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subsequent element as attribute in xml using xslt

need help in making subsequent element as attribute to preceding element if subsequent element contains the preceding element name using XSLT.
For below example, <emp_id> contains the preceding the element name so need to convert this element as attribute to element. can you anyone help for this?. I tried using subsequent functions in xslt but not working. Thanks in advance.
Sample XML:
<root>
<emp>test</emp>
<emp_id>1234</emp_id>
<college>something</college>
</root>
Expected out:
<root>
<emp id="1234">test</emp>
<college>something</college>
</root>

In the given example, you could do:
XSLT 1.0
<xsl:stylesheet version="1.0"
xmlns:xsl="http://www.w3.org/1999/XSL/Transform">
<xsl:output method="xml" version="1.0" encoding="UTF-8" indent="yes"/>
<xsl:strip-space elements="*"/>
<xsl:template match="*">
<xsl:copy>
<xsl:copy-of select="#*"/>
<xsl:apply-templates select="following-sibling::*[starts-with(name(), name(current()))]" mode="attr"/>
<xsl:apply-templates/>
</xsl:copy>
</xsl:template>
<xsl:template match="*" mode="attr">
<xsl:attribute name="{substring-after(name(), '_')}">
<xsl:value-of select="." />
</xsl:attribute>
</xsl:template>
<xsl:template match="*[preceding-sibling::*[name()=substring-before(name(current()), '_')]]"/>
</xsl:stylesheet>
to achieve the expected result.
There is probably a more elegant way, but we need to have some more rules, not just a single example.
Added:
Assuming that every element whose name contains a _ has a "parent" element whose attribute it should become, you can start by applying templates to only the "parent" elements (i.e. elements whose name does not contain a '_').
Then use a key to collect the "child" elements that need to be converted to attributes.
XSLT 1.0
<xsl:stylesheet version="1.0"
xmlns:xsl="http://www.w3.org/1999/XSL/Transform">
<xsl:output method="xml" version="1.0" encoding="UTF-8" indent="yes"/>
<xsl:strip-space elements="*"/>
<xsl:key name="atr" match="*" use="substring-before(name(), '_')" />
<xsl:template match="/root">
<xsl:copy>
<xsl:apply-templates select="*[not(contains(name(), '_'))]"/>
</xsl:copy>
</xsl:template>
<xsl:template match="*">
<xsl:copy>
<xsl:copy-of select="#*"/>
<xsl:for-each select="key('atr', name())">
<xsl:attribute name="{substring-after(name(), '_')}">
<xsl:value-of select="." />
</xsl:attribute>
</xsl:for-each>
<xsl:apply-templates/>
</xsl:copy>
</xsl:template>
</xsl:stylesheet>

How to concat some value in the existing value of a xml using xslt

Apologises if duplicate. I want to perform a concat operation on the values of the xml elements.
I have xml say Input.xml
<collection>
<one>
<part>1</part>
</one>
<two>
<part>2</part>
</two>
<three>
<part>3</part>
</three>
</collection>
I want the output like :
<collection>
<one>
<part>001</part>
</one>
<two>
<part>002</part>
</two>
<three>
<part>003</part>
</three>
</collection>
how to write xslt for it

Quick hacky XSLT , tested it online it seems to work.
<?xml version="1.0"?>
<xsl:stylesheet xmlns:xsl="http://www.w3.org/1999/XSL/Transform"
version="1.0">
<xsl:template match="*">
<xsl:copy>
<xsl:apply-templates select="#*|node()" />
</xsl:copy>
</xsl:template>
<xsl:template match="#*|text()|comment()|processing-instruction">
</xsl:template>
<xsl:template match="//part">
<part>
<xsl:text>00</xsl:text>
<xsl:value-of select="."></xsl:value-of>
</part>
</xsl:template>
</xsl:stylesheet>

Your possible solution might be:
<xsl:stylesheet version="1.0" xmlns:xsl="http://www.w3.org/1999/XSL/Transform">
<xsl:output method="xml"/>
<xsl:template match="part">
<xsl:value-of select="format-number(., '000')"/>
</xsl:template>
<!-- identity copy -->
<xsl:template match="#* | node()">
<xsl:copy>
<xsl:apply-templates select="#* | node()"/>
</xsl:copy>
</xsl:template>
</xsl:stylesheet>
Format the text in part to a 3 digit number format

