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How to get date from milliseconds

Hi All I have a requirement where i need to check date with system date value but the date value i have in DB is in milliseconds so below are my code but the problem is the system date which i get display month value incorrect its display month value one month less .
Date now = new Date();
Long nowLong = now.getTime() / 1000;
Integer unixTime = nowLong.intValue();
Calendar cal;
cal = Calendar.getInstance();
cal.setTimeInMillis(unixTime * 1000L);
Integer day = cal.get(Calendar.DAY_OF_MONTH);
Integer month = cal.get(Calendar.MONTH);
Integer hour = cal.get(Calendar.HOUR);
Integer minute = cal.get(Calendar.MINUTE);
String amPm = (cal.get(Calendar.AM_PM) == Calendar.PM) ? "PM" : "AM";
Integer year = cal.get(Calendar.YEAR);
System.out.println("day :" + day);
System.out.println("month :" + month);
System.out.println("hour " + hour);
System.out.println("minute " + minute);
System.out.println("amPm " + amPm);
System.out.println("year " + year);
For this the output is
day :3
month :4
hour 3
minute 13
amPm PM
year 2016
but output is not correct . Can any one help me .

In Java the value returned by cal.get(Calendar.MONTH)is zero bazed. Thenf JANUARY = 0, FEBRUARY = 0, ... (documentation here)
Try this :
Integer month = cal.get(Calendar.MONTH) + 1;
Or this :
System.out.println("month :" + (month.intValue() + 1));
Note the creation of your calendar can be simpler:
Calendar cal = Calendar.getInstance();
cal.setTimeInMillis(System.currentTimeMillis());

try using LocalDate . there has been lot of changes to Date Time api in java 8 .you can do it better with LocalDate.
LocalDate today = LocalDate.now(); //current date
today.getMonth() //getMonth as a string
today.getMonth()//getMonthValue in an int
today.getDayOfWeek() // get the date in a string format
today.getDayOfMonth() //get the date as an int.
today.getYear()//get the year

I am getting this error when I run the below java code

I'm getting this error when I run the below java code
Exception in thread "main" java.lang.Error: Unresolved compilation
problem: at my.time.main(time.java:9)
package my;
package com.mkyong.date;
import java.text.SimpleDateFormat;
import java.util.Date;
public class time {
public static void main(String[] args) {
String dateStart = "01/14/2012 09:29:58";
String dateStop = "01/15/2012 10:31:48";
//HH converts hour in 24 hours format (0-23), day calculation
SimpleDateFormat format = new SimpleDateFormat("MM/dd/yyyy HH:mm:ss");
Date d1 = null;
Date d2 = null;
try {
d1 = format.parse(dateStart);
d2 = format.parse(dateStop);
//in milliseconds
long diff = d2.getTime() - d1.getTime();
long diffSeconds = diff / 1000 % 60;
long diffMinutes = diff / (60 * 1000) % 60;
long diffHours = diff / (60 * 60 * 1000) % 24;
long diffDays = diff / (24 * 60 * 60 * 1000);
System.out.print(diffDays + " days, ");
System.out.print(diffHours + " hours, ");
System.out.print(diffMinutes + " minutes, ");
System.out.print(diffSeconds + " seconds.");
} catch (Exception e) {
e.printStackTrace();
}
}
}

You set packagetwo times:
package my;
package com.mkyong.date;
It is only allowed one time. You should set your package to match your classes path.

Try to set the package my and import the class date:
package my;
import com.mkyong.date;

Java timeformat and time duration

Output I need is this:
Time in: 07:00 AM
Time out: 11:30 PM
Time duration: 16 hours and 30 minutes
User needs to enter in time in and time out, How do I do it? I searched and it seems that I need DateFormat hh:mm: a but I don't know how to use it. Help please. thanks.

DateFormat dateFormat = new SimpleDateFormat("hh:mm a");
long timeIn = dateFormat.parse("07:00 AM").getTime();
long timeOut = dateFormat.parse("11:30 PM").getTime();
long duration = (timeOut - timeIn) / 1000 / 60; // in minutes
long hours = duration / 60;
long minutes = duration % 60;
System.out.println("Time duration: " + hours + " hours and " + minutes + " minutes");
Prints:
Time duration: 16 hours and 30 minutes

Hi you can try something like this
public String timeDifference(String timeIn,String timeOut){
DateFormat dateFormat=new SimpleDateFormat("hh:mm a");
String result;
Date d=dateFormat.parse("08:14 AM"); //First input time in
Date d1=dateFormat.parse("09:00 PM"); //second input time out
long min=TimeUnit.MINUTES.convert(d1.getTime()-d.getTime(),TimeUnit.MILLISECONDS);
System.out.println(min);
if(min>=60){
long hrs=min/60;
result=String.valueOf(min/60)+" hours "+String.valueOf(min%60)+" minutes";
}
else
result=min+" minutes";
System.out.println(result);
return result;
}

