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Zipping multiple folders and files in one output using java

So iam working on a project where i get to a point when i need to zip multiple folders (4folders to be specific) and one file in one output.zip file using java
So is there anyway for me to do it and by the way putting all the folders and file in one directory and then zipping it doesn't give the same result in other words the folders have to be in root level of the zip file

There are several solutions.
This one for example:
public static void zipDirectory(ZipOutputStream zos, File fileToZip, String parentDirectoryName) throws Exception
{
if (fileToZip == null || !fileToZip.exists())
{
return;
}
String zipEntryName = fileToZip.getName();
if (parentDirectoryName!=null && !parentDirectoryName.isEmpty())
{
zipEntryName = parentDirectoryName + "/" + fileToZip.getName();
}
// If we are dealing with a directory:
if (fileToZip.isDirectory())
{
System.out.println("+" + zipEntryName);
if(parentDirectoryName == null) // if parentDirectory is null, that means it's the first iteration of the recursion, so we do not include the first container folder
{
zipEntryName = "";
}
for (File file : fileToZip.listFiles()) // we iterate over all the folders/files and archive them by keeping the structure too.
{
zipDirectory(zos, file, zipEntryName);
}
} else // If we are dealing with a file, then we zip it directly
{
System.out.println(" " + zipEntryName);
byte[] buffer = new byte[1024];
FileInputStream fis = new FileInputStream(fileToZip);
zos.putNextEntry(new ZipEntry(zipEntryName));
int length;
while ((length = fis.read(buffer)) > 0)
{
zos.write(buffer, 0, length);
}
zos.closeEntry();
fis.close();
}
}
then you could use this function like this:
try
{
File directoryToBeZipped = new File("C:\\New\\test");
FileOutputStream fos = new FileOutputStream("C:\\New\\test\\archive.zip");
ZipOutputStream zos = new ZipOutputStream(fos);
zipDirectory(zos, directoryToBeZipped, null);
zos.flush();
fos.flush();
zos.close();
fos.close();
} catch (Exception e)
{
e.printStackTrace();
}
Or you could use the ZeroTurnAround ZIP Library. And do this in one line:
ZipUtil.pack(new File("D:\\sourceFolder\\"), new File("D:\\generatedZipFile.zip"));

Dead easy way (though you'll get warnings about proprietary classes)
final String[] ARGS = { "-cfM", "x.zip", "folder1", "folder2", "folder3", "folder4", "file.txt" };
sun.tools.jar.Main.main(ARGS);
It might be worth getting a similar thing that won't give you warnings

getting error while unzipping

My UnZip class does not unzip whole the file. This class is called from another activity. My zip file is saved in the main directory of the phone's internal storage. The zip file has folders and some video.
What's wrong with this unzip?
What and how should I read file from zip' decompress and unzip is the same meaning?
Thanks for your help!
public class Unzip {
private static final String INPUT_ZIP_FILE = "sdcard/downloaded_issue.zip";
private static final String OUTPUT_FOLDER = "sdcard/Atlantis/";
public static void main()
{
Unzip unZip = new Unzip();
unZip.unZipIt(INPUT_ZIP_FILE, OUTPUT_FOLDER);
}
/**
* Unzip it
* #param zipFile input zip file
* #param outputFolder zip file output folder
*/
public void unZipIt(String zipFile, String outputFolder){
byte[] buffer = new byte[1024];
try{
//create output directory is not exists
File folder = new File(OUTPUT_FOLDER);
if(!folder.exists()){
folder.mkdir();
}
//get the zip file content
ZipInputStream zis =
new ZipInputStream(new FileInputStream(zipFile));
//get the zipped file list entry
ZipEntry ze = zis.getNextEntry();
while(ze!=null){
String fileName = ze.getName();
File newFile = new File(outputFolder + File.separator + fileName);
System.out.println("file unzip : "+ newFile.getAbsoluteFile());
//create all non exists folders
//else you will hit FileNotFoundException for compressed folder
new File(newFile.getParent()).mkdirs();
FileOutputStream fos = new FileOutputStream(newFile);
int len;
while ((len = zis.read(buffer)) > 0) {
fos.write(buffer, 0, len);
}
fos.close();
if (ze.isDirectory()) {
ze = zis.getNextEntry();
}
}
zis.closeEntry();
zis.close();
System.out.println("Done");
}catch(IOException ex){
ex.printStackTrace();
}
}
}

