Unable to create logger Tomcat Error - java

I have jdk 1.7
path,classpath,catalina_home are set
this was the error
E:\apache-tomcat-7.0.56\bin>tomcat7.exe
The system cannot find the path specified.
Unable to create logger at ''
[2014-11-23 23:03:48] [error] [ 7388] Failed creating java C:\Program Files\Java
\jre7\bin\server\jvm.dll
[2014-11-23 23:03:48] [error] [ 7388] The system cannot find the path specified.
[2014-11-23 23:03:48] [error] [ 7388] ServiceStart returned 1
[2014-11-23 23:03:48] [error] [ 7388] The system cannot find the path specified.
[2014-11-23 23:03:48] [error] [ 7388] Commons Daemon procrun failed with exit va
lue: 3 (Failed to run service as console application)
[2014-11-23 23:03:48] [error] [ 7388] The system cannot find the path specified.
The system cannot find the path specified.
Failed to run service as console application
E:\apache-tomcat-7.0.56\bin>

I had the same problem. Here is what I was able to figure out:
This error happens because you don't have the privilege to modify the E:\apache-tomcat-7.0.56\logs directory. In my case, it was because I installed Tomcat by doing starting a CMD shell in "Run as administrator" mode (which forces you to log in as an administrator), and then doing "unzip apache-tomcat-7.0.57-windows-x64.zip". This seems to not set up the permissions necessary for the files to be accessed correctly by the service installer even when running in the "Run as administrator" privilege.
Now, if I go to my normal user account CMD shell and unzip the .zip file, and then go back to the administrator CMD shell and run service install , it works.
In fact, if I make a copy of the apache-tomcat-7.0.57 directory using COPY /S/D, and then try to install from that directory, it also works when you do a service install as an administrator.
Hope this helps.

Related

Azure Linux Webapp cannot seem to find deployed Spring .jar from DevOps repo

I have a Spring Web Application in a DevOps repository, with a .yml that looks like this (as generated by the tool in the DevOps web client):
# Build your Java project and deploy it to Azure as a Linux web app
# Add steps that analyze code, save build artifacts, deploy, and more:
# https://learn.microsoft.com/azure/devops/pipelines/languages/java
trigger:
- master
variables:
Version: '0.0.1'
# Azure Resource Manager connection created during pipeline creation
azureSubscription: '-snipped-'
# Web app name
webAppName: 'SlackCentralTestApp'
# Environment name
environmentName: 'SlackCentralTestApp'
# Agent VM image name
vmImageName: 'ubuntu-latest'
stages:
- stage: Build
displayName: Build stage
jobs:
- job: MavenPackageAndPublishArtifacts
displayName: Maven Package and Publish Artifacts
pool:
vmImage: $(vmImageName)
steps:
- task: Maven#3
displayName: 'Maven Package'
inputs:
mavenPomFile: 'pom.xml'
publishJUnitResults: true
testResultsFiles: '**/surefire-reports/TEST-*.xml'
javaHomeOption: 'JDKVersion'
jdkVersionOption: '1.11'
mavenVersionOption: 'Default'
mavenAuthenticateFeed: false
effectivePomSkip: false
sonarQubeRunAnalysis: false
- task: CopyFiles#2
displayName: 'Copy Files to artifact staging directory'
inputs:
SourceFolder: '$(System.DefaultWorkingDirectory)'
Contents: '**/target/SlackbotTest-$(Version)-SNAPSHOT.?(war|jar)'
TargetFolder: $(Build.ArtifactStagingDirectory)
- upload: $(Build.ArtifactStagingDirectory)
artifact: drop
- stage: Deploy
displayName: Deploy stage
dependsOn: Build
condition: succeeded()
jobs:
- deployment: DeployLinuxWebApp
displayName: Deploy Linux Web App
environment: $(environmentName)
pool:
vmImage: $(vmImageName)
strategy:
runOnce:
deploy:
steps:
- task: AzureWebApp#1
displayName: 'Azure Web App Deploy: SlackCentralTestApp'
inputs:
azureSubscription: 'Azure for Students (4998490e-1bc4-43fc-a370-80744706d1f5)'
appType: 'webAppLinux'
appName: 'SlackCentralTestApp'
package: '$(Pipeline.Workspace)/drop/target/SlackbotTest-$(Version)-SNAPSHOT.jar'
runtimeStack: 'JAVA|11-java11'
startUpCommand: 'java -jar $(Pipeline.Workspace)/drop/target/SlackbotTest-$(Version)-SNAPSHOT.jar'
The deployment process seems to be successful as seen in this screenshot, yet when I take a look at the server log, I sadly get greeted with the following error:
2020-04-14T09:03:55.658599508Z Initializing App Insights applicationinsights-agent-codeless-2.5.0.jar....
2020-04-14T09:03:55.669449167Z STARTUP_FILE=
2020-04-14T09:03:55.676322304Z STARTUP_COMMAND=java -jar /home/vsts/work/1/drop/target/SlackbotTest-0.0.1-SNAPSHOT.jar
2020-04-14T09:03:55.676350305Z No STARTUP_FILE available.
2020-04-14T09:03:55.676428905Z Running STARTUP_COMMAND: java -jar /home/vsts/work/1/drop/target/SlackbotTest-0.0.1-SNAPSHOT.jar
2020-04-14T09:03:55.681352232Z Error: Unable to access jarfile /home/vsts/work/1/drop/target/SlackbotTest-0.0.1-SNAPSHOT.jar
2020-04-14T09:03:55.694784805Z Finished running startup command 'java -jar /home/vsts/work/1/drop/target/SlackbotTest-0.0.1-SNAPSHOT.jar'. Exiting with exit code 1.
This would lead me to conclude that the path as given in the 'startUpCommand' property from the .yml file is incorrect, yet I have not been able to find what the correct path should be.
I have attempted the following:
Specify no directories, only the filename. Leads to the same result, sadly.
Use the 'find' command in Bash to find any .jars on the Web App, which tells me that there are none.
Manually building the application from the Web App does not seem to be an option either, as it's a Java 11 application and the java SE that seems to be included is version 1.8, regardless of the version I specify during the creation of the Web App resource in Azure.