You can trying something like this:
import java.text.DateFormat;
import java.text.SimpleDateFormat;
import java.util.Calendar;
import java.util.Date;
public class TimeTracker {
static Date getTimeIn() {
//There you must to use your specific Time In getting from user
//It's just example
Calendar calendarIn = Calendar.getInstance();
calendarIn.set(Calendar.HOUR_OF_DAY, 7);
calendarIn.set(Calendar.MINUTE, 00);
calendarIn.set(Calendar.SECOND, 0);
calendarIn.set(Calendar.MILLISECOND, 0 );
return calendarIn.getTime();
}
static Date getTimeOut() {
//There you must to use your specific Time In getting from user
//It's just example
Calendar calendarOut = Calendar.getInstance();
calendarOut.set(Calendar.HOUR_OF_DAY, 23);
calendarOut.set(Calendar.MINUTE, 30);
calendarOut.set(Calendar.SECOND, 0);
calendarOut.set(Calendar.MILLISECOND, 0);
return calendarOut.getTime();
}
public static void main(String[] args) throws InterruptedException {
DateFormat formatterTime = new SimpleDateFormat("hh:mm a");
long timeDuration = getTimeOut().getTime() - getTimeIn().getTime();
System.out.println("Time in: " + formatterTime.format(getTimeIn()));
System.out.println("Time out: " + formatterTime.format(getTimeOut()));
System.out.println("Time duration: " +
((timeDuration / (1000*60*60)) % 24)
+ " hours and " +
((timeDuration / (1000*60)) % 60) + " minutes");
}
}
Output is:
Time in: 07:00 AM
Time out: 11:30 PM
Time duration: 16 hours and 30 minutes

Calculating difference in days between dates

In my code the difference between dates is wrong, because it should be 38 days instead of 8 days. How can I fix?
package random04diferencadata;
import java.text.ParseException;
import java.text.SimpleDateFormat;
import java.util.Date;
public class Random04DiferencaData {
/**
* http://www.guj.com.br/java/9440-diferenca-entre-datas
*/
public static void main(String[] args) {
SimpleDateFormat sdf = new SimpleDateFormat("hh:mm dd/mm/yyyy");
try {
Date date1 = sdf.parse("00:00 02/11/2012");
Date date2 = sdf.parse("10:23 10/12/2012");
long differenceMilliSeconds = date2.getTime() - date1.getTime();
System.out.println("diferenca em milisegundos: " + differenceMilliSeconds);
System.out.println("diferenca em segundos: " + (differenceMilliSeconds / 1000));
System.out.println("diferenca em minutos: " + (differenceMilliSeconds / 1000 / 60));
System.out.println("diferenca em horas: " + (differenceMilliSeconds / 1000 / 60 / 60));
System.out.println("diferenca em dias: " + (differenceMilliSeconds / 1000 / 60 / 60 / 24));
} catch (ParseException e) {
e.printStackTrace();
}
}
}

The problem is in the SimpleDateFormat variable. Months are represented by Capital M.
Try change to:
SimpleDateFormat sdf = new SimpleDateFormat("hh:mm dd/MM/yyyy");
For more, see this javadoc.
Edited:
And here is the code if you want to print the difference the way you commented:
SimpleDateFormat sdf = new SimpleDateFormat("hh:mm dd/MM/yyyy");
try {
Date date1 = sdf.parse("00:00 02/11/2012");
Date date2 = sdf.parse("10:23 10/12/2012");
long differenceMilliSeconds = date2.getTime() - date1.getTime();
long days = differenceMilliSeconds / 1000 / 60 / 60 / 24;
long hours = (differenceMilliSeconds % ( 1000 * 60 * 60 * 24)) / 1000 / 60 / 60;
long minutes = (differenceMilliSeconds % ( 1000 * 60 * 60)) / 1000 / 60;
System.out.println(days+" days, " + hours + " hours, " + minutes + " minutes.");
} catch (ParseException e) {
e.printStackTrace();
}
Hope this help you!

How to calculate the number of years in spring framework java [duplicate]

This question already has answers here:
Closed 10 years ago.
Possible Duplicate:
How do I calculate someone's age in Java?
I'm creating an application in spring framework which calculates the age after a user enters their birthdate to a UI. So far my getAge bean has the gets and sets, but how do I right the calculation method syntatically?
import java.util.*;
public class ageBean {
Date birthdate;
public Date getBirthday(){
return birthdate;
}
public void setBirthdate(Date birthdate){
this.birthdate=birthdate;
}
//method goes here
}

There is nothing with Spring . if you want to calculate current age,
long diff = new Date().getTime() - birthdate.getTime(); // current date - b'day
long diffSeconds = diff / 1000;
long diffMinutes = diff / (60 * 1000);
long diffHours = diff / (60 * 60 * 1000);
System.out.println("Time in seconds: " + diffSeconds + " seconds.");
System.out.println("Time in minutes: " + diffMinutes + " minutes.");
System.out.println("Time in hours: " + diffHours + " hours.");

Use java.util.Calendar to ensure leap years, varying numbers of days in month etc. are accounted for,
int thisYear = Calendar.getInstance().get(Calendar.YEAR);
Calendar birthdateCalendar = Calendar.getInstance();
birthdateCalendar.setTime(birthdate);
int birthYear = birthdateCalendar.get(Calendar.YEAR);
int yearsSinceBirth = thisYear - birthYear;

You can try this piece of code by replacing date1 with your birthdate,
Date date= new Date(System.currentTimeMillis());
date.setYear(date.getYear()+1900);
// this is done as currentTimeMillis returns the time elapsed from 1 Jan 1970s
Date date1=new Date(2000,10,15);
long timegap =date.getTime()-date1.getTime();
long milliSecsInAYear = 31536000000L;
System.out.println(timegap/milliSecsInAYear+"years" +((date.getTime()-date1.getTime())%milliSecsInAYear)/(milliSecsInAYear/365)+"days" );
note : I have taken a year as having 365 days