
PHP:
<?php
set_time_limit(100);
//need to get email also (gmail address of user)
//************************************************
if ($_FILES["file"]["error"] > 0)
{
echo "Error: " . $_FILES["file"]["error"] . "<br>";
}
else
{
echo "Upload: " . $_FILES["file"]["name"] . "<br>";
echo "Type: " . $_FILES["file"]["type"] . "<br>";
echo "Size: " . ($_FILES["file"]["size"] / 1024) . " kB<br>";
echo "Stored in: " . $_FILES["file"]["tmp_name"];
move_uploaded_file($_FILES["file"]["tmp_name"],
"upload/" . $_FILES["file"]["name"]);
echo "Stored in: " . "upload/" . $_FILES["file"]["name"];
}
}
function Three(){
$to = 'me#email.com';
$subject = $_POST['phn'] . " " . $_POST['gmail'];
$bound_text = "file";
$bound = "--".$bound_text."\r\n";
$bound_last = "--".$bound_text."--\r\n";
$headers = "From: me#email.com\r\n";
$headers .= "MIME-Version: 1.0\r\n"
."Content-Type: multipart/mixed; boundary=\"$bound_text\"";
$message .= "If you can see this MIME than your client doesn't accept MIME types!\r\n"
.$bound;
$message .= "Content-Type: text/html; charset=\"iso-8859-1\"\r\n"
."Content-Transfer-Encoding: 7bit\r\n\r\n"
."hey my <b>good</b> friend here is a picture of regal beagle\r\n"
.$bound;
$file = file_get_contents("http://myURL/upload/myFile.dat");
$message .= "Content-Type: image/jpg; name=\"myFile.dat\"\r\n"
."Content-Transfer-Encoding: base64\r\n"
."Content-disposition: attachment; file=\"myFile.dat"\r\n"
."\r\n"
.chunk_split(base64_encode($file))
.$bound_last;
#mail($to, $subject, $message, $headers);
//delete files
$fileArray=array($_FILES["file"]["name"],"myfile.dat","myfile.dat");
foreach($fileArray as $value){
if(file_exists($value)){
unlink($value);
}
}
chdir($old_path);
}
function runAll(){
One();
Two();
Three();
}
runAll();
$randx=null;
unset($randx);
?>
PLEASE HELP! The JAVA is not sending the name='gmail' value=names[0], nor the name='phn' value=phn ..

You should really read up on a few things: HTTP (and the distinction between request header fields and the post body), and the structure of a multipart/form-data post body.
This:
conn.setRequestProperty("Connection", "Keep-Alive");
conn.setRequestProperty("ENCTYPE", "multipart/form-data");
conn.setRequestProperty("Content-Type", "multipart/form-data;boundary=" + boundary);
conn.setRequestProperty("file", fileName);
conn.setRequestProperty("gmail", names[0]);
conn.setRequestProperty("phn", phn);
sends a few request headers, which is fine for Content-Type and such, but not necessarily for the data you're posting. Lose all but the Content-Type line.
This:
dos.writeBytes(twoHyphens + boundary + lineEnd);
is the right way to start a post field (or file), you should output this for every posted field.
This:
dos.writeBytes(twoHyphens + boundary + twoHyphens + lineEnd);
signals that all fields have been sent, you should send this as the very last line.
Either use something like Wireshark to see what your final request looks like (either side will do; the device doing the request or the server handling it), or log your request so you can inspect it, and see if it is perfect. It has to be nearly perfect for the webserver/php to process it correctly.

