How to use the JOption on my guessing game? - java

import java.util.Random;
import java.util.Scanner;
import javax.swing.JOptionPane;
import java.util.*;
public class GuessingGameGUI {
public static void main(String[] args) {
Random rand = new Random();
int value = rand.nextInt(32) + 1;
int guesses = 0, LowGuess = 0, HighGuess = 0; //ADDED LowGuess AND HighGuess
Scanner input = new Scanner(System.in);
int guess;
boolean win = false;
while (win == false) {
JOptionPane.showInputDialog("Guess a number between 1 and 32: ");
guess = input.nextInt();
guesses++;
if (guess == value) {
win = true;
} else if (guess < value) {
JOptionPane.showInputDialog("Your guess is lower than random number");
LowGuess++; //COUNTER TO KEEP TRACK OF LOW GUESSES
} else if (guess > value) {
JOptionPane.showInputDialog("Your guess is higher than random number");
HighGuess++; //COUNTER TO KEEP TRACK OF HIGH GUESSES
}
}
JOptionPane.showMessageDialog(null, "You win! You are the worst guesser in history!");
JOptionPane.showMessageDialog(null, "The number was: " + value);
// ADDED FROM HERE (GUESSES)
JOptionPane.showMessageDialog(null, "Number of Guesses:" + guesses);
for (int x = 1; x <= guesses; x++) {
for (int a = 1; a <= guesses; a++) {
if (a == guesses) {
JOptionPane.showMessageDialog(null, "*");
}
}
} // TO HERE FOR AMOUNT OF GUESSES
// I ADDED FROM HERE (LOW)
JOptionPane.showMessageDialog(null, "Smaller Guesses:" + LowGuess);
for (int Low_i = 1; Low_i <= LowGuess; Low_i++) {
for (int Low_e = 1; Low_e <= LowGuess; Low_e++) {
if (Low_e == LowGuess) {
JOptionPane.showMessageDialog(null, "*");
}
}
} // Then TO HERE FOR LOW
// I ADDED FROM HERE (HIGH)
JOptionPane.showMessageDialog(null, "Largest Guesses:" + HighGuess);
for (int High_i = 1; High_i <= HighGuess; High_i++) {
for (int High_e = 1; High_e <= HighGuess; High_e++) {
if (High_e == HighGuess) {
JOptionPane.showMessageDialog(null, "*");
}
}
} //FINALLY TO HERE FOR HIGH
}
}
// when I run my program the message box pops up when i enter my guessing number, however it seems to stop and nothing else pops up to let me know if i guessed to high or to low.

Take these lines, for example:
JOptionPane.showInputDialog("Guess a number between 1 and 32: ");
guess = input.nextInt();
A prompt displays that asks you to "Guess a number between 1 and 32". So you enter the number, and then execution stops because your Scanner is awaiting your input. You need to completely remove your Scanner so you won't have these frequent interruptions.
The showInputDialog method of JOptionPane returns a String, as shown in the example from the Javadocs:
Show a dialog asking the user to type in a String:
String inputValue = JOptionPane.showInputDialog("Please input a value");
As is, you're throwing away the value returned from the method when you should instead be assigning it to your variables. In order to assign the returned value to your int variable guess, use Integer.parseInt:
guess = Integer.parseInt(JOptionPane.showInputDialog("Guess a number between 1 and 32: "));

JOptionPane.showInputDialog returns String than you have to convert that String to int using Parse methods, every time you receive input.
String input = JOptionPane.showInputDialog();
Int number = Integer.parseInt(input);

