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How do I find the longest words in a string?

I want to find the longest words in a given String.
The following code checks for the longest word, but I want every other word with the same length as well.
try (BufferedReader fileInputReader = new BufferedReader(new FileReader(filePath))){
String line = fileInputReader.readLine();
line = line.replaceAll("[^äÄöÖüÜßa-zA-Z ]", "");
String[] sentence = line.split(" ");
String longestWord = "";
for (int i = 0; i < sentence.length; i++) {
if (sentence[i].length() > longestWord.length()) {
longestWord = sentence[i];
}
}
System.out.println(longestWord);
}

Then you have to use a collection of these longestWords, e.g.
ArrayList<String> longestWords = new ArrayList<String>();
int longestWordLength = 0;
for (int i = 0; i < sentence.length; i++) {
if (sentence[i].length() > longestWordLength) { // longer
longestWordLength = sentence[i].length();
longestWords.clear();
longestWords.add(sentence[i]);
}
else if (sentence[i].length() == longestWordLength) { // same length
longestWords.add(sentence[i]);
}
}
for (int i = 0; i < longestWords.size(); ++i)
System.out.println(longestWords.get(i));

try(BufferedReader fileInputReader = new BufferedReader(new FileReader(filePath))){
String line = fileInputReader.readLine();
line = line.replaceAll("[^äÄöÖüÜßa-zA-Z ]", "");
String[] sentence = line.split(" ");
ArrayList<String> longestWord = new ArrayList<>();
int maxLength = 1;
for(int i = 0; i < sentence.length; i++){
if(sentence[i].length() > maxLength){
longestword.clear();
longestWord.add(sentence[i]);
maxLength=sentece[i].length();
}
else if(sentence[i].length() == maxLength)
{
longestWord.add(sentence[i]);
}
}
System.out.println(longestWord);
}

How to convert char to String in tokenizer in Java

Trying to read a file separated by commas into an array and not sure how to make party into a string to work with tokenizer
for(int i = 0; i < s.length; i++) {
String str = scan.nextLine();
StringTokenizer st = new StringTokenizer(str, ",");
//String [] tokens = str.split(",");
String name = st.nextToken();
String abbreviation = st.nextToken();
long population = Long.parseLong(st.nextToken());
String govName = st.nextToken();
char party = st.nextToken();
int ageWhenElected = Integer.parseInt(st.nextToken());
s[i] = new State(name, abbreviation, population, govName ,party, ageWhenElected);

Try
char party = st.nextToken().charAt(0);

You can join your array of string with comma as separator
StringUtils.join(strArray, ",");

Compare two strings and store the index in integer array

I have :
String1[] having Number,Quantity,Unit of Measure,Find Number parameters
String2[] having Action,Level,Number,Organization ID,Container,Revision,View,Quantity,Unit of Measure,Reference Designators,Trace Code,Find Number,Line Number,Component Reference,Quantity Option,Inclusion Option,Type
this parameters I have compare both the strings split them by commas using for loop. I want string1 found in string2 at which index. I want to store those index in one integer.
Please give any idea.
String[] col=col_name.split(",");
BufferedReader br = new BufferedReader(new FileReader("file.csv"));
String header = br.readLine();
if(header!=null)
{
String[] two = header.split(",");
System.out.println(header);
// String[] columns = header.split(",");
int[] indices = new int[20];
for (int i = 0; i < two.length; i++) {
for (int j = 0; j < col.length; j++) {
if(two[i].equals(col[j])){
System.out.println("("+i+","+j+")");
indices[i]=i;
}
}
Thanks in Advance

You can use the list.indexOf(Object o) method. Example:
String[] col=col_name.split(",");
BufferedReader br = new BufferedReader(new FileReader("file.csv"));
String header = br.readLine();
if(header!=null)
{
String[] two = header.split(",");
System.out.println(header);
int[] indices = new int[col.length];
for(int j = 0; j < col.length; j++){
indices[j]=Arrays.asList(two).indexOf(col[j]);
}
System.out.println(Arrays.toString(indices));
}

