I have the following SQL
SELECT ID,LASTTIMEEXECUTEDDATE as d FROM STATISTICSDATE ORDER BY LASTTIMEEXECUTEDDATE
which using CriteriaBuilder works just fine:
CriteriaBuilder cb = em.getCriteriaBuilder();
CriteriaQuery<StatisticsDate> cq = cb.createQuery(StatisticsDate.class);
Root<StatisticsDate> rootEntry = cq.from(StatisticsDate.class);
CriteriaQuery<StatisticsDate> all = cq.select(rootEntry).orderBy(cb.desc(
rootEntry.get("lastTimeExecutedDate")));
TypedQuery<StatisticsDate> allQuery = em.createQuery(all);
However now i need to get more accurate results using this:
SELECT ID,LASTTIMEEXECUTEDDATE as d FROM STATISTICSDATE ORDER BY
to_timestamp(LASTTIMEEXECUTEDDATE, 'DD.MM.YYYY:HH24:MI:SS') desc;
I can do this via native sql BUT i would like to know if it is possible to use it via CriteriaBuilder.
What troubles me is to_timestamp(LASTTIMEEXECUTEDDATE, 'DD.MM.YYYY:HH24:MI:SS')
Thanks
Try it like this:
CriteriaBuilder cb = entityManager.getCriteriaBuilder();
CriteriaQuery<StatisticsDate> cq = cb.createQuery(StatisticsDate.class);
Root<StatisticsDate> rootEntry = cq.from(StatisticsDate.class);
CriteriaQuery<StatisticsDate> all = cq.select(rootEntry).orderBy(cb.desc(
cb.function(
"to_timestamp", Timestamp.class,
rootEntry.get("lastTimeExecutedDate"),
cb.literal("DD.MM.YYYY:HH24:MI:SS")
)
));
TypedQuery<StatisticsDate> allQuery = em.createQuery(all);
Related
please help me out writing criteria builder for this query
SELECT *
FROM XYZ
WHERE date_v < "2020/01" AND
id NOT IN (SELECT id FROM XYZ WHERE date_v = '2020/01')
i have looked at using subqueries in jpa criteria api but i am unable to figure it
I have tried using subquery and joins but it throwing different error after all i get to know that i need to get more clarity about query criteria usages. any help much appreciated
You have to create XyzEntity with Long id and LocalDate date_v fields.
// query
CriteriaBuilder cb = entityManager.getCriteriaBuilder();
CriteriaQuery<XyzEntity> query = cb.createQuery(XyzEntity.class);
Root<XyzEntity> root = query.from(XyzEntity.class);
LocalDate date = LocalDate.of(2020, 1, 1);
// subquery
Subquery<Long> subQuery = query.subquery(Long.class);
Root<XyzEntity> subRoot = subQuery.from(XyzEntity.class);
Predicate idSubPredicate = cb.equal(root.get("id"), subRoot.get("id"));
Predicate dateSubPredicate = cb.equal(subRoot.get("date_v"), date);
subQuery.select(subRoot.get("id")).where(idSubPredicate, dateSubPredicate);
// query predicates
Predicate datePredicate = cb.greaterThan(root.get("date_v"), date);
Predicate notExistsPredicate = cb.exists(subQuery).not();
// query result
query.select(root).where(datePredicate, notExistsPredicate);
List<XyzEntity> result = entityManager.createQuery(query).getResultList();
I have mentioned the corrections in comments for the answer but I feel providing full solution seems good and helps others:
CriteriaBuilder cb = entityManager.getCriteriaBuilder();
CriteriaQuery<Entity> query = cb.createQuery(Entity.class);
Root<Entity> root = query.from(Entity.class);
// subquery
Subquery<Long> subQuery = query.subquery(Long.class);
Root<Entity> subRoot = subQuery.from(Entity.class);
Predicate subPredicate = cb.equal(subRoot.get("date_v"), dateValue);
subQuery.select(subRoot.get("id")).where(subPredicate);
// query predicates
Predicate datePredicate = cb.lessThan(root.get("date_v"), dateValue);
Predicate notExistsPredicate = root.get("id").in(subQuery).not();
// query result
query.select(root).where(datePredicate, notExistsPredicate);
Query d = entityManager.createQuery(query);
List<Entity> resultList = d.getResultList()
I've used hibernate for a long, now i started using JPA and i can't find a short way to write a simply select in less than seven lines (the use of criteria is a must in this project), is there a shorter way to build this query?
