I am using Spring Boot with Jetty.
I configure the context-path:
server.servlet.context-path=/test
When accessing http://localhost:8080/test, it doesn't work. But going to http://localhost:8080/test/ works.
Is /test and /test/ different? How can I access http://localhost:8080/test
I think you are looking for something similar to setUseTrailingSlashMatch
Docs:
Whether to match to URLs irrespective of the presence of a trailing slash. If enabled a method mapped to "/users" also matches to "/users/".
The default value is true.
Code:
public class Config extends WebMvcConfigurationSupport {
#Override
protected void configurePathMatch(PathMatchConfigurer configurer) {
configurer.setUseSuffixPatternMatch(false)
.setUseTrailingSlashMatch(false);
}
}
There seems to be weird behavior which I can't seem to pinpoint the reason for. When I access a particular url I get a 404 response while other urls that are handled by the same controller class works. I have to add a trailing / to the end of the url in order for the method to be called.
This method DOES NOT get called when accessing localhost:8080/newprofile
#RequestMapping(value="/newprofile", method=RequestMethod.GET)
public String newProfile(Model model, Principal principal) {
return "newprofile";
}
However, this one DOES get called when accessing localhost:8080/login
#GetMapping("/login")
public String login() {
return "login";
}
I have tried both GetMapping and RequestMapping but the methods are never called.
Both methods are contained in my controller class
#Controller
public class HomeResources {
//login
//new profile
}
There is a setting responsible for such behavior:
https://docs.spring.io/spring-framework/docs/current/javadoc-api/org/springframework/web/servlet/mvc/method/annotation/RequestMappingHandlerMapping.html#setUseTrailingSlashMatch-boolean-
Just turn it off:
#Configuration
#EnableWebMvc
public class WebConfig implements WebMvcConfigurer {
#Override
public void configurePathMatch(PathMatchConfigurer configurer) {
configurer.setUseTrailingSlashMatch(false);
}
}
Note that the default behaviour of setUseTrailingSlashMatch changed from true to false since 6.0 in order to support the deprecation of the property.
If you want this to be enabled you have to set it to true now. But as it is marked deprecated, probably best not to do it and instead follow the advice in this Spring Boot 3.0.0 M4 Release Notes
Developers should instead configure explicit redirects/rewrites through a proxy, a Servlet/web filter, or even declare the additional route explicitly on the controller handler (like #GetMapping("/some/greeting", "/some/greeting/") for more targeted cases.
Spring Boot 3+ TLDR
#Configuration
public class WebConfiguration implements WebMvcConfigurer {
#Override
public void configurePathMatch(PathMatchConfigurer configurer) {
configurer.setUseTrailingSlashMatch(true);
}
}
}
Be sure to use as above for Spring Boot 3+ (that uses Spring 6)
to have URL ending with '/' still being processed by mapping in Controllers without ending '/'.
Longer answer:
Note for the snippet the value is exactly true
and #EnableWebMvc is not used with Spring Boot
(as it would in fact disable autoconfiguration for web MVC)
That was exactly recommended in
https://github.com/spring-projects-experimental/spring-boot-migrator/issues/206
"Spring Boot 3.0.0 M4 Release Notes"
And because there are reasons why Spring became less forgiving,
( see "Deprecate trailing slash match and change default value from true to false"
https://github.com/spring-projects/spring-framework/issues/28552 )
I think we should better to think as bad habit to use URLs ending with '/', that now require extra attention.
I am trying to stay declarative, convention-base and XML-less.
So, I have no web.xml, and I have no context configuration XMLs. Unfortunately, Google is spammed with old-fashion Spring examples and it is impossible to find modern answer.
My question is: is it possible to declare interceptor with annotations in Spring? Apparently it would be possible to do the same way as it done with controllers (controller class is annotated with #Controller and it's methods -- with #RequestMapping).
The best way I found is here https://stackoverflow.com/a/16706896/258483
Unfortunately, it is not declarative.
Using Java configuration and the #Configuration annotation it looks like you create an interceptor and register it as described here. It's not as simple as annotating a class as an interceptor but may still adhere to your stipulations.
EDIT:
In java configuration class, we need to extend
WebMvcConfigurerAdapter. To add our interceptor, we override
WebMvcConfigurerAdapter. addInterceptors() method. Find the code
snippet.
