public class mainTest {
public static void main(String[] args) throws Exception {
Scanner KB = new Scanner(System.in);
String VehiclesFile = "Vehicles.txt";
File file1 = new File(VehiclesFile);
Scanner infile1 = new Scanner(VehiclesFile);
Vehicle[] Vehicles = new Vehicle[0];
try {
Scanner scanner = new Scanner(file1);
int lineCount = 0;
while (scanner.hasNextLine()) {
lineCount++;
scanner.nextLine();
}
Vehicles = new Vehicle[lineCount];
scanner = new Scanner(file1);
int VehicleCount = 0;
while (scanner.hasNextLine()) {
String[] temp1 = scanner.nextLine().split(",");
// file has been read into temp1[] now to use Vehicles
// class type
Vehicles[VehicleCount] = new Vehicle();
Vehicles[VehicleCount].setregistration(temp1[0]);
Vehicles[VehicleCount].setmake(temp1[1]);
Vehicles[VehicleCount].setModel(temp1[2]);
Vehicles[VehicleCount].setyear(temp1[3]);
Vehicles[VehicleCount].setodometer(temp1[4]);
Vehicles[VehicleCount].setowner(temp1[5]);
VehicleCount++;
}
} catch (IOException e) {
// Print out the exception that occurred
System.out.println("Unable to find ");
}
//*******This is where I need to access the class to print****************
System.out.println (Vehicle.class.getClasses());
}
}
I cannot seem to understand how to reference a specific part of the class/array of class objects
The class for Vehicle is in defined with get/set so I didn't include the code.
System.out.println(Arrays.toString(Vehicles));
Make sure that the vehicle class has toString() method overriden. Otherwise it will just print out the references.
See:
How to override toString() properly in Java?
If you want to print off data from the Vehicle objects you'll have to loop through that array and call the getter methods you mentioned before.
It should be something like
for(Vehicle v : Vehicles)
{
System.out.print(v.getYear() + " " + v.getMake() + " " + v.getModel());
}
Seems to me like you're mixing up the concept of classes and objects. Class is short for classification, so a class is a type of something. An object is a single instance of a class. So it's a single item of a certain type.
What you have is an array of objects, not classes, and you want to print the information of each object. So say you have five vehicles in your array, you will have to call the function System.out.println(/*data to print*/) five times. One for each element in the array.
To omit repetition, you can use a loop:
for (int index = 0; index < Vehicles.length; ++i) {
System.out.println(Vehicle[index].getMake());
// do the same to print other attributes of the Vehicle class
}
Related
This question already has answers here:
How do I compare strings in Java?
(23 answers)
Closed 5 years ago.
I've created a class called Human that works properly, it takes 2 arguments, age and name, to create a human.
To create a Human with command line arguments, I want to write
java Filename -H "Anna" 25
And it should create a Human with thatname="Anna", and thatage=25, where 25 is an int.
The code I've written is creating a list called Argument, and iterating through it to find -H. I need to do this because I'm going to be using this to create different classes later. I just need help with the syntax on the lines where I've written thename=, and theage=, because I don't know how to get the next item in list, and next-next item in list.
public static void main(String[] args) {
ArrayList<String> Argument = new ArrayList<String>();
for (String item: args) {
Argument.add(item);
}
for (String item2: Argument) {
if (item2 == "-H") {
thatname = Argument.get(item2+1)
thatage = Argument.get(item2+2)
Human person = new Human(thatname,thatage);
System.out.println(person);
}
Why not just loop the args?
for ( int i = 0; i < args.length; i++ ) }
if (args[i].equals("-H")) {
i++;
thatName = args[i];
i++;
thatAge = args[i];
}
}
You should add some code to catch if one does not follow the rules you have set. Probably not enough arguments or other things humans do at the keyboard...
thatname = Argument.get(Argument.indexOf(item2)+1);
thatage = Argument.get(Argument.indexOf(item2)+2);
OR you know that 1st element is -H, 2nd element is name and 3rd is age, so you can use below code directly
thatname = Argument.get(1);
thatage = Integer.parseInt(Argument.get(2));
Your code have some problems, let me explain them to you for your assistance.
You cannot compare Strings with == you have to use equals method
in the String to compare between two Strings.
