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java program to loop and output 2,5,7,10,12 [closed]

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Loop
how to loop this without using array? I'm clearly confuse in this in java module I don't know the solution ;-; I'm new to java pls helppp mee

Try this.
for (int i = 5; i <= 25; i += 5)
System.out.println(i / 2);
Or
for (int i = 1; i <= 5; i++)
System.out.println(i * 5 / 2);
output:
2
5
7
10
12
Think for yourself why this produces the correct result.

public class Main {
public static void main(String[] args) {
int outputNum = 0;
for(int i = 0; i < 5; i++){
if (i % 2 == 0){
outputNum += 2;
}
else {
outputNum += 3;
}
System.out.print(outputNum + (i == 4 ? "" : " "));
}
}
}
This does exactly what you need.
Explanation:
In the loop if the i variable is even we add 2 to the output number (since you need to add 2 then 3 then 2...) and if i is uneven then we add three. At the end of the for loop we print the number without the newline using System.out.print and we separate them by a space if we aren't printing the last number using a ternary operator (i == 4 ? "" : " ") which returns a space if i is not equal to 4 and an empty string if it is, we do this to avoid having a space on the end of our output, so we get this 2 5 7 10 12 instead of this 2 5 7 10 12

How do I find the output of the following code fragment in Java? [closed]

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I have the following code fragment, which yields a sum of 16.
int sum = 1;
for (int i = 0; i <= 5; sum = sum + i++)
System.out.println(sum);
From my understanding of sum = sum + i++ and for loops in general, my thought process for the loop would be like this:
0th loop: sum = 1 (do nothing)
1st loop: sum = 1 + 1 (uses sum = 1 from previous iteration )
2nd loop: sum = 2 + 2
3rd loop: sum = 4 + 3
4th loop: sum = 7 + 4
5th loop: sum = 11 + 5
Obviously, there is an error in my logic. Could you please explain why the sum would be 16?

Change System.out.println(sum); to include the loop number as well. Also, don't forget to print the values after your loop.
int sum = 1;
for (int i = 0; i <= 5; sum = sum + i++) {
System.out.printf("loop=%d, sum=%d%n", i, sum);
}
System.out.printf("after loop, sum=%d%n", sum);
Output
loop=0, sum=1
loop=1, sum=1
loop=2, sum=2
loop=3, sum=4
loop=4, sum=7
loop=5, sum=11
after loop, sum=16
Which I trust explains both how and why sum is 16 after the loop.

How to display a line of numbers equally in java [closed]

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Im having trouble only displaying the correct numbers, I know how to get the formula is have count-1 have 10/2 = 5 but now I want to count up from the start making it 10 15 20.
//Static void dispalySpace(double start, double end, int count){
// Display numbers between start and end inclusively
//The numbers are spaced equally
//Assume start < end and count is at least 2.
//displaySpace(10,20,3)
//The answer to the question is 10.0 15.0 20.0
while(min<max && count>=2)
for(int i=min; i<=max; i++) {
for(double j = count-1; j>=2; j++) {
System.out.print(j + " ");
}
System.out.print(i + " ");
}
System.out.println();
}
I keep just getting 10-20 displaying on a loop.

You first need to calculate the steep size, ie what do you have to add to min so that you end up with count numbers. For the first output, you won't have to add anything, so it's one less than count , ie
double step = (max-min) / count - 1;
That's what you have to add each step of the loop, starting with min , so
for (double i = 0; i <= max ; i = i + step) {
System.out.print(i) ;
}

Problems with array. Java [closed]

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I started learning java yesterday and this is the first time i'm using array. This is the code
import java.util.Scanner;
public class array
{
public static void main(String[] args)
{
int num[];
num = new int[5];
Scanner input = new Scanner(System.in);
int i;
System.out.println("Insert 5 numbers:");
for(i = 0; i < 5; i = i + 1);
{
System.out.print("Insert the " + i + "° number: ");
num[i] = input.nextInt();
}
System.out.print("The numbers you entered are: ");
for(i = 0; i < 5 ; i = i + 1)
{
System.out.println(num[i] + " ");
}
}
}
When i try to run it i get this problem:
Insert 5 numbers:
Insert the 5° number: 1
Exception in thread "main" java.lang.ArrayIndexOutOfBoundsException: 5
at array.main(array.java:14)

Two things.
You have a semicolon at the end of your loop. That will cause the loop to run until i = 5 and you're kind of stuck with that value now. Remove it.
i will remain 5 after the first loop for the same reason as above. Declare and initialize i inside of your for statement.
for(int i = 0; i < 5; i = i + 1) {
// the rest of your block
}

My Java code is not running [closed]

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If I am not mistaken, this bit of code should print out all even numbers smaller than or equal to 100. When I run this code, nothing happens. No error message or anything. I'm using Eclipse.
public class Even {
public static void main(String args[]) {
int number = 1;
int remainder = number % 2;
while(number <= 100) {
number++;
if(remainder == 0) {
System.out.println(number);
}
}
}
}

As others stated before, value of remainder is set only once. However, you check it a hundred times expecting it to tell you something else every time. I'd suggest putting it inside a loop, so you get a "fresh" value for every number.
public class Even {
public static void main(String args[]) {
int number = 1;
int remainder;
while(number <= 100) {
number++;
remainder = number % 2;
if(remainder == 0) {
System.out.println(number);
}
}
}
}

The reminder doesn't change as the assignment is prior to while loop. The statement int remainder = number % 2; has to be inside while loop to see the expected result.

for(int i = 0;i<=100; i= i+2)
System.out.println(i);
You do not need remainder :)