I cannot format a date.
dateFormat.format() accepts a Date as argument. So I created a new Date()
It says the below Date() method is deprecated, and I get the below exception while running.
exception:
Exception in thread "main" java.lang.IllegalArgumentException at
java.util.Date.parse(Date.java:598)
public class MyDate {
public static void main(String[] args) {
Date date = new Date("2012-02-16T00:00:00.000-0500");
SimpleDateFormat dateFormat = new SimpleDateFormat(
"dd-MMM-yyyy HH:mm:ss");
String stringDate = dateFormat.format(date);
System.out.println(stringDate); // how do I test this conversion??
}
}
My database has date of the format - 2012-02-16T00:00:00.000-0500
I need to convert it to string of the format : dd-MMM-yyyy HH:mm:ss
I'm using Java6
Thanks to #Andy Brown. In addition to what Andy Brown has answered, I'm posting the complete snippet
Complete Solution:
import java.text.DateFormat;
import java.text.ParseException;
import java.text.SimpleDateFormat;
import java.util.Date;
public class SampleDate {
public static void main(String[] args) throws ParseException {
DateFormat parseFormat = new SimpleDateFormat(
"yyyy-MM-dd'T'HH:mm:ss.SSSZ");
Date date = parseFormat.parse("2012-03-16T00:00:00.000-0500");
String strDate = parseFormat.format(date);
System.out.println(strDate);
// if you get date of type 'java.sql.Date' directly from database cursor like
//rs.getDate("created_date"), just pass it directly to format()
SimpleDateFormat dateFormat = new SimpleDateFormat(
"dd-MMM-yyyy HH:mm:ss");
String stringDate = dateFormat.format(date);
System.out.println(stringDate);
}
}
/*
Output:
2012-03-16T01:00:00.000-0400
16-Mar-2012 01:00:00
*/
you can also convert java.util.Date to java.sql.Date like this,
String dateString = "03-11-2012";
SimpleDateFormat dateFormat = new SimpleDateFormat("MM-dd-yyyy");
java.util.Date date = dateFormat.parse(dateString);
java.sql.Date sqlDate = new Date(date.getTime());
// set the input param type as OracleTypes.DATE and pass the input param date as sqlDate
If you want to read in the date "2012-02-16T00:00:00.000-0500" you should probably use a SimpleDateFormat to parse it like so:
DateFormat parseFormat = new SimpleDateFormat(
"yyyy-MM-dd'T'HH:mm:ss.SSSZ");
Date date = parseFormat.parse("2012-02-16T00:00:00.000-0500");
Along with the rest of your code this writes:
16-Feb-2012 05:00:00
The parse format pattern letters are listed in the SimpleDateFormat documentation. The T is escaped with apostrophes.
This answer assumes Java 7, or you would be using the new date & time API from Java 8
Related
I have this string: 2018-09-22 10:17:24.772000
I want to convert it to Date:
SimpleDateFormat simpleDateFormat = new SimpleDateFormat("yyyy-MM-dd HH:mm:ss.SSSSSS");
String sdate = "2018-09-22 10:17:24.772000";
Date dateFrom = simpleDateFormat.parse(sdate);
but it shows: Sat Sep 22 10:17:24 GMT+03:30 2018
Here is what you should do instead, you are printing date object itself, you should print its format.
I will provide the code with old date api and new local date api :
SimpleDateFormat simpleDateFormat = new SimpleDateFormat("yyyy-MM-dd HH:mm:ss.SSSSSS");
String sdate = "2018-09-22 10:17:24.772000";
Date dateFrom = simpleDateFormat.parse(sdate);
System.out.println(dateFrom); // this is what you do
System.out.println(simpleDateFormat.format(dateFrom)); // this is what you should do
// below is from new java.time package
DateTimeFormatter formatter = DateTimeFormatter.ofPattern("yyyy-MM-dd HH:mm:ss.SSSSSS");
System.out.println(LocalDateTime.parse(sdate, formatter).format(formatter));
output is :
Sat Sep 22 10:30:16 EET 2018
2018-09-22 10:30:16.000000
2018-09-22 10:17:24.772000
Hope This will help you
public class Utils {
public static void main(String[] args) {
String mytime="2018-09-22 10:17:24.772000";
SimpleDateFormat dateFormat = new SimpleDateFormat(
"yyyy-MM-dd HH:mm:ss.SSSSSS");
Date myDate = null;
try {
myDate = dateFormat.parse(mytime);
} catch (ParseException e) {
e.printStackTrace();
}
SimpleDateFormat timeFormat = new SimpleDateFormat("yyyy-MM-dd");
String finalDate = timeFormat.format(myDate);
System.out.println(finalDate);
}
}
Looks to me like you have converted it to a Date. What is your desired result? I suspect what you are wanting to do is to create another Simple date format that shows your expected format and then use simpledateformat2.format(dateFrom)
I should also point out based on past experience that you should add a Locale to your simple date formats otherwise a device with a different language setting may not be able to execute this code
SimpleDateFormat simpleDateFormat = new SimpleDateFormat("yyyy-MM-dd HH:mm:ss.SSSSSS", Locale.US);
And how to print it as a string.