Related

One expected line of output is not printed

import java.util.Random;
import java.util.Scanner;
public class Activity3 {
public static void main(String[] args) {
//Variables
Scanner input = new Scanner(System.in);
Random Machine = new Random();
int num = Machine.nextInt(10);
do {
System.out.println("Guess the random generated number of the machine from 1-10");
int guess = input.nextInt();
if (guess == num) {
System.out.println("Correct number= " + num);
System.out.println("You Win!");
} else if (guess <= 0 && guess >= 11) {
System.out.println("Invalid Number!");
}
if (guess > 1 && guess < 10){
System.out.println("You Lose:<");
}
System.out.println("Do you want to try again?");
} while (input.next().equalsIgnoreCase("YES"));
input.close();
}
}
If I guess the correct number it outputs " you win!".
If I guess wrong it outputs "you lose". But If I guess a number that isn't in 1-10 it doesn't output the "Invalid Number" and just proceeds to output the "Do you want to try again?".
Random#nextInt(int) will return a value from 0 to bound - 1, so it's possible that the guess could be 0 in your code. You'd correct this by adding 1 to the guess, for example int num = Machine.nextInt(10) + 1;
Look at your logic...
else if(guess <= 0 && guess >= 11) {
if guess <= 0 AND guess >= 11 ... well, that's impossible.
I would change your logic flow, focusing on "happy paths" first.
That is, is the input within the acceptable range? If so, is guess == num if so, you win, otherwise print error messages.
For example...
Scanner input = new Scanner(System.in);
Random Machine = new Random();
int num = Machine.nextInt(10) + 1;
boolean done = false;
do {
System.out.println("Guess the random generated number of the machine from 1-10");
// Read the WHOLE line of text, removing the new line from the
// buffer which would otherwise be left by Scanner#nextInt
// and would cause no end of issues
String text = input.nextLine();
try {
// Try and parse the text to an int
int guess = Integer.parseInt(text);
if (guess >= 1 && guess <= 10) {
if (guess == num) {
System.out.println("Correct number= " + num);
System.out.println("You Win!");
num = Machine.nextInt(10) + 1;
System.out.println("Would you like to play another game? (Yes/No)");
} else {
System.out.println("Incorrect, guess again");
System.out.println("Do you want to try again? (Yes/No)");
}
// Prompt the user to try again or play another game
text = input.nextLine();
done = !"yes".equals(text.toLowerCase());
} else {
System.out.println("Out of range");
}
} catch (NumberFormatException exp) {
System.out.println("Not a valid number");
}
} while (!done);

How to let the user attempt many times?

import java.util.Scanner;
import java.util.Random;
/*
* 1) the user can attempt many times and you need to display the number of successful attempt
* 2) the range of random number 1..49
* 3) output >> You successfully guess the number in 16 attempts
* 4) output >> Do you want to play again?
* */
public class GuessingGame {
public static void main(String[] args) {
Scanner uInput = new Scanner(System.in);
Random randNum = new Random();
int guessNumber, number, count=0;
String in;
char again;
System.out.println("Welcome to Guessing Game");
do {
number = randNum.nextInt(50); // random number in the range of 1..50
for(int i=0; i<5; i++)
{
System.out.println("Enter a number to guess: ");
guessNumber = uInput.nextInt(); // get guess number from user
if(guessNumber > number)
{
System.out.println("Too big");
}else if(guessNumber < number)
{
System.out.println("Too small");
}else
{
System.out.println("Success");
count+=1;
return;
}
}
System.out.println("You successfully guess the number in "+count);
System.out.println("Do you want to play again? ");
in = uInput.nextLine();
again = in.charAt(0); //again will hold the first character from in var
}while(again =='Y'|| again =='y');
System.out.println("Guessing game terminate, thank you");
}
}
public static void main(String[] args) {
System.out.println("Welcome to Guessing Game");
guessNumber();
System.out.println("Guessing game terminate, thank you");
}
private static void guessNumber() {
Scanner uInput = new Scanner(System.in);
Random randNum = new Random();
int guessNumber, number, count = 0;
String in;
char again;
boolean isCorrect = false;
number = randNum.nextInt(50); // random number in the range of 1..50
while (!isCorrect) {
System.out.println("Enter a number to guess: ");
guessNumber = uInput.nextInt(); // get guess number from user
count += 1;
if (guessNumber > number) {
System.out.println("Too big");
} else if (guessNumber < number) {
System.out.println("Too small");
} else {
System.out.println("Success");
isCorrect = true;
}
}
System.out.println("You successfully guess the number in " + count + " attempts");
System.out.println("Do you want to play again? yes/no");
in = uInput.next();
again = in.charAt(0); //again will hold the first character from in var
if (again == 'Y' || again == 'y') {
guessNumber();
}
}
All you have to do is to replace your do while loop with a while loop. But the point is that you must set an initial value 'Y' to your again char to start the while loop. the condition of the loop will be just the same. The code will be like : char again = 'Y';
while (again == 'Y' || again == 'y') {
System.out.println("Welcome to Guessing Game");
number = randNum.nextInt(50);
for (int i = 0; i < 5; i++) {
System.out.println("Enter a number to guess: ");
guessNumber = uInput.nextInt();
if (guessNumber > number) {
System.out.println("Too big");
} else if (guessNumber < number) {
System.out.println("Too small");
} else {
System.out.println("Success");
count += 1;
break;
}
}
System.out.println("You have successfully guessed the number for " + count + " times");
System.out.println("Do you want to play again? ");
in = uInput.next();
again = in.charAt(0); //again will hold the first character from in var
}
System.out.println("Guessing game terminate, thank you");
I must note that your count variable, contains the number of games which user has guessed the number successfully, and not the number of attempts during a single game. If you want to handle this too, create attempts variable inside the while loop and increase it whenever the user attempts.
Also I changed the line in = uInput.nextLine(); to in = uInput.next(); because I believe your scanner input will be skipped.