I think your 'while' loop is broken; you're only fetching the next entry if that next entry is a directory, while I assume you're probably trying to skip the directories.
Anyway, since you create the folders for all files you encounter, you can just skip the folder entries and write the file entries. The only exception would be the creation of empty folders.
Replacing the while-loop by this code should work:
while(ze!=null){
String fileName = ze.getName();
File newFile = new File(outputFolder + File.separator + fileName);
System.out.println("file unzip : "+ newFile.getAbsoluteFile());
//create all non exists folders
//else you will hit FileNotFoundException for compressed folder
if (ze.isDirectory()) {
// create the folder
newFile.mkdirs();
}
else {
// create the parent folder and write to disk
new File(newFile.getParent()).mkdirs();
FileOutputStream fos = new FileOutputStream(newFile);
int len;
while ((len = zis.read(buffer)) > 0) {
fos.write(buffer, 0, len);
}
fos.close();
}
// get the next item
ze = zis.getNextEntry();
}

Java Unzip - no Exception but result is empty

i'm using the following code from the web
File dir = new File(dest.getAbsolutePath(), archiveName);
// create output directory if it doesn't exist
if (!dir.exists()) {
dir.mkdirs();
}
System.err.println(pArchivePath);
ZipFile zipFile = null;
try {
zipFile = new ZipFile(pArchivePath);
Enumeration<?> enu = zipFile.entries();
while (enu.hasMoreElements()) {
ZipEntry zipEntry = (ZipEntry) enu.nextElement();
String name = zipEntry.getName();
long size = zipEntry.getSize();
long compressedSize = zipEntry.getCompressedSize();
System.out.printf("name: %-20s | size: %6d | compressed size: %6d\n",
name, size, compressedSize);
File file = new File(name);
if (name.endsWith("/")) {
System.err.println("make dir " + name);
file.mkdirs();
continue;
}
File parent = file.getParentFile();
if (parent != null) {
parent.mkdirs();
}
InputStream is = zipFile.getInputStream(zipEntry);
FileOutputStream fos = new FileOutputStream(file);
byte[] bytes = new byte[1024];
int length;
while ((length = is.read(bytes)) >= 0) {
fos.write(bytes, 0, length);
}
is.close();
fos.close();
}
zipFile.close();
} catch (Exception e) {
e.printStackTrace();
} finally {
if (zipFile != null) {
try {
zipFile.close();
}
catch (IOException e) {
// TODO Auto-generated catch block
e.printStackTrace();
}
}
}
to unzip an archive. It's packed with 7zip or Winrar as an .zip archive but renamed to .qtz (but i don't thing this causes the problem..)
So if i run the code to unzip my archive everything works fine: i get the output on sysout/err listing all files and also no exception occurs, but if i look in the destination directory ... it's empty - just the root folder exists.
I also used
Runtime.getRuntime().exec(String.format("unzip %s -d %s", pArchivePath, dest.getPath()));
but I can't use this anymore 'cause a new process is started and I'm continuing working on the archive right after the unzip process in the java code.
Well the question is.. why doesn't this peace of code work? There a lot of similar examples but none of them worked for me.
br, Philipp
EDIT: The following solved my Problem
File file = new File(dir.getParent(), name);
So i didn't set the right parent path for this file.

The below fragment in your code:
File parent = file.getParentFile();
if (parent != null) {
parent.mkdirs();
}
where does this create the parent directories? Because I tried your code and it's not creating in the destination directory but rather in my Eclipse's project directory. Looking at your code, the destination directory is nowhere used, right?
The code actually extracts the contents of the zip file but not where I expected it.

I am thinking because I don't see you doing something like this:
ZipOutputStream out = new ZipOutputStream(new FileOutputStream(zipPath+ "Zip.zip"));
out.putNextEntry(new ZipEntry("Results.csv"));
I am still working on it but I think that the problem because that makes the file inside of the zip
Also you should probably use the ZipOutputStream to write; like
out.write(bytes, 0, length);

