I have a date time (which is a string) in the following format: 2/19/2015 5:25:35 p.m, and I wanted to turn it in the following Date Format: Thu Feb 19 5:25:35 p.m. CET 2015 I tried the following code:
String sDatePrecedenteExecution = "19/02/2015 17:30:29";
SimpleDateFormat format = new SimpleDateFormat ("ddd d mmm yyyy HH: mm: ss");
Date date = format.parse (sDatePrecedenteExecution)
but I got the following error:
java.text.ParseException: unparseable Date: "2/19/2015 5:30:29 p.m."
Has java.text.DateFormat.parse (DateFormat.java:337)
You are currently using the "output" format to read your incoming date string (2/19/2015 5:25:35 p.m), which is why you see the error.
You need to specify a second format for parsing your incoming date string, and use that format to parse instead. It should look like this:
SimpleDateFormat inFormat = new SimpleDateFormat ("dd/MM/yyyy HH:mm:ss")
Date date = inFormat.parse(sDatePrecedenteExecution)
Note that you also have a bug in your output format - m means minutes, and you want MMM, which is months. Have a look at the docs.
Your SimpleDateFormat doesn't match the format which you are entering. They should reflect the same.
Try this code
String parseDate = ""19/02/2015 17:30:29";
SimpleDateFormat dateFormat = new SimpleDateFormat("dd/MM/yyyy HH:mm:ss");
Date parsedDate = dateFormat.parse(parseDate);
You need to change your code something like...
String sDatePrecedenteExecution = "19/02/2015 17:30:29";
SimpleDateFormat format = new SimpleDateFormat ("dd/mm/yyyy HH:mm:ss");
try {
Date date = format.parse (sDatePrecedenteExecution);
System.out.println(date);
format = new SimpleDateFormat ("ddd d mmm yyyy HH: mm: ss");
String str = format.format(date);
System.out.println(str);
} catch (ParseException e) {
// TODO Auto-generated catch block
e.printStackTrace();
}
Try this pattern:
SimpleDateFormat format = new SimpleDateFormat ("dd mm yyyy HH:mm:ss");
You went wrong when you made: "ddd d mmm yyyy HH: mm: ss"
Use this pattern "dd/M/yyyy HH:mm:ss" instead & read the documentation
SimpleDateFormat format = new SimpleDateFormat ("dd/M/yyyy HH:mm:ss");
String sDatePrecedenteExecution = "19/02/2015 17:30:29";
try{date =format.parse (sDatePrecedenteExecution);
}catch(Exception ex){//deal with it here}
System.out.println(date.toString()); //Thu Feb 19 17:30:29 UTC 2015
Related
My time format is coming
SimpleDateFormat sdf = new SimpleDateFormat("yyyy-MM-dd'T'HH:mm:ss'Z'");
2108-03-27T17:18:16.985+0530
input Date I have to convert it into other time format
Mar 27,2018 5:18 pm
is expected output can any please suggest me how to convert given time to other time format in java .
SimpleDateFormat sdf = new SimpleDateFormat("MMM d,yyyy h:mm a");
System.out.println(sdf.format(date));
If you have Java 8, use the java.time API:
DateTimeFormatter parser = new DateTimeFormatterBuilder()
.append(DateTimeFormatter.ISO_LOCAL_DATE_TIME)
.appendPattern("XX")
.toFormatter();
OffsetDateTime odt = OffsetDateTime.parse("2108-03-27T17:18:16.985+0530", parser);
DateTimeFormatter fmt = DateTimeFormatter.ofPattern("MMM dd,yyyy h:mm a", Locale.ENGLISH);
String formattedDate = fmt.format(odt); // Mar 27,2108 5:18 PM
SimpleDateFormat has lots of problems, many of them solved by java.time API, and you should prefer to use those.
For older versions of Java, there's a nice backport, with the same classes and functionality.
SimpleDateFormat sdf = new SimpleDateFormat("MMM dd, yyyy hh:mm a");
System.out.println(sdf.format(new Date()));
//Mar 27, 2018 06:28 PM
for more
What are the date formats available in SimpleDateFormat class?