How to display error message instead of java exception?

I am trying to make a Guessing Game for a Java assignment, I have everything I need except exception handling, you see I'm trying to make it display an error message instead of displaying Exception in thread "main" java.util.InputMismatchException when someone tries to enter a numerical number in alphabetical form. The code I have is followed.
(I know I need a try and catch but I don't know what to put exactly.)
package guessNumber;
import java.util.Scanner;
public class GuessNumberApp {
public static void main(String[] args) {
final int LIMIT = 10;
System.out.println("Guess the number!");
System.out.println("I'm thinking of a number from 1 to " + LIMIT);
System.out.println();
// get a random number between 1 and the limit
double d = Math.random() * LIMIT; // d is >= 0.0 and < limit
int number = (int) d; // convert double to int
number++; // int is >= 1 and <= limit
// prepare to read input from the user
Scanner sc = new Scanner(System.in);
int count = 1;
while (true) {
int guess = sc.nextInt();
System.out.println("You guessed: " + guess);
if (guess < 1 || guess > LIMIT) {
System.out.println("Your Guess is Invalid.");
continue;
}
if (guess < number) {
System.out.println("Too Low.");
} else if (guess > number) {
System.out.println("Too High.");
} else {
System.out.println("You guessed it in " + count + " tries.\n");
break;
}
count++;
}
System.out.println("Bye!");
}
}
try something like that:
try {
int guess = sc.nextInt();
} catch(InputMismatchException e) {
System.out.println("some nice error message");
continue;
}
This would replace
int guess = sc.nextInt();

How am i going to use while loop and if else if user enter the same input twice and it will try again

