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How to properly synchronize two threads

This is a problem I have always heard about in school but never had a reason to mess with until I was asked for an interview.
Prompt: Using 2 threads print "Thread i: The number is 'j'" in order where j = 1:100 and i is the thread number. Thread 1 can only print odd j's and Thread 2 can only print even j's.
EDIT the output of j must be ordered
This was my attempt but I did not move on in the interview process. Is there any fundamental part I am missing? Are there any optimizations?
import java.util.concurrent.Semaphore;
public class ThreadSynchronization implements Runnable {
private int start;
private Semaphore semaphore;
private ThreadSynchronization(int start, Semaphore semaphore) {
this.start = start;
this.semaphore = semaphore;
}
public static void main(String[] args) {
Semaphore semaphore = new Semaphore(1, true);
semaphore.acquireUninterruptibly();
start(1, semaphore);
start(2, semaphore);
semaphore.release();
}
private static void start(int start, Semaphore semaphore) {
ThreadSynchronization ts = new ThreadSynchronization(start, semaphore);
Thread thread = new Thread(ts);
thread.start();
while (thread.getState() != Thread.State.WAITING) ;
}
#Override
public void run() {
for (int i = start; i <= 100; i += 2) {
semaphore.acquireUninterruptibly();
System.out.println("Thread " + start + ": The number is '" + i + "'");
semaphore.release();
}
}
}

One thread can keep aquiring and releasing the Semaphore, while the other thread starves.
You can do this with wait and notify, try this:
import java.util.concurrent.atomic.AtomicInteger;
class Odd implements Runnable {
private AtomicInteger integer;
private final Object lock;
public Odd(AtomicInteger integer, Object lock) {
this.integer = integer;
this.lock = lock;
}
#Override
public void run() {
synchronized (lock) {
try {
while (integer.get() <= 100) {
while (integer.get() % 2 == 0) {
lock.notify();
lock.wait();
}
if (integer.get() <= 100) {
System.out.println("Thread " +
Thread.currentThread().getName() + ": The number is '" + integer.get() + "'");
}
integer.getAndIncrement();
lock.notify();
}
} catch (Exception e) {
}
}
}
}
class Even implements Runnable {
private AtomicInteger integer;
private final Object lock;
public Even(AtomicInteger integer, Object lock) {
this.integer = integer;
this.lock = lock;
}
#Override
public void run() {
synchronized (lock) {
try {
while (integer.get() <= 100) {
while (integer.get() % 2 != 0) {
lock.notify();
lock.wait();
}
if (integer.get() <= 100) {
System.out.println("Thread " +
Thread.currentThread().getName() + ": The number is '" + integer.get() + "'");
}
integer.getAndIncrement();
lock.notify();
}
} catch (Exception e) {
}
}
}
}
public class ThreadSynchronization {
public static void main(String[] args) throws Exception{
Object lock = new Object();
AtomicInteger integer = new AtomicInteger(1);
Odd odd = new Odd(integer, lock);
Even even = new Even(integer, lock);
Thread thread1 = new Thread(odd, "1");
Thread thread2 = new Thread(even, "2");
thread1.start();
thread2.start();
thread1.join();
thread2.join();
}
}

Use an object to arbiter:
public class Switch {
private boolean expected;
public Switch(boolean init) {
expected = init;
}
public void waitFor(boolean value) {
synchronized(this) {
while (value != expected) {
try {
wait();
} catch (InterruptedException ex) {
// deal with it
}
}
expected = !expected;
notifyAll();
}
}
}
Then:
public class ThreadSynchronization implements Runnable {
private static Switch arbiter = new Switch(true);
private int start;
private ThreadSynchronization(int start) {
this.start = start;
}
public static void main(String[] args) {
start(1);
start(2);
}
private static void start(int start) {
ThreadSynchronization ts = new ThreadSynchronization(start);
Thread thread = new Thread(ts);
thread.start();
}
#Override
public void run() {
boolean odd = start%2 != 0;
for (int i = start; i <= 100; i += 2) {
arbiter.waitFor(odd);
System.out.println("Thread " + start + ": The number is '" + i + "'");
}
}
}