Replace element tag to empty tag

My requirements is to generate an empty element with the given scenario. I have the same in this Replacing the element tag with value to end tag. However, the output generated is not what I am expecting.
CONDITION:
Map according to priority:
1. If Test1 is equal to Payment1, generate this empty element <st:Test1/> 2. else if Test2 is equal to Payment2, generate this empty element <st:Test2/> 3. else if Test3 is equal to Payment3, generate this empty element <st:Test3/>.
MY XSLT:
<?xml version="1.0" encoding="UTF-8"?>
<xsl:stylesheet version="1.0" xmlns:xsl="http://www.w3.org/1999/XSL/Transform" xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance" xmlns:st="http://www.ebinterface.at/schema/4p1/" xmlns:po="http://schema.ebinterface.at/schema/4p1/" exclude-result-prefixes="po">
<xsl:output method="xml" version="1.0" encoding="UTF-8" indent="yes"/>
<xsl:template match="#* | node()">
<xsl:copy>
<xsl:apply-templates select="#* | node()"/>
</xsl:copy>
</xsl:template>
<xsl:template match="*">
<xsl:element name="st:{local-name()}">
<xsl:apply-templates select="node()|#*"/>
</xsl:element>
</xsl:template>
<xsl:template match="po:DEFG" priority="1">
<st:DEFG>
<!--handle any existing child content-->
<xsl:apply-templates select="#* | node()"/>
<xsl:if test="not(po:Test1)">
<xsl:call-template name="Test1"/>
</xsl:if>
<xsl:if test="not(po:Test2)">
<xsl:call-template name="Test2"/>
</xsl:if>
<xsl:if test="not(po:Test3)">
<xsl:call-template name="Test3"/>
</xsl:if>
</st:DEFG>
</xsl:template>
<xsl:template match="po:Test1[.='Payment1']" name="Test1" priority="1">
<st:Test1/>
</xsl:template>
<xsl:template match="po:Test2[.='Payment2']" name="Test2" priority="1">
<st:Test2/>
</xsl:template>
<xsl:template match="po:Test3[.='Payment3']" name="Test3" priority="1">
<st:Test3/>
</xsl:template>
<xsl:template match="*[namespace-uri()='http://www.ebinterface.at/schema/4p1/']">
<xsl:element name="po:{local-name()}">
<xsl:apply-templates/>
</xsl:element>
</xsl:template>
<xsl:template match="*[namespace-uri()='http://www.ebinterface.at/schema/4p1/']/#*">
<xsl:attribute name="po:{local-name()}"><xsl:value-of select="."/></xsl:attribute>
</xsl:template>
</xsl:stylesheet>
INPUT FILE:
<?xml version="1.0" encoding="UTF-8"?>
<Statistics xmlns="http://schema.ebinterface.at/schema/4p1/" xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance" xsi:schemaLocation="http://www.ebinterface.at/schema/4p1/" Type="abc" Title="Statistics">
<ABC dsig="fh">Sample ABC</ABC>
<DEFG>
<Note>Wir ersuchen um termingerechte Bezahlung.</Note>
<Amount currencyCode="EUR">12.36</Amount>
<Test1>Payment1</Test1>
</DEFG>
</Statistics>
GENERATED OUTPUT:
<?xml version="1.0" encoding="UTF-8"?>
<st:Statistics xmlns:st="http://www.ebinterface.at/schema/4p1/" xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance" xsi:schemaLocation="http://www.ebinterface.at/schema/4p1/" Type="abc" Title="Statistics">
<st:ABC dsig="fh">Sample ABC</st:ABC>
<st:DEFG>
<st:Note>Wir ersuchen um termingerechte Bezahlung.</st:Note>
<st:Amount currencyCode="EUR">12.36</st:Amount>
<st:Test1/>
<st:Test2/> **This empty element should not appear since there's no Test2=Payment2**
<st:Test3/> **This empty element should not appear since there's no Test3=Payment3**
</st:DEFG>
</st:Statistics>
EXPECTED OUTPUT:
<?xml version="1.0" encoding="UTF-8"?>
<st:Statistics xmlns="http://schema.ebinterface.at/schema/4p1/" xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance" xsi:schemaLocation="http://www.ebinterface.at/schema/4p1/" st:Type="abc" st:Title="Statistics">
<st:ABC st:dsig="fh">Sample ABC</st:ABC>
<st:DEFG>
<st:Note>Wir ersuchen um termingerechte Bezahlung.</st:Note>
<st:Amount st:currencyCode="EUR">12.36</st:Amount>
<st:Test1/>
</st:DEFG>
</stStatistics>
Thank you in advance.
Your response is greatly appreciated.