You have to use this for loop for(int i = 0; i < Argument.size();
i++) syntax so that you can iterate from zero to the number of
items in the list.
get method in ArrayList take the index as parameter and return the value at that index.
You can add i += 2 to skip the next two iterations which will
return the name and age value of the human. (It is optional)
Here is the working code:
public static void main(String[] args) {
ArrayList<String> Argument = new ArrayList<String>();
for (String item: args) {
Argument.add(item);
}
String currentItem;
for (int i = 0; i < Argument.size(); i++) { // it will iterate through all items
currentItem = Argument.get(i); // getting the value with index;
if (currentItem.equals("-H")) {
String thatname = Argument.get(i+1);
String thatage = Argument.get(i+2);
i += 2; // Skipping 2 iterations of for loop which have name and age human.
Human person = new Human(thatname,thatage);
System.out.println(person);
}
}
}
You cannot iterate the list using String. When iterating a list you required a index number like list.get(indexNumber);
public static void main(String[] args) {
ArrayList<String> Argument = new ArrayList<String>();
for (String item: args) {
Argument.add(item);
}
for (int i=0;i<args.length;i++) {
if (args[i].trim().equals("-H")) {
i++;
thatname = Argument.get(i);
i++;
thatage = Argument.get(i);
Human person = new Human(thatname,thatage);
System.out.println(person.getName()+" "+person.getAge());
}
Why using array list when you can directly use args? and while you're having only two parameters don't use a for loop access them direclty.
One thing you should know is that String is an object in java so comparing two Strings with == sign will return false even if they have same value (== will compare the id of the object), you should use .equale() function to compare the value of the object.
Check out this code :
public static void main(String[] args) {
if(args.length>0)
{
try{
if (args[0].equals("-H")) {
Human person = new Human( args[1],args[2]);
System.out.println(person);
}
}catch(ArrayIndexOutOfBoundsException exception) {
System.out.println("error with parameters");
}
}else
System.out.println("No command");
}
I am a novice Java programmer trying to use classes defined in a different file. So, I've written these two .java files:
First, there's MyLibrary.java:
package mymainprogram;
public class MyLibrary {
public class MyRecord {
int number;
char letter;
}
public static int TriplePlusThree(int input_number) {
return ((input_number*3) + 3);
}
}
Then, MyMainProgram.java:
package mymainprogram;
import java.util.Scanner;
public class MyMainProgram {
public static void main(String[] args) {
Scanner keyread = new Scanner(System.in);
System.out.print("Enter Number to Process: ");
int num = keyread.nextInt();
int result = MyLibrary.TriplePlusThree(num);
System.out.println("3x + 3 = "+result);
String letters = "ABCDEFGHIJ";
MyLibrary.MyRecord[] TenRecs = new MyLibrary.MyRecord[10];
for (int i = 0; i < 10; i++) {
TenRecs[i].number = i; //NullPointerException here
TenRecs[i].letter = letters.charAt(i);
}
}
}
I had no problem getting the method to work just fine; now my goal is to create an array where each member of the array has an integer and character. (Note: I'm not looking for better ways to accomplish this objective; I'm merely using this trivial example to try to get this working).
When I tried to run my program, I got:
java.lang.NullPointerException
I researched this, and found this page, which says:
If we try to access the objects even before creating them, run time errors would occur. For instance, the following statement throws a NullPointerException during runtime which indicates that [this array] isn't yet pointing to [an] object. The objects have to be instantiated using the constructor of the class and their references should be assigned to the array elements in the following way.
studentArray[0] = new Student();
So, I tried to do that in my Main Program:
MyRecordArray[0] = new MyLibrary.MyRecord();
but that gives this error:
an enclosing instance that contains MyLibrary.MyRecord is required
That error message led me to this Stack Exchange question, which says:
you have to create an object of X class (outer class) and then use objX.new InnerClass() syntax to create an object of Y class.
X x = new X();
X.Y y = x.new Y();
So, in accordance with that answer, I've added these two lines to my program:
MyLibrary mylibrary = new MyLibrary();
MyLibrary.MyRecord myrecord = mylibrary.new MyRecord();
Those lines don't give any warnings or compilation errors, so I feel like I'm one step closer, but I'm still trying to figure out how to make an array. I know if I wanted to make an array of integers, I would simply do this:
int[] TenInts = new int[10];
So, I've tried things like:
myrecord[] TenRecs = new myrecord[10];
MyRecord[] TenRecs = new MyRecord[10];
But nothing is working, and I feel like I'm grasping at straws now. I get the feeling that the right set of eyes could solve this pretty quickly.
