Constructing a List<T> from an Enum - java

What it comes down to is I'm attempting to construct a List<T> from the java.util.List package based on an enumerator, but here's the catch- I don't want the first value to be in the list. The way that I've come up with doing this... Well... It can't be a good thing.
Here's the code I'm using:
Arrays.asList(Arrays.asList(MyEnum.values()).remove(0));
This effectively creates a List<> from my enum, and removes the first value, then tries to create another list with the created list.
This may actually be the correct way to do it, but just looking at it is screaming "Inefficient". I showed it to a few people on a forum that I'm a member of and they all said how ugly it was, and laughed; However not a single one of them could/would provide a better way to go about doing it.

I don't think that code is really ugly or inefficient. The bigger problem is it doesn't work because the list returned by Arrays.asList is backed by the underlying array, and so it has a fixed size.
You can use subList instead of remove to get it working:
List<MyEnum> list = Arrays.asList(MyEnum.values());
list = list.subList(1, list.size());
This means that the resulting list actually consists of two list objects (the asList and its subList), which may or may not bother you. However, you can create a flat ArrayList from the resulting list:
list = new ArrayList<>(list);
If you'd rather minimize object allocation, loop the values and add them to a single list directly:
MyEnum[] values = MyEnum.values();
List<MyEnum> list = new ArrayList<>(values.length - 1);
for (int i = 1; i < values.length; i++)
list.add(values[i]);

How about:
Arrays.asList(MyEnum.values()).subList(1, MyEnum.values().length);

Are you sure you can't (wouldn't want to) use MyEnum.values and treat your first element differently where it's used?
public enum Enums {
first,
b,
c,
d,
e,
f;
public boolean isFirst(Enums e) {
return e == first;
}
}

This would work:
List<T> enums = Arrays.asList(Arrays.copyOfRange(MyEnum.values(), 1, MyEnum.values().length - 1));
Or java 8:
Arrays.stream(MyEnum.values()).collect(Collectors.toList()).subList(1, MyEnum.values() - 1);
Hmmm... not much better .

Related

How to implement a 2d array of LinkedLists

I'm working on implementing an algorithm from a paper. The paper describes using a grid, where each grid square holds a linked list of integers that represent objects in that grid square.
I decided to implement this using LinkedList<Integer>[][], which of course gives me a generic array creation error.
I can't think of a better way of representing the idea of a grid of linked lists. I also understand that using LinkedList[][] would compile but is bad practice as it is untyped. However, I would prefer not to use ArrayList<ArrayList<LinkedList<Integer>>> because that is unreadable, at least to me.
Is there a way around using an untyped LinkedList here? Or perhaps some other solution?
The list version
List<List<List<Integer>>> grid;
is not unreadable. To access a grid square it's just
List<Integer> items = grid.get(x).get(y);
Not that tough on the brane.
Bohemian's answer is on the mark. If you're using Guava, a possible alternative is to use an ArrayTable<Integer, Integer, List<Integer>>. From the documentation:
Fixed-size Table implementation backed by a two-dimensional array.
The allowed row and column keys must be supplied when the table is
created. The table always contains a mapping for every row key /
column pair. The value corresponding to a given row and column is null
unless another value is provided.
The table's size is constant: the product of the number of supplied
row keys and the number of supplied column keys. The remove and clear
methods are not supported by the table or its views. The
erase(java.lang.Object, java.lang.Object) and eraseAll() methods may
be used instead.
Here's an example of its usage:
private static final int NUM_ROWS = 20; //for example
private static final int NUM_COLS = 20; //
private static final ArrayTable<Integer, Integer, List<Integer>> TABLE =
ArrayTable.create(
Ranges.closed(1, NUM_ROWS).asSet(DiscreteDomains.integers()),
Ranges.closed(1, NUM_COLS).asSet(DiscreteDomains.integers())
);
public static List<Integer> getGridQuareList(int row, int col) {
#Nullable List<Integer> list = TABLE.at(row, col);
if (list == null) {
list = Lists.newArrayList(); //or newLinkedList() if you insist
TABLE.set(row, col, list);
}
return list;
}
I would use the embedded ArrayList/LinkedList. What you can do to clean it up, since you know what kind of generic type they will have, is to wrap them inside some other class. Like so:
public class Grid {
private List<List<List<Object>>> inner;
public List<Object> objectsAtPosition(int x, int y) {
return inner.get(x).get(y);
}
// etc
}
I don't know why on earth you would need a 3 dimensional list (2d array of a list, considering ArrayLists is really a 3d list/array). But if you do need that, then you should use what #Bohemian wrote:
List<List<List<Integer>>> grid;
What you should consider:
Declare variables to interfaces, not implementations, eg.:
List<Integer> list = new ArrayList<Integer>
instead of
ArrayList<Integer> list = new ArrayList<Integer>
Also, generally it's not a good idea to mix generics with arrays, it can get nasty. If you wan't to do it in java and that's what you need do it the java way, as the others stated:
List<List<List<Integer>>>
You can declare an array of the linked list as follows.. but do not forget to declare when you are going to use the linked list otherwise you will get the nullpointeexception
LinkedList<Integer>[][] ll = new LinkedList[24][24];
ll[0][0] = new LinkedList<>();
ll[0][0].addFirst(3);
System.out.println(ll[0][0].removeFirst());
Output : 3
First: You proably can avoid LinkedList. In Algorithm books, they did not know the ArrayList, Linked List, is more a synonym for dynamic list.
In nearly all cases ArrayList is faster, and especially for 2D arrays, need much less memory.
I personaly when having a fixed grid, with dynamic content, I use arrays:
List grid[][];
// init with
grid = new ArrayList[numX][numY];
that way i have an grid of object. This uses much less memory.
That way its is much handier when adding objetcs:
List list = grid[i][j];
if (list == null) {
list = new ArrayList();
this.cells[i][j] = list;
}
list.add(obj);
I decided to implement this using LinkedList[][], which of
course gives me a generic array creation error.
I can't think of a better way of representing the idea of a grid of
linked lists. I also understand that using LinkedList[][] would
compile but is bad practice as it is untyped.
Simple. To solve those problems just do
LinkedList<Integer>[][] grid = (LinkedList<Integer>[][])new LinkedList<?>[5][3];

