I'm storing dates in a database as a single string in the format "2 15 2015" (presumably "M d yyyy"?). strDate in the code below contains the return value of a method that grabs the date. I want to parse the date so as to set a datepicker. Based on the examples in Java string to date conversion
I've created the following code for parsing the date, but am getting an "Unhandled Exception: java.text.ParseException" at
Date date = format.parse(strDate);
Scratching my head.
Calendar mydate = new GregorianCalendar();
String strDate = datasource.get_Column_StrVal(dbData,
MySQLiteHelper.dbFields.COLUMN_SPECIAL_DAYS_DATE);
SimpleDateFormat format = new SimpleDateFormat("M d yyyy", Locale.ENGLISH);
Date date = format.parse(strDate);
mydate.setTime(date);
You are getting this compile-time error because you are not handling the ParseException that the parse method throws. This is necessary because ParseException is not a runtime exception (it is a checked exception since it extends directly from java.lang.Exception).
You need to surround your code with try/catch to handle the exception, like this :
try {
SimpleDateFormat format = new SimpleDateFormat("M d yyyy", Locale.ENGLISH);
Date date = format.parse(strDate);
mydate.setTime(date);
} catch (ParseException e) {
//handle exception
}
Well, you indeed have it. Just surround it with try/catch as the compiler will hint you.
Related
This question already has answers here:
Java Date Error
(8 answers)
Closed 4 years ago.
I want to convert String values in the format of mm/dd/yy to YYYY-MM-DD Date. how to do this conversion?
The input parameter is: 03/01/18
Code to convert String to Date is given below
public static Date stringToDateLinen(String dateVlaue) {
Date date = null;
SimpleDateFormat formatter = new SimpleDateFormat("yyyy-MM-dd");
try {
date = formatter.parse(dateVlaue);
} catch (ParseException e) {
e.printStackTrace();
}
return date;
}
When tried to convert using this method it shows the following error
java.text.ParseException: Unparseable date: "03/01/18"
As you say the input is in a different format, first convert the String to a valid Date object. Once you have the Date object you can format it into different types , as you want, check.
To Convert as Date,
SimpleDateFormat formatter = new SimpleDateFormat("MM/dd/yy");
date = formatter.parse(dateVlaue);
To Print it out in the other format,
SimpleDateFormat formatter1 = new SimpleDateFormat("yyyy-MM-dd");
dateString = formatter1.format(date)
You are writing it the wrong way. In fact, for the date you want to convert, you need to write
SimpleDateFormat formatter = new SimpleDateFormat("MM/dd/yy");
The format you are passing to SimpleDateFormat is ("yyyy-MM-dd") which expects date to be in form 2013-03-01 and hence the error.
You need to supply the correct format that you are passing your input as something like below
public static Date stringToDateLinen(String dateVlaue) {
Date date = null;
SimpleDateFormat formatter = new SimpleDateFormat("dd/MM/yy");
try {
date = formatter.parse(dateVlaue);
} catch (ParseException e) {
e.printStackTrace();
}
return date;
}
The solution for the above problem
Convert the String date value in the Format of "dd/mm/yy" to Date.
By using the converted Date can able to frame the required date format.
The method has given below
public static String stringToDateLinen(String dateVlaue) {
Date date = null;
SimpleDateFormat formatter = new SimpleDateFormat("dd/mm/yy");
String dateString = null;
try {
// convert to Date Format From "dd/mm/yy" to Date
date = formatter.parse(dateVlaue);
// from the Converted date to the required format eg : "yyyy-MM-dd"
SimpleDateFormat formatter1 = new SimpleDateFormat("yyyy-MM-dd");
dateString = formatter1.format(date);
} catch (ParseException e) {
e.printStackTrace();
}
return dateString;
}
EDIT: Your question said “String values in the format of mm/dd/yy”, but I understand from your comments that you meant “my input format is dd/mm/yy as string”, so I have changed the format pattern string in the below code accordingly. Otherwise the code is the same in both cases.
public static Optional<LocalDate> stringToDateLinen(String dateValue) {
DateTimeFormatter dateFormatter = DateTimeFormatter.ofPattern("dd/MM/yy");
try {
return Optional.of(LocalDate.parse(dateValue, dateFormatter));
} catch (DateTimeParseException dtpe) {
return Optional.empty();
}
}
Try it:
stringToDateLinen("03/01/18")
.ifPresentOrElse(System.out::println,
() -> System.out.println("Could not parse"));
Output:
2018-01-03
I recommend you stay away from SimpleDateFormat. It is long outdated and notoriously troublesome too. And Date is just as outdated. Instead use LocalDate and DateTimeFormatter from java.time, the modern Java date and time API. It is so much nicer to work with. A LocalDate is a date without time of day, so this suites your requirements much more nicely than a Date, which despite its name is a point in time. LocalDate.toString() produces exactly the format you said you desired (though the LocalDate doesn’t have a format in it).
