How to set space as thousand separator for DecimalFormat in float? I want to show 13,52 as 13,5, but 13,00 as 13 and I did this with
new DecimalFormat("#.#").format(fIncome)
but I want to 1400,5 be 1 400,5 and 1400 to be 1 400.
For double I use this code (I don't want to shows numbers after comma in dCount):
String.format("%,d", (int)dCount)
But how to use this for floating number with 1 number after comma?
The accepted answer probably lacks a few lines of code, because it doesn't work as described. Here's how I did it:
private static final String DECIMAL_FORMAT = "###,###.#";
private String formatValue(Number value, String formatString) {
DecimalFormatSymbols formatSymbols = new DecimalFormatSymbols(Locale.ENGLISH);
formatSymbols.setDecimalSeparator('.');
formatSymbols.setGroupingSeparator(' ');
DecimalFormat formatter = new DecimalFormat(formatString, formatSymbols);
return formatter.format(value);
}
I then call it like this:
formatValue(value, DECIMAL_FORMAT);
To explain how it works, the . in DECIMAL_FORMAT is replaced with decimalSeparator and the , is replaced with groupingSeparator, which is a space in this case.
Ok I got what I want :)
new DecimalFormat("###,###.#").format(fIncome)
Related
I am attempting to use the DecimalFormat java class for the first time, and I am running into a strange issue. I would like 125.295 to round to 125.30. I would think the format should automatically include the 0, but maybe I'm incorrect.
double num = 125.295;
DecimalFormat df = new DecimalFormat("#.##");
df.setRoundingMode(RoundingMode.HALF_UP);
String str = df.format(num);
System.out.println(str); //this is yielding 125.3 instead of 125.30
Please help and thank you in advance!
The DecimalFormat class treats '#' as "hide trailing zeroes" or '0' as "show the zeroes". As per the API for DecimalFormat:
0 Number Yes Digit
# Number Yes Digit, zero shows as absent
So you should use DecimalFormat("#.00") instead of DecimalFormat("#.##") if you want it to show trailing zeroes.
Try to use DecimalFormat like this:
double num = 125.295;
DecimalFormat df = new DecimalFormat("###.00");
System.out.println("sum (DecimalFormat) : " + df.format(num));
Output:
125.30
I need to right align an input string of digits with a mask using plus symbols.
For example:
String input = "893";
String mask = "&&&&&&";
should return
String output = "+++893";
I'm very confused on how to implement this with NumberFormat and or DecimalFormat as I haven't used them before. Any help would be appreciated.
If you need to use DeciamlFormat you could use:
int input = 893;
DecimalFormat decFormat = new DecimalFormat("000000"); //as many palces as you need
String output = decFormat.format(input);
And then replace all leading zeros with + sign.
String.format("%06d", input); //also gives you leading zeros
You still have to check if the output is too long, if you always want 6 places.
You could try this: If the length of the mask is greater than the length of the input, take the difference and add that many plus signs to the front of the input.
I am trying to format prices using DecimalFormat, but this isn't working for all variations.
DecimalFormat df = new DecimalFormat("0.##")
df.format(7.8)
df.format(85.0)
prints
7.80
and
85
but "7.79999" gets formatted as "7.8", not "7.80". I have tried doing things this way
DecimalFormat df = new DecimalFormat("0.00")
to force two dp, but then "85.0" gets formatted as "85.00" not "85"!
Is there a way of capturing all variations, so that prices are printed either as #, ##, or #.##? For example:
5, 55, 5.55, 5.50, 500, 500.40
There is a slight difference between these two formats. The "#.##" means it will print the number with maximum two decimal places whereas "#.00" means it will always display two decimal places and if the decimal places are less than two, it will replace them with zeros. see the example below with output.
public static final DecimalFormat df1 = new DecimalFormat( "#.##" );
public static final DecimalFormat df2 = new DecimalFormat( "#.00" );
System.out.println(df1.format(7.80));
System.out.println(df1.format(85));
System.out.println(df1.format(85.786));
System.out.println(df2.format(7.80));
System.out.println(df2.format(85));
System.out.println(df2.format(85.786));
And the output will be
7.8
85
85.79
7.80
85.00
85.79
This doesn't seem to be solved by a single formatter. I suggest you use "0.00" format and replace ".00" with an empty string.
public static String myFormat(double number) {
DecimalFormat df = new DecimalFormat("0.00");
return df.format(number).replaceAll("\\.00$", "");
}
I don't think it's possible, at least not with Java SE formatters. You need to make a custom formatter. I would do it like this
String res = df.format(number).replace(".00", "");
Use the BigDecimal number class instead:
e.g. if n is a BigDecimal,
then you can use
String s = NumberFormat.getCurrencyInstance().format(n);
By the way, it's best practice to use BigDecimal when working with money.