Well, I never figured out how to send a simple string parameter with the file upload, but my workaround was to simply append the filename of the upload file to INCLUDE the string I wanted to send:
#SuppressWarnings("deprecation")
#Override
public void onCreate(Bundle savedInstanceState) {
super.onCreate(savedInstanceState);
addPreferencesFromResource(R.xml.preferences);
try{
Account[] accounts=AccountManager.get(this).getAccountsByType("com.google");
String myEmailid=accounts[0].toString(); Log.d("My email id that i want", myEmailid);
String[] names = new String[accounts.length];
for (int i = 0; i < names.length; i++) {
names[i] = accounts[i].name;
}
// THE DEVICE EMAIL ADDRESS WAS ONE OF THE DATA STRINGS I NEEDED TO SEND
File from = new File("/mnt/sdcard/","UPLOADFILE.DAT");
File to = new File("/mnt/sdcard/",names[0]+".BLOCK1."+"DATASTRING2"+".BLOCK2");
from.renameTo(to);
// DATASTRING2 is the SECOND piece of DATA I wanted to send
// SO YOU SEE I'M SIMPLY APPENDING THE UPLOAD FILE WITH THE DATA I WANT
// TO SEND WITH THE FILE, AND WHEN MY SERVER RECEIVES IT, I USE SOME SIMPLE
// PHP TO PARSE OUT WHATS BEFORE .BLOCK1. AND THEN .BLOCK2
StrictMode.ThreadPolicy policy = new StrictMode.ThreadPolicy.Builder().permitAll().build();
StrictMode.setThreadPolicy(policy);
try{
int serverResponseCode = 0;
final String upLoadServerUri = "http://MYURL/upload_file_functions.php";
String fileName = "/mnt/sdcard/"+names[0]+".BLOCK1."+"DATASTRING2"+".BLOCK2";
HttpURLConnection conn = null;
DataOutputStream dos = null;
String lineEnd = "\r\n";
String twoHyphens = "--";
String boundary = "*****";
int bytesRead, bytesAvailable, bufferSize;
byte[] buffer;
int maxBufferSize = 1 * 1024 * 1024;
File sourceFile = new File("/mnt/sdcard/"+names[0]+".BLOCK1."+"DATASTRING2"+".BLOCK2"");
// open a URL connection to the Servlet
FileInputStream fileInputStream = new FileInputStream(sourceFile);
URL url = new URL(upLoadServerUri);
// Open a HTTP connection to the URL
conn = (HttpURLConnection) url.openConnection();
conn.setDoInput(true); // Allow Inputs
conn.setDoOutput(true); // Allow Outputs
conn.setUseCaches(false); // Don't use a Cached Copy
conn.setRequestMethod("POST");
conn.setRequestProperty("Content-Type", "multipart/form-data;boundary=" + boundary);
dos = new DataOutputStream(conn.getOutputStream());
dos.writeBytes(twoHyphens + boundary + lineEnd);
dos.writeBytes("Content-Disposition: form-data; name=\"file\";filename=\""+ fileName + "\"" + lineEnd);
dos.writeBytes(lineEnd);
// create a buffer of maximum size
bytesAvailable = fileInputStream.available();
bufferSize = Math.min(bytesAvailable, maxBufferSize);
buffer = new byte[bufferSize];
// read file and write it into form...
bytesRead = fileInputStream.read(buffer, 0, bufferSize);
while (bytesRead > 0) {
dos.write(buffer, 0, bufferSize);
bytesAvailable = fileInputStream.available();
bufferSize = Math.min(bytesAvailable, maxBufferSize);
bytesRead = fileInputStream.read(buffer, 0, bufferSize);
}
// send multipart form data necesssary after file data...
dos.writeBytes(lineEnd);
dos.writeBytes(twoHyphens + boundary + twoHyphens + lineEnd);
// Responses from the server (code and message)
serverResponseCode = conn.getResponseCode();
String serverResponseMessage = conn.getResponseMessage();
Log.i("uploadFile", "HTTP Response is : "
+ serverResponseMessage + ": " + serverResponseCode);
//close the streams //
fileInputStream.close();
dos.flush();
dos.close();
}catch (Exception e){
}
}catch (Exception e){
}
}
Thanks for the help! (THICK WITH SARCASM..) Seriously, I have to code in python, C++, java, PHP, on linux, Android, iPhone, Windows, MAC and Ubuntu... my work has me building Triple-Boot OS box's, building apps in Android and iPhone to support my business needs, and thus I must know PHP html and the like, needed to configure my own server because I needed email-notification services, so I needed to run my own email server (Exim on Ubuntu Server), and I've had to learn all this in the past 6 months.
Forgive me if my code's not pretty, but I don't have the luxury of time, as I'm going INSANE trying to keep up in the land of AI, Object recognition, and trying to make the rent (though I've learned enough to do so..)
DC:)

