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Inject Resolved Properties Object to Another Bean

I'd like to inject a java.util.Properties object into another bean through XML config. I have tried the solution listed here without success, presumably because the bean is being injected before the property resolution occurs. Is there a way that I can force the java.util.Properties object to be resolved before being injected to my class?
Below is the trimmed/edited version of what I have. PropertiesConsumingClass does receive the merged, but unresolved properties of a, b, and c properties files.
<bean id="propertyConfigurer" class="org.springframework.beans.factory.config.PropertyPlaceholderConfigurer">
<property name="properties" ref="allProperties" />
</bean>
<bean id="allProperties" class="org.springframework.beans.factory.config.PropertiesFactoryBean">
<property name="propertiesArray">
<util:list>
<util:properties location="classpath:a.properties" />
<util:properties location="classpath:b.properties" />
<util:properties location="classpath:c.properties" />
</util:list>
</property>
</bean>
<bean class="PropertiesConsumingClass">
<constructor-arg index="0" ref="allProperties" />
</bean>

Your example doesn't work because what Spring calls a property isn't the same thing as what Java calls a property. Basically, a Spring property lives in a <property> tag, and this is what gets resolved by PropertyPlaceholderConfigurer. You can also use property placeholders inside #Value annotations. Either way you have a string with ${} placeholders that get resolved, possibly the string is converted to the correct type, and injected into your bean.
java.util.Properties are used to resolve placeholders in Spring properties, but they aren't considered for resolution themselves. Any properties in a., b., or c.properties will be substituted into Spring property placeholders, but PropertyPlaceholderConfigurer doesn't know or care if the values it gets from those files have ${} in them.
Now, Spring Boot does resolve placeholders inside its config files, but it has special sauce to accomplish that. It's also a very opinionated library that wants to control your app's lifecycle and does lots of magical things behind the scenes, so it's very hard to adopt or drop except at the very beginning of a project.

Determining properties available for Spring Beans?

In the Spring Framework, how do you determine what "properties" and other related values are available to be set in the context.xml file(s)? For example, I need to set the isolation level of a TransactionManager. Would that be:
<property name="isolation" value="SERIALIZABLE" />
<property name="isolation_level" value="Isolation.SERIALIZABLE" />
or some other values?

Each bean represents a class, which you can easily find by class="" attribute. Now you simply open JavaDoc or source code of that class and look for all setters (methods following setFooBar() naming convention). You strip set prefix and un-capitalize the first character, making it fooBar. These are your properties.
In your particular case you are probably talking about PlatformTransactionManager and various implementations it has.

Putting the properties into . properties file is a good way of handling.
First define a properties file in your project structure. It is better to put .properties file with the same directory as spring applicationContext.xml.
Your properties file may seem like this :
isolation = "SERIALIZABLE"
isolation_level = Isolation.SERIALIZABLE
You can access this properties file by defining a spring bean like :
<bean id="applicationProperties" class="org.springframework.beans.factory.config.PropertyPlaceholderConfigurer">
<property name="location" value="classpath:YourProperties.properties"/>
</bean>
Finally you can access these properties inside Spring beans like :
<bean id="BeanName" class="YourClass">
<property name="PropertyName1" value="${isolation}"/>
<property name="PropertyName" value="${isolation_level}"/>
</bean>
There is another way to inject these values using annotations.

How do I load a bean value from a file with job parameter substitution?

In my spring batch project I can do something like this:
<bean id="exampleTasklet" class="my.custom.Tasklet">
<property name="message" value="job parameter value: #{jobParameters['arg1']}"/>
</bean>
and the message property will have a value taken from the spring batch job parameters. However, the value that I actually want to assign is very large and I don't want to put it in the xml file. I know this syntax doesn't work, but I would like to do something like:
<bean id="exampleTasklet" class="my.custom.Tasklet">
<property name="message" read-value-from-file="/path/to/file.txt"/>
</bean>
and that file would contain the line "job parameter value: #{jobParameters['arg1']}" which spring will parse as if the file content was in a value="" attribute.
Is there a nice way to do this?

I think what you are looking for is a PropertyPlaceholderConfigurer.
<bean class="org.springframework.beans.factory.config.PropertyPlaceholderConfigurer">
<property name="location" value="/path/to/file.properties" />
<property name="placeholderPrefix" value="#{" />
<property name="placeholderSuffix" value="}" />
</bean>
This is run by Spring as a bean processor and will attempt to resolve placeholder tokens. There is a default instance that will resolve against system properties, using this notation: ${propertyname}. For your notation, you would need to specify the placeholderPrefix/Suffix. When there are multiple bean processors, the order is determined by the order property. By default, if a processor fails to resolve a placeholder, execution fails, but this can be altered by setting ignoreUnresolvablePlaceholders. Since the mechanism is property driven, you probably want to consider a notation like:
<property name="message" value="job parameter value: #{jobParameters.arg1}"/>
Or, if what you're trying to convey is that arg1 is also a parameter, you might try:
<property name="message" value="job parameter value: #{jobParameters.${arg1}}"/>
Spring loops over the bean processors until no replacements are performed, or an exception is raised. So defining a property as ${something.${orOther}} is valid.