Reverse a string as per length of first word

I am new to Java Strings.
Actually I have the code to reverse words:
import java.io.BufferedReader;
import java.io.IOException;
import java.io.InputStreamReader;
public class Test2 {
public static void main(String[] args) throws IOException
{
System.out.println("enter a sentence");
BufferedReader br = new BufferedReader(new InputStreamReader(System.in));
String rev =br.readLine();
String [] bread = rev.split(" ");
for(int z =bread.length-1;z>=0;z--)
{
System.out.println(bread[z]);
}
}
}
For the above code I get:
Input :Bangalore is a city
Output: City is a Bangalore
But I want the output to be like below:
Input: Bangalore is a city
Output:cityaisba ng a lore
Another Example:
Input: Hello Iam New To Java.Java is object Oriented language.
Output: langu age Ori en tedo bjec ti sjava. javaToNe wIamolleH
Please help me out

Here is one way you could do it:
String rev = br.readLine();
String [] bread = rev.split(" ");
int revCounter = 0;
for(int z = bread.length - 1; z >= 0; z--)
{
String word = bread[z];
for(int i = 0; i < word.length(); i++)
{
// If char at current position in 'rev' was a space then
// just print space. Otherwise, print char from current word.
if(rev.charAt(revCounter) == ' ')
{
System.out.print(' ');
i--;
}
else
System.out.print(word.charAt(i));
revCounter++;
}
}

When I run your code I get following result:
city
a
is
Bangalore
So to have it in a single line, why don't you add a space and print a single line?
System.out.println("enter a sentence");
BufferedReader br = new BufferedReader(new InputStreamReader(System.in));
String rev = br.readLine();
String[] bread = rev.split(" ");
for (int z = bread.length - 1; z >= 0; z--) {
System.out.print(bread[z] + " ");
}

I didn't check the validity of your code like GHajba did. But if you want spaces to remain on specific places it might be an option to remove all spaces and put them back according to their index in the original String.
Remove all
newBread = newBread.replace(" ", "");
Put them back
StringBuilder str = new StringBuilder(newBread);
for (int index = oldBread.indexOf(" ") ;
index >= 0 ;
index = oldBread.indexOf(" ", index + 1))
{
str.insert(index, ' ');
}
newBread = str.toString();
I came up with this quick and there might be better ways to do this, maybe without StringBuilder, but this might help you until you find a better way.

Try with this (i've used a string as input):
String original = "Bangalore is a city";
System.out.println("Original : "+original);
StringBuilder inverted = new StringBuilder();
StringBuilder output = new StringBuilder();
String temp = "";
String[] split = original.split("\\s+");
for (int i = split.length - 1; i >= 0; i--) {
inverted.append(split[i]);
}
temp = inverted.toString();
for (String string : split) {
int currLenght = string.length();
String substring = temp.substring(0,currLenght);
temp = temp.replaceAll(substring, "");
output.append(substring).append(" ");
}
System.out.println("Converted : "+output.toString());

Append the reversed words without the spaces into a StringBuffer.
StringBuffer b = new StringBuffer();
for (int i = bread.length-1; i >= 0 ; i--) {
b.append(bread[i]);
}
Then insert the spaces of the original String into the StringBuffer.
int spaceIndex, prevIndex = 0;
while ((spaceIndex = rev.indexOf(" ", prevIndex + 1)) != -1) {
b.insert(spaceIndex, ' ');
prevIndex = spaceIndex;
}

Tokenize devnagari words into letters

I have something like
a = "बिक्रम मेरो नाम हो"
I want to achieve something like in Java
a[0] = बि
a[1] = क्र
a[3] = म

Java internally stores each character of any language in UTF-16(2 bytes) so you can safely access the characters individually.