ArrayList with returned index on add value

I am looking for a java data structure similar to an ArrayList that when I do an add or a push with only a value argument an index will be returned for me automatically.
For example:
ArrayList<String> elements = new ArrayList<String>();
String element = "foo";
String elementTwo = "bar";
int index1 = elements.add(element); //note this does not exist, i.e. returns bool in api
int index2 = elements.add(elementTwo);
System.out.println(elements.get(index1)); //would give "foo"
I could see writing a wrapper class around ArrayList that manages a counter that is incremented on every add operation and invoking:
ArrayList.add(int index, E element)
Do you really need to write a wrapper around ArrayList for this? This seems like something simple enough to be provided out of the box somewhere?
Edit:
I need the index (key) to be fixed and unique for this usecase. A map was suggested and I agree with that. Does anyone know of a map implementation that gives you an automatically (uniquely) generated key on a value insert? I am just trying to decide if I need to implement my own wrapper for this.
The element will be added at the end of the list. So you can use elements.size()-1 to get the new elements index.
Note that this will not work reliable if multiple threads are modifying the list at the same time.
EDIT: Also note that it might not be a good idea to use an ArrayLists index as a unique ID because an elements index can change (for example when you remove an element or insert a new one using add(int, Object)). If this is a problem depends on what you want to do with the index: If you only need it for a short time after adding an element and can be sure that the list is not modified in the meantime, there is no problem. In the other case even a method returning the index when calling add(Object) would not help because the index does not get updated in anyway. To prevent this issue you can:
Make sure you never remove elements from the list and never add elements using add(int, Object).
Instead of removing elements you could also set them to null using the method set(int, null). This way no elements index will change.
Use some other data structure like for example a map with a custom ID like helloannalil suggests in his answer.
EDIT 2: I did not find a appropriate, ready to use implementation (but this does not mean there is none, of course). To suggest a good solution, more information on the intended use of the data structure is needed, but here are some ideas and notes:
If the maximum number of elements is not to large, an ArrayList could be used and the elements index represents the ID. As stated above, to remove an element it can be set to null so that no indices are changed. When inserting, positions with null values can be reused.
You can also use one of the two methods show in this answer: https://stackoverflow.com/a/8939049/1347968 (keywords AtomicLong or IdentityHashMap)
Do not depend on the "uniqueness" of Object.hashCode() or System.identityHashCode(Object) as it is not guaranteed (try it by running the example at the bottom of Suns/Oracles Bug #6321873).
Well what I do in that cases (I love ArrayLists) is to get the last index by asking the size of the list:
String thing = "theThing";
List<String> strList = new ArrayList<String>();
strList.add(thing);
int indexOfThing = strList.size() - 1;
I mean, is easier than implement your own List and just works.
if you really want this function, you can use map but not list
Based on your comments and edited question I think you can extend a HashMap for your use like this:
public class MyMap<V> extends HashMap<Integer, V> {
private static final long serialVersionUID = 1L;
public int add(V elem) {
int key = System.identityHashCode(elem);
super.put(key, elem);
return key;
}
}
Then inside your class declare MyMap like this:
private MyMap<String> map = new MyMap<String>();
And then add your elements to MyMap like this:
.....
.....
String element = "foo";
String elementTwo = "bar";
int index1 = map.add(element);
int index2 = map.add(elementTwo);
Now you have index1 and index2 as indices of you inserted strings that you can use or pass around for the lifetime of your application. You can insert or remove elements in MyMap as many times you want but your indices (index1 and index2) will give you back your inserted elements like this:
String elem1 = map.get(index1); // will return "foo"
String elem2 = map.get(index2); // will return "bar"
String thing = "theThing";
List<String> strList = new ArrayList<String>();
strList.add(thing);
int indexOfThing = strList.size() - 1;
If you remove an item, this will no longer work.