You was very close to the right solution, but the task requires 2 semaphores:
public class ThreadSynchronization implements Runnable {
private int start;
private Semaphore semaphore1;
private Semaphore semaphore2;
private ThreadSynchronization(int start, Semaphore semaphore1, Semaphore semaphore2) {
this.start = start;
this.semaphore1 = semaphore1;
this.semaphore2 = semaphore2;
}
private static void start(int start, Semaphore semaphore1, Semaphore semaphore2) {
ThreadSynchronization ts = new ThreadSynchronization(start, semaphore1, semaphore2);
Thread thread = new Thread(ts);
thread.start();
}
#Override
public void run() {
for (int i = start; i <= 100; i += 2) {
semaphore1.acquireUninterruptibly();
System.out.println("Thread " + start + ": The number is '" + i + "'");
semaphore2.release();
}
}
public static void main(String[] args) {
Semaphore semaphore1 = new Semaphore(1);
Semaphore semaphore2 = new Semaphore(0);
start(1, semaphore1, semaphore2);
start(2, semaphore2, semaphore1); // in reverse order
}
}

For this simple task it is enough to use AutomicInteger:
public static class CounterTask implements Runnable {
private final int id;
private final AtomicInteger counter;
private final int max;
private final IntPredicate predicate;
public CounterTask(int id, AtomicInteger counter, int max, IntPredicate predicate) {
this.id = id;
this.counter = counter;
this.max = max;
this.predicate = predicate;
}
#Override
public void run() {
while (counter.get() <= max) {
if (predicate.test(counter.get())) {
System.out.format("Thread %d: The number is '%d'\n", id, counter.get());
counter.incrementAndGet();
}
}
}
}
public static void main(String... args) throws InterruptedException {
final int max = 100;
final AtomicInteger counter = new AtomicInteger();
Thread oddThread = new Thread(new CounterTask(1, counter, max, val -> val % 2 == 0));
Thread evenThread = new Thread(new CounterTask(2, counter, max, val -> val % 2 != 0));
oddThread.start();
evenThread.start();
oddThread.join();
evenThread.join();
}

While wait and notify can do the job, I think the use of Semaphore can make for more readable code. The code below focusses on a solution for threads "talking" to each other and synchornizing where needed: I imagine in a real use case 2 threads do important work and at some point need to synchronize and determine who goes first.
import java.util.concurrent.Semaphore;
public class LockStep {
public static void main(String[] args) {
Semaphore evenTurn = new Semaphore(1);
Semaphore oddTurn = new Semaphore(0);
int max = 50;
Thread even = new Thread(new Worker(evenTurn, oddTurn, max));
even.start();
Thread odd = new Thread(new Worker(oddTurn, evenTurn, max));
odd.start();
try {
even.join();
odd.join();
} catch (Exception e) {
System.out.println("No join for me: " + e);
}
System.out.println("Finished");
}
static class Worker implements Runnable {
final Semaphore myTurn;
final Semaphore theirTurn;
final int maxTurns;
public Worker(Semaphore myTurn, Semaphore theirTurn, int maxTurns) {
this.myTurn = myTurn;
this.theirTurn = theirTurn;
this.maxTurns = maxTurns;
}
#Override
public void run() {
int turn = 0;
while (turn < maxTurns) {
try {
myTurn.acquire();
turn += 1;
System.out.println(Thread.currentThread().getName() + " " + turn);
theirTurn.release();
} catch (Exception e) {
System.out.println("Oops: " + e);
}
}
}
}
}

multithreading using 3 threads Java

I'm trying to create a program which uses threads: thread 1 puts integers into a list, thread 2 filters the even numbers into an even list and thread 3 does the same for odd numbers.
public class Manage {
private Object lock = new Object();
private LinkedList<Integer> intStorage = new LinkedList<Integer>();
private LinkedList<Integer> evens = new LinkedList<>();
private LinkedList<Integer> odds = new LinkedList<>();
public void intCollection() throws InterruptedException {
for (int i = 0; i <= 20; i++) {
synchronized(lock) {
while(i == 20) {
lock.wait();
}
intStorage.add(i);
lock.notifyAll();
System.out.println(intStorage);
}
Thread.sleep(100);
}
}
public void evens() throws InterruptedException {
for(int i = 0; i < intStorage.size() ; i++) {
synchronized(lock) {
if(intStorage.get(i) % 2 != 0) {
lock.wait();
}
if(intStorage.get(i) % 2 == 0) {
int j = intStorage.remove(i);
evens.add(j);
lock.notifyAll();
}
System.out.println(evens);
}
Thread.sleep(1000);
}
}
public void odds() throws InterruptedException {
for(int i = 0; i < intStorage.size() ; i++) {
synchronized(lock) {
if(intStorage.get(i) % 2 == 0) {
lock.wait();
}
if(intStorage.get(i) % 2 != 0) {
int j = intStorage.remove(i);
odds.add(j);
lock.notifyAll();
}
System.out.println(odds);
}
Thread.sleep(1000);
}
}
public static void main(String[] args) throws InterruptedException {
Manager m = new Manager();
Thread t1 = new Thread(){
public void run() {
try {
m.intCollection();
} catch (InterruptedException e) {
}
}
};
Thread t2 = new Thread(){
public void run() {
try {
m.evens();
} catch (InterruptedException e) {
}
}
};
Thread t3 = new Thread(){
public void run() {
try {
m.odds();
} catch (InterruptedException e) {
}
}
};
t1.start();
t2.start();
t3.start();
t1.join();
t2.join();
t3.join();
}
}
thread 1 runs, however I can't get thread 2 and thread 3 to filter the odds and evens. The program terminates after thread 1 is done.

