Java DefaultHttpClient HTTP PUT and Cookie - java

I'm send a request to YouTrack api to create issue.
String url = yBaseUrl + "/rest/issue?Task&"+ URLEncoder.encode(subject)+"&"+URLEncoder.encode(desc);
HttpClient client = new DefaultHttpClient();
HttpPut request = new HttpPut(url);
// add request header
((DefaultHttpClient) client).setCookieStore(cookie);
HttpResponse response = null;
//client.execute(post);
try {
response = client.execute(request);
System.out.println(response.getStatusLine().getStatusCode());
} catch (IOException e) {
e.printStackTrace();
}
result - 403 code.
Why setCookieStore not working?

The problem was incorrect api url. Need use /rest/issue?project=Task&summary="+ URLEncoder.encode(subject)... The question is closed

Related

Get java.net.SocketException: java.lang.IllegalStateException: No factory found. While trying to send POST request to HTTP server

I am writing an Android application in Android Studio which is sending a POST request to the server.
I have made a class for the HTTP connection:
public class PostTask extends AsyncTask {
#Override
protected Object doInBackground(Object[] objects) {
Requester requester = new Requester();
HttpClient httpclient = new DefaultHttpClient();
HttpPost httppost = new HttpPost("https://dev-api.shping.com/serialization-service/reassignment/task");
HttpResponse response = null;
HttpHost httpproxy = new HttpHost("hmkproxy1.fmlogistic.fr",8080);
httpclient.getParams().setParameter(ConnRoutePNames.DEFAULT_PROXY, httpproxy);
try {
httppost.setHeader("authenticateit_identity_ticket","63eb8926-e661-42c1-998d-3f008665c8e5");
httppost.setHeader("cache-control","no-cache");
httppost.setHeader("content-type", "application/json");
StringEntity params = new StringEntity(requester.getJsonObject().toString());
httppost.setEntity(params);
// Execute HTTP Post Request
response = httpclient.execute(httppost);
System.out.println(response);
} catch (ClientProtocolException e) {
System.out.println("FUCK1");
} catch (IOException e) {
System.out.println(e);
}
return null;
}
}
I am connecting through a proxy. I get this exception while my app works: java.net.SocketException: java.lang.IllegalStateException: No factory found
Please help me, there is nearly no information about this exception on the internet. I tried to add some socket factories to my method, but it doesn't seems to work so I deleted them.
Thanks!
Remove android:networkSecurityConfig from manifest.

Send HTTPS request with JSON through Java [duplicate]

