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stopped copying large number of files using FileUtils

i am using library apache common io to copy file in my java program. when i tried to copy a lot of files (about 250.000) it just copied 4.454 and then stopped copying.
i saw in the task manager it's still running.
public void copyFiles(File source, File dest) {
Collection<File> all = new ArrayList<File>();
try {
addTree(source, all);
for (File elem : all) {
int p = 1;
File newFile = new File(dest.toString() + "\\" + elem.getName().replace(".", " ("+p+")."));
if (findFile(elem.getName(), dest)) {
for (int x = 1; newFile.exists() == true; x++) {
newFile = new File(dest.toString() + "\\" + elem.getName().replace(".", " ("+x+")."));
}
FileUtils.copyFile(elem.getAbsoluteFile(), newFile);
// jika file TIDAK di hidden maka copy file ke direktori
} else if (!(elem.isHidden())) {
FileUtils.copyFileToDirectory(elem, dest);
}
}
} catch (Exception e) {
e.printStackTrace();
}
}

How to speed up File Storage Access?

I am trying to get a list of all Folders that contain MP3 Files on the user's Internal Storage.
Here is the recursive function that I am calling for this purpose -
public void listAllMusicFiles(String pathToDirectory) {
String lastFolderPath = "";
int mp3Count = 0;
File f = new File(pathToDirectory);
File[] files = f.listFiles();
for (File inFile : files) {
if (inFile.isDirectory()) {
//reset last folder path
lastFolderPath = "";
Log.d("Directory ", inFile.getPath());
listAllMusicFiles(inFile.getPath());
} else {
if (inFile.getAbsolutePath().endsWith(".mp3") || inFile.getAbsolutePath().endsWith(".MP3")) {
mp3Count++;
Log.wtf("MP3 Count", mp3Count + " ");
//add each folder only once
String folderName = inFile.getParentFile().getName();
String folderPath = inFile.getParentFile().getPath();
Log.e("FOUND in", folderPath);
//create a new Folder object
Folder currentFolder = new Folder(folderName, folderPath, mp3Count + "");
if (!lastFolderPath.equals(folderPath)) {
Log.d("NEW", folderPath);
lastFolderPath = folderPath;
folderArrayList.add(currentFolder);
} else {
Log.d("OLD", folderPath);
//find a Folder object in folderArrayList where the object's path matches current folderPath
for (Folder folder : folderArrayList) {
String currentPath = folder.getFolder_Path();
if (currentPath.equals(folderPath)) {
//found a match
//update count
folder.setFolder_Song_Count(mp3Count + "");
}
}
}
}
}
}
}
When I run this code on my device, I am able to list the required folders in a RecyclerView, but with a delay of about 6-7 seconds.
I have already moved this task into an AsyncTask, so that my UIThread does not hang because of this intensive operation.
But I am totally at a loss when it comes to improving File System Performance. Kindly help. Thanks !

Instead of storing currentFolder in an ArrayList and in the next step iterating through complete list to find that folder and updating the value, you can simply use HashMap like this
HashMap<String, Folder> folders = new HashMap<>();
public void listAllMusicFiles(String pathToDirectory) {
int mp3Count = 0;
File f = new File(pathToDirectory);
File[] files = f.listFiles();
Folder folder;
String folderName, folderPath;
for (File inFile : files) {
if (inFile.isDirectory()) {
//reset last folder path
Log.d("Directory ", inFile.getPath());
listAllMusicFiles(inFile.getPath());
} else {
if (inFile.getAbsolutePath().endsWith(".mp3") || inFile.getAbsolutePath().endsWith(".MP3")) {
mp3Count++;
Log.wtf("MP3 Count", mp3Count + " ");
//add each folder only once
folderName = inFile.getParentFile().getName();
folderPath = inFile.getParentFile().getPath();
Log.e("FOUND in", folderPath);
if (folders.containsKey(folderPath)) {
folder = folders.get(folderPath);
folder.setFolder_Song_Count(mp3Count + "");
folders.put(folderPath, folder);
} else {
folder = new Folder(folderName, folderPath, mp3Count + "");
folders.put(folderPath, folder);
}
}
}
}
}