Arrays.asList(T[] array)?

So there's Arrays.asList(T... a) but this works on varargs.
What if I already have the array in a T[] a? Is there a convenience method to create a List<T> out of this, or do I have to do it manually as:
static public <T> List<T> arrayAsList(T[] a)
{
List<T> result = new ArrayList<T>(a.length);
for (T t : a)
result.add(t);
return result;
}
Just because it works with varargs doesn't mean you can't call it normally:
String[] x = { "a", "b", "c" };
List<String> list = Arrays.asList(x);
The only tricky bit is if T is Object, where you should use a cast to tell the compiler whether it should wrap the argument in an array or not:
Object[] x = ...;
List<Object> list = Arrays.asList((Object[]) x);
or
Object[] x = ...;
List<Object[]> list = Arrays.asList((Object) x);
As you probably already know, there is a Static class called java.util.Collections which has a number of useful methods for dealing wit arrays such as searching and sorting.
As for your question, the Collection interface specifies methods to add, remove and toArray, amongst others. For one reason or another, the API's authors decided that the add and addAll method will be the only input functions provided to the user.
One explanation for why Java Lists cannot add arrays of objects is that Lists use an iterator and iterators are more strict in their scrolling (i.e. going to the next value) than Arrays which do not have to have all their index values i=(1, 2, 5, 9, 22, ...).
Also, Arrays are not type safe; that is, they cannot guarantee that all their elements conform to a specific super-class or interface, whereas generics (of which List is a member) can guarantee type safety. Hence, the list has the chance to validate each item using the add method.
I think that you can rest assure that your method of adding an array to a list is one of the most (if not most) efficient way of achieving this effect in Java.

How to get a sublist without using the sublist method in java

This is what I have right now:
public ArrayList subList(int fromIndex, int toIndex){
ArrayList a = new ArrayList();
for (int i=fromIndex;i<toIndex;i++) {
a.add(stuff[i]); //stuff is a array of strings
}
return list;
}
But is it possible to return the sublist without creating a new array? I am restrict from using any methods from the Array/ArrayList class.
If you want have the same behaviour as the Java subList method you need to retain a pointer to the original list and use an offset and length to index into the original list.
Heres a start showing the implementation of the get method.
public class SubList extends AbstractList {
private final List original;
private final int from;
private final int to;
public SubList(List original, int from, int to) {
this.original = original;
this.from = from;
this.to = to;
}
public Object get(int i) {
if (i < 0 || i > to - from) {
throw new IllegalArguementException();
}
return original.get(from + i);
}
}
public static List subList(List original, int from, int to) {
return new SubList(original, from, to);
}
To avoid creating a new list for storage, you would have to pass in a reference to the original list, keep the sublist, and then delete the remaining items from from the list, but this would leave the list missing those other items.
If that isn't your goal you will have to create a new list at some point to hold the sublist.
I assume you have to return the standard ArrayList, and not your own version of ArrayList, and I assume that 'stuff' is an array, not a list.
First off, get bonus points for making the ArrayList have the initial size of the array (toIndex - fromIndex). For more bonus points, make sure that the to and from indecies actually exist in 'stuff' otherwise you get a nice crash.
ArrayList uses an internal array for its storage and you can't change that so you have no choice but to create a copy.
EDIT
You could make things interested and much more complex but it'll impress someone... Do it by creating your own ArrayList class implementing List. Get it to use that original array. Pretty unstable since if that array is modified somewhere else externally, you're in trouble, but it could be fun.
There's three sensible things you could return. An array, a List, or an Iterator. If my assumption that you're supposed to re-implement subList was correct, then there's no way around creating the new ArrayList.
A sublist is "a new list", so you'll have to create something to represent the sublist of the array. This can either be a new array or a list. You chose an ArrayList which looks good to me. You're not creating a new array (directly), so I don't actually get that point of your question. (If you want to avoid creating a new array indirectly through ArrayList, choose another List implementation, LinkedListfor example)
If you're looking for slight improvements:
Consider passing the source array as a method parameter. Now stuff[] is a static field.
Consider initializing the new ArrayList with the size of the sublist (toList-fromList+1)
Consider using generics (only if you already now this concept). So the return type would be ArrayList<String>

Cannot create an array of LinkedLists in Java...?