I want to apply this function in java. Inside while loop, you need to input number of repetition you want to input a number. if you input a number that equals to the number that you enter previously, it will repeat a loop and enter a number again. This code is not finish yet. I hope u understand what i want to achive. thank you
System.out.print("Enter number of times: ");
int times = number.nextInt();
int i = 1;
while ( i <= times){
System.out.print("Enter a number : ");
int input = number.nextInt();
i++;
if( input == input){
System.out.println("It is already taken");
}
}
}
}
Let's use a temp variable to store the value of previous input. If new input is same as previous input, the iterator i should not increase, so we use i--
System.out.print("Enter number of times: ");
int times = number.nextInt();
int i = 1;
int temp=0;
int inputArray[] = new int[times];
while ( i <= times){
System.out.print("Enter a number : ");
int input = number.nextInt();
i++;
if( input == temp){
System.out.println("It is already taken");
i--;
}else {
inputArray[i-2]=input;
}
temp=input;
}
}
The thing with that solution is that is only checks for the number just entered before the current one. I understood that you want to check that the number the user entered is unique and it has to be checked against every number that he/she has entered before.
See the code for that:
import java.util.Scanner;
import java.util.ArrayList;
public class testMe{
public static void main(String[] args){
Scanner scanner = new Scanner(System.in);
System.out.print("Enter number of times: ");
int times = scanner.nextInt();
int i = 0;
ArrayList<Integer> listWithEntries = new ArrayList<Integer>();
while (i < times){
System.out.print("Enter a number : ");
int input = scanner.nextInt();
if(listWithEntries.size() == 0){
listWithEntries.add(input);
i++;
} else {
for(int j = 0; j < listWithEntries.size(); j++){
if(input == listWithEntries.get(j)){
System.out.println("It is already taken!");
break;
}
if(j == listWithEntries.size()-1 && input !=
listWithEntries.get(j)){
listWithEntries.add(input);
i++;
break;
}
}
}
}
}
}