You can try with:
DecimalFormat df = new DecimalFormat("#.##",new DecimalFormatSymbols(Locale.US));
System.out.println(new java.text.DecimalFormat("#.##").format(5.00));
This will print 5
System.out.println(new java.text.DecimalFormat("#.00").format(500.401));
This will print 500.40
I'd like to use Java's DecimalFormat to format doubles like so:
#1 - 100 -> $100
#2 - 100.5 -> $100.50
#3 - 100.41 -> $100.41
The best I can come up with so far is:
new DecimalFormat("'$'0.##");
But this doesn't work for case #2, and instead outputs "$100.5"
Edit:
A lot of these answers are only considering cases #2 and #3 and not realizing that their solution will cause #1 to format 100 as "$100.00" instead of just "$100".
Does it have to use DecimalFormat?
If not, it looks like the following should work:
String currencyString = NumberFormat.getCurrencyInstance().format(currencyNumber);
//Handle the weird exception of formatting whole dollar amounts with no decimal
currencyString = currencyString.replaceAll("\\.00", "");
Use NumberFormat:
NumberFormat n = NumberFormat.getCurrencyInstance(Locale.US);
double doublePayment = 100.13;
String s = n.format(doublePayment);
System.out.println(s);
Also, don't use doubles to represent exact values. If you're using currency values in something like a Monte Carlo method (where the values aren't exact anyways), double is preferred.
See also: Write Java programs to calculate and format currency
Try
new DecimalFormat("'$'0.00");
Edit:
I Tried
DecimalFormat d = new DecimalFormat("'$'0.00");
System.out.println(d.format(100));
System.out.println(d.format(100.5));
System.out.println(d.format(100.41));
and got
$100.00
$100.50
$100.41
Try using
DecimalFormat.setMinimumFractionDigits(2);
DecimalFormat.setMaximumFractionDigits(2);
You can check "is number whole or not" and choose needed number format.
public class test {
public static void main(String[] args){
System.out.println(function(100d));
System.out.println(function(100.5d));
System.out.println(function(100.42d));
}
public static String function(Double doubleValue){
boolean isWholeNumber=(doubleValue == Math.round(doubleValue));
DecimalFormatSymbols formatSymbols = new DecimalFormatSymbols(Locale.GERMAN);
formatSymbols.setDecimalSeparator('.');
String pattern= isWholeNumber ? "#.##" : "#.00";
DecimalFormat df = new DecimalFormat(pattern, formatSymbols);
return df.format(doubleValue);
}
}
will give exactly what you want:
100
100.50
100.42
You can use the following format:
DecimalFormat dformat = new DecimalFormat("$#.##");
I know its too late. However following worked for me :
DecimalFormatSymbols otherSymbols = new DecimalFormatSymbols(Locale.UK);
new DecimalFormat("\u00A4#######0.00",otherSymbols).format(totalSale);
\u00A4 : acts as a placeholder for currency symbol
#######0.00 : acts as a placeholder pattern for actual number with 2 decimal
places precision.
Hope this helps whoever reads this in future :)
You can try by using two different DecimalFormat objects based on the condition as follows:
double d=100;
double d2=100.5;
double d3=100.41;
DecimalFormat df=new DecimalFormat("'$'0.00");
if(d%1==0){ // this is to check a whole number
DecimalFormat df2=new DecimalFormat("'$'");
System.out.println(df2.format(d));
}
System.out.println(df.format(d2));
System.out.println(df.format(d3));
Output:-
$100
$100.50
$100.41
You could use the Java Money API to achieve this. (although this is not using DecialFormat)
long amountInCents = ...;
double amountInEuro = amountInCents / 100.00;
String customPattern;
if (minimumOrderValueInCents % 100 == 0) {
customPattern = "# ¤";
} else {
customPattern = "#.## ¤";
}
Money minDeliveryAmount = Money.of(amountInEuro, "EUR");
MonetaryAmountFormat formatter = MonetaryFormats.getAmountFormat(AmountFormatQueryBuilder.of(Locale.GERMANY)
.set(CurrencyStyle.SYMBOL)
.set("pattern", customPattern)
.build());
System.out.println(minDeliveryAmount);
printf also works.