You need to declare the inner class as static.
You can modify the code as follows to suit your requirements:
This is the code for MyLibrary
public class MyLibrary {
public static class MyRecord{
int number;
char letter;
public MyRecord(){
number = 0;
letter = '\0';
}
public MyRecord(int number, char letter){
this.number = number;
this.letter = letter;
}
}
public static int TriplePlusThree(int input_number){
return (input_number * 3 + 3);
}
}
This is the code for the MyMainProgram
import java.util.Scanner;
public class MyMainProgram {
public static void main(String[] args){
Scanner in = new Scanner(System.in);
System.out.println("Enter number to process");
int num = in.nextInt();
System.out.println("3x + 3 = " + MyLibrary.TriplePlusThree(num));
String letters = "ABCDEFGHIJ";
MyLibrary.MyRecord[] TenRecords = new MyLibrary.MyRecord[2];
for (int i=0; i<TenRecords.length; i++){
TenRecords[i] = new MyLibrary.MyRecord();
TenRecords[i].number = i;
TenRecords[i].letter = letters.charAt(i);
}
// Printing class records
for (int i=0; i<TenRecords.length; i++){
System.out.println("Printing records of record " + i + " : ");
System.out.println("Number : " + TenRecords[i].number);
System.out.println("Letter : " + TenRecords[i].letter);
}
in.close();
}
}
You can create the instance of the inner class as follows:
TenRecords[i] = new MyLibrary.MyRecord();
Hope this helps.
The nested class MyRecord contains a hidden reference to the outer class MyLibrary and therefore must be associated with an instance of MyLibrary. This way MyRecord can access private members of MyLibrary.
MyLibrary.MyRecord myrecord = mylibrary.new MyRecord();
Wow, this is funny syntax. In all my years of java programming, I never used such a construct. Typically, you would create objects of inner classes (MyRecord) within the outer class (MyLibrary). Another common thing is to declare the inner class as static which would eliminate the need for an instance of the outer class.
MyRecord[] TenRecs = new MyRecord[10];
This will create an array where all the elements are NULL. You have to initialize each of them (e.g. with a loop).
If you initialize MyRecord[10] the array has null objects. You still have to initialize each element in the array to a new MyRecord object. Otherwise you will get the NPE.
one way to do is : List<MyRecord> TenRecs = new ArrayList<MyRecord>();
TenRecs.add( new MyRecord() );
or for ( int i = 0; i < 10; i++ ) TenRecs[i] = new MyRecord();
also if you add an import statement : import mymainpackage.MyLibrary.MyRecord; You don't need to do mylibrary.new MyRecord(); just do new MyRecord();
You have to create each object in array before initialize. Refer to this link.
Create each object like this.
MyLibrary outer = new MyLibrary();
TenRecs[i] = outer.new MyRecord();
Full code:
MyLibrary.MyRecord[] TenRecs = new MyLibrary.MyRecord[10];
for (int i = 0; i < 10; i++) {
MyLibrary outer = new MyLibrary();
TenRecs[i] = outer.new MyRecord();
TenRecs[i].number = i;
TenRecs[i].letter = letters.charAt(i);
}
There are several points you need to note.
First, difference between a instance inner class and a static inner class.