I tried this but I get the date in (YYYMMMMDDD HHSSMM) format:
System.out.println(LocalDateTime.now());
What is the easiest way to get the current date in (YYYYMMDD) format?
is that what you are looking for?
DateTimeFormatter formatter = DateTimeFormatter.ofPattern("yyyyMMdd");
System.out.println(LocalDate.now().format(formatter));
This does the trick but may not be the easiest:
import java.util.*;
import java.text.*;
class Test {
public static void main (String[] args) {
DateFormat dateFormat = new SimpleDateFormat("yyyy/MM/dd");
Date date = new Date();
System.out.println(dateFormat.format(date));
}
}
DateTimeFormatter.BASIC_ISO_DATE.format(LocalDate.now());
This is a very old question but gets me every time. There is a much simpler way now in one line:
String now = Instant.now().atZone(ZoneOffset.UTC).format(DateTimeFormatter.ISO_LOCAL_DATE);
System.out.println(now);
outputs: 2020-07-09
Just use: SimpleDateFormat
// Create an instance of SimpleDateFormat used for formatting
// the string representation of date (month/day/year)
DateFormat df = new SimpleDateFormat("MM/dd/yyyy HH:mm:ss");
// Get the date today using Calendar object.
Date today = Calendar.getInstance().getTime();
// Using DateFormat format method we can create a string
// representation of a date with the defined format.
String reportDate = df.format(today);
// Print what date is today!
System.out.println("Report Date: " + reportDate);
http://www.mkyong.com/java/how-to-convert-string-to-date-java/
I recive a date in this format
2014-12-09 02:18:38
which i need to convert it to
09-12-2014 02:18:38
I tried converting this way
import java.text.ParseException;
import java.text.SimpleDateFormat;
public class TestDate {
public static void main(String[] args) throws ParseException {
SimpleDateFormat sdf = new SimpleDateFormat("dd-mm-YYYY HH:mm:ss");
String input = "2014-12-09 02:18:38";
String strDate = sdf.format(input);
System.out.println(strDate);
}
}
But i am getting this exception during Runtime
Exception in thread "main" java.lang.IllegalArgumentException: Cannot format given Object as a Date
at java.text.DateFormat.format(DateFormat.java:301)
at java.text.Format.format(Format.java:157)
at TestDate.main(TestDate.java:15)
Could anybody please help me how to resolve this .
Try this
public static void main(String[] args) throws ParseException {
SimpleDateFormat sdfIn = new SimpleDateFormat("yyyy-MM-dd HH:mm:ss");
SimpleDateFormat sdfOut = new SimpleDateFormat("dd-MM-yyyy HH:mm:ss");
String input = "2014-12-09 02:18:38";
Date date = sdfIn.parse(input);
System.out.println(sdfOut.format(date));
}
Also, note that m is for minutes, while M is for months.
Instead of
String strDate = sdf.format(input);
use
String strDate = sdf.parse(input);
Also see this question
SimpleDateFormat sdf = new SimpleDateFormat("dd-mm-YYYY HH:mm:ss");
// String to Date:
String input = "2014-12-09 02:18:38";
Date date = sdf.parse(input);
// Date to String:
String strDate = sdf.format(date);
System.out.println(strDate);
SimpleDateFormat in can be used to format a Date object.
First you have to parse your string to a Data object using format on the SimpleDateFormat you declared.
After that you can output it using a second SimpleDataFromat to a string you want.
SimpleDateFormat sdf = new SimpleDateFormat("yyyy-MM-dd HH:mm:ss");
String input = "2014-12-09 02:18:38";
Date dt = sdf.parse(input);
SimpleDateFormat sdf2 = new SimpleDateFormat("dd-MM-yyyy HH:mm:ss");
String strDate = sdf2.format(dt);
System.out.println(strDate);
Hy guys,
I would like to know how convert date with timezone like 2013-08-22T10:47:12+02:00 to another date 2013-08-22 10:47:12.