#Override
public void addInterceptors(InterceptorRegistry registry) {
registry.addInterceptor(new LoggingInterceptor());
registry.addInterceptor(new TransactionInterceptor()).addPathPatterns("/person/save/*");
}
I'm writing a Spring MVC application deployed on Tomcat. See the following minimal, complete, and verifiable example
public class Application extends AbstractAnnotationConfigDispatcherServletInitializer {
protected Class<?>[] getRootConfigClasses() {
return new Class<?>[] { };
}
protected Class<?>[] getServletConfigClasses() {
return new Class<?>[] { SpringServletConfig.class };
}
protected String[] getServletMappings() {
return new String[] { "/*" };
}
}
Where SpringServletConfig is
#Configuration
#ComponentScan("com.example.controllers")
#EnableWebMvc
public class SpringServletConfig {
#Bean
public InternalResourceViewResolver resolver() {
InternalResourceViewResolver vr = new InternalResourceViewResolver();
vr.setPrefix("/WEB-INF/jsps/");
vr.setSuffix(".jsp");
return vr;
}
}
Finally, I have a #Controller in the package com.example.controllers
#Controller
public class ExampleController {
#RequestMapping(path = "/home", method = RequestMethod.GET)
public String example() {
return "index";
}
}
My application's context name is Example. When I send a request to
http://localhost:8080/Example/home
the application responds with an HTTP Status 404 and logs the following
WARN o.s.web.servlet.PageNotFound - No mapping found for HTTP request with URI `[/Example/WEB-INF/jsps/index.jsp]` in `DispatcherServlet` with name 'dispatcher'
I have a JSP resource at /WEB-INF/jsps/index.jsp I expected Spring MVC to use my controller to handle the request and forward to the JSP, so why is it responding with a 404?
This is meant to be a canonical post for questions about this warning message.
Your standard Spring MVC application will serve all requests through a DispatcherServlet that you've registered with your Servlet container.
The DispatcherServlet looks at its ApplicationContext and, if available, the ApplicationContext registered with a ContextLoaderListener for special beans it needs to setup its request serving logic. These beans are described in the documentation.
Arguably the most important, beans of type HandlerMapping map
incoming requests to handlers and a list of pre- and post-processors
(handler interceptors) based on some criteria the details of which
vary by HandlerMapping implementation. The most popular implementation
supports annotated controllers but other implementations exists as
well.
The javadoc of HandlerMapping further describes how implementations must behave.
The DispatcherServlet finds all beans of this type and registers them in some order (can be customized). While serving a request, the DispatcherServlet loops through these HandlerMapping objects and tests each of them with getHandler to find one that can handle the incoming request, represented as the standard HttpServletRequest. As of 4.3.x, if it doesn't find any, it logs the warning that you see
No mapping found for HTTP request with URI [/some/path] in DispatcherServlet with name SomeName
and either throws a NoHandlerFoundException or immediately commits the response with a 404 Not Found status code.
Why didn't the DispatcherServlet find a HandlerMapping that could handle my request?
The most common HandlerMapping implementation is RequestMappingHandlerMapping, which handles registering #Controller beans as handlers (really their #RequestMapping annotated methods). You can either declare a bean of this type yourself (with #Bean or <bean> or other mechanism) or you can use the built-in options. These are:
Annotate your #Configuration class with #EnableWebMvc.
Declare a <mvc:annotation-driven /> member in your XML configuration.
As the link above describes, both of these will register a RequestMappingHandlerMapping bean (and a bunch of other stuff). However, a HandlerMapping isn't very useful without a handler. RequestMappingHandlerMapping expects some #Controller beans so you need to declare those too, through #Bean methods in a Java configuration or <bean> declarations in an XML configuration or through component scanning of #Controller annotated classes in either. Make sure these beans are present.
If you're getting the warning message and a 404 and you've configured all of the above correctly, then you're sending your request to the wrong URI, one that isn't handled by a detected #RequestMapping annotated handler method.
The spring-webmvc library offers other built-in HandlerMapping implementations. For example, BeanNameUrlHandlerMapping maps
from URLs to beans with names that start with a slash ("/")
and you can always write your own. Obviously, you'll have to make sure the request you're sending matches at least one of the registered HandlerMapping object's handlers.
If you don't implicitly or explicitly register any HandlerMapping beans (or if detectAllHandlerMappings is true), the DispatcherServlet registers some defaults. These are defined in DispatcherServlet.properties in the same package as the DispatcherServlet class. They are BeanNameUrlHandlerMapping and DefaultAnnotationHandlerMapping (which is similar to RequestMappingHandlerMapping but deprecated).
