How can I print a 2d Array? [duplicate] - java

This question already has answers here:
What causes a java.lang.ArrayIndexOutOfBoundsException and how do I prevent it?
(26 answers)
Closed 6 years ago.
I need to print this array for a tic tac toe program I am writing for APCS. I am getting an ArrayIndexOutOfBoundsException.
String[][] ticBoard = {
{"-","-","-"},
{"-","-","-"},
{"-","-","-"}
};
for(int d = 0; d < ticBoard.length; d++){
for(int r = 0; r < ticBoard.length; d++){
System.out.print(ticBoard[d][r]);
}
}

You should change d++ to r++ like #Maroun Maroun said but also:
for(int d=0; d<ticBoard.length;d++){
for(int r = 0; r<ticBoard[d].length;r++){
System.out.print(ticBoard[d][r]);
}
System.out.println();
}
Just incase your number of rows doesn't equal your number of columns.

You're using the wrong limit in the inner loop; you should be using the length of a row, not the number of columns. (Since your two-dimensional array doesn't have the same number of rows and columns, this is especially noticeable.)
Because of this, you're going off the end of the first row of the array when you try to access the 4th element. Your code specifies a maximum value for the column index of ticBoard.length (i.e. 4), which does not correspond to the actual number of items in that row (i.e. 3).
This can be fixed by looping up to the number of elements in the row (i.e. ticBoard[d].length), not the number of rows in the array (i.e. ticBoard.length)
Furthermore, you're incrementing the wrong value in the inner loop; it should be r, not d.
for(int d = 0; d < ticBoard.length; d++) {
for(int r = 0; r < ticBoard[d].length; r++) {
System.out.print(ticBoard[d][r]);
}
System.out.println(); // So that each new row gets its own line
}

This,
for(int r = 0; r < ticBoard.length; d++){
should be something like
for(int r = 0; r < ticBoard[d].length; r++){
Or, you could use Arrays.deepToString(Object[]) to print the 2d array like
System.out.println(Arrays.deepToString(ticBoard));

Related

Java Matrix how to assign int 1 or 0 to a 2D array? [duplicate]

This question already has answers here:
How can I avoid ArrayIndexOutOfBoundsException or IndexOutOfBoundsException? [duplicate]
(2 answers)
Closed 7 years ago.
Here is part of my code. I want to assign random number to the matrix population[][] first, then compare the random number to a specific number ranP, if population[][] < ranP, then re-assign population[][] to 1, otherwise 0. But it shows
arrayindexoutofboundsexception 0
Need help on the issue. Thanks!
randGen = new Random();
double randNum = randGen.nextDouble();
for ( int i = 0; i < 11; i++){
for (int k = 0; k < inipopulationsize; k++){
for (int j = 0; j < 25; j++){
ranP = 0.5;
//TMaxtrix[i][j] = matrix[i][j];
System.out.println(matrix[i][j] + " ");
population = new double[k][j];
System.out.println("randNum: " + randNum);
population[k][j] = randNum;
if (randNum <= ranP){
population[k][j] = 1;
}
else
population[k][j] = 0;
System.out.println("population: " + population[k][j]);
}//j loop
}//k loop
}//i loop
I am learning this by myself, and not taking any classes. If this really bothers you "experts", why dont you just ignore and save your time go home watching a movie or spending more time with your family? Appreciate the help from nice people here. But shame on you who only knows sarcasm. Here is what works finally:
randGen = new Random();
population = new int[inipopulationsize][25];
for ( int i = 0; i < population.length; i++){
for (int j = 0; j < population[i].length; j++){
double randNum = randGen.nextDouble();
ranP = 0.5;
if (i < 11){
//System.out.println(matrix[i][j] + " ");
}
if (randNum <= ranP){
population[i][j] = 1;
}
else
population[i][j] = 0;
//System.out.println("population index: " + i + " Dieasease index: " + j + " DI on (1) or off (0): " + population[i][j] + "");
}//j loop
}//i loop
Is the third loop because you want i 2d arrays? If so you should probably look at ArrayLists of 2d arrays.
int inipopulationsize = 25;
double[][] population;
Random randGen = new Random();
double randNum = randGen.nextDouble();
double ranP = 0.5;// outside loops
population = new double[inipopulationsize][25]; // out
for (int k = 0; k < inipopulationsize; k++){
for (int j = 0; j < 25; j++){
randNum = randGen.nextDouble();//i assume you want new random every time
if (randNum <= ranP){
population[k][j] = 1;
}
else
population[k][j] = 0;
}//j loop
}//k loop
System.out.println(Arrays.deepToString(population));
I don't see a reason for having 3 loops with a 2d array.
Random randGen = new Random();
double randNum;
for(int i=0; i<population.length; i++){
for(int j=0; j<population[i].length; j++){
randNum = ranGen.nextDouble();
if(randNum<0.5) population[i][j] = 0;
else population[i][j] = 1.0;
}//j loop
}//i loop
Your issue is that you are referring to an item outside the bounds of your 2D array.
Let's take a look at your code. This line: population = new double[k][j]; declares a new 2D arrays of size kxj. Then in this line: population[k][j] = randNum; you try to reference the item in the kth column and jth row of this same 2D array. This is not legal in Java arrays.
Java arrays are 0-indexed, which means with an array of size k, your indexes range from 0 to k-1. There is no item at index k. This is why you are receiving an index out of bounds error.
Please look at this link instructing you on the basic use of Java Arrays.
The exact error arrayindexoutofboundsexception 0 appears because on your first iteration, you create a population of size 0 by 0. Then you try to access the item in column 0 and row 0, that is to say, the first item. However as your population array has 0 size, it has no space, and even the index 0 is out of bounds.
However, I am not even sure this is what you want to be doing.
You are declaring a 2D array on each iteration of your loop. If all you are trying to do is make a single array of size inipopulationsizeby25 (these are the initial values of k and j) then you need to declare this outside of these two nested loops. Perhaps even outside of the third loop, as I am not even sure what that loop is doing.
Take a loop at anaxin's answer for how to effectively assign 0's and 1's to your population array randomly. (With randP set to 0.5 you are giving each a 50% chance of appearing.)