How to get the path of a file but without the actual file name

For example C:\Desktop and not C:\Desktop\file.txt.
Here's the code, what can i do to get only the path excluding the actual name of the file or do i have to mechanically remove the name part(String) with the split("\") method.
import java.io.*;
public class FilesInfo {
File file = new File("C:\\Users\\CCKS\\Desktop\\1");
public void viewFiles() throws IOException {
File[] files = file.listFiles();
String path = "";
for(int i = 0; i < files.length; i++){
if(!files[i].isDirectory()){
System.out.println("[DIRECTORY]" + files[i].getPath() + " [NAME] " + files[i].toString() + " [SIZE] " + files[i].length() + "KB");
} else {
path = files[i].getAbsolutePath();
file = new File(path);
}
}
if(path.equals("")){
return;
} else {
viewFiles();
}
}
public static void main(String [] args){
try {
new FilesInfo().viewFiles();
} catch (Exception e){
e.printStackTrace();
}
}
}

Like this,
File file = new File("C:\Desktop\file.txt");
String parentPath= file.getParent();

File file = new File( "C:/testDir/test1.txt" );
String justPath = file.getParent();

Java Path Files.copy rename if exists

just a simple question, with a hard (for me) to find answer :D. Here is my code (im going to try to translate the spanish part):
File carpetanueva = new File("C:"+File.separator+"sistema" + File.separator +
fechasal+File.separator+doc);
carpetanueva.mkdirs();
carpetanueva.setWritable(true);
rutadestino = ("c:"+File.separator+"sistema" +
File.separator + fechasal+File.separator +
doc+File.separator+"imagen.jpg");
//realizo la copia de la imagen desde el jfilechooser a su destino:
Path desde = Paths.get(rutaorigen);
Path hacia = Paths.get(rutadestino);
try {
Files.copy(desde, hacia);
JOptionPane.showMessageDialog(null,
"Se adjunto la planilla de ambulancia correctamente");
} catch (IOException e) {
JOptionPane.showMessageDialog(null, "error: "+e.getLocalizedMessage());
}
I get "rutaorigen" (frompath) from a JFileChooser. And I create "rutadestino" (topath) by using some variables so this way i can give an order. The problem is.. .if directories and the file "imagen.jpg" already exists, it gives an error.. (exception).. How can i make to check if image already exists, and if it does, rename the new image to , for example, imagen2? I cant figure out code, because im a newbie, I did a research and couldnt find something like this! Thanks in advance :)

OK, here is a quick solution if src is a Path to the file you want to copy, dst a Path to the file you want to write, and newName a Path to the file you want to rename to:
if (Files.exists(dst))
Files.move(dst, newName);
Files.copy(src, dst);
Note that you can use the methods in Path to facilitate your path building: .resolve(), .resolveSibling(), .relativize().
Edit: here is a function which will return a suitable name given a directory (dir), a base filename baseName and an "extension" (without the dot) extension:
private static Path findFileName(final Path dir, final String baseName,
final String extension)
{
Path ret = Paths.get(dir, String.format("%s.%s", baseName, extension));
if (!Files.exists(ret))
return ret;
for (int i = 0; i < Integer.MAX_VALUE; i++) {
ret = Paths.get(dir, String.format("%s%d.%s", baseName, i, extension));
if (!Files.exists(ret))
return ret;
}
throw new IllegalStateException("What the...");
}

I think this link will help How do I check if a file exists?
So for your case, probably do something like:
File toFile = new File(rutadestino);
if (toFile.exists()) {
// rename file
toFile.renameTo(new File("newFilePath/newName.jpg"));
} else {
// do something if file does NOT exist
}
Hope that helps! For more info, also check the Java Docs for File

sory late. but my code can help to litle bit.
public void copyFile(File source, File dest) throws IOException,
FileAlreadyExistsException {
File[] children = source.listFiles();
if (children != null) {
for (File child : children) {
if (child.isFile() && !child.isHidden()) {
String lastEks = child.getName().toString();
StringBuilder b = new StringBuilder(lastEks);
File temp = new File(dest.toString() + "\\"
+ child.getName().toString());
if (child.getName().contains(".")) {
if (temp.exists()) {
temp = new File(dest.toString()
+ "\\"
+ b.replace(lastEks.lastIndexOf("."),
lastEks.lastIndexOf("."), " (1)")
.toString());
} else {
temp = new File(dest.toString() + "\\"
+ child.getName().toString());
}
b = new StringBuilder(temp.toString());
} else {
temp = new File(dest.toString() + "\\"
+ child.getName());
}
if (temp.exists()) {
for (int x = 1; temp.exists(); x++) {
if (child.getName().contains(".")) {
temp = new File(b.replace(
temp.toString().lastIndexOf(" "),
temp.toString().lastIndexOf("."),
" (" + x + ")").toString());
} else {
temp = new File(dest.toString() + "\\"
+ child.getName() + " (" + x + ")");
}
}
Files.copy(child.toPath(), temp.toPath());
} else {
Files.copy(child.toPath(), temp.toPath());
}
} else if (child.isDirectory()) {
copyFile(child, dest);
}
}
}
}
features :
1. rename if file exist in the destination. example: document.doc if exist document (1).doc if exist document (2).doc if exist ...
2. copy all file from source (only file) to one folder in destination