The issue here is you have three threads competing for a lock, but you need the intCollection thread to win the lock first. If any othe thread wins the lock first you will get an out of bounds exception due to this segment:
for(int i = 0; i < intStorage.size() ; i++) {
synchronized(lock) {
if(intStorage.get(i) % 2 == 0) {
even though intStorage is empty it will invoke get(0) and produce an out of bounds exception.
You also did not need the notify and wait calls. I removed those in my solution. I added a check to see if intStorage is empty, thats all there was to it.
Here is the complete answer:
import java.util.*;
public class Manager {
private Object lock = new Object();
private boolean running = true;
private LinkedList<Integer> intStorage = new LinkedList<Integer>();
private LinkedList<Integer> evens = new LinkedList<>();
private LinkedList<Integer> odds = new LinkedList<>();
public void intCollection() throws InterruptedException {
for (int i = 0; i <= 20; i++) {
synchronized(lock) {
intStorage.add(i);
System.out.println("storage: " + intStorage);
}
Thread.sleep(100);
}
running = false;
}
public void evens() throws InterruptedException {
while( (!intStorage.isEmpty()) || running ) {
synchronized (lock) {
if(!intStorage.isEmpty()) {
if (intStorage.get(0) % 2 == 0) {
int j = intStorage.remove(0);
evens.add(j);
}
System.out.println("evens: " + evens);
}
}
Thread.sleep(1);
}
}
public void odds() throws InterruptedException {
while( (!intStorage.isEmpty()) || running ) {
synchronized (lock) {
if(!intStorage.isEmpty()) {
if (intStorage.get(0) % 2 != 0) {
int j = intStorage.remove(0);
odds.add(j);
}
System.out.println("odds: " + odds);
}
}
Thread.sleep(1);
}
}
public static void main(String[] args) throws InterruptedException {
//must be final to access
final Manager m = new Manager();
Thread t1 = new Thread(){
public void run() {
try {
m.intCollection();
} catch (InterruptedException e) {
}
}
};
Thread t2 = new Thread(){
public void run() {
try {
m.evens();
} catch (InterruptedException e) {
}
}
};
Thread t3 = new Thread(){
public void run() {
try {
m.odds();
} catch (InterruptedException e) {
}
}
};
t1.start();
t2.start();
t3.start();
t1.join();
t2.join();
t3.join();
}
}