I'm working on a sparse matrix class that needs to use an array of LinkedList to store the values of a matrix. Each element of the array (i.e. each LinkedList) represents a row of the matrix. And, each element in the LinkedList array represents a column and the stored value.
In my class, I have a declaration of the array as:
private LinkedList<IntegerNode>[] myMatrix;
And, in my constructor for the SparseMatrix, I try to define:
myMatrix = new LinkedList<IntegerNode>[numRows];
The error I end up getting is
Cannot create a generic array of LinkedList<IntegerNode>.
So, I have two issues with this:
What am I doing wrong, and
Why is the type acceptable in the declaration for the array if it can't be created?
IntegerNode is a class that I have created. And, all of my class files are packaged together.
For some reason you have to cast the type and make the declaration like this:
myMatrix = (LinkedList<IntegerNode>[]) new LinkedList<?>[numRows];
You can't use generic array creation. It's a flaw/ feature of java generics.
The ways without warnings are:
Using List of Lists instead of Array of Lists:
List< List<IntegerNode>> nodeLists = new LinkedList< List< IntegerNode >>();
Declaring the special class for Array of Lists:
class IntegerNodeList {
private final List< IntegerNode > nodes;
}
Aside from the syntax issues, it seems strange to me to use an array and a linked list to represent a matrix. To be able to access arbitrary cells of the matrix, you would probably want an actual array or at least an ArrayList to hold the rows, as LinkedList must traverse the whole list from the first element to any particular element, an O(n) operation, as opposed to the much quicker O(1) with ArrayList or an actual array.
Since you mentioned this matrix is sparse, though, perhaps a better way to store the data is as a map of maps, where a key in the first map represents a row index, and its value is a row map whose keys are a column index, with the value being your IntegerNode class. Thus:
private Map<Integer, Map<Integer, IntegerNode>> myMatrix = new HashMap<Integer, Map<Integer, IntegerNode>>();
// access a matrix cell:
int rowIdx = 100;
int colIdx = 30;
Map<Integer, IntegerNode> row = myMatrix.get(rowIdx); // if null, create and add to matrix
IntegerNode node = row.get(colIdx); // possibly null
If you need to be able to traverse the matrix row by row, you can make the row map type a TreeMap, and same for traversing the columns in index order, but if you don't need those cases, HashMap is quicker than TreeMap. Helper methods to get and set an arbitrary cell, handling unset null values, would be useful, of course.
class IntegerNodeList extends LinkedList<IntegerNode> {}
IntegerNodeList[] myMatrix = new IntegerNodeList[numRows];
myMatrix = (LinkedList<IntegerNode>[]) new LinkedList[numRows];
casting this way works but still leaves you with a nasty warning:
"Type safety: The expression of type List[] needs unchecked conversion.."
Declaring a special class for Array of Lists:
class IntegerNodeList { private final List< IntegerNode > nodes; }
is a clever idea to avoid the warning. maybe a little bit nicer is to use an interface for it:
public interface IntegerNodeList extends List<IntegerNode> {}
then
List<IntegerNode>[] myMatrix = new IntegerNodeList[numRows];
compiles without warnings.
doesn't look too bad, does it?
List<String>[] lst = new List[2];
lst[0] = new LinkedList<String>();
lst[1] = new LinkedList<String>();
No any warnings. NetBeans 6.9.1, jdk1.6.0_24
There is no generic array creation in Java 1.5 (or 1.6 as far as I can tell). See https://community.oracle.com/message/4829402.
If I do the following I get the error message in question
LinkedList<Node>[] matrix = new LinkedList<Node>[5];
But if I just remove the list type in the declaration it seems to have the desired functionality.
LinkedList<Node>[] matrix = new LinkedList[5];
Are these two declarations drastically different in a way of which I'm not aware?
EDIT
Ah, I think I've run into this issue now.
Iterating over the matrix and initializing the lists in a for-loop seems to work. Though it's not as ideal as some of the other solutions offered up.
for(int i=0; i < matrix.length; i++){
matrix[i] = new LinkedList<>();
}
You need an array of List, one alternative is to try:
private IntegerNode[] node_array = new IntegerNode[sizeOfYourChoice];
Then node_array[i] stores the head(first) node of a ArrayList<IntegerNode> or LinkedList<IntegerNode> (whatever your favourite list implementation).
Under this design, you lose the random access method list.get(index), but then you could still traverse the list starting with the head/fist node store in the type safe array.
This might be an acceptable design choice depending on your use case. For instance, I use this design to represent an adjacency list of graph, in most use cases, it requires traversing the adjacency list anyway for a given vertex instead of random access some vertex in the list.

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