I would suggest you to use a String as file name and in your bean open that file.
I'm not sure if I get your problem right. I'm just suggesting something like Spring MessageBundle
Something like this:
<bean id="exampleTasklet" class="my.custom.Tasklet">
<property name="messagePath" location="/path/to/file.txt"/>
</bean>
And in your exampleTasklet read the file and do your thing (I'm not sure what it is)

If anybody came here to do something like this from a properties-file:
If you want a property from a .properties-file to appear in the JobParameters, you won't find ready-to-use solution. You can do the following:
Wrap a bean around your properties file.
Pass this bean to another one which has access to the JobParameters and can pump the properties from the file into that class.
Then you should be able to access your properties with Spring's Expression Language and do something like:
<bean id="myBean" class="my.custom.Bean">
<property name="prop" value="#{jobParameters['arg1']}"/>
</bean>
Alternatively, I think the solution proposed by Devon_C_Miller is much easier. You don't have the properties in your JobParameters then. But if the replacement in the XML configuration is the only thing you want, you only have to change your placeholders to:
${myPropFromFile}
Happy batching, everyone ;-)

Spring: Get inline bean by name

I would like to get inner bean by it's name. Is it possible with Spring API?
Right now I'm using such Spring 2.5 API
ConfigurableApplicationContext.getBean(String paramString)
Example of XML:
<bean id="parent" parent="t_Parent">
<property name="items">
<bean id="child" parent="t_Child">
<property name="ABC" value="test"/>
</bean>
</property>
</bean>
I would like to get inner (t_Child) bean by id "child". E.g. ConfigurableApplicationContext.getBean("child"). Spring can't find such bean (because it's inner). At the same time .getBean("parent") works fine.
Any thoughts?

You can't.
From the docs:
A element inside the or elements is used to define a so-called inner bean. An inner bean definition does not need to have any id or name defined, and it is best not to even specify any id or name value because the id or name value simply will be ignored by the container.
If you need it like that, define it as a regular bean.

You can't, but you can create you inner bean outside (so it's no longer an inner bean...) and then reference it inside the property:
<bean id="child" parent="t_Child">
<property name="ABC" value="test"/>
</bean>
<bean id="parent" parent="t_Parent">
<property name="items" ref="child"/>
</bean>

Apart from the other (mostly valid) answers and solutions, I guess the spring way would be to use the BeanWrapper interface:
final BeanWrapper bw =
new BeanWrapperImpl(applicationContext.getBean("parent"));
Object innerBean = bw.getPropertyValue("child");
But I guess that implies that there must be a getter for the property (not only a setter).
Reference:
BeanWrapper (javadoc, 2.5 version)
Bean manipulation and the BeanWrapper (reference, 2.5 version)

If you move up to Spring 3.x, you should be able to do this with the Spring Expression Language. There are examples of directly referencing a bean property from another property (like in link text). The code to do this from Java would be somewhat similar, although I can't find an exact example of this scenario.
However, I would say that if you're trying to use "getBean()", you're doing something wrong. You could just as easily use the SpEL in your context to define a bean or a bean property that references that inner bean.

spring - constructor injection and overriding parent definition of nested bean

I've read the Spring 3 reference on inheriting bean definitions, but I'm confused about what is possible and not possible.
For example, a bean that takes a collaborator bean, configured with the value 12
<bean name="beanService12" class="SomeSevice">
<constructor-arg index="0" ref="serviceCollaborator1"/>
</bean>
<bean name="serviceCollaborator1" class="SomeCollaborator">
<constructor-arg index="0" value="12"/>
<!-- more cargs, more beans, more flavor -->
</bean>
I'd then like to be able to create similar beans, with slightly different configured collaborators. Can I do something like
<bean name="beanService13" parent="beanService12">
<constructor-arg index="0">
<bean>
<constructor-arg index="0" value="13"/>
</bean>
</constructor>
</bean>
I'm not sure this is possible and, if it were, it feels a bit clunky. Is there a nicer way to override small parts of a large nested bean definition? It seems the child bean has to know quite a lot about the parent, e.g. constructor index.
This is a toy example - in practice the service is a large bean definition relying on many other collaborator beans, which have also other bean dependencies. For example, a chain of handlers were created with each bean referencing the next in the chain, which references the next. I want to create an almost identical chain with some small changes to handlers in the middle, how do I it?
I'd prefer not to change the structure - the service beans use collaborators to perform their function, but I can add properties and use property injection if that helps.
This is a repeated pattern, would creating a custom schema help?
Thanks for any advice!
EDIT: The nub of my question is, if I have a really large bean definition, with a complex hiearchy of beans being created (bean having properites that are bean etc.), and I want to create a bean that is almost the same with a few changes, how to I do it? Please mention if your solution has to use properites, or if constructor injection can be used.
Nested vs. top-level beans are not the issue (in fact, I think all the beans are top level in practice.)
EDIT2: Thank you for your answers so far. A FactoryBean might be the answer, since that will reduce the complexity of the spring context, and allow me to specify just the differences as parameters to the factory. But, pushing a chunk of context back into code doesn't feel right. I've heard that spring can be used with scripts, e.g. groovy - does that provide an alternative? Could the factory be created in groovy?

