Exception calling an URL from a servlet - java

I'm trying to call an URL (URL contains only json code) from a servlet but I keep getting a read time out exceptions on getInputStream().
public class SimpleServlet extends HttpServlet {
public void doGet(HttpServletRequest request, HttpServletResponse esponse) throws IOException, ServletException {
BufferedReader reader = null;
StringBuilder stringBuilder;
InputStream in=null;
String json=null;
URL url = new URL("http://localhost:8080/SimpleWeb/users");
try{
HttpURLConnection conn = (HttpURLConnection) url.openConnection();
conn.setDoInput(true);
conn.setRequestMethod("GET");
conn.setRequestProperty("Content-type", "application/json");
conn.setReadTimeout(5000);
conn.connect();
reader = new BufferedReader(new InputStreamReader(conn.getInputStream(),"UTF-8"));
stringBuilder = new StringBuilder();
String line=null;
while((line = reader.readLine()) != null){
stringBuilder.append(line + "\n");
}
json = stringBuilder.toString();
System.out.println(json);
}catch(Exception e){
System.out.println(e);
}finally{
if(reader!=null)
reader.close();
}
}
}
The code works by replacing http://localhost:8080/SimpleWeb/users with http://localhost:8080/SimpleWeb/users.txt(but only when called from a plain java app, not a servlet)
Can anyone help to see what I might be doing wrong?

Related

Json Result from News API is null

#Override
protected String doInBackground(String... strings) {
String result = HttpRequest.getExecute("http://newsapi.org/v2/everything?q=bitcoin&from=2020-05-30&sortBy=publishedAt&apiKey=myAPIkey");
return result;
}
I am getting a null response on passing this URL even though the same URL when opened on the browser shows a lot of stuff. I am getting a Null Pointer Exception. Please help. Below is my HttpRequest class.
HTTPRequest Class:
public class HttpRequest {
public static String getExecute(String targetUrl)
{
URL url;
HttpURLConnection httpURLConnection = null;
try
{
url = new URL(targetUrl);
httpURLConnection = (HttpURLConnection) url.openConnection();
httpURLConnection.setRequestMethod("GET");
InputStream inputStream;
if (httpURLConnection.getResponseCode() != HttpURLConnection.HTTP_OK)
inputStream = httpURLConnection.getErrorStream();
else
inputStream = httpURLConnection.getInputStream();
BufferedReader bufferedReader = new BufferedReader(new InputStreamReader(inputStream));
String line;
StringBuffer response = new StringBuffer();
while ( (line = bufferedReader.readLine()) != null)
{
response.append(line);
response.append('\r');
}
bufferedReader.close();
return response.toString();
}
catch (Exception e)
{
e.printStackTrace();
return null;
}
finally {
if(httpURLConnection != null)
{
httpURLConnection = null;
}
}
}
}
You have to call connect method before reading the result or response code. Add the below line after setting up the request method
httpURLConnection.connect()

Requesting POST in Java using HttpUrlConnection is returning "propertyValue: false"

What i want?
I'm developing a Java application using the HttpUrlConnection library to send a POST and return the response from the site.
What is going on?
The code does not display syntax errors but when I execute it, it prints the message "propertyValue: false" even though I have not put any command to print anything.
What i need?
I need to know where this error is (propertyValue: false), because as I said, it does not show as if it had an error.
source:
import java.util.*;
import java.io.*;
import java.net.*;
public class Main
{
public static void main(String[] args) throws IOException
{
String target = "http://google.com";
String parameters = "contentOfPost";
URL url = new URL(target);
HttpURLConnection conn = (HttpURLConnection)url.openConnection();
try{
conn.setRequestMethod("POST");
conn.setRequestProperty("Content-Type","application/x-www-form-urlencoded");
conn.setRequestProperty("Content-Length", parameters + Integer.toString(parameters.getBytes().length));
conn.setRequestProperty("Content-Language", "pt-BR");
conn.setRequestProperty("Referer", "https://www.google.com");
conn.setUseCaches(false);
conn.setDoInput(true);
conn.setDoOutput(true);
DataOutputStream wr = new DataOutputStream(conn.getOutputStream());
wr.writeBytes(parameters);
wr.flush();
wr.close();
InputStream in = conn.getInputStream();
BufferedReader rd = new BufferedReader(new InputStreamReader(in));
String line=null;
StringBuffer response = new StringBuffer();
while((line = rd.readLine()) != null) {
response.append(line);
response.append('\r');
}
rd.close();
} catch (IOException e){}
}
}
Out: propertyValue:false

How do i send http request in java?