CreateJavaVM Failed

I have installed one of the old project using Java 11.0.2. When I tried starting tomcat 9 as a service I am getting below errors.
[2019-05-03 05:01:36] [info] [13044] Starting service...
[2019-05-03 05:01:36] [error] [ 9764] CreateJavaVM Failed
[2019-05-03 05:01:36] [error] [ 9764] The system cannot find the file
specified.
[2019-05-03 05:01:36] [error] [13044] Failed to start Java
[2019-05-03 05:01:36] [error] [13044] ServiceStart returned 4
[2019-05-03 05:01:36] [info] [13152] Run service finished.
[2019-05-03 05:01:36] [info] [13152] Commons Daemon procrun finished
I verified jvm.dll path. Its correct. Below are the command used to start tomcat service
C:\Java11\bin\tomcat9.exe //IS//TOMCATSERVER --StartClass
org.apache.catalina.startup.Bootstrap --StopClass
org.apache.catalina.startup.Bootstrap --StartParams start --StopParams
stop
Any help is appreciated.
Thanks in advance,
AKJ.

RemoteSwingLibraryTimeoutError: Agent port not received before timeout

I am trying to run a basic robotframework test with RemoteSwingLibrary, but I can't seem to get it to work.
I was able to run the following test just fine with SwingLibrary:
*** Settings ***
Library SwingLibrary
*** Test Cases ***
Foobar Test
Start Application fully.qualified.name.of.my.class
I am running it from within Eclipse via the robot framework standalone jar. I put robotframework-3.0.2.jar and swinglibrary-1.9.7.jar on my class path, created a new run configuration using my projects default classpath with the main class being org.robotframework.RobotFramework. In the arguments, I specify the name of my test file.
So, that seems to work fine. Then I tried to do almost exactly the same thing with RemoteSwingLibrary:
*** Settings ***
Library RemoteSwingLibrary
*** Test Cases ***
Foobar Test
Start Application my_app java fully.qualified.name.of.my.class
I replaced the swinglibrary jar on my classpath with remoteswinglibrary-2.2.1.jar and I ran the same test. The output says:
console: Failed to install '': java.nio.charset.UnsupportedCharsetException: cp0.
==============================================================================
Remotetest
==============================================================================
Foobar Test | FAIL |
RemoteSwingLibraryTimeoutError: Agent port not received before timeout
------------------------------------------------------------------------------
Remotetest | FAIL |
1 critical test, 0 passed, 1 failed
1 test total, 0 passed, 1 failed
==============================================================================
Output: C:\<path>\output.xml
Log: C:\<path>\log.html
Report: C:\<path>\report.html
(note that the "console: Failed to install..." part is normal and I don't think I need to be concerned about it)
When I dig into the report for the Start Application Keyword, it says
13:48:40.070 INFO Link to stdout
13:48:40.070 INFO Link to stderr
13:48:40.070 INFO -javaagent:"C:<pathToProject>\__pyclasspath__"=127.0.0.1:63110
13:48:40.071 INFO Starting process:
java fully.qualified.name.of.my.class
13:49:40.145 INFO Failed to start application: Traceback (most recent call last):
File "__pyclasspath__/RemoteSwingLibrary.py", line 307, in start_application
File "__pyclasspath__/RemoteSwingLibrary.py", line 353, in _application_started
File "__pyclasspath__/RemoteSwingLibrary.py", line 373, in _get_agent_address
RemoteSwingLibraryTimeoutError: Agent port not received before timeout
13:49:40.155 INFO Waiting for process to complete.
13:49:40.165 INFO Process completed.
