How to execute Bro using Java Runtime - java

On Ubuntu 14.04:
I would like to execute Bro using the Jave Runtime as follows:
String[] command = {"gksudo", "bro -r ../../pcaps/test1.pcap"};
process = Runtime.getRuntime().exec(c);
Where the bro commands are correct and the path to the pcap is relative from the source of my java project.
I used gksudo to have sudo privileges, but nothing happens. There are no log-files created.
Other commands (like mkdir) work and provides me of the right results, however with Bro it does not.
It appears that gksudo cannot initiate Bro because it is not actually a root user.
How can I bypass this?

Related

How do I sequentially execute wsl commands from java?

I want to execute wsl commands from java.
I'm trying to do this using Process and ProcessBuilder.
As I understand, there are two ways to do this:
Run wsl along with command as argument (for example: wsl ls -l) (do this per-command).
Run wsl, and then execute the commands one by one.
But there are some problems with 1 and 2.
With point 1:
When the command terminates, the process does not stop. So even if i run wsl ls, I can not determine the moment when I can call next command.
wsl does not save the state between such calls, so it's not very convenient
With point 2:
Since wsl does not show bash prompt, I can not track when the command stopped displaying information. For example:
ProcessBuilder pb = new ProcessBuilder("wsl");
pb.redirectErrorStream(true);
Process p = pb.start();
Thread.sleep(1000);
OutputStreamWriter osw = new OutputStreamWriter(p.getOutputStream());
osw.write("ls\n");
osw.flush();
And all I can read is:
build.gradle
gradle
gradlew
gradlew.bat
out
settings.gradle
src
No selya#selya-pc:/mnt/c/Users/selya$ read. So I can't use it as a separator between commands. I think that wsl somehow tracks, in what environment it was launched, for example, through isatty(), and therefore the output is different.
With both:
Аs far as I know, for programs that are running outside the terminal, stdout is not buffered. So there are some problems with, for example, sudo, because it asks fro a password without newline/flush ([sudo] password for selya:), therefore I can't read this line...
I found a solution - pass command as argument to unbuffer util, for example:
wsl unbuffer -p sudo apt-get update
(-p stands for pipeline).
But other problems still remain. Is there any way to do this? Or maybe there is lib for it? Even c or c++ lib will suit my needs...
P.S. I tried to find a solution for several days. Russian-speaking SO didn't help me, that's why I'm here. Sorry for my English...
The problem was solved with the help of pty4j. It works on linux, mac and windows. (It works like pseudo terminal on linux, but have nice java interface).

"su <otheruser>" fails with "standard in must be atty"

I researched this question and all answers suggest visudo to add:
Defaults:user !requiretty
It does not work!
I have two Linux boxes (RedHat). I have a Java class which uses ProcessBuilder/Process to execute commands. The class runs under a system account.
On both boxes, I run
su other-user -c 'some-command'
and provide the password for other-user in an input stream to the Process object.
On one box, the command succeeds and on the other I get the error above.
The sudoers files on both machines did not have exclusions for requiretty ('Defaults requiretty' is set on both files).
I tried adding the exclusion as suggested by the answers I found. I tried both the system user running the process and 'other-user'...
Does not work.
What else can be the issue? Do I need to restart the system after adding the requiretty exceptoin(s)?
sudoers is for sudo rather than su so you should use sudo.
According to su manual:
-c, --command COMMAND
Specify a command that will be invoked by the shell using its -c.
The executed command will have no controlling terminal. This option cannot be used to execute interactive programs which need a controlling TTY.
you can use a TTY spawning if you are trying to avoid using sudo or you don't have a sudo privileges.
Just invoke one of the following codes before running the code which giving you the error you mentioned.
here are some examples of codes you can use, depends on the code or the system you are using:
python -c 'import pty; pty.spawn("/bin/sh")'
echo os.system('/bin/bash')
/bin/sh -i
perl —e 'exec "/bin/sh";'
perl: exec "/bin/sh";
ruby: exec "/bin/sh"
lua: os.execute('/bin/sh')
(From within IRB)
exec "/bin/sh"
(From within vi)
:!bash
(From within vi)
:set shell=/bin/bash:shell
(From within nmap)
!sh
the first three choices up are my common used ones, and I am trusting their results.
I am using them while pentesting.