I added this method to my MainActivity.java
But i'm getting error on the static: Inner classes cannot have static declatarions.
protected static String excutePost(String targetURL, String urlParameters) {
HttpURLConnection connection = null;
try {
//Create connection
URL url = new URL(targetURL);
connection = (HttpURLConnection)url.openConnection();
connection.setRequestMethod("POST");
connection.setRequestProperty("Content-Type",
"application/x-www-form-urlencoded");
connection.setRequestProperty("Content-Length",
Integer.toString(urlParameters.getBytes().length));
connection.setRequestProperty("Content-Language", "en-US");
connection.setUseCaches(false);
connection.setDoOutput(true);
//Send request
DataOutputStream wr = new DataOutputStream(
connection.getOutputStream());
wr.writeBytes(urlParameters);
wr.close();
//Get Response
java.io.InputStream is = connection.getInputStream();
BufferedReader rd = new BufferedReader(new java.io.InputStreamReader(is));
StringBuilder response = new StringBuilder(); // or StringBuffer if not Java 5+
String line;
while((line = rd.readLine()) != null) {
response.append(line);
response.append('\r');
}
rd.close();
return response.toString();
} catch (Exception e) {
e.printStackTrace();
return null;
} finally {
if(connection != null) {
connection.disconnect();
}
}
}
I can remove the static and then i'm getting no errors.
But where do i call this method from now ? From inside the onCreate ?
Tried but it's not exist when i type excute....in the onCreate it's not exist can't call it.
How do i use this method ? And what should i put as urlParameters ?
The outer class which holds the "excutePost" is an inner class therefore it cannot have static methods in it. What you can do is move the outer class to a separate file and make it non static - this will solve your problem.

Jersey request.getInputStream()

#POST
#Path("/getphotos")
#Produces(MediaType.TEXT_HTML)
public String getPhotos() throws IOException{
BufferedReader rd = new BufferedReader(new InputStreamReader(request.getInputStream(),"UTF-8"));
String line;
while ((line = rd.readLine()) != null) {
System.out.println(line);
}
return "ok";
}
The code above is for my server.
But in this code, the String "line" has no value.(always)
Is there any problem with the code?
client side code
String message = "message";
URL url = new URL(targetURL);
HttpURLConnection urlConnection = (HttpURLConnection) url.openConnection();
urlConnection.setDoInput(true);
urlConnection.setDoOutput(true);
OutputStreamWriter wr = new OutputStreamWriter(urlConnection.getOutputStream());
wr.write(message);
You can manually consume a request's data in Jersey, as long as you have a valid handle to the actual HttpServletRequest. On a slight side note, keep in mind that you can only consume the request body once:
#Context
private HttpServletRequest request;
#POST
#Path("/")
public Response consumeRequest() {
try {
final BufferedReader rd = new BufferedReader(new InputStreamReader(
request.getInputStream(), "UTF-8"));
String line = null;
final StringBuffer buffer = new StringBuffer(2048);
while ((line = rd.readLine()) != null) {
buffer.append(line);
}
final String data = buffer.toString();
return Response.ok().entity(data).build();
} catch (final Exception e) {
return Response.status(Status.BAD_REQUEST)
.entity("No data supplied").build();
}
}
Side note: Libraries like Apache Commons IO provide robust functions for reading IO data

Catch errors of HttpUrlConnection in AsyncTask

I'm searching for a best practice to handle errors in an HttpURLConnection especially if the host is not available. How did I have to change my source?:
protected String doInBackground(String... strings) {
URL aURL;
String line;
HttpURLConnection connection;
BufferedReader reader;
StringBuilder stringBuilder = null;
try {
aURL = new URL(strings[0]);
connection = (HttpURLConnection) aURL.openConnection();
InputStream aInputStream = connection.getInputStream();
BufferedInputStream aBufferedInputStream = new BufferedInputStream(aInputStream);
reader = new BufferedReader(new InputStreamReader(connection.getInputStream()));
stringBuilder = new StringBuilder();
while ((line = reader.readLine()) != null)
{
stringBuilder.append(line);
}
} catch (IOException e) {
Log.d("svc", e.toString());
}
return stringBuilder.toString();
}
you will get different responsecode using connection.getResponseCode()
Check for the response codes for host not available and you will be set.

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