I'm not entirely sure what you are trying to achieve. I don't think you can achieve exactly what you want without creating your own custom schema (which is non-trivial for nested structures), but the following example is probably pretty close without doing that.
First, define an abstract bean to use as a template for your outer bean (my example uses a Car as the outer bean and an Engine as the inner bean), giving it default values that all other beans can inherit:
<bean id="defaultCar" class="Car" abstract="true">
<property name="make" value="Honda"/>
<property name="model" value="Civic"/>
<property name="color" value="Green"/>
<property name="numberOfWheels" value="4"/>
<property name="engine" ref="defaultEngine"/>
</bean>
Since all Honda Civics have the same engine (in my world, where I know nothing about cars), I give it a default nested engine bean. Unfortunately, a bean cannot reference an abstract bean, so the default engine cannot be abstract. I've defined a concrete bean for the engine, but mark it as lazy-init so it will not actually be instantiated unless another bean uses it:
<bean id="defaultEngine" class="Engine" lazy-init="true">
<property name="numberOfCylinders" value="4"/>
<property name="volume" value="400"/>
<property name="weight" value="475"/>
</bean>
Now I can define my specific car, taking all the default values by referencing the bean where they are defined via parent:
<bean id="myCar" parent="defaultCar"/>
My wife has a car just like mine, except its a different model (again, I know nothing about cars - let's assume the engines are the same even though in real life they probably are not). Instead of redefining a bunch of beans/properties, I just extend the default car definition again, but override one of its properties:
<bean id="myWifesCar" parent="defaultCar">
<property name="model" value="Odyssey"/>
</bean>
My sister has the same car as my wife (really), but it has a different color. I can extend a concrete bean and override one or more properties on it:
<bean id="mySistersCar" parent="myWifesCar">
<property name="color" value="Silver"/>
</bean>
If I liked racing minivans, I might consider getting one with a bigger engine. Here I extend a minivan bean, overriding its default engine with a new engine. This new engine extends the default engine, overriding a few properties:
<bean id="supedUpMiniVan" parent="myWifesCar">
<property name="engine">
<bean parent="defaultEngine">
<property name="volume" value="600"/>
<property name="weight" value="750"/>
</bean>
</property>
</bean>
You can also do this more concisely by using nested properties:
<bean id="supedUpMiniVan" parent="myWifesCar">
<property name="engine.volume" value="600"/>
<property name="engine.weight" value="750"/>
</bean>
This will use the "defaultEngine". However, if you were to create two cars this way, each with different property values, the behavior will not be correct. This is because the two cars would be sharing the same engine instance, with the second car overriding the property settings set on the first car. This can be remedied by marking the defaultEngine as a "prototype", which instantiates a new one each time it is referenced:
<bean id="defaultEngine" class="Engine" scope="prototype">
<property name="numberOfCylinders" value="4"/>
<property name="volume" value="400"/>
<property name="weight" value="475"/>
</bean>
I think this example gives the basic idea. If your data structure is complex, you might define multiple abstract beans, or create several different abstract hierarchies - especially if your bean hierarchy is deeper than two beans.
Side note: my example uses properties, which I believe are much clearer to understand, both in Spring xml and in Java code. However, the exact same technique works for constructors, factory methods, etc.

Your example will not work as specified, because the nested bean definition has no class or parent specified. You'd need to add more information, like this:
<bean name="beanService13" parent="beanService12">
<constructor-arg index="0">
<bean parent="beanBaseNested">
<constructor-arg index="0" value="13"/>
</bean>
</constructor>
Although I'm not sure if it's valid to refer to nested beans by name like that.
Nested bean definitions should be treated with caution; they can quickly escalate into unreadability. Consider defining the inner beans as top-level beans instead, which would make the outer bean definitions easier to read.
As for the child beans needing to know the constructor index of the parent bean, that's a more basic problem with Java constructor injection, in that Java constructor arguments cannot be referred to by name, only index. Setter injection is almost always more readable, at the cost of losing the finality of constructor injection.
A custom schema is always an option, as you mentioned, although it's a bit of a pain to set up. If you find yourself using this pattern a lot, it might be worth the effort.

Have you thought of using a factory instead?
You can config beans to have a factory and you could encode the varying parameters in the factory creation...

To expand on the factory pattern from Patrick: you can use a prototype bean to get pre-wired dependencies:
<bean id="protoBean" scope="prototype">
<property name="dependency1" ref="some bean" />
<property name="dependency2" ref="some other bean" />
...
</bean>
Now, this works best if you use setter injection (rather than constructor arguments), i'm not sure you can even do it you require constructor args.
public class PrototypeConsumingBean implements ApplicationContextAware {
public void dynmicallyCreateService(String serviceParam) {
// creates a new instance because scope="prototype"
MyService newServiceInstance = (MyService)springContext.getBean("protoBean");
newServiceInstance.setParam(serviceParam);
newServiceInstance.mySetup();
myServices.add(newServiceInstance);
}
public void setApplicationContext(ApplicationContext ctx) {
m_springContext = ctx;
}
}