Example:
double anyNumber = 100;
printf("The value is %4.2f ", anyNumber);
Output:
The value is 100.00
4.2 means force the number to have two digits after the decimal. The 4 controls how many digits to the right of the decimal.
What is the best way to format the following number that is given to me as a String?
String number = "1000500000.574" //assume my value will always be a String
I want this to be a String with the value: 1,000,500,000.57
How can I format it as such?
You might want to look at the DecimalFormat class; it supports different locales (eg: in some countries that would get formatted as 1.000.500.000,57 instead).
You also need to convert that string into a number, this can be done with:
double amount = Double.parseDouble(number);
Code sample:
String number = "1000500000.574";
double amount = Double.parseDouble(number);
DecimalFormat formatter = new DecimalFormat("#,###.00");
System.out.println(formatter.format(amount));
This can also be accomplished using String.format(), which may be easier and/or more flexible if you are formatting multiple numbers in one string.
String number = "1000500000.574";
Double numParsed = Double.parseDouble(number);
System.out.println(String.format("The input number is: %,.2f", numParsed));
// Or
String numString = String.format("%,.2f", numParsed);
For the format string "%,.2f" - "," means separate digit groups with commas, and ".2" means round to two places after the decimal.
For reference on other formatting options, see https://docs.oracle.com/javase/tutorial/java/data/numberformat.html
Given this is the number one Google result for format number commas java, here's an answer that works for people who are working with whole numbers and don't care about decimals.
String.format("%,d", 2000000)
outputs:
2,000,000
Once you've converted your String to a number, you can use
// format the number for the default locale
NumberFormat.getInstance().format(num)
or
// format the number for a particular locale
NumberFormat.getInstance(locale).format(num)
I've created my own formatting utility. Which is extremely fast at processing the formatting along with giving you many features :)
It supports:
Comma Formatting E.g. 1234567 becomes 1,234,567.
Prefixing with "Thousand(K),Million(M),Billion(B),Trillion(T)".
Precision of 0 through 15.
Precision re-sizing (Means if you want 6 digit precision, but only have 3 available digits it forces it to 3).
Prefix lowering (Means if the prefix you choose is too large it lowers it to a more suitable prefix).
The code can be found here. You call it like this:
public static void main(String[])
{
int settings = ValueFormat.COMMAS | ValueFormat.PRECISION(2) | ValueFormat.MILLIONS;
String formatted = ValueFormat.format(1234567, settings);
}
I should also point out this doesn't handle decimal support, but is very useful for integer values. The above example would show "1.23M" as the output. I could probably add decimal support maybe, but didn't see too much use for it since then I might as well merge this into a BigInteger type of class that handles compressed char[] arrays for math computations.
you can also use the below solution
public static String getRoundOffValue(double value){
DecimalFormat df = new DecimalFormat("##,##,##,##,##,##,##0.00");
return df.format(value);
}
public void convert(int s)
{
System.out.println(NumberFormat.getNumberInstance(Locale.US).format(s));
}
public static void main(String args[])
{
LocalEx n=new LocalEx();
n.convert(10000);
}
You can do the entire conversion in one line, using the following code:
String number = "1000500000.574";
String convertedString = new DecimalFormat("#,###.##").format(Double.parseDouble(number));
The last two # signs in the DecimalFormat constructor can also be 0s. Either way works.
Here is the simplest way to get there:
String number = "10987655.876";
double result = Double.parseDouble(number);
System.out.println(String.format("%,.2f",result));
output:
10,987,655.88
The first answer works very well, but for ZERO / 0 it will format as .00
Hence the format #,##0.00 is working well for me.
Always test different numbers such as 0 / 100 / 2334.30 and negative numbers before deploying to production system.
According to chartGPT
Using DecimalFormat:
DecimalFormat df = new DecimalFormat("#,###.00");
String formattedNumber = df.format(yourNumber);
Using NumberFormat:
NumberFormat nf = NumberFormat.getNumberInstance();
nf.setGroupingUsed(true);
String formattedNumber = nf.format(yourNumber);
Using String.format():
String formattedNumber = String.format("%,.2f", yourNumber);
Note: In all the above examples, "yourNumber" is the double value that you want to format with a comma. The ".2f" in the format string indicates that the decimal places should be rounded to 2 decimal places. You can adjust this value as needed.