Try This:
String a = "बिक्रम मेरो नाम हो";
int strLen = a.length();
char array[] = new char[strLen];
String strArray1[] = new String[strLen];
for (int i=0 ; i< strLen ; i++)
{
array[i] = a.charAt(i);
strArray1[i] = Character.toString(a.charAt(i));
System.out.println ("Index = " + i + "* Char = " +array[i] + "** String =" +strArray1[i] );
}
Output:
Index = 0* Char = ब** String =ब
Index = 1* Char = ि** String =ि
Index = 2* Char = क** String =क
Index = 3* Char = ्** String =्
Index = 4* Char = र** String =र
Index = 5* Char = म** String =म
Index = 6* Char = ** String =
Index = 7* Char = म** String =म
Index = 8* Char = े** String =े
Index = 9* Char = र** String =र
Index = 10* Char = ो** String =ो
Index = 11* Char = ** String =
Index = 12* Char = न** String =न
Index = 13* Char = ा** String =ा
Index = 14* Char = म** String =म
Index = 15* Char = ** String =
Index = 16* Char = ह** String =ह
Index = 17* Char = ो** String =ो
Note:
In order to allow eclipse to allow you to save your java program with foreign characters(Hindi alphabets), do the following:
Go to:
"Windows > Preferences > General > Content Types > Text > {Choose file type}
{Selected file type} > Default encoding > UTF-8" and click Update.

Did you try icu4j?
BreakIterator character instance has a possibility to split String to characters

My code is not at all optimized, sorry about that but it works!
Just change the path of the file in which you are going to enter the devnagri sentence and it should work.
public static void main(String[] args) throws IOException
{
BufferedReader br = new BufferedReader(new FileReader("/home/ubuntu/Documents/trainforjava.txt")); //PLEASE ENTER PATH HERE
String[] devFull = new String[]{
"अ","आ", "इ", "ई", "उ", "ऊ", "ऋ"
, "ऌ" ,"ऍ", "ए", "ऐ", "ऑ", "ओ", "औ",
"क", "ख", "ग", "घ" ,"ङ",
"च" ,"छ" ,"ज"," झ"," ञ",
"ट","ठ", "ड"," ढ"," ण",
"त", "थ", "द", "ध", "न",
"प", "फ", "ब"," भ","म",
"य", "र", "ल", "ळ",
"व", "श" ,"ष","स" ,"ह"
};
String[] uniDev = new String[]
{
"905","906","907","908","909","90a","90b",
"90c","90d","90f","910","911","913","914",
"915","916","917","918","919",
"91a","91b","91c","91d","91e",
"91f","920","921","922","923",
"924","925","926","927","928",
"92a","92b","92c","92d","92e",
"92f","930","932","933",
"935","936","937","938","939"
};
String[] devHalf = new String[]
{
"$़","ऽ","$ा","$ि" ,
"$ी", "$ ु","$ू","$ृ","$ॄ","$ॅ",
"$े","$ै","$ॉ",
"$ो","$ौ"
};
String[] gujHalf = new String[]
{
"$઼","ઽ","$ા","$િ" ,
"$ી","$ુ","$ૂ","$ૃ","$ૄ","$ૅ",
"$ે","$ૈ","$ૉ",
"$ો","$ૌ"
};
try
{
StringBuilder sb = new StringBuilder();
String line = br.readLine();
while( (line = br.readLine() ) != null)
{
line=line.replaceAll(" ", ""); //remove white spaces if any
System.out.println();
//System.out.println(line);
int strLength = line.length();
// String a = "बिक्रम मेरो नाम हो";
int strLen = line.length();
char array[] = new char[strLen];
String strArray1[] = new String[strLen];
int mark[] = new int[strLen+1];
String unis[]=new String[strLen];
int cnt=0;
String newCharD[]=new String [strLen];
String newCharG[]=new String [strLen];
String tempD=null;
String tempG=null;
String arr = null;
String next =null;
String temp=null;
String uniNext=null;
int hold=0;
int j=0;
for (int i=0 ; i< strLen ; i++)
{
j=i+1;
array[i] = line.charAt(i);
strArray1[i] = Character.toString(line.charAt(i));
if(i<(strLen-1))
{
char nbit = line.charAt(j);
next=Character.toString(line.charAt(j));
uniNext=Integer.toHexString(nbit);
//System.out.print("\nUninext:\t"+uniNext);
}
unis[i]=Integer.toHexString(array[i]);
mark[strLen]=1;
if((Arrays.asList(devFull).contains(Character.toString(array[i]))) && (!uniNext.equalsIgnoreCase("94d")) )
{
mark[i]=1;
}
else
{
mark[i]=0;
}
//
//System.out.println();
//System.out.println ("Index = " + i + "* Char = " +array[i] + "** String =" +strArray1[i]+ "Unicode="+unis[i]+"Mark="+mark[i]);
//System.out.print(unis[i].toString());
}
int start=0;
start=0;
for(int l1=0;l1<=strLen;l1++)
{
//start=0;
if(l1==0)
{
temp=Character.toString(array[l1]);
}
else
{
if(mark[l1]==0)
{
temp=temp+Character.toString(array[l1]);
}
else
{
System.out.print(" "+temp);
newCharD[start]=temp;
start++;
temp=null;
if(l1!=strLen)
{
temp=Character.toString(array[l1]);
}
}
}
}
/* for(int s=0;s<start;s++)
{
System.out.print(" "+newCharD[s]);
}*/
for(int s=0;s<start;s++)
{
}
}
}
finally {
br.close();
}
//PrintStream out = new PrintStream(new //FileOutputStream("/home/ubuntu/Documents/trainforjavaoutput.txt"));
//System.setOut(out);
}

