I have trouble splitting a name by a space, and I can't seem to figure out why. Could someone please provide me with a solution?
My code is like this:
public void getPlayerNames(int id){
try {
Document root = Jsoup.connect("http://www.altomfotball.no/element.do?cmd=team&teamId=" + id).get();
Element table = root.getElementById("sd_players_table");
Elements names = table.getElementsByTag("a");
for(Element name : names){
getPlayers().add(new Player(name.text()));
}
} catch (IOException e) {
// TODO Auto-generated catch block
e.printStackTrace();
}
}
which returns the name of football players as a string. The names are retrieved such as Mario Balotelli, Steven Gerrard, and so on, and I assumed I could use string.split(" "); to get me the first and last names, but whenever I try to access the second space of the string array it gives me an index out of bounds exception. Here is the code trying to fetch me the first name
/**
* Method to get the first name of a player
*/
public static String getFirstName(String name){
String[] nameArray = name.split(" ");
return nameArray[0];
}
Thanks for answers!
Sindre M
EDIT ######
So I got it to work, but thanks for the effort. The problem was that even though I could not see it in a simple sysout statement, the names actually contained a " "; character, so I solved it by running a replaceAll("  ;" , " ") on the names for a better formatting.
If you're trying to write a screen-scraper you need to be more defensive in your code... Definitely test the length of the array first and log any unexpected inputs so you can incorporate them later...
public static String getFirstName(String name) {
String[] nameArray = name.split(" ");
if (nameArray.length >= 1) { // <== check length before you access nameArray[0]
return nameArray[0];
} else {
// log error
}
return null;
}
Additionally java.util.Optional in Java 8 provides a great alternative to returning null...
public static Optional<String> getFirstName(String name) {
String[] nameArray = name.split(" ");
if (nameArray.length >= 1) {
return Optional.of(nameArray[0]);
} else {
// log error
}
return Optional.empty();
}
You might be getting in the actual string as you are retrieving from html page. try to debug and check.
package com.appkart.examples;
public class SplitProgram {
public void firstNameArray(String nameString) {
String strArr[] = nameString.split(",");
for (String name : strArr) {
String playerName = name.trim();
String firstName = playerName.substring(0, playerName.indexOf(" "));
System.out.println(firstName);
}
}
public static void main(String[] args) {
String nameString = "Mario Balotelli, Steven Gerrard";
SplitProgram program = new SplitProgram();
program.firstNameArray(nameString);
}
}
I think that the correct answer should be:
String[] nameArray = name.split("\\s+");
But to be honest, there are couple of answers at stackoverflow.
Eg.
How to split a String by space
How do I split a string with any whitespace chars as delimiters?
First try to replace white space as
string.replace(" ","");
then try to split with [,] as
String strAr[] = string.split(",");
Related
I have the following code which, by means of a keyboard input, gives me the start and arrival .. the start is determined according to the "da" proposition, while the arrival determines it according to the preposition "a" so I'm fighting now is: I want to get the start and the arrival even if I change the order of the propositions .. you know how I could proceed ..
this is the OUTPUT I get :
I want to go from ostuni to trapani
Partenza :ostuni
Arrivo :trapani
but if I wrote like this:
I want to go to ostuni by trapani
I would like to print the same start and finish correctly ..that is
Patenza :trapani
Arrivo :ostuni
Is this processing possible?
thanks a lot for the attention! Good day
package eubot.controller;
import eubot.intent.Intent;
public class EubotEngine {
public Intent getIntent(String stringInput) {
String str1 = "";
String str2 = "";
Intent dictionary = null;
for (String str3 : Intent.keyWord) {
if (stringInput.contains(str3)) {
//System.out.println("La stringa contiene : " + str3);
int indice1 = stringInput.indexOf(str3) + str3.length();
String splittable =
stringInput.substring(indice1,stringInput.length()).trim();
String splittable2[] = splittable.split(" ");
int index = 0;
for (String str : splittable2) {
str = splittable2[index +1];
str1 = str;
System.out.println("Partenza :" + str1);
break;
}
String splittable3[] = splittable.split(" ");
for(String str : splittable3) {
str = splittable3[index + 3];
str2 = str;
System.out.println("Arrivo :" + str2);
break;
}
index++;
dictionary = new Intent();
dictionary.setTesto(stringInput);
}
}
return dictionary;
}
}
package eustema.eubot.intent;
public class Intent {
public String testo;
public String getTesto() {
return testo;
}
public void setTesto(String testo) {
this.testo = testo;
}
public static String[] keyWord = { "devo andare", "voglio andare", "vorrei andare", "devo recarmi"};
public static String[] parameter = { "bari", "roma", "milano","pisa","firenze","napoli","como","torino" };
}
package eustema.eubot.main;
import java.util.Scanner;
import eustema.eubot.controller.*;
import eustema.eubot.intent.*;
public class Test {
public static void main(String[] args) {
System.out.println("<<-|-|-|-|-|-|-|-|-|<<<BENVENUTO IN EuBoT>>>|-|-|-|-|-|-|-|-|->>");
EubotEngine controller = new EubotEngine();
Scanner input = new Scanner(System.in);
String string;
while (true) {
string = input.nextLine();
Intent intent = controller.getIntent(string);
}
}
}
I know this will not be considered a good answer:)
This is non-trivial to solve by means of imperative programming. The reason is there are many forms in which one can express the same intent. Things like filler words, synonyms, inversions and in general things you did not think about could disrupt your algorithm.
