calling a function containg enum in java - java

I have defined a class
class Prop{
public static enum property{
NAME,
CITY,
ADDRESS;
}
private String NAME;
private String CITY;
private String ADDRESS;
public String getValue(property pro){
switch(pro){
case NAME:
return NAME;
case CITY:
return CITY;}
return null;}
}
class CallPro{
private String name;
name=Prop.getValue("");
}
I am not exactly getting how to call getValue from class CallPro.
Basically what parameters should be passed to get the desired value.
I am a beginner in java

To run this program you need a public static void main(String[]) method first. That's your entry point into any Java program. Since, you want to assign the values inside callPro, add the main() method there.
Next, you want to call getProperty() which is an instance method belonging to class prop, so you'll need to create an instance of it first using the new constructor() syntax.
class callPro {
private static String name;
private static String city;
private static String address;
public static void main(String[] args) {
// create prop instance
prop property = new prop();
// call prop's method getValue()
name = property.getValue(prop.property.CITY);
city = property.getValue(prop.property.NAME);
address = property.getValue(prop.property.ADDRESS);
// New York, John, Central Park
System.out.println(name + ", " + city + ", " + address);
}
}
Notice, how I had to make callPro's members static to be able to access them inside the main() method because that's static too. Also, note how I referenced the Enums: className.enumType.enumValue.
To be able to see the values print from the main() method, you'll also need to provide values for your prop class members as
private String NAME = "John";
private String CITY = "New York";
private String ADDRESS = "Central Park";
public String getValue(property pro) {
switch (pro) {
case NAME:
return NAME;
case CITY:
return CITY;
case ADDRESS:
return ADDRESS;
}
return null;
}
Yes, you can loop through an enum's values and retrieve your properties in a loop as
prop property = new prop();
for (prop.property prop : prop.property.values()) {
System.out.println(property.getValue(prop));
}
enumType.values() returns an enumType[] of all enumValues which can be used with a for-each loop as shown above.

Related

Object to string delimited format

I have set of objects of different types.
Ex : Employee emp, adress adr
These two classes have list of properties
public class Employee{
private Stringname;
private int age;
}
public class Adress {
private String HouseNo;
private string Street;
private string pin;
}
Each attribute is assigned with some 2 character value
Name (NA), age (AG), HouseNo(HN),Street(ST), pin(PN)
I need to construct a string with these data and delimit with a %
Output:
NA%Vidhya%AG%30%HN%80%ST%1st cross%PN%100100
Each class knows it own data best so I would let each class be responsible for generating the string. As I understand it the two char codes for each field are unique for each class and member and only used when generating the string so only the class would need them.
interface AttributeDescription {
String generateDescription();
}
public class Employee implements AttributeDescription {
//members...
public String generateDescription() {
return String.format(“NA%%%s%%AG%%%d”, name, age)
}
Then simply call this method for all objects implementing the interface.
AttributeDescription object = ...
String attr = object.generateDescription();
I don't think it can be generalized more than this given the requirements.
Update
It might be better to have a builder class for building the string to get a more unified behavior between classes. Here is an example
public class AttributeBuilder {
private builder = new StringBuilder();
public String getAttribute() {
return builder.toString();
}
public void add(String code, String value) {
if (value == null) {
return;
}
builder.append(code);
builder.append(‘%’);
builder.append(value);
builder.append(‘%’);
}
}
And then you would also have to implement add(...) methods for other data types in a similar fashion. The builder could then be used like
public String generateDescription() {
AttributeBuilder builder = new AttributeBuilder();
builder.add(“NA”, name);
builder.add(“AG”, age);
return builder.getAttribute();
}

Could a superclass differ to subclasses?

Lets say we have:
1) Superclass containing a string parameter: companyName
2) Subclasses containing string parameters: firstName, lastName
If we have subClassA, subClassB, subClassC, subClassD, etc. Can these subclasses have same superclass, but with different strings companyName, or the companyName meaning/value will be the same for every subclass no matter what?
Every instance of the parent class can have a different value for companyName whether it's of a subtype or not.
public class Parent {
private final String companyName;
public Parent(String name) {
this.companyName = name; // ignoring error-checking here
}
public String getCompanyName() {
return companyName;
}
}
public class Subsidiary extends Parent {
private final String subsidiaryName;
public Subsidiary(String parentName, String subsidiaryName) {
super(parentName);
this.subsidiaryName = subsidiaryName;
}
public String getSubsidiaryName() {
return subsidiaryName;
}
}
In some client code you can call:
Subsidiary subsidiary = new Subsidiary("Holdings, Inc.", "Puppet");
System.out.println(subsidiary.getCompanyName() + " owns "
+ subsidiary.getSubsidiaryName());
You see, the child-type object inherits the accessor method getCompanyName that gives it access to the information in the parent section of the object.