The code below checks if the file already exists in destination, if it does, it appends #1 to file name just before the extension. If that file name also exists, it keeps appending #2,#3,#4... till the file name doesn't exist in destination. Since () and spaces create problems in Unix environment, I used # instead.
You can extend this and do a SUMCHECK if the file in destination with the identical name also has the same content and act accordingly.
Credit goes to johan indra Permana
String lastEks = file.getName().toString();
StringBuilder b = new StringBuilder(lastEks);
File temp = new File(backupDir.toString() + File.separator + file.getName().toString());
if (file.getName().contains(".")) {
if(temp.exists()) {
temp = new File(backupDir.toString() + File.separator +
b.replace(lastEks.lastIndexOf("."), lastEks.lastIndexOf("."),"#1").toString());
} else {
temp = new File(backupDir.toString() + File.separator + file.getName().toString());
}
b = new StringBuilder(temp.toString());
} else {
temp = new File(backupDir.toString() + File.separator + file.getName());
}
if (temp.exists()) {
for (int x=1; temp.exists(); x++) {
if(file.getName().contains(".")) {
temp = new File (b.replace(
temp.toString().lastIndexOf("#"),
temp.toString().lastIndexOf("."),
"#" + x ).toString());
} else {
temp = new File(backupDir.toString() + File.separator
+ file.getName() + "#" + x );
}
}
Files.copy(file.toPath(), temp.toPath());
} else {
Files.copy(file.toPath(), temp.toPath());
}

Deleting Multiple Files Java (Android)

I'm new to programming Android, and I want to delete Files on the sd-card. This is my current (working) code...
File appvc = new File(Environment.getExternalStorageDirectory()
.getAbsolutePath(), "ApplifierVideoCache");
if (appvc.isDirectory()) {
String[] children = appvc.list();
for (int i = 0; i < children.length; i++) {
new File(appvc, children[i]).delete();
}
}
Now I want to delete multiple files, but dont want to mention each file with that big block. Am I able to combine all files in one variable? Thanks ;)

Make a recursive method:
/*
* NOTE: coded so as to work around File's misbehaviour with regards to .delete(),
* which does not throw an exception if it fails -- or why you should use Java 7's Files
*/
public void doDelete(final File base)
throws IOException
{
if (base.isDirectory()) {
for (final File entry: base.listFiles())
doDelete(entry);
return;
}
if (!file.delete())
throw new IOException ("Failed to delete " + file + '!');
}

Another possibility would be using the Apache commons-io library and calling
if (file.isDirectory())
FileUtils.deleteDirectory(File directory);
else {
if(!file.delete())
throw new IOException("Failed to delete " + file);
}

You should make a method out of this chunk of code, pass file name and call it whenever you like:
public void DeleteFile(String fileName) {
File appvc = new File(Environment.getExternalStorageDirectory()
.getAbsolutePath(), fileName);
if (appvc.isDirectory()) {
String[] children = appvc.list();
for (int i = 0; i < children.length; i++) {
new File(appvc, children[i]).delete();
}
}
}

File dir = new File(android.os.Environment.getExternalStorageDirectory(),"ApplifierVideoCache");
Then call
deletedir(dir);
public void deletedir(File dir) {
File listFile[] = dir.listFiles();
if (listFile != null) {
for (int i = 0; i < listFile.length; i++) {
listFile[i].delete();
}
}
}
or if your folder as sub folders then
public void walkdir(File dir) {
File listFile[] = dir.listFiles();
if (listFile != null) {
for (int i = 0; i < listFile.length; i++)
{
if (listFile[i].isDirectory())
{
walkdir(listFile[i]);
} else
{
listFile[i].delete();
}
}
}

For kotlin
Create a array of path list
val paths: MutableList<String> = ArrayList()
paths.add("Yor path")
paths.add("Yor path")
.
.
delete file for each path
try{
paths.forEach{
val file = File(it)
if(file.exists(){
file.delete()
}
}
}catch(e:IOException){
}