Arrays in array, 100 rows, dynamic columns

I'm trying to get this:
arrays[1][0] = 5
arrays[2][0] = 7
arrays[2][1] = 2
arrays[3][0] = 6
arrays[3][1] = 9
arrays[3][2] = 11
So I want arrays[1][] to have one element of random data, arrays[2][] to have 2 elements of random data and so on until I have 100 arrays. So my last array would be arrays[100][] with 100 elements of random data.
This is the code I have now but I get a NullPointerException when arrays[i][j] = generator.nextInt(max) is executed:
Comparable[][] arrays = new Comparable[100][];
for (int i=1; i<101;i++){
for (int j=0; j <= i-1; j++){
arrays[i][j] = generator.nextInt(max);
}
}
Your
Comparable[][] arrays = new Comparable[100][];
line only creates the outermost array. You need to create the arrays that go in it, e.g. something like this:
Comparable[][] arrays = new Comparable[100][];
for (int i=1; i<101;i++){
arrays[i] = new Comparable[/* relevant length here*/]; // <====
for (int j=0; j <= i-1; j++){
arrays[i][j] = generator.nextInt(max);
}
}
It's unclear to me why you start i at 1 or where the randomness should be (I'm guessing at /* relevant length here */), but hopefully that points you the right way.

2D array not printing the last element during comparison

I am trying to replace rows from an original 2d array to a updated 2d array. Problem is it won't store the last element during the replacement.
Here's my code:
String[][] updatedArray = {{"red","a","b","c"},{"yellow","a","b","c"}, {"purple","a","b","c"}};
String[][] originalArray = {{"red","aa","bb","cc"},{"yellow","ww","vv","zz"}, {"green","yy","uu","pp"}, {"purple","nn","mm","bb","hello"}};
for (int i = 0; i < updatedArray.length;i++ ) {
for (int j = 0; j < updatedArray[i].length; j++){
for(int x = 0; x < originalArray.length;x++){
for(int z = 0; z < originalArray[x].length;z++){
if(originalArray[x][0].equals(updatedArray[i][0])) {
updatedArray[i][j] = originalArray[x][j];
System.out.println("There's a match!!");
}else{
System.out.println("No match!");
}
}
}
}
}
System.out.println("originalArray:");
System.out.println(Arrays.deepToString(originalArray));
System.out.println("updatedArray:");
System.out.println(Arrays.deepToString(updatedArray));
For example, initially updatedArray in last row "purple" has {"purple","a","b","c"}. When it does the replacement using values from originalArray, the code above only outputs:
... [purple, nn, mm, bb]
which is wrong because it doesn't add the last element "hello". It should output:
... [purple, nn, mm, bb, hello]
I am aware the problem is in this line:
updatedArray[i][j] = originalArray[x][j];
Problem is no matter what I try to change originalArray[x][j] to originalArray[x][z] ... its screws up everything.
Any ideas on this? Still trying to get the jist of 2D arrays.
If there is a match, instead of trying to set each element in the updatedArray to the corresponding element in the original array you can just set the entire array to the original array.
String[][] updatedArray = {{"red","a","b","c"},{"yellow","a","b","c"}, {"purple","a","b","c"}};
String[][] originalArray = {{"red","aa","bb","cc"},{"yellow","ww","vv","zz"}, {"green","yy","uu","pp"}, {"purple","nn","mm","bb","hello"}};
for (int i = 0; i < updatedArray.length;i++ ) {
for (int j = 0; j < originalArray.length; j++){
if(originalArray[j][0].equals(updatedArray[i][0])) {
updatedArray[i] = originalArray[j];
System.out.println("There's a match!!");
}else{
System.out.println("No match!");
}
}
}
The issue is how you chose to iterate over the dimensions of updatedArray which are different than the dimensions of originalArray.
Let just look at the case i=2 which is the 'row' for purple:
for (int j = 0; j < updatedArray[i].length; j++){
updatedArray[i=2].length = 4
in updated:
index = 0 , 1 , 2 , 3
{"purple","a","b","c"}
in original:
index = 0 , 1 , 2 , 3 , 4
{"purple","nn","mm","bb","hello"}
Therefore since j will always be < 4 it can never be used to index originalArray[x][4] = "hello"
DANGER: this code also doesn't handle the fact that you would need to extend the purple array for updatedArray. Java may do some magic to handle this for you but I wouldn't trust it to work that way.
Suggestion:
- compare the lengths of each row and allocate extra memory where necessary before copying data from originalArray to updatedArray
- if possible just copy the whole row between original and updated.