Debugging
Spring MVC will log handlers registered through RequestMappingHandlerMapping. For example, a #Controller like
#Controller
public class ExampleController {
#RequestMapping(path = "/example", method = RequestMethod.GET, headers = "X-Custom")
public String example() {
return "example-view-name";
}
}
will log the following at INFO level
Mapped "{[/example],methods=[GET],headers=[X-Custom]}" onto public java.lang.String com.spring.servlet.ExampleController.example()
This describes the mapping registered. When you see the warning that no handler was found, compare the URI in the message to the mapping listed here. All the restrictions specified in the #RequestMapping must match for Spring MVC to select the handler.
Other HandlerMapping implementations log their own statements that should hint to their mappings and their corresponding handlers.
Similarly, enable Spring logging at DEBUG level to see which beans Spring registers. It should report which annotated classes it finds, which packages it scans, and which beans it initializes. If the ones you expected aren't present, then review your ApplicationContext configuration.
Other common mistakes
A DispatcherServlet is just a typical Java EE Servlet. You register it with your typical <web.xml> <servlet-class> and <servlet-mapping> declaration, or directly through ServletContext#addServlet in a WebApplicationInitializer, or with whatever mechanism Spring boot uses. As such, you must rely on the url mapping logic specified in the Servlet specification, see Chapter 12. See also
How are Servlet url mappings in web.xml used?
With that in mind, a common mistake is to register the DispatcherServlet with a url mapping of /*, returning a view name from a #RequestMapping handler method, and expecting a JSP to be rendered. For example, consider a handler method like
#RequestMapping(path = "/example", method = RequestMethod.GET)
public String example() {
return "example-view-name";
}
with an InternalResourceViewResolver
#Bean
public InternalResourceViewResolver resolver() {
InternalResourceViewResolver vr = new InternalResourceViewResolver();
vr.setPrefix("/WEB-INF/jsps/");
vr.setSuffix(".jsp");
return vr;
}
you might expect the request to be forwarded to a JSP resource at the path /WEB-INF/jsps/example-view-name.jsp. This won't happen. Instead, assuming a context name of Example, the DisaptcherServlet will report
No mapping found for HTTP request with URI [/Example/WEB-INF/jsps/example-view-name.jsp] in DispatcherServlet with name 'dispatcher'
Because the DispatcherServlet is mapped to /* and /* matches everything (except exact matches, which have higher priority), the DispatcherServlet would be chosen to handle the forward from the JstlView (returned by the InternalResourceViewResolver). In almost every case, the DispatcherServlet will not be configured to handle such a request.
Instead, in this simplistic case, you should register the DispatcherServlet to /, marking it as the default servlet. The default servlet is the last match for a request. This will allow your typical servlet container to chose an internal Servlet implementation, mapped to *.jsp, to handle the JSP resource (for example, Tomcat has JspServlet), before trying with the default servlet.
That's what you're seeing in your example.
I resolved my issue when in addition to described before:`
#Bean
public InternalResourceViewResolver resolver() {
InternalResourceViewResolver vr = new InternalResourceViewResolver();
vr.setPrefix("/WEB-INF/jsps/");
vr.setSuffix(".jsp");
return vr;
}
added tomcat-embed-jasper:
<dependency>
<groupId>org.apache.tomcat.embed</groupId>
<artifactId>tomcat-embed-jasper</artifactId>
<scope>provided</scope>
</dependency>
`
from: JSP file not rendering in Spring Boot web application
In my case, I was following the Interceptors Spring documentation for version 5.1.2 (while using Spring Boot v2.0.4.RELEASE) and the WebConfig class had the annotation #EnableWebMvc, which seemed to be conflicting with something else in my application that was preventing my static assets from being resolved correctly (i.e. no CSS or JS files were being returned to the client).
After trying a lot of different things, I tried removing the #EnableWebMvc and it worked!
Edit: Here's the reference documentation that says you should remove the #EnableWebMvc annotation
Apparently in my case at least, I'm already configuring my Spring application (although not by using web.xml or any other static file, it's definitely programmatically), so it was a conflict there.
Try to amend your code with the following change on your config file. Java config is used instead of application.properties.
Do not forget to enable configuration in configureDefaultServletHandling method.
WebMvcConfigurerAdapter class is deprecated, so we use WebMvcConfigurer interface.