An instance inner class, declared without static modifier,
public class OutterClass {
public class InstanceInnerClass {}
}
should be created like this:
OutterClass outter = new OutterClass();
InstanceInnerClass iInner = outter.new InstanceInnerClass();
while a static inner class, declared with static modifier,
public class OutterClass {
public static class StaticInnerClass {}
}
should be created like this:
StaticInnerClass sInner = new OutterClass.StaticInnerClass();
Secondly, you accessed an array entry before it is filled
MyLibrary library = new MyLibrary();
MyLibrary.MyRecord[] TenRecs = new MyLibrary.MyRecord[10];
for (int i = 0; i < 10; i++) {
// Create new instance
TenRecs[i] = library.new MyRecord();
TenRecs[i].number = i;
TenRecs[i].letter = letters.charAt(i);
}
so I have this code that input stuff and store it to an listarray
public class manage extends admin{
public ArrayList<Game> thegame = new ArrayList<Game>();
public List<Game> ajout_jeux() {
boolean loop = true;
while(loop) {
Scanner agame = new Scanner(System.in);
System.out.print("name: \n");
String Cgame = agame.nextLine();
Scanner qty = new Scanner(System.in);
System.out.print("the qty: \n");
int CQty = qty.nextInt();
Console wertgame = new Console(Cgame,Cqty);
thegame.add(new Game(Cgame,Cqty));
System.out.println("continue?");
Scanner autre = new Scanner(System.in);
int continu = other.nextInt();
if(continu==1) {
}
else if(continu==2) {
Main.menu();
}
}
return thegame;
}
and a method in this class that should print the array:
public void information(List<Game> thegame) {
System.out.print(thegame);
}}
And then,from another class I need to call it like this
manage management = new manage(); //the instance
manage.information();
Theres no erros,however,even if I take care of creating an object and putting it in array before trying to print the array, when I call manage.information(); it just return an empty [] list.I dont know why?
heres the class that needs to calls it
public class themenu{
public static void adminmenu(){
boolean loop=true;
while(loop){
System.out.print("1:List items \n");
System.out.print("4:Add \n");
System.out.print("6:Infos \n");
System.out.print("7:Quit \n");
System.out.print("Choice:");
Scanner choiceuser = new Scanner(System.in);
String userchoix = choiceuser.nextLine();
manage management = new manage();
if(userchoice.equals("1")){
manage.information(thegame); //here I get the error
}
else if(userchoice.equals("4")){
manage.ajout_jeux();
}
thank you
instead of calling the type of the object
manage management = new manage(); //the instance
manage.information();
you should call the method inside the object and pass an array to it.
management.information(new ArrayList<Game>());
You need to call manage.ajout_jeux before manage.information(); and then pass that list to information method. But please note that currently the return type of ajout_jeux method isList<Jeux> while you are returning from inside the method List<Game>. So you need to fix that also. Method invocation will look like this
manage management = new manage(); //the instance
manage.information(yourListName);
I'm having trouble with calling a method. The basis of the program is to read in data from data.txt, grab the name token given, then all of the grades that follow, then implement some operations on the grades to give details of the person's grades. I do all of the methods in a separate file named Grades.java, which has the Grades class. I'm just having trouble because I MUST have the testGrades method in my code (which I don't find necessary). I have done everything I need to do for the results to be perfect in a different program without having two different .java files. But it's necessary to do it this way. I think I have mostly everything pinned down, I'm just confused on how to implement and call the testGrades method. I commented it out and have the question on where it is in the program. Quite new to classes and objects, and java in general. Sorry for the lame question.
public class Lab2 {
public static void main(String[] args) {
Scanner in = null; //initialize scanner
ArrayList<Integer> gradeList = new ArrayList<Integer>(); //initialize gradeList
//grab data from data.txt
try {
in = new Scanner(new File("data.txt"));
} catch (FileNotFoundException exception) {
System.err.println("failed to open data.txt");
System.exit(1);
}
//while loop to grab tokens from data
while (in.hasNext()) {
String studentName = in.next(); //name is the first token
while (in.hasNextInt()) { //while loop to grab all integer tokens after name
int grade = in.nextInt(); //grade is next integer token
gradeList.add(grade); //adding every grade to gradeList
}
//grab all grades in gradeList and put them in an array to work with
int[] sgrades = new int[gradeList.size()];
for (int index = 0; index < gradeList.size(); index++) {
sgrades[index] = gradeList.get(index); //grade in gradeList put into grades array
}
//testGrades(sgrades); How would I implement this method call?
}
}
public static void testGrades(Grades grades) {
System.out.println(grades.toString());
System.out.printf("\tName: %s\n", grades.getName());
System.out.printf("\tLength: %d\n", grades.length());
System.out.printf("\tAverage: %.2f\n", grades.average());
System.out.printf("\tMedian: %.1f\n", grades.median());
System.out.printf("\tMaximum: %d\n", grades.maximum());
System.out.printf("\tMininum: %d\n", grades.minimum());
}
}
This is a little snippet of the beginning of the Grades.java file
public class Grades {
private String studentName; // name of student Grades represents
private int[] grades; // array of student grades
public Grades(String name, int[] sgrades) {
studentName = name; // initialize courseName
grades = sgrades; // store grades
}
public String getName() {
return studentName;
} // end method getName
public int length() {
return grades.length;
}
well your test grades take a Grades object so you need to construct a Grades object using your data and pass it to your test grades method
i.e.