My method interprets your 2-digit year as 2000-based, that is, from 2000 through 2099. Please think twice before deciding that this is what you want.
What would you want to happen if the string cannot be parsed into a valid date? I’m afraid that returning null is a NullPointerException waiting to happen and a subsequent debugging session to track down the root cause. You may consider letting the DateTimeParseException be thrown out of your method (just declare that in Javadoc) so the root cause is in the stack trace. Or even throw an AssertionError if the situation is not supposed to happen. In my code I am returning an Optional, which clearly signals to the caller that there may not be a result, which (I hope) prevents any NullPointerException. In the code calling the method I am using the ifPresentOrElse method introduced in Java 9. If not using Java 9 yet, use ifPresent and/or read more about using Optional elsewhere.
What went wrong in your code?
The other answers are correct: Your format pattern string used for parsing needs to match the input (not your output). The ParseException was thrown because the format pattern contained hyphens and the input slashes. It was good that you got the exception because another problem is that the order of year, month and day doesn’t match, neither does the number of digits in the year.
Link
Oracle tutorial: Date Time explaining how to use java.time.
This question already has answers here:
Conversion from 12 hours time to 24 hours time in java
(17 answers)
Closed 6 years ago.
I am storing time in the database in this format: "hh:mm:ss" (example- 09:30:00) and then retrieving and trying to show it to users in this format: "hh:mm AM/PM" (example- 09:30 AM).
I'm using below code for converting it:
DateFormat currentTime = new SimpleDateFormat("hh:mm a");
String startTimeInSF = currentTime.format(startTime);
String endTimeInSF = currentTime.format(endTime);
where startTime and endTime is in hh:mm:ss format, but the above code is producing this error: java.lang.IllegalArgumentException: Bad class: class java.lang.String.
Please let me know how can I successfully convert the time from hh:mm:ss to hh:mm AM/PM?
I think you should parse your "hh:mm:ss" time into a Date Object, then use formatter to format it to "hh:mm a".
Like this :
DateFormat format1 = new SimpleDateFormat("hh:mm:ss");
try {
Date date = format1.parse("01:11:22");
SimpleDateFormat format2 = new SimpleDateFormat("hh:mm a");
String result = format2.format(date);
return result;
} catch (ParseException e) {
e.printStackTrace();
}
I believe you're looking for the parse(String source) method. The format() methods take in a Date object and output a String representation of the object. the parse methods take in a String object and converts it to a Date object.
To do what you want, you'll need to have a DateFormat with hh:mm:ss, convert the database String to a Date using parse, and then use your existing DateFormat and use format on the Date object to get the output String to display to your user.
http://docs.oracle.com/javase/7/docs/api/java/text/DateFormat.html
You need to change your code something like this, format function will not work directly on String object that is root cause of your exception.
DateFormat inputFormatter1 = new SimpleDateFormat"HH:mm:ss");
Date date1 = inputFormatter1.parse("22:10:11");
DateFormat outputFormatter1 = new SimpleDateFormat("hh:mm a");
String output1 = outputFormatter1.format(date1); //
Out will be 10:10 pm
How to differentiate between data-entry being (a) invalid date or (b) invalid format?
I have the following code for handling date inputs from an text file.
public boolean dateIsValid(String date) {
DateFormat formatter = new SimpleDateFormat("MM/dd/yyyy");
formatter.setLenient(false);
try {
Date dateParsed = (Date) formatter.parse(date);
} catch (ParseException e) {
e.printStackTrace();
}
return false;
}
I have everything working as I want it to. The only problem I have is I am unable to differentiate the different parse exceptions thrown. For example:
if String date = 18/10/2012 --> java.text.ParseException: Unparseable date: "18/10/2012"
if String date = 2-12-2001 --> java.text.ParseException: Unparseable date: "2-12-2001"
As you can see, both the wrong formats throw the same error. How can I differentiate them so that I can handle them differently?
EDIT
To be more precise, in case of date 18/10/2012, I should throw an invalid date error and in the case of date 2-12-2001, I need to throw an invalid format exception. I dont need to handle different formats. I just need a way of getting different exceptions for these two different cases.