Try this for Hindi :-
import java.io.*;
import java.text.BreakIterator;
import java.util.Locale;
public class Test {
public static void main(String[] args) throws IOException
{
String text = "बिक्रम मेरो नाम हो";
Locale hindi = new Locale("hi", "IN");
BreakIterator breaker = BreakIterator.getCharacterInstance(hindi);
breaker.setText(text);
int start = breaker.first();
for (int end = breaker.next();
end != BreakIterator.DONE;
start = end, end = breaker.next()) {
System.out.println(text.substring(start,end));
}
}
}
OUTPUT:-
बि
क्र
म
मे
रो
ना
म
हो
BreakIterator Java Documentation: https://docs.oracle.com/javase/tutorial/i18n/text/about.html

In order to split the string by letters rather than characters, going by dvasanth's suggestion, you can try below:
String x = "बिक्रम मेरो नाम हो";
x=x.replaceAll(" ", ""); // Remove all spaces
int strLength = x.length();
String [] letterArray = new String (strLength /2);
String combined = "";
for (int i=0, j=0; i < strLength ; i=i+2,j++)
{
strArray1[i] = Character.toString(x.charAt(i));
if (i+1 < strLength)
{
strArray1[i+1] = Character.toString(x.charAt(i+1));
combined = strArray1[i]+strArray1[i+1]; // This line provides the letters.
// Assumption is that each letter is 2 unicode characters long.
}
else
{
combined = strArray1[i];
}
letterArray [j] = combined;
System.out.println("Split string by letters is : "+combined);
System.out.println("Split string by letters in array is : "+letterArray [j]);
}
Output is:
Split string by letters is : बि
Split string by letters is : क्
Split string by letters is : रम
Split string by letters is : मे
Split string by letters is : रो
Split string by letters is : ना
Split string by letters is : मह
Split string by letters is : ो
Note:
In order to allow eclipse to allow you to save your java program with foreign characters(Hindi alphabets), do the following:
Go to:
"Windows > Preferences > General > Content Types > Text > {Choose file type}
{Selected file type} > Default encoding > UTF-8" and click Update.