13:49:40.165 INFO STDOUT: Error occurred during initialization of VM
agent library failed to init: instrument
13:49:40.175 INFO STDERR: Error opening zip file or JAR manifest missing : C:<pathToProject>\__pyclasspath__
Picked up JAVA_TOOL_OPTIONS: -javaagent:"C:<pathToProject>\__pyclasspath__"=127.0.0.1:63110
Picked up _JAVA_OPTIONS: -Djava.security.policy="C:\<UserFolder>\
AppData\Local\Temp\2\grant_all_f_vfit.policy"
13:49:40.195 FAIL RemoteSwingLibraryTimeoutError: Agent port not received before timeout
I'm not sure if this hunch is really founded on anything, but my suspicion is that there's a classpath issue. I would think that when I call the Start Application keyword with "java fully.qualified.name.of.my.class" I would probably have to pass along my classpath. I was hoping that maybe I wouldn't since the non-remote version seems to handle that just fine (probably because its running my app in the same JVM as I launched robot framework in, and that already included everything I needed in my classpath).
So if that's the issue, I can probably fix it by using the -cp option in my java command. However, the classpath for this particular project is actually quite long (my project is dependent on a lot of other projects) and I would rather not have to list it all out. Also, when I add a new dependency down the road, I would rather not have to update the classpath in my test file as well.
Is there some magic way that I can pass the current classpath along to the remote app? Or perhaps some other solution to this problem?
Update
I tried again with -cp and my giant classpath and it gave me the same errors, so its possible that my classpath has nothing to do with whatever is going on.
I also tried specifying the port number explicitly and it gives me slightly different output (though it still doesn't work). I also discovered that there's a debug setting that gives a little more detail. Here's me new setup:
*** Settings ***
Library RemoteSwingLibrary debug=True port=8242
*** Test Cases ***
Foobar Test
Start Application my_app java -cp <classpath> <fully.qualified.name.of.my.class> remote_port=8242
And here is my new output:
13:48:40.070 INFO Link to stdout
13:48:40.070 INFO Link to stderr
13:48:40.070 DEBUG Picked old JAVA_TOOL_OPTIONS=''
13:48:40.070 DEBUG Picked old _JAVA_OPTIONS=''
13:48:40.070 INFO -javaagent:"C:<pathToProject>\__pyclasspath__"=127.0.0.1:51509:DEBUG
13:48:40.070 DEBUG Set JAVA_TOOL_OPTIONS='-javaagent:"C:<pathToProject>\__pyclasspath__"=127.0.0.1:8242:APPORT=8242:DEBUG'
13:48:40.070 DEBUG SET _JAVA_OPTIONS='-Djava.security.policy="C:\<UserFolder>\AppData\Local\Temp\4\grant_all_haud6t.policy"'
13:48:40.071 INFO Starting process:
java -cp <classpath> <fully.qualified.name.of.my.class>
13:48:40.071 DEBUG Process configuration:
cwd: C:<PathToProject>
shell: True
stdout: C:<PathToProject>\<someBigPath>.txt
stderr: C:<PathToProject>\<someBigPath>.txt
alias: my_app
env: None
13:48:40.100 DEBUG Returned old JAVA_TOOL_OPTIONS=''
13:48:40.100 DEBUG Returned old _JAVA_OPTIONS=''
13:48:40.102 INFO connection to started application at 127.0.0.1:8242
13:48:40.120 DEBUG remote swinglibrary instantiated
13:48:40.121 DEBUG remote services instantiated
13:48:40.121 INFO waiting for api at 127.0.0.1:8242
13:49:40.145 INFO Failed to start application: Traceback (most recent call last):
File "__pyclasspath__/RemoteSwingLibrary.py", line 307, in start_application
File "__pyclasspath__/RemoteSwingLibrary.py", line 357, in _application_started