Of course it depends on the level of accuracy you want to achieve. If you are happy that this will not work for all cases, you could always put in conditions like:
if (arr[index-1] == "from") setStart(arr[index]);
if (arr[index-1] == "to") setDestination(arr[index]);
Google, Amazon and Apple are battling to improve this sort of human-computer interaction, but they are using a more mathematical/statistical approach through machine learning.
So, if you're looking for state of the art:
Main search terms: context-free grammars.
Other key words: Markov models, Information extraction, vector space models, tf-idf
This is a snippet of my txt file "Q.txt".
12.54778255173505 : ^FinishedLine
15.416218875438748 :
^FinishedLine
16.245508427720914 : ^FinishedLine
9.595696051997852 : &^FinishedLine
11.971100145959943 : ! '^FinishedLine
11.678678199807727 : " $^FinishedLine
14.905855346233682 : # %^FinishedLine
15.98343143372184 : $ "^FinishedLine
16.053542916378102 : % #^FinishedLine
I need to sort my text file "Q.txt" which contains a double and a string.
It has been separated using " : " and at the end of each phrase there is ("^FinishedLine"). When I run this, all it is coming up with is a "NumberFormatException: empty string" error.
public class Sorting {
public static void sort() throws IOException {
Scanner s = new Scanner(new File("Q.txt"));
ArrayList<Qpair> set = new ArrayList<>();
String line = "";
while (s.hasNext()) {
String[] parts = line.split(" : ");
set.add(new Qpair(Double.parseDouble(parts[0]), parts[1]));
s.useDelimiter("^FinishedLine");
}
s.close();
System.out.println(set);
}
private static class Qpair{
private double d;
private String s;
public Qpair(double d, String s){
this.d = d;
this.s = s;
}
public double getDouble(){
return d;
}
public String getString(){
return s;
}
}
private static class QpairCompare implements Comparator<Qpair>{
public int compare(Qpair x, Qpair y){
return (int) (x.getDouble() - y.getDouble());
}
}
}
As far as I can see: You are setting line to the empty string. You enter the while loop without changing line. You split this empty string at :. I admit I had to try it out to be sure: it yields an array of 1 element, an empty string. You try to parse this empty string from the array as a double.
And you tell us you get NumberFormatException: empty string. Sounds like agreement to me.
I hope you can figure out what code line is missing and where you should insert it?
I am currently working on a Java program that crawls a webpage and prints out some information from it.
There is one part that I can't figure out, and thats when I try to print out one specific String Array with some information in it, all it gives me is " ] " for that line. However, a few lines before, I also try printing out another String array in the exact same way and it prints out fine. When I test what is actually being passed to the "categories" variable, its the correct information and can be printed out there.
public class Crawler {
private Document htmlDocument;
String [] keywords, categories;
public void printData(String urlToCrawl)
{
nextURL=urlToCrawl;
crawl();
//This does what its supposed to do. (Print Statement 1)
System.out.print("Keywords: ");
for (String i :keywords) {System.out.print(i+", ");}
//This doesnt. (Print Statement 2)
System.out.print("Categories: ");
for (String b :categories) {System.out.print(b+", ");}
}
public void crawl()
{
//Gather Data
//open up JSOUP for HTTP parsing.
Connection connection = Jsoup.connect(nextURL).userAgent(USER_AGENT);
Document htmlDocument = connection.get();
this.htmlDocument=htmlDocument;
System.out.println("Recieved Webpage "+ nextURL);
int guacCounter = 0;
for(Element guac : htmlDocument.select("script"))
{
if(guacCounter==5)
{
//String concentratedGuac = guac.toString();
String[] items = guac.toString().split("\\n");
categories = processGuac(items);
break;
}
else if(guacCounter<5) {
guacCounter++;
}
}
}
public String[] processKeywords(String totalKeywords)
{
String [] separatedKeywords = totalKeywords.split(",");
//System.out.println(separatedKeywords.toString());
return separatedKeywords;
}
public String[] processGuac(String[] inputGuac)
{
int categoryIsOnLine = 6;
String categoryData = inputGuac[categoryIsOnLine-1];
categoryData = categoryData.replace(",","");
categoryData = categoryData.replace("'","");
categoryData = categoryData.replace("|",",");
categoryData = categoryData.split(":")[1];
//this prints out the list of categories in string form.(Print Statement 3)
System.out.println("Testing here: " + categoryData.toString());
String [] categoryList=categoryData.split(",");
//This prints out the list of categories in array form correctly.(Print statement 4)
System.out.println("Testing here too: " );
for(String a : categoryList) {System.out.println(a);}
return categoryList;
}
}
I cut out a lot of the irrelevant parts of my code so there might be some missing variables.