The issue seems to be at this line
DateFormat formatter = new SimpleDateFormat("MM/dd/yyyy");
For the first error it looks like that the date is coming first and the month later so it should be like
DateFormat formatter = new SimpleDateFormat("dd/MM/yyyy");
Second error shows the incorrect format of the date supplied since it is containing - whereas you are expecting the format containing / ie like
DateFormat formatter = new SimpleDateFormat("dd-MM-yyyy");
If you want to handle different formats then try like this:
String[] formatDates= {"MM/DD/yyyy", "dd/MM/yyyy", "MM-dd-yyyy","dd-MM-yyyy"};
Date tryParse(String dateString)
{
for (String formatDate: formatDates)
{
try
{
return new SimpleDateFormat(formatDate).parse(dateString);
}
catch (ParseException e) {}
}
return null;
}
Unless you write code to parse the date strings yourself, you will not know why the format threw the exception.
I recommend a variation of the R. T. answer above.
Specifically, instead of creating a new formatter every time, create four (in that example) formatters at startup (in the constructor or in a static block).
I would use
public Date dateIfValid(String format, String date) {
DateFormat formatter = new SimpleDateFormat(format);
formatter.setLenient(false);
try {
return dateParsed = (Date) formatter.parse(date);
} catch (ParseException e) {
return null;
}
}
Date mmddyy = dateIfavlid("MM/dd/yy", date.replace("[^0-9]", "/"));
Date ddmmyy = dateIfavlid("dd/MM/yy", date.replace("[^0-9]", "/"));
if (mmddyy != null && ddmmyy == null) {
Note: this can be used to detect ambigous dates such as 01/02/03 which might be 3rd Feb 2001
I'm having a hard time Parsing/Formatting a Date string received back from a web service. I've attempted multiple approaches, but with no luck.
Sample Date String:
2011-10-05T03:00:00Z
Exception:
W/System.err(10072): java.text.ParseException: Unparseable date: "2011-10-05T05:00:00Z" (at offset 10)
W/System.err(10072): at java.text.DateFormat.parse(DateFormat.java:626)
Sample Code:
SimpleDateFormat formatter = new SimpleDateFormat("yyyy-MM-dd HH:mm:SSSS");
Date date = formatter.parse(info.AiringTime);
I've found that if I remove the "T" between the date and the time and replace it with a space, it will format just fine. Anybody have any suggestions?
--UPDATE--
After looking deeper into the API documentation, I found this:
All response DateTime values are in UTC format. You need to apply the UTC offset to calculate the local time for display.
DateTime is a date-and-time value specified in one of the following formats:
UTC format: YYYY-MM-DDThh:mm:ssZ. For example: 2011-03-15T02:00:00Z.
Local time with an offset: YYYY-MM-DDThh:mm:ss + or - hh:mm (positive or negative offset). For example, for US Pacific time: 2011-03-14T06:00:00 -08:00.
Any suggestions on the UTC format approach?
You could try:
DateFormat dateFormat = new SimpleDateFormat("yyyy-MM-dd'T'HH:mm:ssZ");
String dateString = dateString.replace("Z", "GMT+00:00");
Date date = dateFormat.parse(dateString);
The above code should correctly handle the case where a timezone is specified in the date. As Z represents the UTC/GMT timezone it is replaced by GMT so the SimpleDateFormat can interpret it correctly (i would love to know a cleaner way of handling this bit if anyone knows one).
Try,
SimpleDateFormat formatter = new SimpleDateFormat("yyyy-MM-dd'T'HH:mm:ss'Z'");
This pattern should parse the date you provide: "yyyy-MM-dd'T'HH:mm:ss'Z'".
If you want to use SimpleDateFormat and you have a limited number of variations, you can create separate formatters for each pattern and chain them:
Date date = formatter1.parse(info.AiringTime);
if (date == null)
{
date = formatter2.parse(info.AiringTime);
if (date == null)
{
date = formatter2.parse(info.AiringTime);
if (date == null)
{
date = formatter3.parse(info.AiringTime);
}
}
}
or put them in a list and iterate until non-null or no more formatters.
If you have too many patterns for this to be practical, you can parse it yourself or try one of these libraries.
This worked for me
SimpleDateFormat isoDateFormat = new SimpleDateFormat("yyyy-mm-dd'T'hh:mm:ss'Z'");
SimpleDateFormat viewFriendlyDateFormat = new SimpleDateFormat("dd/MMM/yyyy hh:mm:ss aaa");
String viewFriendlyDate = "";
try {
Date date = isoDateFormat.parse(timestamp);
viewFriendlyDate = viewFriendlyDateFormat.format(date);
} catch (ParseException e) {
e.printStackTrace();
}
SimpleDateFormat isoDateFormat = new SimpleDateFormat("yyyy-mm-dd'T'hh:mm:ss'Z'");
SimpleDateFormat viewFriendlyDateFormat = new SimpleDateFormat("dd/MMM/yyyy hh:mm:ss aaa");
String viewFriendlyDate = "";
try {
Date date = isoDateFormat.parse(timestamp);
viewFriendlyDate = viewFriendlyDateFormat.format(date);
} catch (ParseException e) {
e.printStackTrace();
}
While trying to transform the date format I get an exception:unparseable date and don't know how to fix this problem.