Grades myGrade = new Grades(studentName,sgrades);
testGrades(myGrade);
It looks like what you need to do is have some type of local variable in your main method, that would hold your custom Grade type. So you need add a line like..
Grades myGrades = new Grades(studentName, sgrades);
Then you can call your testGrades method with a line like...
testGrades(myGrades);
Looks like you may also need a toString method in your Grades class.
Seems like homework, so I tried to leave a bit to for you to figure out :)
I am very new to Java and writing this program to shuffle words and fix the suffle words. The following is my program. After I call mix(), I would like to be able to assign the output of word to team array within main.
For some reason, I can call mix() it works but I cannot access word which is in the shuffle function. Since I am in main and all these function within main, I thought I can access the variables. Any ideas what I am missing here?
import java.util.Scanner;
import java.io.*;
import java.util.*;
public class Project2
{
public static void main(String[] args)
{
System.out.println("Select an item from below: \n");
System.out.println("(1) Mix");
System.out.println("(2) Solve");
System.out.println("(3) Quit");
int input;
Scanner scan= new Scanner(System.in);
input = scan.nextInt();
//System.out.println(input);
if(input==1) {
mix();
System.out.println(word);
char team[]=word.toCharArray();
for(int i=0;i<team.length;i++){
System.out.println("Data at ["+i+"]="+team[i]);
}
}
else{
System.out.println("this is exit");
}
}
static void mix()
{
String [] lines=new String[1000];//Enough lines.
int counter=0;
try{
File file = new File("input.txt");//The path of the File
FileReader fileReader1 = new FileReader(file);
BufferedReader buffer = new BufferedReader(fileReader1);
boolean flag=true;
while(true){
try{
lines[counter]=buffer.readLine();//Store a line in the array.
if(lines[counter]==null){//If there isn't any more lines.
buffer.close();
fileReader1.close();
break;//Stop reading and close the readers.
}
//number of lines in the file
//lines is the array that holds the line info
counter++;
}catch(Exception ex){
break;
}
}
}catch(FileNotFoundException ex){
System.out.println("File not found.");
}catch(IOException ex){
System.out.println("Exception ocurred.");
}
int pick;
Random rand = new Random();
pick = rand.nextInt(counter ) + 0;
System.out.println(lines[pick]);
///scramble the word
shuffle(lines[pick]);
}
static void shuffle(String input){
List<Character> characters = new ArrayList<Character>();
for(char c:input.toCharArray()){
characters.add(c);
}
StringBuilder output = new StringBuilder(input.length());
while(characters.size()!=0){
int randPicker = (int)(Math.random()*characters.size());
output.append(characters.remove(randPicker));
}
String word=output.toString();
}
}
Return string value from shuffle() method using return statement:
static String shuffle(String input) {
// . . .
return output.toString();
}
...and then use it in mix:
String word = shuffle(lines[pick]);
But it is better to read basic java tutorials before programming.
In Java, variables cannot be seen outside of the method they are initialized in. For example, if I declare int foo = 3; in main, and then I try to access foo from another method, it won't work. From the point of view of another method, foo does not even exist!
The way to pass variable between methods is with the return <variable> statement. Once the program reaches a return statement, the method will quit, and the value after the return (perhaps foo) will be returned to the caller method. However, you must say that the method returns a variable (and say what type is is) when you declare that method (just like you need to say void when the method does not return anything!).
public static void main(String[] args){
int foo = 2;
double(foo); //This will double foo, but the new doubled value will not be accessible
int twoFoo = double(foo); //Now the doubled value of foo is returned and assigned to the variable twoFoo
}
private static int double(int foo){//Notice the 'int' after 'static'. This tells the program that method double returns an int.
//Also, even though this variable is named foo, it is not the same foo
return foo*2;
}
Alternatively, you could use instance variable to have variables that are accessible by all the methods in your class, but if you're new to Java, you should probably avoid these until you start learning the basics of object-oriented programming.
Hope this helps!
-BritKnight