When you call a template by name, that template will be executed regardless of whether it matches anything or not.
Not directly related to your question, you also have a template conflict between <xsl:template match="#* | node()"> and <xsl:template match="*">. Overall, you have way too much code; I believe you could do with just:
XSLT 1.0
<xsl:stylesheet version="1.0"
xmlns:xsl="http://www.w3.org/1999/XSL/Transform"
xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance"
xmlns:po="http://schema.ebinterface.at/schema/4p1/"
xmlns:st="http://www.ebinterface.at/schema/4p1/"
exclude-result-prefixes="po">
<xsl:output method="xml" version="1.0" encoding="UTF-8" indent="yes"/>
<xsl:strip-space elements="*"/>
<!-- move elements to new namespace -->
<xsl:template match="*">
<xsl:element name="st:{local-name()}">
<xsl:apply-templates select="node()|#*"/>
</xsl:element>
</xsl:template>
<!-- move attributes to new namespace -->
<xsl:template match="#*">
<xsl:attribute name="st:{local-name()}">
<xsl:value-of select="."/>
</xsl:attribute>
</xsl:template>
<!-- except attributes that are NOT in the default namespace -->
<xsl:template match="#*[namespace-uri()]">
<xsl:copy/>
</xsl:template>
<xsl:template match="po:Test1[.='Payment1']">
<st:Test1/>
</xsl:template>
<xsl:template match="po:Test2[.='Payment2']">
<st:Test2/>
</xsl:template>
<xsl:template match="po:Test3[.='Payment3']">
<st:Test3/>
</xsl:template>
</xsl:stylesheet>
Result
<?xml version="1.0" encoding="UTF-8"?>
<st:Statistics xmlns:st="http://www.ebinterface.at/schema/4p1/" xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance" xsi:schemaLocation="http://www.ebinterface.at/schema/4p1/" st:Type="abc" st:Title="Statistics">
<st:ABC st:dsig="fh">Sample ABC</st:ABC>
<st:DEFG>
<st:Note>Wir ersuchen um termingerechte Bezahlung.</st:Note>
<st:Amount st:currencyCode="EUR">12.36</st:Amount>
<st:Test1/>
</st:DEFG>
</st:Statistics>
Note:
The three choices are not mutually exclusive as your question would suggest.
Your expected output is not well-formed XML: you cannot have a prefix without binding it to a namespace.

