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How would I use Jackson to flatten JSON with nested array?

I am using JackSon to parse the following JSON:
{
"AwardID": "1111111",
"AwardTitle": "Test Title",
"Effort":
"[
{
"PersonFirstName": "Jon",
"PersonLastName": "Snow"
}
]"
}
I would like to flatten this to be used in the following class:
public class Award {
private String awardId;
private String awardTitle;
private String personFirstName;
private String personLastName;
}
I have tried the following and have gotten the first two values, but I haven't been able to get the values from Effort trying to use JsonUnwrapped. I noted that it doesn't work with arrays, but I am trying the objectMapper.configure(DeserializationFeature.UNWRAP_SINGLE_VALUE_ARRAYS, true) configuration in the main method used to get the values.
public class Award {
#JsonProperty("AwardID")
private String awardId;
#JsonProperty("AwardTitle")
private String awardTitle;
#JsonUnwrapped
private Effort effort;
}
public class Effort {
private String personFirstName;
private String personLastName;
}
Note that I only expect one value in the Effort array from the API response at this time.
What is recommended to try next? Thank you!

The easiest way is having a List<Effort> if you have a JSON Array.
If there is always 1 item for Effort, the returning JSON should not have Effort as a JSON Array and instead should be a JSON Object.
But if you can only handle it codewise, you can have something like this (Note that there should always contain one item in Effort, otherwise it will throw Exception):
public class Award {
#JsonProperty("AwardID")
private String awardId;
#JsonProperty("AwardTitle")
private String awardTitle;
#JsonProperty("Effort")
private Effort effort;
}
public class Effort {
#JsonProperty("PersonFirstName")
private String personFirstName;
#JsonProperty("PersonLastName")
private String personLastName;
}
And your ObjectMapper needs to be enabled with DeserializationFeature.UNWRAP_SINGLE_VALUE_ARRAYS as well:
ObjectMapper mapper = new ObjectMapper();
mapper.enable(DeserializationFeature.UNWRAP_SINGLE_VALUE_ARRAYS);
Award award = mapper.readValue(rawJson, Award.class); // rawJson is your JSON String
And it should have the following output:
Award(awardId=1111111, awardTitle=Test Title, effort=Effort(personFirstName=Jon, personLastName=Snow))
Note that the annotation #JsonUnwrapped can only apply on JSON Object, not JSON Array:
Value is serialized as JSON Object (can not unwrap JSON arrays using this mechanism)

How to serialize an object and read it into JsonNode?

I have a simple Java object that has a String property that contains serialized java objects:
#Data
private class Test {
int id;
String data;
}
The data is created with
test.setData(mapper.writeValueAsString(anyJavaObjectThatShouldBeSerialized));
Then I send the Test Object to another server, where I want to deserialize the object from the data property into a JSONNode:
JsonNode node = mapper.readTree(test.getData());
The problem is, that the result of readTree is a TextNode and not a JsonNode. Therefore I can not access the properties of the serialized data.
The problem might be that the serialized object is interpreted as a String because when I print it it has quotationsmarks around it:
"{\"id\":39,\"name\":\"Im a test value\"}"
How do I get a JsonNode from the String that contains serialized objects? Please note that the data can be ANY Java object, that's why I serialized it into a String.

Make a double deserialization - first deserialize the string payload to json, then deserialize the json to class, or JsonNode in your case.
public class Temp {
public static void main(String[] args) throws Exception {
String payload = //your string payload;
ObjectMapper mapper = new ObjectMapper();
String json = mapper.readValue(payload, String.class);
JsonNode node = mapper.readTree(json);
}
}
As you noted, the cause is that you are making double serialization - first when setting the data field, then again when sending data to the other server.
You can avoid this double serialization/deserialization by making data an object.
#Data
class Test {
int id;
Object data;
}
test.setData(anyJavaObjectThatShouldBeSerialized);
Like this it will be serialized like JsonObject.
{
"id": 39,
"name": "Im a test value"
}

How to convert complex dynamic json to pojo class

I have below json
[{
"Maindata": "{\"SubData\":[{\"Name\":\"a\",\"rollnumber\":1,\"ParentName\":c},{\"Name\":\"b\",\"rollnumber\":2,\"ParentName\":d},{\"Name\":\"m\",\"rollnumber\":3,\"ParentName\":n}],\"schooltime\":123213,\"lunchtime\":2321,\"TeacherName\":\"abc\",\"ClassTeacherName\":\"abc\",\"Subjects\":null,\"ClassName\":\"xyz\",\"PrincipleName\":[\"sdffd\"],\"ClassID\":\"21312\",\"books\":\"\",\"classdata\":{\"scienceclass\":\"2hrs\",\"Projects\":\"True\",\"Games\":\"Nothing\"},\"real\":null,\"classuniqueid\":\"21323234234\",\"schoolbelltime\":21323321}"
}]
In above Json we have
MainData - Main data has two main sections
SubData
ClassData
When i tried to view the above Json viewer it displays MainData as main Json and doesnot display sub data json
Now i want to convert above json to Pojo class, in a way say if i give Name of Subdata as "a" it should give me all details of "a". Now Subdata is dynamic, it has three sections now, it can have 100 when new students data are available or it can have only two. How to write a pojo class which reads this and gives data.
I am using gson and Below is my pojo class
public class MyPojo
{
private String Maindata;
public String getMaindata ()
{
return Maindata;
}
public void setMaindata (String Maindata)
{
this.Maindata = Maindata;
}
#Override
public String toString()
{
return "ClassPojo [Maindata = "+Maindata+"]";
}
}