Count characters in a multidimensional array, Java

Below is my code:
public int maxTurns = 0;
public String[][] bombBoard = new String[9][9];
...
public void loadBombs()
{
//loadArray();
Random randomGen = new Random();
for (int u=1; u<=9; u++)
{
int randomRow = randomGen.nextInt(9);
int randomCol= randomGen.nextInt(9);
bombBoard[randomRow][randomCol] = "#";
}
//counting #'s -- setting variable
for (int d = 0; d < bombBoard[bombRow].length; d++)
{
for (int e = 0; e < bombBoard[bombCol].length; e++)
{
if (bombBoard[d].equals("#") || bombBoard[e].equals("#"))
{
maxTurns++;
}
}
}
All I want to do is count the amount of (#)'s in the multidimensional array and assign it to a variable called maxTurns.
Probably very simple, just having a super hard time with it tonight. Too much time away from Java >.<
This line is equating the character # with the entire dth row or eth row. Does not make sense really because an array row cannot equal to a single character.
if (bombBoard[d].equals("#") || bombBoard[e].equals("#"))
Instead, access a single cell like this
if (bombBoard[d][e].equals("#"))
And initialize maxTurns before counting i.e. before your for loop:
maxTurns = 0;
You need to change the if codition
if (bombBoard[d].equals("#") || bombBoard[e].equals("#"))
to
if (bombBoard[d][e].equals("#"))
You are using 2D Array, and do array[i][j] can populate its value for a gavin position.
do you want to count from the whole array or certain parts of the array only?
From the code snippet you gave above, I can't really tell how you iterate the array since I'm not sure what is
bombBoard[bombRow].length and bombBoard[bombCol].length
But if you want to iterate the whole array, think you should just use:
for (int d = 0; d < 9; d++) // as you declared earlier, the size of array is 9
{
for (int e = 0; e < 9; e++) // as you declared earlier, the size of array is 9
{
if (bombBoard[d][e].equals("#"))
{
maxTurns++;
}
}
}

How to return print line values stored in an array using a for loop [duplicate]

This question already has answers here:
C++ - Using 'i' to check different variables in a for loop
(3 answers)
Closed 10 years ago.
So you can do it the very simple but long way as below
System.out.println(myArray[1]); //This = 1.56
System.out.println(myArray[2]); //This = 1.72
But how would you do it using a for loop to retrieve the values and print them? So it could look something like
for (int i = myArray[]; j < myArray.length; i++) {
System.out.println(i);
}
So the for loop will then go through the array and println all the values stored at its positions e.g [1] = 1.56, [2] = 1.72. How could you get the for loop to do this? Thanks
Just print myArray[i] in the loop:
for (int i = 0; i < myArray.length; ++i) {
System.out.println(myArray[i]);
}
I also had to fix your loop variable.
Another way is to use a "for each" loop:
for (double val : myArray) {
System.out.println(val);
}
Just changing a couple of things in your code gives you your answer:
for (int i = 0; i < myArray.length; i++) {
System.out.println(myArray[i]);
}
This sets i = 0 initially, looping as long as i is less than the length of your array, and incrementing i with one each iteration. This will make i step from 0 ... (myArray.length - 1), and print all the values.
int[] myArray ={1,3,2};
for (int i : myArray) {
System.out.println(i);
}
You mean something like this using for-each loop?
Use Formatter to print in the way you want, and a simple for to get the values from array.
for (int i = 0; i < myArray.length; i++) {
System.out.format("[%d] = %.2f\n", i, myArray[i]);
}
For an array like {1.567, 1.444, ...} it will print
[0] = 1.57
[1] = 1.44
You can modify the format to what you desire.

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