Wondering if I'm doing this immutability exercise correctly

My professor just went over mutable and immutable, and gave us this coding exercise to complete.
1) Create a Customer object called customer with initial values of 1 and "Cust1"
respectively.
2) Display the customer object to the screen using the toString() method.
3) Create a String object reference called name and assign to it the customer's name.
4) Assign the value "Bo Beep" to the object reference name.
5) Display the customer object to the screen using the toString() method.
The output should look like this.
Customer{id=1, name=Cust1}
Customer{id=1, name=Cust1}
I currently have 2 seperate classes, here they are. I'm not sure whether I'm doing it correctly, I think I have done the first 2 right, but I'm not sure about 3-5.
Any input is helpful, thanks!
Here's my main class,
package hw01;
public class Main {
static Customer customer = new Customer(1, "cust1");
static Customer name = new Customer(1, "Bo Peep");
public static void main(String[] args) {
System.out.println(customer);
System.out.print(customer);
}
}
And here's my Customer class.
package hw01;
public class Customer {
private int id;
private String name;
public Customer() {
}
public Customer(int id, String name) {
this.id = id;
this.name = name;
}
public int getId() {
return id;
}
public String getName() {
return name;
}
#Override
public String toString() {
return "Customer{" + "id=" + id + ", name=" + name + '}';
}
}
Sounds like for #3 it should be something like this:
String name = customer.getName();
and then #4 would be:
name = "Bo Peep";
The goal of the exercise I think is to demonstrate that even though name and customer.name reference the same String object, since a String is immutable when you set name = "Bo Peep"; you're not changing the actual String object but instead creating and referencing a new String object. If the String were mutable then printing the customer the 2nd time would display the name "Bo Peep".

Array of custom Java objects

I am trying to create an array of Person (a class that with variables String name, and double total). But for some reason, creating a second Person replaces(?) the first person. . .
Person[] p = new Person[40];
p[0] = new Person("Jango", 32);
p[1] = new Person("Grace", 455);
System.out.println( p[0].getName() );
System.out.println( p[1].getName() );
System.out.println( p[0].equals(p[1]) );
The output is:
Grace
Grace
false
Why isn't it:
Jango
Grace
false
????????????
public class Person {
#SuppressWarnings("unused")
private Person next;
private String name;
private double total;
public Person(String _name)
{
name = _name;
total = 0.0;
next = null;
}
public Person(String _name, double _total)
{
name = _name;
total = _total;
next = null;
}
public String getName()
{
return name;
}
}
Your problem is that the name instance variable is declared as static, making it a class variable. Any change to name will be changed for every instance of that class.. You need to remove the static identifier from name and from total and your code will work fine.
Currently these variables are static which means that they they will retain the last values assigned.
private static String name;
private static double total;
You need to make these fields class instance variables:
private String name;
private double total;
See Understanding Instance and Class Members
Your fields are static. They should not be, if you want them to be able to store a separate instance of a name and total for each instance of the class.

Initialize final variable before constructor in Java

Is there a solution to use a final variable in a Java constructor?
The problem is that if I initialize a final field like:
private final String name = "a name";
then I cannot use it in the constructor. Java first runs the constructor and then the fields. Is there a solution that allows me to access the final field in the constructor?
I do not really understand your question. That
public class Test3 {
private final String test = "test123";
public Test3() {
System.out.println("Test = "+test);
}
public static void main(String[] args) {
Test3 t = new Test3();
}
}
executes as follows:
$ javac Test3.java && java Test3
Test = test123
Do the initialization in the constructor, e.g.,
private final String name;
private YourObj() {
name = "a name";
}
Of course, if you actually know the value at variable declaration time, it makes more sense to make it a constant, e.g.,
private static final String NAME = "a name";
We're getting away from the question.
Yes, you can use a private final variable. For example:
public class Account {
private final String accountNumber;
private final String routingNumber;
public Account(String accountNumber, String routingNumber) {
this.accountNumber = accountNumber;
this.routingNumber = routingNumber;
}
}
What this means is that the Account class has a dependency on the two Strings, account and routing numbers. The values of these class attributes MUST be set when the Account class is constructed, and these number cannot be changed without creating a new class.
The 'final' modifier here makes the attributes immutable.
Marking it static, will allow you to use it in the constructor, but since you made it final, it can not be changed.
private static final String name = "a_name";
is is possible to use a static init block as well.
private static final String name;
static { name = "a_name"; }
If you are trying to modify the value in the constructor, then you can't assign a default value or you have to make it not final.
private String name = "a_name";
Foo( String name )
{
this.name = name;
}
or
private final String name;
Foo( String name )
{
if( s == null )
this.name = "a_name";
else
this.name = name;
}
In this case, you can mark the field as 'static' also.
Another possiblity is to initialize the field in an instance initializer blocK:
public class Foo {
final String bar;
{
System.out.println("initializing bar");
bar = "created at " + System.currentTimeMillis();
}
public Foo() {
System.out.println("in constructor. bar=" + bar);
}
public static void main(String[] args) {
new Foo();
}
}
In that case, you might as well make it static, too. And Java convention is to name such constants in ALL_CAPS.
private static final String name = getName();
where getName() is a static function that gets you the name.
I cannot use it in the constructor, while java first runs the constructor an then the fields...
This is not correct, fields are evaluated first, otherwise you couldn't access any default values of members in your constructors, since they would not be initialized. This does work:
public class A {
protected int member = 1;
public A() {
System.out.println(member);
}
}
The keyword final merely marks the member constant, it is treated as any other member otherwise.
EDIT: Are you trying to set the value in the constructor? That wouldn't work, since the member is immutable if defined as final.

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