How to add the environment variables to the android Runtime.getRuntime().exec command?

There's an issue when I run the android Runtime.getRuntime().exec method.
I have a native binary file to be run on android and I start it with the java method Runtime.getRuntime().exec. But running this native binary file requires the addition of an environment variable. So I execute this command:
envSetCmd = {"sh", "-c", "export LD_LIBRARY_PATH="+excBinFilepath+":$LD_LIBRARY_PATH"}.
It doesn't work when I check the environment variable with the command:
sh, -c, echo $LD_LIBRARY_PATH.
I think the reason is that when I set the environment variables I start a shell and when I check it with the command "echo" another shell was started. So the environment variables didn't work in the shell I check it.
I think there are two ways to solve this issue. The one is that running two commands in one shell. So I tried to use the command:
{"sh", "-c", "export LD_LIBRARY_PATH="+excBinFilepath+":$LD_LIBRARY_PATH", "-c", "echo $LD_LIBRARY_PATH"}.
Unfortunately it is illegal. The other is that I add the environment variables to the android user startup files. I tried to echo the $PATH, and I see the /system/bin/ and other path was loaded at the startup of android.
So I think there must be a file just like the ~/.bashrc in linux which could set the users' environment.
Any one could give me some clues about the ways I listed above? By the way, I shouldn't root the phone!
try to execute whatever you need to execute with env:
{"env", "LD_LIBRARY_PATH="+excBinFilepath, "yourCmd"}

Java JAR file does not execute in startup script in Ubuntu 14.04

The following process normally works for my startup scripts. However, when I introduce a command to execute a JAR file, it does not work. This script works while I am logged in. However, it does not work as a startup script.
In /etc/init.d I create a bash script (test.sh) with the following contents:
#!/bin/bash
pw=$(curl http://169.254.169.254/latest/meta-data/instance-id)
pwh=$(/usr/bin/java -jar PWH.jar $pw &)
echo $pwh > test.txt
Make script executable
In /etc/rc.local, I add the following line:
sh /etc/init.d/test.sh
Notes:
I make a reference to the script in /etc/rc.local, because this script needs to run last after all services have started.
Please do not ask me to change the process (i.e., create script in /etc/init.d/ and reference it from /etc/rc.local), because it works for my other startup scripts.
I have tried adding nohup in front of java command, and it still did not work.
Thanks
As written, there is insufficient information to say what is going wrong. There are too many possibilities to enumerate.
Try running those commands one at a time in an interactive shell. The java command is probably writing something to standard error, and that will give you some clues.

How i run cygwin using java program?

I have installed cygwin on window to start crawling. It work well.
Now i want to run cygwin and run a crawl program at starting of cygwin using java program code.
If you provide some code for it ,it will be great help for me.
I looked at adatapost's link. It seems like a world of trouble awaits you down this path.
I mean, I like Cygwin a lot, but I wouldn't use it like this.
A few centimetres to the right of the 'Your Answer' box I'm typing in is a link to a Related question 'How can I run cygwin from Java?'
Who's putting the cart before the horse? I don't know.
Does Cygwin have to be involved at all ?
If you are trying to run a binary that requires the cygwin1.dll (which includes most commands you can execute from the cygwin bash shell) then you can run it by specifying the cygwin\bin directory in the path environment variable like this:
Process p = Runtime.getRuntime().exec("C:/path/to/cygwin/binary.exe", new String[] { "PATH=C:\\cygwin\\bin" });
This assumes you installed cygwin in C:\cygwin

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