I am receiving a string which represents an event date and would like to display this date in different format in GUI.
What I was trying to do is the following:
private String modifyDateLayout(String inputDate){
try {
//inputDate = "2010-01-04 01:32:27 UTC";
Date date = new SimpleDateFormat("yyyy-MM-dd HH:mm:ss z").parse(inputDate);
return new SimpleDateFormat("dd.MM.yyyy HH:mm:ss").format(date);
} catch (ParseException e) {
e.printStackTrace();
return "15.01.2010";
}
}
Anyway the line
String modifiedDateString = originalDate.toString();
is dummy. I would like to get a date string in the following format:
dd.MM.yyyy HH:mm:ss
and the input String example is the following:
2010-01-04 01:32:27 UTC
Does anyone know how to convert the example date (String) above into a String format dd.MM.yyyy HH:mm:ss?
Thank you!
Edit: I fixed the wrong input date format but still it doesn't work. Above is the pasted method and below is the screen image from debugging session.
alt text http://img683.imageshack.us/img683/193/dateproblem.png
#Update
I ran
String[] timezones = TimeZone.getAvailableIDs();
and there is UTC String in the array. It's a strange problem.
I did a dirty hack that works:
private String modifyDateLayout(String inputDate){
try {
inputDate = inputDate.replace(" UTC", "");
Date date = new SimpleDateFormat("yyyy-MM-dd HH:mm:ss").parse(inputDate);
return new SimpleDateFormat("dd.MM.yyyy HH:mm:ss").format(date);
} catch (ParseException e) {
e.printStackTrace();
return "15.01.2010";
}
}
But still I would prefer to transform the original input without cutting timezone away.
This code is written for Android phone using JDK 1.6.
What you're basically doing here is relying on Date#toString() which already has a fixed pattern. To convert a Java Date object into another human readable String pattern, you need SimpleDateFormat#format().
private String modifyDateLayout(String inputDate) throws ParseException{
Date date = new SimpleDateFormat("yyyy-MM-dd HH:mm:ss z").parse(inputDate);
return new SimpleDateFormat("dd.MM.yyyy HH:mm:ss").format(date);
}
By the way, the "unparseable date" exception can here only be thrown by SimpleDateFormat#parse(). This means that the inputDate isn't in the expected pattern "yyyy-MM-dd HH:mm:ss z". You'll probably need to modify the pattern to match the inputDate's actual pattern.
Update: Okay, I did a test:
public static void main(String[] args) throws Exception {
String inputDate = "2010-01-04 01:32:27 UTC";
String newDate = new Test().modifyDateLayout(inputDate);
System.out.println(newDate);
}
This correctly prints:
03.01.2010 21:32:27
(I'm on GMT-4)
Update 2: as per your edit, you really got a ParseException on that. The most suspicious part would then be the timezone of UTC. Is this actually known at your Java environment? What Java version and what OS version are you using? Check TimeZone.getAvailableIDs(). There must be a UTC in between.
I encountered this error working in Talend. I was able to store S3 CSV files created from Redshift without a problem. The error occurred when I was trying to load the same S3 CSV files into an Amazon RDS MySQL database. I tried the default timestamp Talend timestamp formats but they were throwing exception:unparseable date when loading into MySQL.
This from the accepted answer helped me solve this problem:
By the way, the "unparseable date" exception can here only be thrown by SimpleDateFormat#parse(). This means that the inputDate isn't in the expected pattern "yyyy-MM-dd HH:mm:ss z". You'll probably need to modify the pattern to match the inputDate's actual pattern
The key to my solution was changing the Talend schema. Talend set the timestamp field to "date" so I changed it to "timestamp" then I inserted "yyyy-MM-dd HH:mm:ss z" into the format string column view a screenshot here talend schema
I had other issues with 12 hour and 24 hour timestamp translations until I added the "z" at the end of the timestamp string.
From Oracle docs, Date.toString() method convert Date object to a String of the specific form - do not use toString method on Date object. Try to use:
String stringDate = new SimpleDateFormat(YOUR_STRING_PATTERN).format(yourDateObject);
Next step is parse stringDate to Date:
Date date = new SimpleDateFormat(OUTPUT_PATTERN).parse(stringDate);
Note that, parse method throws ParseException