You can convert type any-to-any of date format.
You just need to pass String format to SimpleDateFormate.
Use this method as static and call it from anywhere by passing inputDate
Simplified Date convert method:
public static String getFormattedDate(String inputDate)
{
String outputFormattedDate = "";
try
{
SimpleDateFormat inputFormat = new SimpleDateFormat("yyyy-MM-dd'T'HH:mm:ss'Z");
Date inputFormatDate = inputFormat.parse(inputDate);
SimpleDateFormat outputFormat = new SimpleDateFormat("MMM dd,yyyy h:mm a");
outputFormattedDate = outputFormat.format(inputFormatDate);
}
catch (Exception ex)
{
outputFormattedDate = inputDate;
ex.printStackTrace();
}
return outputFormattedDate;
}
Hope it will help you.
String startDateStr = "2017-02-03"
DateFormat formatter = new SimpleDateFormat("yyyy-MM-DD",Locale.US);
Date date = (Date)formatter.parse(startDateStr);
2017-02-03 date is parsed to Tue Jan 03 00:00:00 GMT+05:45 2017
Did I
miss something?
Update
I needed a string to be converted to a date object
while maintaining the same format.
The reason for this is I want to make use of public boolean after(Date when) method
This will work ^_^
DateFormat inputFormat = new SimpleDateFormat("yyyy-MM-dd");
DateFormat outputFormat = new SimpleDateFormat("dd MMM yyyy");
String startDateStr ="2017-02-03";
Date date = null;
try {
date = inputFormat.parse(startDateStr);
String startDateStrNewFormat = outputFormat.format(date);
} catch (ParseException e) {
e.printStackTrace();
}
Little explanation of your output :
D is Day in year (1-365)
d is day in month (1-31)
Check the document
Use SimpleDateFormat type for fomatter. You are creating DateFormat object but using SimpleDateFormat.
String startDateStr = "2017-02-03"
SimpleDateFormat formatter = new SimpleDateFormat("yyyy-MM-dd",Locale.US);
Date date = (Date)formatter.parse(startDateStr);
Yes you missed something. You used DD instead of dd in your yyyy-MM-DD format string. Here is how you do it:
SimpleDateFormat sdf = new SimpleDateFormat("yyyy-MM-dd");
String formattedDate = sdf.format(new Date());
I try to parse string (russian locale) "01 августа 2014, пятница. 20:00 МСК" to java.util.Date. I try this code:
String dateString = "01 августа 2014, пятница. 20:00 МСК"
Locale rusLocale = new Locale.Builder().setLanguage("ru").setScript("Cyrl").build();
String pattern = "dd MMMM yyyy, EEEE. HH:mm z"
Date date = SimpleDateFormat(pattern, rusLocale).parse(dateString)
With month and weekday this code work fine, but when I try to parse string with timezone name МСК I get java.text.ParseException: Unparseable date. When I change MCK to MSK "01 августа 2014, пятница. 20:00 MSK" code also work fine. So we can parse strings month and weekday, but can't do it with timezone or "MCK" is just not valid?
Try this code. I think it is something relevant with your code.
String dateString = "17 октябрь 2014, пятница. 20:00";
Locale rusLocale = new Locale.Builder().setLanguage("ru").setScript("Cyrl").build();
String pattern = "dd MMMM yyyy, EEEE. HH:mm";
try {
SimpleDateFormat dateFormat = new SimpleDateFormat(pattern, rusLocale);
dateFormat.setTimeZone(TimeZone.getTimeZone("МСК"));
Date date = dateFormat.parse(dateString);
} catch (ParseException e) {
...
I'm trying to convert a String that represents a date stored in SQLITE.
The date was stored into sqlite as follows:
Date date;
date.toString();
According with Java documentation, toString() method:
Returns a string representation of this Date. The formatting is
equivalent to using a SimpleDateFormat with the format string "EEE MMM
dd HH:mm:ss zzz yyyy", which looks something like "Tue Jun 22 13:07:00
PDT 1999". The current default time zone and locale are used. If you
need control over the time zone or locale, use SimpleDateFormat
instead.