#Configuration
#EnableWebMvc
#ComponentScan
public class WebConfig implements WebMvcConfigurer {
#Override
public void configureViewResolvers(ViewResolverRegistry registry) {
registry.jsp("/WEB-INF/views/", ".jsp");
}
#Override
public void configureDefaultServletHandling(DefaultServletHandlerConfigurer configurer) {
configurer.enable();
}
}
I use gradle, your should have the following dependencies in pom.xml:
dependencies {
compile group: 'org.springframework.boot', name: 'spring-boot-starter-web', version: '2.3.0.RELEASE'
compile group: 'org.apache.tomcat.embed', name: 'tomcat-embed-jasper', version: '9.0.35'
}
I came across another reason for the same error. This could also be due to the class files not generated for your controller.java file. As a result of which the the dispatcher servlet mentioned in web.xml is unable to map it to the appropriate method in the controller class.
#Controller
Class Controller{
#RequestMapping(value="/abc.html")//abc is the requesting page
public void method()
{.....}
}
In eclipse under Project->select clean ->Build Project.Do give a check if the class file has been generated for the controller file under builds in your workspace.
Clean your server. Maybe delete the server and add the project once again and Run.
Stop the Tomcat server
Right click the server and select "Clean"
Right click server again and select "Clean Tomcat Work Directory"
In my case using a tutorial for SpringBoot(2.7.3) RestController, startup failed with java.lang.ClassNotFoundException: javax.validation.ParameterNameProvider
I thought that Spring REST does not use WebMvc so I removed 'spring-boot-starter-web' and that resolved the startup problem. However, POST requests failed with the '404 Not Found' issue described here and spent several hours experimenting with
server.servlet.context-path
#RestController vs #Controller etc, and
SecurityConfig options
I finally resolved the 404 issue by
restoring dependency 'spring-boot-starter-web'
adding dependency
javax.validation
validation-api
and after undoing my 101 debug hacks it worked.
Very painful because even with root logger at DEBUG, there were no server-side logs to help.
For me, I found that my target classes were generated in a folder pattern not same as source. This is possibly in eclipse I add folders for containing my controllers and not add them as packages. So I ended up defining incorrect path in spring config.
My target class was generating classes under app and I was referring to com.happy.app
<context:annotation-config />
<context:component-scan
base-package="com.happy.app"></context:component-scan>
I added packages (not folders) for com.happy.app and moved the files from folders to packages in eclipse and it resolved the issue.
In my case, I was playing around with import of secondary java config files into a main java config file. While making secondary config files, I had changed the name of the main config class, but I had failed to update the name in web.xml. So, every time that I had restarted my tomcat server, I was not seeing mapping handlers noted in the Eclipse IDE console, and when I tried to navigate to my home page I was seeing this error:
Nov 1, 2019 11:00:01 PM org.springframework.web.servlet.PageNotFound
noHandlerFound WARNING: No mapping found for HTTP request with URI
[/webapp/home/index] in DispatcherServlet with name 'dispatcher'
The fix was to update the web.xml file so that the old name "WebConfig" would be instead "MainConfig", simply renaming it to reflect the latest name of the main java config file (where "MainConfig" is arbitrary and the words "Web" and "Main" used here are not a syntax requirement). MainConfig was important, because it was the file that did the component scan for "WebController", my spring mvc controller class that handles my web requests.
#ComponentScan(basePackageClasses={WebController.class})
web.xml had this:
<init-param>
<param-name>contextConfigLocation</param-name>
<param-value>
com.lionheart.fourthed.config.WebConfig
</param-value>
</init-param>
web.xml file now has:
<init-param>
<param-name>contextConfigLocation</param-name>
<param-value>
com.lionheart.fourthed.config.MainConfig
</param-value>
</init-param>
Now I am seeing the mapping in the console window:
INFO: Mapped "{[/home/index],methods=[GET]}" onto public
org.springframework.web.servlet.ModelAndView
com.lionheart.fourthed.controller.WebController.gotoIndex()
And my web page is loading again.
In my case, I had created Config.java (class) and also config.xml and mapping was done partially in both of them. And since config.java uses #Configuration annotation , it was considered priority. And was not considering config.xml.
If anyone gets in trouble like this , just delete config.java with annotation and try to keep config.xml , it works fine.
For me, the issue was hidden in the web.xml file.