File "__pyclasspath__/RemoteSwingLibrary.py", line 344, in _wait_for_api
RuntimeError: Connecting to api at 127.00.1:8242 has failed: ''
13:49:40.155 INFO Waiting for process to complete.
13:49:40.165 INFO Process completed.
13:49:40.165 INFO STDOUT: Error occurred during initialization of VM
agent library failed to init: instrument
13:49:40.175 INFO STDERR: Error opening zip file or JAR manifest missing : C:<pathToProject>\__pyclasspath__
Picked up JAVA_TOOL_OPTIONS: -javaagent:"C:<pathToProject>\__pyclasspath__"=127.0.0.1:8242:APPORT=8242:DEBUG
Picked up _JAVA_OPTIONS: -Djava.security.policy="C:\<UserFolder>\
AppData\Local\Temp\2\grant_all_f_vfit.policy"
13:49:40.195 FAIL Connecting to api at 127.0.0.1:8242 has failed: ''
13:49:40.195 DEBUG Traceback (most recent call last):
File "__pyclasspath__/RemoteSwingLibrary.py", line 498, in run_keyword
File "__pyclasspath__/RemoteSwingLibrary.py", line 307, in start_application
File "__pyclasspath__/RemoteSwingLibrary.py", line 357, in _application_started
File "__pyclasspath__/RemoteSwingLibrary.py", line 344, in _wait_for_api
Yet another update
I think that this may have something to do with the "__pyclasspath__" that shows up in the error message. I put my java command in a .bat file preceded by a "set" command to list my environment variables. I can run the .bat file from the command line just fine (it launches the java app).
Then I modified my .robot file to do:
Foobar Test
Start Application my_app cd robotframework/tests && Run.bat remote_port=8242
I get essentially the same error output that I got before:
Error opening zip file or JAR manifest missing : C:<pathToProject>\__pyclasspath__
Picked up JAVA_TOOL_OPTIONS: -javaagent:"__pyclasspath__"=127.0.0.1:8242:APPORT=8242:DEBUG
Picked up _JAVA_OPTIONS: -Djava.security.policy="C:\\AppData\Local\Temp\1\grant_all_lgirs7.policy"
The environment that my batch script prints out appears the same except for JAVA_TOOL_OPTIONS and _JAVA_OPTIONS (which match with what the error output says). There is no environment variable called __pyclasspath__ so I'm wondering if that's the issue.
I set JAVA_TOOL_OPTIONS in my cmd environment to match the output that I saw from my robot run and now I get the same error message when I try to run my .bat script from the command line, so that environment variable seems to be the issue.
Well, I came up with a fix, though its definitely not an ideal fix.
I found out that when the framework kicks of my remote app, it sets:
JAVA_TOOL_OPTIONS=-javaagent:"C:\<pathToProject>\__pyclasspath__
But __pyclasspath__ is not actually an environment variable. I figured out that the javaagent has to point to the remote framework library, so I decided to just set it explicitly.
So now I changed my robot file to something like this:
*** Settings ***
Library RemoteSwingLibrary
*** Test Cases ***
Foobar Test
Start Application my_app run.bat remote_port=1234
And then made a file called run.bat that does:
set JAVA_TOOL_OPTIONS=-javaagent:"C:\<pathToProject\lib\remoteswinglibrary-2.2.1.jar"=127.0.0.1:1234:APPORT=1234
java -cp <classPath> fully.qualified.name.of.class
This is obviously sort of a hacky solution and it will take a little work to make it portable (I'll need to get rid of the hardcoded "pathToProject" and also make it support Linux environments as well). It also requires hardcoding in a port, whereas it would be nice if the robotframework could just select a port for me.
So, I would definitely like to see a better solution if anyone can find one, but for now, this will at least work.