I try to do that with SimpleDateFormat object, but I have the same exception:
java.text.ParseException: Unparseable date: "2013-08-22T10:47:12+02:00"
Can you help me? thanks
UPDATE
I show here my failing code:
String CURRENT_TIME_PATTERN ="yyyy-MM-dd'T'HH:mm:yyX";
String NEW_TIME_PATTERN ="yyyy-MM-dd HH:mm:ss";
String data="2013-08-22T10:47:12+02:00";
SimpleDateFormat sdf = new SimpleDateFormat(CURRENT_TIME_PATTERN);
SimpleDateFormat output = new SimpleDateFormat(NEW_TIME_PATTERN);
Date d = sdf.parse(data);
String formattedTime = output.format(d);
System.out.println(formattedTime);
In this manner I will have exception over invalid parameter 'X'.
If I use this pattern String CURRENT_TIME_PATTERN ="yyyy-MM-dd'T'HH:mm:ss.SSS'Z'";, I'll get unparsable date exception.
I would suggest using Joda-Time to do any date and time formatting / parsing.
With the following imports:
import org.joda.time.DateTime;
import org.joda.time.format.DateTimeFormat;
import org.joda.time.format.DateTimeFormatter;
And the following code:
String input = "2013-08-22T10:47:12+02:00";
DateTimeFormatter formatterA = DateTimeFormat.forPattern("yyyy-MM-dd'T'HH:mm:ssZ");
DateTimeFormatter formatterB = DateTimeFormat.forPattern("yyyy-MM-dd HH:mm:ss");
DateTime dateTime = formatterA.parseDateTime(input);
String output = dateTime.toString(formatterB);
You should try this if you always have T within your String :
String s = "2013-08-22T10:47:12+02:00";
SimpleDateFormat formatter = new SimpleDateFormat("yyyy-MM-dd'T'HH:mm:yyX"); // here X is for ISO 8601 time zone
Date parseDate = formatter.parse(s);
formatter.applyPattern("yyyy-MM-dd HH:mm:yy");
String formattedStr = formatter.format(parseDate);
System.out.println(formattedStr);
doc for ISO 8601 time zone
Update : removed String#replace() method and changed the formatter pattern to "yyyy-MM-dd'T'HH:mm:yyX".
Try this..
SimpleDateFormat dateFormat = new SimpleDateFormat("yyyy-MM-dd'T'HH:mm:ssXXX");
String date = "2013-08-22T10:47:12+02:00";
Date date1 = dateFormat.parse(date);
SimpleDateFormat dateFormat1 = new SimpleDateFormat("yyyy-MM-dd HH:mm:ss");
String myDate = dateFormat1.format(date1);
System.out.println("Date :: " + myDate);
Hi I am trying to convert a string 19611015 to a date formate of ("yyyy-MM-dd HH:mm:ss") before storing it into a sybase database table. I have tried the below code which gives me the error:
Unparseable date: "19611015"
DateFormat formatter = new SimpleDateFormat("yyyy-MM-dd HH:mm:ss");
System.out.println(formatter.parse("19611015"));
I have been reading some long and complex solutions to this, some suggesting to use Locale. Could someone explain maybe an alternative simple solution to convert string I have to a date format I am after above. Thank you.
The date in string is in yyyyMMdd format and want to convert it into yyyy-MM-dd HH:mm:ss so use below code :
DateFormat originalFormat = new SimpleDateFormat("yyyyMMdd");
DateFormat targetFormat = new SimpleDateFormat("yyyy-MM-dd HH:mm:ss");
Date date = originalFormat.parse("19611015");
String formattedDate = targetFormat.format(date);
System.out.println(formattedDate);
Output :
1961-10-15 00:00:00
Achilles, below code might solve your problem:
package com.test;
import java.text.DateFormat;
import java.text.SimpleDateFormat;
import java.util.Calendar;
public class LongToDate {
public static void main(String[] args) {
Calendar cal = Calendar.getInstance();
cal.setTimeInMillis(19611015 * 1000);
String dateFormatString = "yyyy-MM-dd HH:mm:ss";
DateFormat dateFormat = new SimpleDateFormat(dateFormatString);
String result = dateFormat.format(cal.getTime());
System.out.println(result);
//Output: 1969-12-10 15:46:18
}
}