I would like to make a simple HTTP POST using JSON in Java.
Let's say the URL is www.site.com
and it takes in the value {"name":"myname","age":"20"} labeled as 'details' for example.
How would I go about creating the syntax for the POST?
I also can't seem to find a POST method in the JSON Javadocs.
Here is what you need to do:
Get the Apache HttpClient, this would enable you to make the required request
Create an HttpPost request with it and add the header application/x-www-form-urlencoded
Create a StringEntity that you will pass JSON to it
Execute the call
The code roughly looks like (you will still need to debug it and make it work):
// #Deprecated HttpClient httpClient = new DefaultHttpClient();
HttpClient httpClient = HttpClientBuilder.create().build();
try {
HttpPost request = new HttpPost("http://yoururl");
StringEntity params = new StringEntity("details={\"name\":\"xyz\",\"age\":\"20\"} ");
request.addHeader("content-type", "application/x-www-form-urlencoded");
request.setEntity(params);
HttpResponse response = httpClient.execute(request);
} catch (Exception ex) {
} finally {
// #Deprecated httpClient.getConnectionManager().shutdown();
}
You can make use of Gson library to convert your java classes to JSON objects.
Create a pojo class for variables you want to send
as per above Example
{"name":"myname","age":"20"}
becomes
class pojo1
{
String name;
String age;
//generate setter and getters
}
once you set the variables in pojo1 class you can send that using the following code
String postUrl = "www.site.com";// put in your url
Gson gson = new Gson();
HttpClient httpClient = HttpClientBuilder.create().build();
HttpPost post = new HttpPost(postUrl);
StringEntity postingString = new StringEntity(gson.toJson(pojo1));//gson.tojson() converts your pojo to json
post.setEntity(postingString);
post.setHeader("Content-type", "application/json");
HttpResponse response = httpClient.execute(post);
and these are the imports
import org.apache.http.HttpEntity;
import org.apache.http.HttpResponse;
import org.apache.http.client.HttpClient;
import org.apache.http.client.methods.HttpPost;
import org.apache.http.entity.StringEntity;
import org.apache.http.impl.client.HttpClientBuilder;
and for GSON
import com.google.gson.Gson;
#momo's answer for Apache HttpClient, version 4.3.1 or later. I'm using JSON-Java to build my JSON object:
JSONObject json = new JSONObject();
json.put("someKey", "someValue");
CloseableHttpClient httpClient = HttpClientBuilder.create().build();
try {
HttpPost request = new HttpPost("http://yoururl");
StringEntity params = new StringEntity(json.toString());
request.addHeader("content-type", "application/json");
request.setEntity(params);
httpClient.execute(request);
// handle response here...
} catch (Exception ex) {
// handle exception here
} finally {
httpClient.close();
}
It's probably easiest to use HttpURLConnection.
http://www.xyzws.com/Javafaq/how-to-use-httpurlconnection-post-data-to-web-server/139
You'll use JSONObject or whatever to construct your JSON, but not to handle the network; you need to serialize it and then pass it to an HttpURLConnection to POST.
protected void sendJson(final String play, final String prop) {
Thread t = new Thread() {
public void run() {
Looper.prepare(); //For Preparing Message Pool for the childThread
HttpClient client = new DefaultHttpClient();
HttpConnectionParams.setConnectionTimeout(client.getParams(), 1000); //Timeout Limit
HttpResponse response;
JSONObject json = new JSONObject();
try {
HttpPost post = new HttpPost("http://192.168.0.44:80");
json.put("play", play);
json.put("Properties", prop);
StringEntity se = new StringEntity(json.toString());
se.setContentType(new BasicHeader(HTTP.CONTENT_TYPE, "application/json"));
post.setEntity(se);
response = client.execute(post);
/*Checking response */
if (response != null) {
InputStream in = response.getEntity().getContent(); //Get the data in the entity
}
} catch (Exception e) {
e.printStackTrace();
showMessage("Error", "Cannot Estabilish Connection");
}
Looper.loop(); //Loop in the message queue
}
};
t.start();
}
Try this code:
HttpClient httpClient = new DefaultHttpClient();
try {
HttpPost request = new HttpPost("http://yoururl");
StringEntity params =new StringEntity("details={\"name\":\"myname\",\"age\":\"20\"} ");
request.addHeader("content-type", "application/json");
request.addHeader("Accept","application/json");
request.setEntity(params);
HttpResponse response = httpClient.execute(request);
// handle response here...