Procrun cannot find the Registry key for service

I'm trying to get my program to be a service so I found procrun from http://commons.apache.org/proper/commons-daemon/procrun.html but I made a installService.bat and keep recieving the same error message when I try to run
./prunsrv.exe //TS//InkEstService
The error code is this
[2016-06-15 09:44:06] [warn] [ 7136] The system cannot find the Registry key for service 'InkEstService'
[2016-06-15 09:44:06] [error] [ 7136] Load configuration failed
[2016-06-15 09:44:06] [error] [ 7136] The system cannot find the file specified.
[2016-06-15 09:44:06] [error] [ 7136] Commons Daemon procrun failed with exit value: 2 (Failed to load configuration)
[2016-06-15 09:44:06] [error] [ 7136] The system cannot find the file specified.
my installService.bat is as follows
set SERVICE_NAME=InkEstService
set PR_INSTALL=C:\Users\TStraley\Desktop\commons-daemon\prunsrv.exe
REM Service log configuration
set PR_LOGPREFIX=%SERVICE_NAME%
set PR_LOGPATH=c:\logs
set PR_STDOUTPUT=auto
set PR_STDERROR=auto
set PR_LOGLEVEL=Error
REM Path to java installation
set PR_JVM=C:\Program Files\Java\jdk1.8.0_92\jre\bin\server\jvm.dll
set PR_CLASSPATH=C:\Users\TStraley\Desktop\Ink/Estimator\InkDataCollection.jar
REM Startup configuration
set PR_STARTUP=auto
set PR_STARTMODE=jvm
set PR_STARTCLASS=Platform.Platform
set PR_STARTMETHOD=start
REM Shutdown configuration
set PR_STOPMODE=jvm
set PR_STOPCLASS=Platform.Platform
set PR_STOPMETHOD=stop
REM JVM configuration
set PR_JVMMS=256
set PR_JVMMX=1024
set PR_JVMSS=4000
REM Install service
prunsrv.exe //IS//%SERVICE_NAME%
I've been following the tutorial provided on https://joerglenhard.wordpress.com/2012/05/29/build-windows-service-from-java-application-with-procrun/ ... any ideas would be greatly appreciated!
You need to rename the prunsrv.exe to the name same as your service i.e "InkDataCollection.exe"
I have tried this it works for me.

Xampp Tomcat service (is not a valid win32)

I've read many topics such as Tomcat server is not starting as service: %1 is not a valid Win32 application or Tomcat 7 won't start
But it did not worked for me.
First of all I'm running Windows Server 64bits. I performed the following steps:
Downloaded Xampp (I believe it's 64bits..because I couldn't find a
64 bits in their website)
Download JDK 8.20 x64 bits
Since I was in doubt about the Tomcat in Xampp, I've download the Tomcat x64 and replace the whole content in the c:\xampp\tomcat\
After everything is installed I needed to update the Environment Variables, and so I did.
After completed this steps I installed successfully the Tomcat Service, although it gives error when starting. I found the logs of the errors I and get the following:
[info] [ 5096] Commons Daemon procrun (1.0.15.0 32-bit) started
[info] [ 5096] Running 'Tomcat7' Service...
[info] [ 4876] Starting service...
[error] [ 4876] %1 is not a valid Win32 application.
[error] [ 4876] Failed creating java C:\Program Files\Java\jdk1.8.0_20\bin\server\jvm.dll
[error] [ 4876] %1 is not a valid Win32 application.
[error] [ 4876] ServiceStart returned 1
[error] [ 4876] %1 is not a valid Win32 application.
[info] [ 5096] Run service finished.
[info] [ 5096] Commons Daemon procrun finished
So I check if the file jvm.dll existed in that folder (C:\Program Files\Java\jdk1.8.0_20\bin\server\jvm.dll), but I found that it does not. I searched a little more and I found that file is actually in the folder C:\Program Files\Java\jre1.8.0_20\bin\server\jvm.dll!
I then open Tomcat7 at C:\xampp\tomcat\bin and changed the path to the correct one.
But still, I keep getting the same error. What am I doing wrong?
Solved.
So, I had to do two steps.
Download jre-7u67-windows-x64.exe
Select, in the Tomcat7, in the tab "Java", the option "Use Default".
After that I was able to start the service properly. Plus, I've changed the port of tomcat in xampp, since by default is 8080, I changed to 9000 and I can now enter the project by localhost:9000/myproject

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