Parsing nested XML File as node set

I have a problem. I have an xml file as below :
Main.xml
<?xml version="1.0" encoding="ISO-8859-1"?>
<msrsw>
<software>
<chapter>
<name> Hello world</sample>
<xref type="xml">C:\ABC\NestedXML.xml</xref>
</chapter>
</software>
</msrsw>
NestedXml.xml :
<?xml version="1.0" encoding="ISO-8859-1"?>
<msrsw>
<software>
<chapter>
<name> Nested XML </sample>
<age>14</age>
<country>Canada</country>
</chapter>
</software>
</msrsw>
I am using Apache FOP to produce PDF document (Using Java). FOP needs src and dest params. Src being Main.xml.
My XSLT is as below:
<xsl:param name="xmlFileName" />
<xsl:param name="XMLFile" select="document($xmlFileName)"/>
<xsl:template name="Chapters_1_2_Template">
<xsl:apply-templates select="$XMLFile/*" mode="chapter" />
</xsl:template>
<xsl:template match="node()" mode="chapter">
<xsl:for-each select="node()">
<xsl:if test="current()[name() = 'xref']">
<xsl:apply-templates select="current()[name() = 'xref']" mode="x" />
</xsl:if>
<xsl:if test="current()[name() = 'name']">
<xsl:apply-templates select="current()[name() = 'name']" mode="name" />
</xsl:if>
<xsl:if test="current()[name() = 'age']">
<xsl:apply-templates select="current()[name() = 'age']" mode="age" />
</xsl:if>
</xsl:for-each>
</xsl:template>
<xsl:template match="name" mode="name">
<xsl:value-of select="current()" />
</xsl:template>
<xsl:template match="age" mode="age">
<xsl:value-of select="current()" />
</xsl:template>
<xsl:template match="country" mode="country">
<xsl:value-of select="current()" />
</xsl:template>
<xsl:template match="xref" mode="x">
<xsl:param name="XMLFile" select="document(current())"/>
<xsl:call-template name="Chapters_1_2_Template" />
</xsl:template>
When I execute the above code, i get the following error in the line <xsl:apply-templates select="$XMLFile/*" mode="chapter" />:
Invalid token XMLFile.
When I remove $XMLFile - <xsl:apply-templates select="*" mode="chapter" /> , it works fine for me with Main.xml file's content.
When I just display the value of current() in xref template, it is parses the NestedXml.xml file and displayes string values in PDF.
Expected Output is:
Hello world
Nested XML
14
Canada
My requirement is to embed the node-set of NestedXML.xml within the<xref></xref> tags and recursively applyTemplates on that node-set.
But the document() function gives me the parsed String content of NestedXml.xml.
I do not want to use the document() function and just get the String value of NestedXml.xml. I need to parse all the tags of NestedXml.xml using the same XSLT.
Please suggest me where am I going wrong. Is this approach right? Is there any other way to do this?
Or it is not possible to do in this way using XSLT and that XSLT allows including only the parsed String values?

If it is that you want just some text nodes, the stylesheet needn't be that complex. Try this simpler stylesheet:
<?xml version="1.0"?>
<xsl:stylesheet version="1.0" xmlns:xsl="http://www.w3.org/1999/XSL/Transform" >
<xsl:output method="text" indent="yes"/>
<xsl:strip-space elements="*"/>
<xsl:template match="/">
<xsl:apply-templates select="msrsw/software/chapter/name"/>
<xsl:apply-templates select="document(msrsw/software/chapter/xref)/*"/>
</xsl:template>
<xsl:template match="text()">
<xsl:value-of select="normalize-space()"/>
<xsl:text>
</xsl:text>
</xsl:template>
</xsl:stylesheet>

Replace parts of string on line using XSLT 2

I have a WSDL, in which I would like to override the soap address location using XSLT 2.0.
For example:
<soap:address location="https://xyz.company.com/portal/services/Service?param1=myapp&webService=TestWebService"/>
For the location attribute, I would like
xyz.company.com to become abc.company.com
myapp to become xyzapp.
I have written the following xslt:
<?xml version="1.0" encoding="ISO-8859-1"?>
<xsl:stylesheet xmlns:xsl="http://www.w3.org/1999/XSL/Transform" version="2.0" xmlns:soap="http://schemas.xmlsoap.org/wsdl/soap/" xmlns:soapenc="http://schemas.xmlsoap.org/soap/encoding/" xmlns:wsdl="http://schemas.xmlsoap.org/wsdl/">
<xsl:output method="xml"/>
<xsl:template match="node()|#*">
<xsl:copy>
<xsl:apply-templates select="node()|#*"/>
</xsl:copy>
</xsl:template>
<xsl:variable name="vLocation" select="wsdl:definitions/wsdl:service/wsdl:port/soap:address/#location"/>
<xsl:template match="#location">
<xsl:attribute name="location">
<xsl:value-of select="replace($vLocation, xyz.company.com', 'abc.company.com')"/>
</xsl:attribute>
</xsl:template>
</xsl:stylesheet>
This works for replacing point 1 -> xyz.company.com to become abc.company.com.
But how can I also replace point 2. ->myapp to become xyzapp
Please advise.
Thanks,

You can simply call replace again as in
<xsl:template match="soap:address/#location">
<xsl:attribute name="location" select="replace(replace(., 'xyz\.company\.com', 'abc.company.com'), 'myapp', 'xyzapp')"/>
</xsl:template>