Inside the servlet tag, you'll find:
<init-param>
<param-name>contextConfigLocation</param-name>
<param-value>/WEB-INF/todo-servlet.xml</param-value>
</init-param>
Make sure that in the <param-value> you have kept the correct location of the dispatcher servlet (aka Front Controller).
I had kept an incorrect location, hence I was able to view the homepage but all other pages were giving HTTP 404 error.
I had same problem as **No mapping found for HTTP request with URI [/some/path] in DispatcherServlet with name SomeName**
After I analyzed for 2 to 4 days I found out the root cause. Class files was not generated after I run the project. I clicked the project tab.
Project-->CloseProject-->OpenProject-->Clean-->Build project
Class files for source code have been generated. It solved my problem. To check whether class files have been generated or not, Please check the Build folder in your project folder.
So the problem can be as simple as an additional space in the path of the project. Make sure that there is no space in the path which took me quite some time to solve.
I have a MVC Java configuration but the HandlerInterceptor is not excluding some patterns.
At the line marked with xxx, if
1) I add both addPatterns("/**") and excludePathPatterns("*.ecxld") to the HandlerInterceptor's InterceptorRegistration, the HandlerInterceptor.preHanlde() is NOT invoked at all. e.g .addPathPatterns("/**").excludePathPatterns("*.ecxld")
2) I add only excludePathPatterns("*.ecxld") to the HandlerInterceptor's InterceptorRegistration, the HandlerInterceptor.preHanlde() is still executed.
(the other interceptors are invoked fine).
Any pointers appreciated.
Thanks
#Configuration
public class MyMVCConfigurerAdapter extends WebMvcConfigurerAdapter {
#Override
public void addInterceptors(final InterceptorRegistry registry) {
registry.addInterceptor(getInterceptorOne());
registry.addInterceptor(getMyHandlerInterceptor())
.excludePathPatterns("*.ecxld"); // **xxx**
registry.addInterceptor(getInterceptorTwo()
);
}
The patterns you specify for include and exclude are ant bases path expressions and not normal URL expressions as you would express in web.xml to map a servlet or filter for instance.
To make an exclude work you have to also include an include path (as you already noticed with your second remark). Next change your exclude pattern to /**/*.ecxld.
Your current expression *.ecxld would match file.ecxld but it will not match /file.ecxld or even /foo/file.ecxld. The /**/ part takes care of that. However to make it work it also requires an includePathExpression (the code checks if there is an includePathExpression when not it is ignoring the excludePathExpression).
So in short change your configuration to the following should solve your problem.
#Configuration
public class MyMVCConfigurerAdapter extends WebMvcConfigurerAdapter {
#Override
public void addInterceptors(final InterceptorRegistry registry) {
registry.addInterceptor(getInterceptorOne());
registry.addInterceptor(getMyHandlerInterceptor())
.includePathPatterns("/**")
.excludePathPatterns("/**/*.ecxld");
registry.addInterceptor(getInterceptorTwo()
);
}
I know this was a long while ago but I just stumbled over the same problem. During my search I found the following blog. There it is mentioned that if the interceptors are configured as beans they will be automatically added to the chain.
I am now using Spring 4.1.x so there might be a difference but what solved it for me was the following:
(I tried to avoid defining them as a spring beans. It didn't help.)
I configured the interceptors as spring beans (so I could autowire stuff into them see here)
I changed my definition as follows:
registry.addInterceptor(getMyHandlerInterceptor())
.addPathPatterns("/**")
.excludePathPatterns("/user/login");
By putting the addPathPatterns before the excludePathPatterns the behavior of the interceptor suddenly worked fine.
After debugging, the interceptors are not executed in the order they were added. In the above example, interceptorOne, then interceptorTwo, then the handler (with the excluded pattern) was executed.
I run into this trouble, can't exclude the path.
After I debug, found out is because Spring security redirect to "/login", because of "/login" is included in "/**", that why cannot access.
Solution is add the login & logout link as exclude paths too!
I've faced a similar problem while working with SpringBoot.
How I solved this problem?
I made a method to return a new instance of the Interceptor. And you will have to write the excludePathPatters after the addPathPattern method of the registry.
Here's the code snippet:
#Bean
public AuthInterceptor getAuthInterceptor() {
return new AuthInterceptor();
}
#Override
public void addInterceptors(InterceptorRegistry registry) {
registry.addInterceptor(**getAuthInterceptor()**)
.addPathPatterns("/**")
.excludePathPatterns("/login/**");
}
I hope this helps.