You can use Jackson to convert JSON data to POJOs and POJOs to JSON data.
For complex JSON data like yours, you will need to create ArrayLists of complex types in your corresponding classes.

Paste your valid JSON into this site and select
Target language: Java
Annotation Style: GSON
and download the Zip file, extract it after that you get all POJO classes of your JSON response

Deserialize an array of objects with Gson

I know how to deserialize normal JSON object with "Gson" library but I am facing problem to deserialize an JSON array with several JSON object and arrays. I am trying to get the time in the arrival_time JSON object in this simple below but I don't know how to structure my class to accomplish that. Can someone explain me how to do that?
Simple:
[{"route": 1,
"info": [
{"direction": "Surrey Quays"},
{"stops": [{"stops_name": " Tenison Way"},
{"arrival_time":{
"mon-fri": [ "05:38", "06:07","06:37"],
"sat": ["05:34","06:01","06:31"],
"son": ["06:02","06:34","07:04"]
}
}
]
}
]
}]

You can parse this Json using following structure:
class ArrivalTime {
public List<String> mon_fri;
public List<String> sat;
public List<String> son;
}
class Stop {
public String stop_name;
public ArrivalTime arrival_time;
}
class Info {
public String direction;
public List<Stop> stops;
}
class RouteInfo {
public Integer route;
public List<Info> info;
}
and then use it like this:
Gson gson = new Gson();
RouteInfo[] routes = gson.fromJson(/* your json string*/, RouteInfo[].class);
Arrival times will be available at something like this (it is ugly but I just want you to present the sample structure for this json string):
System.out.println(routes[0].info.get(1).stops.get(1).arrival_time.sat.get(0));

To learn the structure you could use a javascript object or a online builder.
http://www.jsonschema2pojo.org/

"Dotting" in JSON using Gson on Android

I'm trying to parse a JSON feed using Gson in Android. I know the JSON is valid. I suspect that it is because the format is like this:
"Info":[
{
"Id":"",
"Name":"",
"Description":"",
"Date":""
}
In order to parse this I need to "dot" in. Ex: Info.Name
How can I do this in a serialized DTO?
#SerializedName("Name")
public String name;
#SerializedName("Description")
public String desc;
#SerializedName("Date")
public String date;
I tried to put "Info." in front of each serializedName but that didn't work either. I also know my JSON parsing method works properly, because it's used somewhere else with a different DTO. But in that parsing, I don't have to "dotting" issue.
Can anyone help?
EDIT: I have tried everything you guys posted, and nothing works. The error says:
The JsonDeserializer failed to deserialize json object {"Info":[{".......
SECOND EDIT:
I was able to get rid of the error, but now it returns null. Haha, getting pretty damn frustrated right about now!

I am assuming that the actual JSON you are intaking is valid because the example you provided is not. In your JSON example, you have "Info":[ but there is no outer object containing the "Info" property, which is a must. The valid JSON would be:
{
"Info": [
{
"Id":"",
"Name":"",
"Description":"",
"Date":"",
}
]
}
This is a JSON object that has a property "Info" which has a value that is a list of objects. This list of objects contains one object that has the properties "Id", "Name", "Description", and "Date", all of which have empty-string values.
Here is a quick tutorial on how to use GSON to parse a JSON feed such as the above JSON:
You will need a class to represent the items in the list:
public class InfoItem {
public String Id;
public String Name;
public String Description;
public String Date;
public InfoItem() {}
}
And one to represent the list of Items:
public class InfoItemList extends LinkedList<InfoItem> {
public InfoItemList() { super() };
}
This added complexity is because GSON cannot otherwise get the type of a generic collection from the class data.
And one to represent the overall JSON message:
public class InfoMessage {
public InfoItemList Info;
public InfoMessage() {};
}
And then just:
gson.fromJson(jsonString, InfoMessage.getClass());
If just de-serializing a collection:
Type listType = new TypeToken<List<InfoItem>>() {}.getType();
gson.fromJson(jsonString2, listType);

The Info object is a list because of the []. You have to use the following code to deserialze it:
EDIT:
public class Info {
// as in your question
public String name;
...
}
public class Data {
#SerializedName("Info")
public List<Info> info;
}
Then just use the data class to deserialize your json.