CriteriaBuilder cb = em.getCriteriaBuilder();
CriteriaQuery<Transaction> cq = cb.createQuery(Transaction.class);
Root<Transaction> root = cq.from(Transaction.class);
Collection<Predicate> predicates = new ArrayList<Predicate>();
predicates.add(cb.equal(root.get("originalOperationId"), originalOperationId));
cq.where(predicates.toArray(new Predicate[predicates.size()]));
List<Transaction> resultado = em.createQuery(cq).getResultList();
return resultado;
I'm trying to delete a bunch of objects with one query using the CriteriaBuilder API. I'm looking for something like this select:
CriteriaBuilder criteriaBuilder = entityManager.getCriteriaBuilder();
CriteriaQuery<T> query = criteriaBuilder.createQuery(entityClass);
Root<T> root = query.from(entityClass);
query.select(root).where(/*some condition*/);
return entityManager.createQuery(query).getResultList();
but then a delete instead of a select. As far as I can see, there's no remove or delete method on CriteriaQuery. Is it possible using this API?
I can of course execute the select, then call entityManager.remove(object) for each result, but that feels very inefficient.
Try this:
CriteriaBuilder criteriaBuilder = entityManager.getCriteriaBuilder();
CriteriaDelete<SomeClass> query = criteriaBuilder.createCriteriaDelete(SomeClass.class);
Root<SomeClass> root = query.from(SomeClass.class);
query.where(root.get("id").in(listWithIds));
int result = entityManager.createQuery(query).executeUpdate();
The where clause can laso look like this:
query.where(criteriaBuilder.lessThanOrEqualTo(root.get("id"), someId));
in JPA 2.1, there are Criteria APIs exactly as what you want.it looks like this:
CriteriaBuilder cBuilder = em.getCriteriaBuilder();
CriteriaDelete<T> cq = cBuilder.createCriteriaDelete(entityClass);
Root<T> root = cq.from(entityClass);
cq.where(/*some codition*/);
int result = em.createQuery(cq).executeUpdate();
you can refert to JPA 2.1 SPEC and API here
My named query looks like this, thanks to here.
#NamedQuery(
name="Cat.favourites",
query="select c
from Usercat as uc
inner join uc.cat as c
where uc.isFavourtie = true
and uc.user = :user")
And the call to implement looks like this :
Session session = sessionFactory.getCurrentSession();
Query query = session.getNamedQuery("Cat.favourites");
query.setEntity("user", myCurrentUser);
return query.list();
What would be the equivalent criteria query that returns a list of cats ?
With JPA 2.0 Criteria:
(This is one of the many ways you can achieve this using JPA 2.0 Criteria api)
final CriteriaQuery<Cat> cq = getCriteriaBuilder().createQuery(Cat.class);
final CriteriaBuilder cb = entityManager.getCriteriaBuilder();
final Root<Usercat> uc= cq.from(Usercat.class);
cq.select(uc.get("cat");
Predicate p = cb.equal(uc.get("favourtie", true);
p = cb.and(p, cb.equal(uc.get("user"), user));
cq.where(p);
final TypedQuery<Cat> typedQuery = entityManager.createQuery(cq);
return typedQuery.getResultList();
How can I formulate the following JPA2 criteria query without using the metamodel classes:
CriteriaBuilder cb = em.getCriteriaBuilder();
CriteriaQuery<Employee> cq = cb.createQuery(Employee.class);
Root<Employee> emp = cq.from(Employee.class);
cq.where(cb.isEmpty(emp.get(Employee_.projects)));
cq.select(emp);
I would like to use:
cq.where(cb.isEmpty(emp.get("projects")));
But I cant figure out how to convert the Path to an Expression, which is needed by cb.isEmpty...
Thanks.
Try this:
CriteriaBuilder cb = em.getCriteriaBuilder();
CriteriaQuery cq = cb.createQuery(Employee.class);
Root emp = cq.from(Employee.class);
cq.where(cb.isEmpty(emp.<List<Project>>get("projects")));
cq.select(emp);
Or, using a Path variable:
CriteriaBuilder cb = em.getCriteriaBuilder();
CriteriaQuery cq = cb.createQuery(Employee.class);
Root emp = cq.from(Employee.class);
Path<List<Project>> projects = emp.get("projects"));
cq.where(cb.isEmpty(projects);
cq.select(emp);
Reference
javax.persistence.criteria API
<Y> Path<Y> Path.get(String):