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JodaTime IllegalArgumentException Invalid format "yyyy-MM-dd hh:mm:ss"

Before to post, i search this format in previous questions but i dont found it
Here is the simple code that i want to try :
String YYYYMMDD_HHMMSS = "yyyy/MM/dd HH:mm:ss";
DateTimeFormatter yyyyMMddHHmmssFormatter = DateTimeFormat.forPattern(YYYYMMDD_HHMMSS);
DateTime fromDate = DateTime.parse("2019-01-17 11:01:15", yyyyMMddHHmmssFormatter);
I got this error :
java.lang.IllegalArgumentException: Invalid format: "2019-01-17 11:01:15" is malformed at "-01-17 11:01:15"
I think, i must change something in the string format ?
Thank's for your help

You shoud use format yyyy-MM-dd HH:mm:ss for input 2019-01-17 11:01:15, yyyy/MM/dd HH:mm:ss works when the input like 2019/01/17 11:01:15.
Update
You need two format to convet:
DateTimeFormatter inputFormat = DateTimeFormat.forPattern("yyyy-MM-dd HH:mm:ss");
DateTimeFormatter outputFormat = DateTimeFormat.forPattern("yyyy/MM/dd HH:mm:ss");
DateTime fromDate = DateTime.parse("2019-01-17 11:01:15", inputFormat);
System.out.println(outputFormat.print(fromDate));

Try changing
String YYYYMMDD_HHMMSS = "yyyy/MM/dd HH:mm:ss";
to
String YYYYMMDD_HHMMSS = "yyyy-MM-dd HH:mm:ss";

Java SimpleDateFormat use pattern with jolly character

Is there a way to parse a date with a pattern containing some "special char" or "jolly char" as separator with standard SimpleDateFormat? I want to parse my date using the patterns "yyyy MM dd", "yyyy/MM/dd", "yyyy-MM-dd" and so on..., so I'm searching something like "yyyy*MM*dd" where * is a special character meanings 'a random character'
SimpleDateFormat fmt = new SimpleDateFormat("yyyy-MM-dd");
Date d = fmt.parse(stringdate);

Use a RegEx to filter out the funny characters, then parse the filtered string?
String stringdate = "2017x01-18";
SimpleDateFormat fmt = new SimpleDateFormat("yyyy-MM-dd", Locale.ENGLISH);
Date d = fmt.parse(Pattern.compile("(....).(..).(..)").matcher(stringdate).replaceAll("$1-$2-$3"));

you should try this
String pattern = "yyyy-MM-dd";
SimpleDateFormat simpleDateFormat = new SimpleDateFormat(pattern);
String date = simpleDateFormat.format(new Date());
System.out.println(date);

You can try to 'normalize' your input to desired format:
SimpleDateFormat fmt = new SimpleDateFormat("yyyy-MM-dd");
fmt.parse(stringdate.replaceAll(" ", "-").replaceAll("/","-"));

Converting Date format to other format on Java

I have been developing application with GWT on Java. I used calendar tool for my project on this site. When i select any date, give this format (23-Aug-13) to me.
I use this code:
final DateField txtBirthofDay = new DateField("Birth of Day", "dob", 190);
txtBirthofDay.setValue(new Date());
I want to insert this date to database. So, I have to convert this format (2013-08-23). I converted lots of date format each other before but I didn't convert string type (Aug).

Reference these formats Java Date Format Docs:
try this:
SimpleDateFormat dt = new SimpleDateFormat("dd-MMM-yyyy");
Date date = dt.parse("23-Aug-2013");;
// *** same for the format String below
SimpleDateFormat dt1 = new SimpleDateFormat("yyyy-MM-dd");
System.out.println(dt1.format(date));

SimpleDateFormat formats your Date to the given pattern
SimpleDateFormat sdf = new SimpleDateFormat("yyyy-MM-dd");
System.out.println(sdf.format(new Date()));

Try this,
DateFormat df=new SimpleDateFormat("dd-MMM-yy");
Date date=df.parse("23-Aug-13");
System.out.println(df.format(date));
df=new SimpleDateFormat("yyyy-MM-dd");
String requiredFormatedDate=df.format(date);
System.out.println(requiredFormatedDate);// 2013-08-23

format date using SimpleDateFormat

I am getting parser Exception while parsing the below date using simple date format API.
String inputTimeStamp = "2012/07/19 09:49:00 - GMT -08:00";
java.text.SimpleDateFormat dateformate= new SimpleDateFormat("yyyy-MM-dd HH:mm:ss");
effDate = dateformate.parse(inputTimeStamp);
Please help me out on this.

Change
java.text.SimpleDateFormat dateformate=
new SimpleDateFormat("yyyy-MM-dd HH:mm:ss");
to
java.text.SimpleDateFormat dateformate=
new SimpleDateFormat("yyyy/MM/dd HH:mm:ss");
You have slashes (/) in your inputTimeStamp

Because you are parsing a date which is in a different format then you have described it to the SimpleDateFormat. If effDate is of type String and should hold the formatted date, the following code might solve it, although there is not supposed to be an space between GMTand -08:00 .
String inputTimeStamp = "2012/07/19 09:49:00 - GMT -08:00";
SimpleDateFormat inputDateformat = new SimpleDateFormat("yyyy/MM/dd HH:mm:ss - z");
SimpleDateFormat dateformate = new SimpleDateFormat("yyyy-MM-dd HH:mm:ss");
effDate = dateformate.format(inputDateFormat.parse(inputTimeStamp));
I would highly recommend also joda time, especially when you want to do calculations on the date.
String inputTimeStamp = "2012/07/19 09:49:00 - GMT -08:00";
DateTimeFormatter inputDateformat = DateTimeFormat.forPattern("yyyy/MM/dd HH:mm:ss - z Z");
DateTimeFormatter dateformate = DateTimeFormat.forPattern("yyyy-MM-dd HH:mm:ss");
effDate = dateformate.print(inputDateFormat.parseDateTime(inputTimeStamp));

The pattern would be: yyyy/MM/dd HH:mm:ss - z where z is for General Time Zone. SimpleDateFormat.

Try this:
new SimpleDateFormat("yyyy/MM/dd HH:mm:ss - z");
See this FYR

change value of a timestamp format into other timestamp format?

Hi can anyone tell me how can i change a given timestamp format into other timestamp format
like
DateFormat formatter = new SimpleDateFormat("yyyy-MM-dd HH:mm:ss");
Calendar d1 = Calendar.getInstance();
d1.setTime(formatter.parse("2012-03-08 17:32:56"));
to
"dd-MMM-yyyy HH:mm:ss"
format

format the date with new date format dd-MMM-yyyy HH:mm:ss
DateFormat formatter = new SimpleDateFormat("yyyy-MM-dd HH:mm:ss");
Date oldFormatedDate = formatter.parse("2012-03-08 17:32:56");
System.out.println(new SimpleDateFormat("dd-MMM-yyyy HH:mm:ss").
format(oldFormatedDate));

Continue with DateFormat#format(Date):
SimpleDateFormatter newFormat = new SimpleDateFormatter("dd-MMM-yyyy HH:mm:ss");
String newFormattedDate = newFormat.format(d1);