Letter guessing game Java

I have been working on a java guessing game for letters (a-z)! However i have created the game perfectly by using the number 1-26, but i cannot figure out how to convert each integer to a letter ie a = 1, b = 2,....z = 26!
I want the user to try and guess the letter and not the number, but i cannot workout how to do this!
(I know how to generate a random character but i cant implement and link it to each integer within the game correctly)
Random r = new Random();
char targetLetter = (char)(r.nextInt(26) + 'a');
Any help would be greatly appreciated! And i can display my code if it is needed
public class Stack {
public static void main(String[] args) {
Random rand = new Random(); //This is were the computer selects the Target
int guess;
int numGuesses = 0;
int Target;
String userName;
String playagain;
boolean play = true;
int session = 0;
int sessions = 0;
int bestScore = 0;
Scanner consoleIn = new Scanner(System.in);
Scanner name = new Scanner(System.in);
System.out.println("Hello! Please enter your name:\n"); //This is were the user enters his/her name
userName = name.nextLine();
System.out.println("Hello " + userName + " :) Welcome to the game!\n");
while (play = true) {
session++;
Target = rand.nextInt(26) + 1;
System.out.println("Guess a number between 1 and 26? You will have 5 attempts to guess the correct number"); //This is where the computer asks the user to guess the number and how many guesses they will have
do {
guess = consoleIn.nextInt();
numGuesses++;
if (guess > 26)
System.out.println("Error! Above MAXIMUM range");
else if (guess <= 0)
System.out.println("Error! Below MINIMUM range");
else if (guess > Target)
System.out.println("Sorry! Your guess was too high! :)"); //This is to help the player get to the answer
else if (guess < Target)
System.out.println("Sorry! Your guess was too low! :)"); //This is to help the player get to the answer
} while (guess != Target && numGuesses < 5);
if (guess == Target) {
System.out.println("Congratulations " + userName + ", it took you " + numGuesses + " attempts to guess correctly!"); //This tells the player that they got the correct answer and how many attempts it took
sessions++;
} else {
System.out.println("Sorry " + userName + ", You've used up all of your guesses! The correct answer was " + Target + "!"); //This tells the player that they failed to find the number and then tells them what the correct answer
}
{
Scanner answer = new Scanner(System.in);
System.out.println("Would you like another GO " + userName + "? [Y/N]");//This asks the player if they would like to play again
playagain = answer.nextLine();
if (playagain.equalsIgnoreCase("Y")) {//This is what happens if the player opts to play again
play = true;
numGuesses = 0;
} else if (playagain.equalsIgnoreCase("N")) {//This is what happens if the player opts to exit the game
play = false;
System.out.println("Thanks for playing " + userName + "! :) Please come back soon!");
System.out.println("You had " + session + " Goes");
System.out.println("The number of times you guessed correctly: " + sessions + "");
break;
}
}
}
}
}
use arrays of characters
char[] chars = ['A','B','C'...];
and use the random numbers to map to each character
char targetLetter = chars[r.nextInt(26)];
public static void main(String args[])
{
Scanner scan = new Scanner(System.in);
System.out.println("Guess the Letter");
String myLetter=scan.nextLine();
//get the letter of myLetter variable then convert to Uppercase
char enteredLetter=Character.toUpperCase(myLetter.charAt(0));
//26 only because the characters array starts with index 0
char[] characters ={'A','B','C','D','E','F','G','H','I','J','K','L','M','N','O','P','Q','R','S','T','U','V','W','X','Y','Z'};
//I had created a parrallel array symbolizing int value of each letter
int[] range={1,2,3,4,5,6,7,8,9,10,11,12,13,14,15,16,17,18,19,20,21,22,23,24,25,26};
//this variable convert user input to one of the array element of range
int userInputToInt=0;
//this variable is for knowing what int[] range array element must the value of userInputToInt fall
int userInputControlLoop=0;
char randomLetter=characters[(int)(Math.random()*26)];
// get the random input of computer convert it to int
int computerInputToInt=0;
//this loop is for getting the int value of randomLetter input by the computer
for(int i=0;i<characters.length;++i)
{
if(randomLetter==characters[i])
{
computerInputToInt=range[i];
}
}
//this loop is for getting the int value of user inputted letter
for(char i:characters)
{
if(enteredLetter==i)
{
userInputToInt=range[userInputControlLoop];
}
++userInputControlLoop;
}
//test the entered letter of user
if(enteredLetter==randomLetter)
{
System.out.println("Correct Guess");
System.out.println("The letter is:"+randomLetter);
}
//test the entered letter of user if greater than computer input
else if(userInputToInt>computerInputToInt)
{
System.out.println("Incorrect Guess");
System.out.println("The letter is too high");
System.out.println("The letter is:"+randomLetter);
}
//test the entered letter of user if lesser than computer input
else if(userInputToInt<computerInputToInt)
{
System.out.println("Incorrect Guess");
System.out.println("The letter is too low");
System.out.println("The letter is:"+randomLetter);
}
}
Use the same method that you do for your random characters. Assuming you have your guessed character as an int variable called "guess", and it has value 1-26 corresponding A-Z:
Random r = new Random();
char targetLetter = (char)(r.nextInt(26) + 'a');
...
int guess = ...
char guessChar = (char)guess + 'a';
if (guessChar == targetLetter) {
System.out.println("Correct!");
} else {
System.out.println("Guess again!")
}
You can implement it in this approach :
1- Create a String alphabet with the characters that you want.
2- declare the size of alphabet as n variable which will control the random generator range.
3- alphabet.charAt(random.nextInt(n)) is a random char from the alphabet.
program code will be :
String alphabet = "ABCDEFGHIJKLMNOPQRSTUVWXYZ";
int n = alphabet.length();
Random r = new Random();
System.out.println(alphabet.charAt(r.nextInt(n)));
hope will help solve your problem.
public class Picnic1 {
// RULE 0: This code is provided as a working example.
// This rule tests for whether a word starts with the letter 'b' (allowed to the picnic).
public static boolean rule0(char[] array) {
if (array[0] == 'b') {
return true;
}
else {
return false;
}
// itemMessage:
// Return message about whether a particular item is allowed to the picnic.
public static String item ( double[] a){
// This code works, providing output like these examples:
// "banana: true"
// "collie: false"
// It needs to be replaced with a more suitable output.
// Instead it should return, for example:
// "Yes, you can bring a banana to the picnic."
// "No, you cannot bring a collie to the picnic."
if (a[0] == 'b') {
System.out.println("Yes, you can bring a" + 'a' + "to the picnic");
}
else if (a[0] != 'b') {
System.out.print("No, you can not bring a " + 'a' + "to the picnic");
}
}
}
}

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