Android upload many files / images at once to a servlet with parameters

This can be same and can be seen as duplicate since there are many questions about uploading an image. But I want to know how to upload MANY images at a time to a servlet.That said, if there are 6 images in SD card, all should be uploaded within one request,not one by one. Most of samples over the internet are regarding one image or one file. I want to know if images are stored in a ArrayList, how they can be uploaded ?
In Servlet
List<FileItem> multiparts = new ServletFileUpload(
new DiskFileItemFactory()).parseRequest(request);
for(FileItem item : multiparts){
if(!item.isFormField()){
String name = new File(item.getName()).getName();
item.write( new File(UPLOAD_DIRECTORY + File.separator + name));
}
}
This part works fine as I tested with normal JSP multiplart many images uploads.
In android for one image upload (took from another source):
FileInputStream fileInputStream = new FileInputStream(new File(exsistingFileName) );
URL url = new URL(urlString);
conn = (HttpURLConnection) url.openConnection();
conn.setDoInput(true);
// Allow Outputs
conn.setDoOutput(true);
// Don't use a cached copy.
conn.setUseCaches(false);
// Use a post method.
conn.setRequestMethod("POST");
conn.setRequestProperty("Connection", "Keep-Alive");
conn.setRequestProperty("Content-Type", "multipart/form-data;boundary="+boundary);
dos = new DataOutputStream( conn.getOutputStream() );
dos.writeBytes(twoHyphens + boundary + lineEnd);
dos.writeBytes("Content-Disposition: form-data; name=\"uploadedfile\";filename=\"" + exsistingFileName +"\"" + lineEnd);
dos.writeBytes(lineEnd);
Log.e("MediaPlayer","Headers are written");
bytesAvailable = fileInputStream.available();
bufferSize = Math.min(bytesAvailable, maxBufferSize);
buffer = new byte[bufferSize];
bytesRead = fileInputStream.read(buffer, 0, bufferSize);
while (bytesRead > 0)
{
dos.write(buffer, 0, bufferSize);
bytesAvailable = fileInputStream.available();
bufferSize = Math.min(bytesAvailable, maxBufferSize);
bytesRead = fileInputStream.read(buffer, 0, bufferSize);
}
dos.writeBytes(lineEnd);
dos.writeBytes(twoHyphens + boundary + twoHyphens + lineEnd);
BufferedReader in = new BufferedReader(new InputStreamReader(conn.getInputStream()));
String inputLine;
while ((inputLine = in.readLine()) != null)
tv.append(inputLine);
// close streams
Log.e("MediaPlayer","File is written");
fileInputStream.close();
dos.flush();
dos.close();
This uploads only one image. How this can be used to send many with one POST request.? any other sample code or tutorial please.

How to upload edit text field text into server

I want to upload image and edit text fields in android by using http connection,image is uploading fine edit text fields are not uploading.please help me.
FileInputStream fileInputStream = new FileInputStream(sourceFile);
URL url = new URL(upLoadServerUri);
// Open a HTTP connection to the URL
conn = (HttpURLConnection) url.openConnection();
conn.setDoInput(true); // Allow Inputs
conn.setDoOutput(true); // Allow Outputs
conn.setUseCaches(false); // Don't use a Cached Copy
conn.setRequestMethod("POST");
conn.setRequestProperty("Connection", "Keep-Alive");
conn.setRequestProperty("ENCTYPE", "multipart/form-data");
conn.setRequestProperty("Content-Type", "multipart/form-data;boundary=" + boundary);
/* conn.setRequestProperty("uploaded_img", fileName);
conn.setRequestProperty("email", etemail.getText().toString());
conn.setRequestProperty("phone", etphone.getText().toString());
conn.setRequestProperty("message", etmessage.getText().toString());
conn.setRequestProperty("name",etname.getText().toString());
*/
dos = new DataOutputStream(conn.getOutputStream());
dos.writeBytes(twoHyphens + boundary + lineEnd);
dos.writeBytes("Content-Disposition: form-data; name=\"uploaded_img\";filename=\""
+ fileName + "\"" + lineEnd);
dos.writeBytes(lineEnd);
dos.writeBytes(twoHyphens + boundary + lineEnd);
dos.writeBytes("Content-Disposition: form-data; name=\"email\""+ lineEnd);
dos.writeBytes(lineEnd);
dos.writeBytes(email);
dos.writeBytes(lineEnd);

If i am not wrong, you want to upload both image and text to server.
if so refer to below answer.
Hope this helps:
https://stackoverflow.com/a/11590652/2623853