Until here, it's fine but, when I try to get the String and convert it to date again, Java throws an exception.
The String comes from sqlite:
Mon Jan 20 18:26:25 BRT 2014
So, I do:
SimpleDateFormat sdf = new SimpleDateFormat("EEE MMM dd HH:mm:ss zzz yyyy", Locale.US);
Date date= sdf.parse("Mon Jan 20 18:26:25 BRT 2014");
What I'm doing wrong?
Thanks.
try this code
String dateString = "here your date";
SimpleDateFormat dateFormat = new SimpleDateFormat("dd/MM/yyyy");
Date convertedDate = new Date();
try {
convertedDate = dateFormat.parse(dateString);
} catch (ParseException e) {
// TODO Auto-generated catch block
e.printStackTrace();
}
System.out.println(convertedDate);
Try this:
String w = "Mon Jan 20 18:26:25 BRT 2014";
SimpleDateFormat pre = new SimpleDateFormat("EEE MMM dd HH:mm:ss zzz yyyy");
SimpleDateFormat sdf = new SimpleDateFormat("dd/MM/yyyy");
try{
Date date = pre.parse(w);
System.out.println(sdf.format(date));
}catch(Exception e){
e.printStackTrace();
}
Output:
20/01/2014
Formatter for storing and restoring data value in format dd/MM/yyyy
SimpleDateFormat simpleDateFormat = new SimpleDateFormat("dd/MM/yyyy");
Storing data
String dataAsString = simpleDateFormat.format(date); // 20/01/2014
Restoring data
Date data = simpleDateFormat.parse(dataAsString);
I have my date and time stored in string i.e my string contains str ="18/01/2013 5:00:00 pm". How can I convert it to 24 format time in android?
You can use two SimpleDateFormat instances: one to parse the input as a date and a second to format the date as a string with the desired format.
For example, formattedDate in the code below will be 18/01/2013 17:00:00:
String str = "18/01/2013 5:00:00 pm";
SimpleDateFormat input = new SimpleDateFormat("dd/MM/yyyy hh:mm:ss a");
Date dt = input.parse(str);
SimpleDateFormat output = new SimpleDateFormat("dd/MM/yyyy HH:mm:ss");
String formattedDate = output.format(dt); //contains 18/01/2013 17:00:00
Notes:
hh is for Hour in am/pm (1-12) whereas HH is for Hour in day (0-23).
for more formatting options, check the javadoc
try
String str ="18/01/2013 5:00:00 pm";
Date date = new SimpleDateFormat("dd/MM/yyyy hh:mm:ss a").parse(str);
str = new SimpleDateFormat("dd/MM/yyyy HH:mm:ss").format(date);
System.out.println(str);
output
18/01/2013 17:00:00
To get AM PM and 12 hour date format use hh:mm:ss a as string formatter WHERE hh is for 12 hour format and a is for AM PM format.
Note: HH is for 24 hour and hh is for 12 hour date format
SimpleDateFormat formatter = new SimpleDateFormat("mm/dd/yyyy hh:mm:ss a");
String newFormat = formatter.format(testDate);
Example
String date = "18/01/2013 5:00:00 pm";
SimpleDateFormat sdf = new SimpleDateFormat("yyyy/mm/dd HH:MM:SS");
Date testDate = null;
try {
testDate = sdf.parse(date);
}catch(Exception ex){
ex.printStackTrace();
}
SimpleDateFormat formatter = new SimpleDateFormat("mm/dd/yyyy hh:mm:ss a");
String newFormat = formatter.format(testDate);
System.out.println(".....Date..."+newFormat);
You can use SimpleDateFormat for that:
SimpleDateFormat dateFormat = new SimpleDateFormat(dd/mm/yyyy HH:mm:ss");
Refer to this which was opposite to your requirement. Just posted the link so you might get the idea of difference that HH and hh makes.
Try using the java SimpleDateFormat class.
Example:
SimpleDateFormat df = new SimpleDateFormat("dd/MM/yyyy HH:mm:ss");
df.parse(date);
The upper case HH use a 24h format