I keep getting java.io.FileNotFoundException with my zip extractor

Could anybody help me with my java zip extractor as stated in the title I keep getting java.io.FileNotFoundException on the folders with files in them
public void UnZip() {
try {
byte[] data = new byte[1000];
int byteRead;
BufferedOutputStream bout = null;
ZipInputStream zin = new ZipInputStream(new BufferedInputStream(new FileInputStream(sourceFile)));
ZipEntry entry;
while ((entry = zin.getNextEntry()) != null) {
String filename = entry.getName();
File newfile = new File(Deobf2 + File.separator + filename);
System.out.println("file unzip : " + newfile.getAbsoluteFile());
new File(newfile.getParent()).mkdirs();
FileOutputStream fos = new FileOutputStream(newfile);
int len;
while ((len = zin.read(data)) > 0) {
fos.write(data, 0, len);
}
fos.close();
entry = zin.getNextEntry();
}
zin.closeEntry();
zin.close();
System.out.println("Done");
} catch (Exception e) {
e.printStackTrace();
}
}
error log
http://pastebin.com/crMKaa37
values
static String tempDir = System.getProperty("java.io.tmpdir");
public static File Deobf = new File(tempDir + "Deobf");
public static String Deobf2 = Deobf.toString();
entire code paste
http://pastebin.com/1vTfABR1

I have copy pasted same code and it is working fine. I think u dont have administrator permission on C drive. login As Administrator and run . it will work.
Access Denied Exception will come when u don have administrator level of permission on C drive.

The problem is Your doing
String Deobf2 = Deobf.toString();//this does not give the location of the file
use
file.getAbsolutePath();
in your case Deobf.getAbsolutePath();
instead. Check http://www.mkyong.com/java/how-to-get-the-filepath-of-a-file-in-java/
if you want to get the path only till the parent directory check this How to get absolute path of directory of a file?

Problem fixed changed some code
for anyone whos wants a copy of the working zip extraction code here you go http://pastebin.com/bXL8pUSg
The variable Deobf2 in the output of the zip

Java util zip creates "corrupt" zip files

I'm zipping up the contents of a directory, but running into an error when trying to open the zipped up files.
Can anyone tell what's going on with my code? Perhaps I'm not allocating enough bytes?
Look inside zipDirectory() and you will see that I'm zipping up folders which contain special extension files.
Not sure where the error's occurring, so maybe someone can help me out there!
Much appreciated
private void zipDirectory() {
File lazyDirectory = new File(defaultSaveLocation);
File[] files = lazyDirectory.listFiles();
for (File file : files) {
if (file.isDirectory()) {
System.out.println("Zipping up " + file);
zipContents(file);
}
}
}
public static void addToZip(String fileName, ZipOutputStream zos) throws FileNotFoundException, IOException {
System.out.println("Writing '" + fileName + "' to zip file");
File file = new File(fileName);
FileInputStream fis = new FileInputStream(file);
ZipEntry zipEntry = new ZipEntry(fileName);
zos.putNextEntry(zipEntry);
byte[] bytes = new byte[1024];
int length;
while ((length = fis.read(bytes)) >= 0) {
zos.write(bytes, 0, length);
}
zos.closeEntry();
fis.close();
}
public static void zipContents(File dirToZip) {
List<File> fileList = new ArrayList<File>();
File[] filesToZip = dirToZip.listFiles();
for (File zipThis : filesToZip) {
String ext = "";
int i = zipThis.toString().lastIndexOf('.');
if (i > 0) {
ext = zipThis.toString().substring(i+1);
}
if(ext.matches("cpp|bem|gz|h|hpp|pl|pln|ppcout|vec|xml|csv")){
fileList.add(zipThis);
}
}
try {
FileOutputStream fos = new FileOutputStream(dirToZip.getName() + ".zip");
ZipOutputStream zos = new ZipOutputStream(fos);
for (File file : fileList) {
addToZip(file.toString(), zos);
}
} catch (FileNotFoundException e) {
// TODO Auto-generated catch block
e.printStackTrace();
} catch (IOException e) {
e.printStackTrace();
}

Like most issues with IO streams in Java, your fault is almost certainly that you are not closing the streams properly. You need to add:
zos.finish(); // good practice
zos.close();
after the for loop.

For me the fix is that you need to do this for EVERY file entry
zos.finish()
zos.flush()
zos.closeEntry()
Then do the above things again to close the zos. Otherwise, the default windows can't open the zipped folder properly, but third-party application works.

This may also happen if you use a character-oriented writer (e.g. FileWriter) to create the unzipped files (that actually contain binary data)
I was unable to read files that I was extracting and switching to a binary output stream (FileOutputStream) fixed the issue