}catch (Exception ex) {
// handle exception here
} finally {
httpClient.getConnectionManager().shutdown();
}
I found this question looking for solution about how to send post request from java client to Google Endpoints. Above answers, very likely correct, but not work in case of Google Endpoints.
Solution for Google Endpoints.
Request body must contains only JSON string, not name=value pair.
Content type header must be set to "application/json".
post("http://localhost:8888/_ah/api/langapi/v1/createLanguage",
"{\"language\":\"russian\", \"description\":\"dsfsdfsdfsdfsd\"}");
public static void post(String url, String json ) throws Exception{
String charset = "UTF-8";
URLConnection connection = new URL(url).openConnection();
connection.setDoOutput(true); // Triggers POST.
connection.setRequestProperty("Accept-Charset", charset);
connection.setRequestProperty("Content-Type", "application/json;charset=" + charset);
try (OutputStream output = connection.getOutputStream()) {
output.write(json.getBytes(charset));
}
InputStream response = connection.getInputStream();
}
It sure can be done using HttpClient as well.
You can use the following code with Apache HTTP:
String payload = "{\"name\": \"myname\", \"age\": \"20\"}";
post.setEntity(new StringEntity(payload, ContentType.APPLICATION_JSON));
response = client.execute(request);
Additionally you can create a json object and put in fields into the object like this
HttpPost post = new HttpPost(URL);
JSONObject payload = new JSONObject();
payload.put("name", "myName");
payload.put("age", "20");
post.setEntity(new StringEntity(payload.toString(), ContentType.APPLICATION_JSON));
For Java 11 you can use the new HTTP client:
HttpClient client = HttpClient.newHttpClient();
HttpRequest request = HttpRequest.newBuilder()
.uri(URI.create("http://localhost/api"))
.header("Content-Type", "application/json")
.POST(ofInputStream(() -> getClass().getResourceAsStream(
"/some-data.json")))
.build();
client.sendAsync(request, BodyHandlers.ofString())
.thenApply(HttpResponse::body)
.thenAccept(System.out::println)
.join();
You can use publishers from InputStream, String, File. Converting JSON to a String or IS can be done with Jackson.
Java 11 standardization of HTTP client API that implements HTTP/2 and Web Socket, and can be found at java.net.HTTP.*:
String payload = "{\"name\": \"myname\", \"age\": \"20\"}";
HttpClient client = HttpClient.newHttpClient();
HttpRequest request = HttpRequest.newBuilder(URI.create("www.site.com"))
.header("content-type", "application/json")
.POST(HttpRequest.BodyPublishers.ofString(payload))
.build();
HttpResponse<String> response = client.send(request, BodyHandlers.ofString());
Java 8 with apache httpClient 4
CloseableHttpClient client = HttpClientBuilder.create().build();
HttpPost httpPost = new HttpPost("www.site.com");
String json = "details={\"name\":\"myname\",\"age\":\"20\"} ";
try {
StringEntity entity = new StringEntity(json);
httpPost.setEntity(entity);
// set your POST request headers to accept json contents
httpPost.setHeader("Accept", "application/json");
httpPost.setHeader("Content-type", "application/json");
try {
// your closeablehttp response
CloseableHttpResponse response = client.execute(httpPost);
// print your status code from the response
System.out.println(response.getStatusLine().getStatusCode());
// take the response body as a json formatted string
String responseJSON = EntityUtils.toString(response.getEntity());
// convert/parse the json formatted string to a json object
JSONObject jobj = new JSONObject(responseJSON);
//print your response body that formatted into json
System.out.println(jobj);
} catch (IOException e) {
e.printStackTrace();
} catch (JSONException e) {
e.printStackTrace();
}
} catch (UnsupportedEncodingException e) {
e.printStackTrace();
}
I recomend http-request built on apache http api.
HttpRequest<String> httpRequest = HttpRequestBuilder.createPost(yourUri, String.class)
.responseDeserializer(ResponseDeserializer.ignorableDeserializer()).build();
public void send(){
ResponseHandler<String> responseHandler = httpRequest.execute("details", yourJsonData);
int statusCode = responseHandler.getStatusCode();
String responseContent = responseHandler.orElse(null); // returns Content from response. If content isn't present returns null.
}
If you want send JSON as request body you can:
ResponseHandler<String> responseHandler = httpRequest.executeWithBody(yourJsonData);
I higly recomend read documentation before use.