Here is what my printouts look like:
PS1:
Keywords: What makes a good friend, making friends, signs of a good friend, supporting friends, conflict management,
PS2:
]
PS3:
Testing here: wellbeing,friends-and-family,friendships
PS4:
Testing here too:
wellbeing
friends-and-family
friendships
I have a simple textfile:
type = "hello"
number = 66
type = "hey"
number = 77
I'm basically just checking to see if the string "type" is found in the textfile, if yes, I'd also like to get the values "hello" and "hey" i.e the types. However, my program doesn't work at all in that sense it all always prints no, when checking if "type" is in the file.
public static void main(String[] args) {
if(args.length == 1)
parseText(argv[0]); // call with textfile name
}
public void parseText(String inPath) {
try {
Scanner s = new Scanner(inPath);
while(s.hasNextLine()) {
if("type".equals(s.nextLine().trim()))
System.out.println("Yes");
else {
System.out.println("no");
}
}
}catch (Exception e ) {
System.out.println("\nFILE NOT FOUND");
}
}
Any help would be much appreciated.
if("type".equals(s.nextLine().trim()))
You really want to read the line of data from the file into a String so you can do processing on the string.
You want to know if the line starts with "type":
String line = s.nextLine()
if (line.startsWith("type"))
{
String value = line.substring(8);
System.out.println(value);
}
Check if the line starts with "type" (not is equal to "type").
if("type".equals(s.nextLine().trim()))
should be something like
String line = s.nextLine().trim();
if (line.startsWith("type"))
I am new to eclipse plugin development and I am trying to convert a IMethod to a string representation of the full method name. I.E.
my.full.package.ClassName.methodName(int param, String string)
so far I have had to hand roll my own solution. Is there a better way?
private static String getMethodFullName(IMethod iMethod)
{
String packageString = "[Default Package]";
try {
IPackageDeclaration[] declarations = iMethod.getCompilationUnit().getPackageDeclarations();
if(declarations.length > 0)
{
packageString = declarations[0].getElementName();
}
} catch (JavaModelException e) {
}
String classString = iMethod.getCompilationUnit().getElementName();
classString = classString.replaceAll(".java", "");
String methodString = iMethod.getElementName() + "(";
for (String type : iMethod.getParameterTypes()) {
methodString += type + ",";
}
methodString += ")";
return packageString + "." + classString + "." + methodString;
}
You can get the Fully qualified name for the type using
method.getDeclaringType().getFullyQualifiedName();
This is probably easier than accessing the package from the compilation unit. The rest of you function looks correct.
One small point: you should use StringBuilder to build up the string instead of adding to a standard String. Strings are immutable so addition creates loads of unrecesary temparary objects.
private static String getMethodFullName(IMethod iMethod)
{
StringBuilder name = new StringBuilder();
name.append(iMethod.getDeclaringType().getFullyQualifiedName());
name.append(".");
name.append(iMethod.getElementName());
name.append("(");
String comma = "";
for (String type : iMethod.getParameterTypes()) {
name.append(comma);
comma = ", ";
name.append(type);
}
name.append(")");
return name.toString();
}
Thanks to iain and some more research I have come up with this solution. It seems like something like this should be built into the JDT....
import org.eclipse.jdt.core.Signature;
private static String getMethodFullName(IMethod iMethod)
{
StringBuilder name = new StringBuilder();
name.append(iMethod.getDeclaringType().getFullyQualifiedName());
name.append(".");
name.append(iMethod.getElementName());
name.append("(");
String comma = "";
String[] parameterTypes = iMethod.getParameterTypes();
try {
String[] parameterNames = iMethod.getParameterNames();
for (int i=0; i<iMethod.getParameterTypes().length; ++i) {
name.append(comma);
name.append(Signature.toString(parameterTypes[i]));
name.append(" ");
name.append(parameterNames[i]);
comma = ", ";
}
} catch (JavaModelException e) {
}
name.append(")");
return name.toString();
}
I am not sure it would take into account all cases (method within an internal class, an anonymous class, with generic parameters...)
When it comes to methods signatures, the classes to look into are:
org.eclipse.jdt.internal.corext.codemanipulation.AddUnimplementedMethodsOperation
org.eclipse.jdt.internal.corext.codemanipulation.StubUtility2
You need to get the jdt.core.dom.IMethodBinding, from which you can extract all what you need.
If you have a MethodInvocation, you can:
//MethodInvocation node
ITypeBinding type = node.getExpression().resolveTypeBinding();
IMethodBinding method=node.resolveMethodBinding();