Use Java to get Github repositories

I'm using the following code to send a http request to github.
String url = "https://api.github.com/repositories";
try {
CloseableHttpClient httpClient = HttpClientBuilder.create().build();
HttpPost request = new HttpPost(url);
// StringEntity params = new StringEntity(body);
request.addHeader("content-type", "application/json");
// request.setEntity(params);
HttpResponse result = httpClient.execute(request);
String json = EntityUtils.toString(result.getEntity(), "UTF-8");
System.out.println(json);
} catch (IOException ex) {
}
I got output: {"message":"Not Found","documentation_url":"https://developer.github.com/v3"}
If use directly put "https://api.github.com/repositories" in browser, a lot of useful information will be shown. My question is how can I get the information I see when using browser by using Java.
You should use HttpGet instead of HttpPost. Just like your browser sends a GET request.

How to send a request (and receive it) in XML format from some web-service?

I'm working in a E-Commerce website, with JSF 2.
In order to communicate with the company that makes all the operation with the banks, I need to send this XML to them (it's just a sample provided from them):
<?xml version="1.0" encoding="ISO-8859-1"?>
<requisicao-transacao versao="1.2.0" id="6560a94c-663b-4aec-9a45-e45f278e00b4" xmlns="http://ecommerce.cbmp.com.br">
<dados-ec>
<numero>1001734898</numero>
<chave>e84827130b9837473681c2787007da5914d6359947015a5cdb2b8843db0fa832</chave>
</dados-ec>
<dados-pedido>
<numero>1603662828</numero>
<valor>100</valor>
<moeda>986</moeda>
<data-hora>2010-07-14T15:50:11</data-hora>
<idioma>PT</idioma>
</dados-pedido>
<forma-pagamento>
<bandeira>visa</bandeira>
<produto>A</produto>
<parcelas>1</parcelas>
</forma-pagamento>
<url-retorno>https://www.dummyurl.du/dummypage.do?id=trhjgnerifvnidjfnvmd</url-retorno>
<autorizar>1</autorizar>
<capturar>true</capturar>
</requisicao-transacao>
So after reading a lot about how to send and XML and receive it, I create this method:
public String rent(){
//String folderAndFile = createTransaction();
//creating the HTTP Post
DefaultHttpClient client = new DefaultHttpClient();
HttpPost post = new HttpPost("https://qasecommerce.cielo.com.br/servicos/ecommwsec.do");
try {
//Reading the file as an entity
FileEntity entity = new FileEntity(new File("/home/valter.silva/sample.xml"));
entity.setContentType("text/xml");
post.setEntity(entity);
HttpResponse response = client.execute(post);
HttpEntity httpEntity = response.getEntity();
System.out.println(EntityUtils.toString(httpEntity));
} catch (IOException e) {
e.printStackTrace();
}
return null;
}
But the output is always :
INFO: <?xml version="1.0" encoding="ISO-8859-1"?> <erro xmlns="http://ecommerce.cbmp.com.br"> <codigo>001</codigo> <mensagem>Requisição inválida</mensagem> </erro>
Which means that my .xml that I'm sending is invalid. That for some reason, the XML is wrong.. but what ?
Is alright the way that I'm sending the file ? What can I do about it ?
update
I was trying another approach but still the output is always the same, ..., is something wrong with my code ?
//approach v1
public String rent(){
//String folderAndFile = createTransaction();
try {
File file = new File("/home/valter.silva/test.xml");
HttpPost post = new HttpPost("https://qasecommerce.cielo.com.br/servicos/ecommwsec.do");
post.setEntity(new InputStreamEntity(new FileInputStream(file),file.length()));
post.setHeader("Content-type", "text/xml; charset=ISO-8859-1");
//creating the HTTP Post
DefaultHttpClient client = new DefaultHttpClient();
HttpResponse response = client.execute(post);
HttpEntity httpEntity = response.getEntity();
System.out.println(EntityUtils.toString(httpEntity));
} catch (IOException e) {
e.printStackTrace();
}
return null;
}
//approach v2
public String rent(){
//String folderAndFile = createTransaction();
try {
File file = new File("/home/valter.silva/test.xml");
HttpPost post = new HttpPost("https://qasecommerce.cielo.com.br/servicos/ecommwsec.do");
//creating the HTTP Post
DefaultHttpClient client = new DefaultHttpClient();
String fileInString = fileToString("/home/valter.silva/test.xml");
InputStream inputStream=new ByteArrayInputStream(fileInString.getBytes());//init your own inputstream
InputStreamEntity inputStreamEntity=new InputStreamEntity(inputStream,fileInString.length());
post.setEntity(inputStreamEntity);
HttpResponse response = client.execute(post);
HttpEntity httpEntity = response.getEntity();
System.out.println(EntityUtils.toString(httpEntity));
} catch (IOException e) {
e.printStackTrace();
}
return null;
}
Can you check that the url where you trying to post can handle your xml correctly ?
I have tried to upload the xml you provided using just simple http post to the specified url and got
<?xml version="1.0" encoding="ISO-8859-1"?> <erro xmlns="http://ecommerce.cbmp.com.br"> <codigo>001</codigo> <mensagem>Requisição inválida</mensagem> </erro>
I prefer you first try to upload the xml from outside and then try with your code .
For example i used RESTClient of Mozilla addon .

How to connect Android app with MySQL database through PHP

I am still a little skeptical as to how to connect my Android app to a PHP script. I saw somewhere that the following code will connect the app to the server. But I am new at android so I do not know how to really use it.
DefaultHttpClient httpClient = new DefaultHttpClient();
HttpGet httpGet = new HttpGet("http://url.to.my.app.com");
HttpResponse response = httpClient.execute(httpGet);
// handle response'
I understand that this opens a connection to an online server, but what I do not understand is what kind of response is returned by the server and how to process it. Also, I want to know how to send data through POST to the server from my app.
(If you could provide some code of your own, that would be helpful too) Thanks!
This will open a connection and send a http GET request to server. Your PHP script executes on the server side for this request and returns some contents. You can use folowing code to process the response.
HttpEntity entity = response.getEntity();
if (entity != null) {
InputStream instream = entity.getContent();
String result = RestClient.convertStreamToString(instream);
}
For POST execution you need to do something like this.
// Create a new HttpClient and Post Header
HttpClient httpclient = new DefaultHttpClient();
HttpPost httppost = new HttpPost("http://www.yoursite.com/script.php");
try {
// Add your data
List <NameValuePair> nvps = new ArrayList <NameValuePair>();
nvps.add(new BasicNameValuePair("test1","test1" ));
nvps.add(new BasicNameValuePair("test2", "test2" ));
httppost.setEntity(new UrlEncodedFormEntity(nvps, HTTP.UTF_8));
// Execute HTTP Post Request
HttpResponse response = httpclient.execute(httppost);
} catch (ClientProtocolException e) {
// TODO Auto-generated catch block
} catch (IOException e) {
// TODO Auto-generated catch block
}

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