Here you go...this is working fine : Only thing to notice is change in order of threads join :)
import java.util.LinkedList;
public class Manager {
private Object lock = new Object();
private LinkedList<Integer> intStorage = new LinkedList<Integer>();
private LinkedList<Integer> evens = new LinkedList<>();
private LinkedList<Integer> odds = new LinkedList<>();
public void intCollection() throws InterruptedException {
for (int i = 0; i < 20; i++) {
synchronized (lock) {
while (i == 20) {
lock.wait();
}
intStorage.add(i);
lock.notifyAll();
System.out.println(intStorage);
}
Thread.sleep(100);
}
}
public void evens() throws InterruptedException {
for (int i = 0; i < intStorage.size(); i++) {
synchronized (lock) {
if (intStorage.get(i) % 2 != 0) {
lock.wait();
}
if (intStorage.get(i) % 2 == 0) {
int j = intStorage.remove(i);
evens.add(j);
lock.notifyAll();
}
System.out.println("even" + evens);
}
Thread.sleep(1000);
}
}
public void odds() throws InterruptedException {
for (int i = 0; i < intStorage.size(); i++) {
synchronized (lock) {
if (intStorage.get(i) % 2 == 0) {
lock.wait();
}
if (intStorage.get(i) % 2 != 0) {
int j = intStorage.remove(i);
odds.add(j);
lock.notifyAll();
}
System.out.println("odd:" + odds);
}
Thread.sleep(1000);
}
}
public static void main(String[] args) throws InterruptedException {
Manager m = new Manager();
Thread t1 = new Thread() {
public void run() {
try {
m.intCollection();
} catch (InterruptedException e) {
}
}
};
Thread t2 = new Thread() {
public void run() {
try {
m.evens();
} catch (InterruptedException e) {
}
}
};
Thread t3 = new Thread() {
public void run() {
try {
m.odds();
} catch (InterruptedException e) {
}
}
};
t1.start();
t1.join();
t2.start();
t2.join();
t3.start();
t3.join();
}
}

How to run while loops in different threads? [duplicate]

I got asked this question recently in an interview.
Write a program with two threads (A and B), where A prints 1 , B prints 2 and so on until 50 is reached.
How do we go about doing that ?

The essence of the assignment is to demonstrate how a thread can signal another one. Most common way is to use blocking queues, but here a signal does not carry any information, so a Semaphore is sufficient.
Create thread class which is parameterized with 2 Semaphores: input and output:
class ThreadPrinter implements Runnable {
int counter;
Semaphore ins, outs;
ThreadPrinter(int counter, Semaphore ins, Semaphore outs) {
this.counter = counter;
this.ins = ins;
this.outs = outs;
}
#Override
public void run() {
for (int i = 0; i < 25; i++) {
ins.aquire(); // wait for permission to run
System.out.println("" + counter);
outs.release(); // allow another thread to run
counter += 2;
}
}
Create 2 Semaphores and pass them to 2 threads:
Semaphore a = new Semaphore(1); // first thread is allowed to run immediately
Semaphore b = new Semaphore(0); // second thread has to wait
ThreadPrinter tp1 = new ThreadPrinter(1, a, b);
ThreadPrinter tp2 = new ThreadPrinter(2, b, a);
Note semaphores a and b are passed in different order.

public class Test {
private static int count = 0;
public static void main(String[] args) throws InterruptedException {
Thread t1 = new Thread(new Runnable() {
#Override
public void run() {
for (int i = 0; i < 25; i++) {
synchronized (CommonUtil.mLock) {
incrementCount();
CommonUtil.mLock.notify();
try {
CommonUtil.mLock.wait();
} catch (InterruptedException e) {
// TODO Auto-generated catch block
e.printStackTrace();
}
}
}
}
});
Thread t2 = new Thread(new Runnable() {
#Override
public void run() {
for (int i = 0; i < 25; i++) {
synchronized (CommonUtil.mLock) {
incrementCount();
CommonUtil.mLock.notify();
try {
CommonUtil.mLock.wait();
} catch (InterruptedException e) {
// TODO Auto-generated catch block
e.printStackTrace();
}
}
}
}
});
t1.start();
Thread.sleep(400);
t2.start();
t1.join();
t2.join();
}
private static void incrementCount() {
count++;
System.out.println("Count: " + count + " icnremented by: " + Thread.currentThread().getName());
}
}
class CommonUtil {
static final Object mLock = new Object();
}

I encountered the same problem and was expected to use only basics so I choose wait notify on shared object between threads
public class Message implements Runnable {
private static final int N = 10;
private Thread thread;
private static Object object = new Object();
public Message(String name){
thread = new Thread(this, name);
thread.start();
}
public void run(){
for(int i=0; i<N; i++){
synchronized (object) {
System.out.println(i + "--" + thread.getName());
object.notify();
try {
object.wait();
} catch (InterruptedException e) {
e.printStackTrace();
}
}
}
}
}
In main method :
Message message1 = new Message("Ping");
Message message2 = new Message("Pong");

public class ThreadCounter implements Runnable {
private static int count = 0;
private Thread t;
public ThreadCounter(String tName){
t= new Thread(this, tName);
t.start();
}
#Override
public void run() {
for(int i=1; i<=5; i++){
synchronized (CommonUtil.mLock) {
incrementCount(t.getName());
CommonUtil.mLock.notify();
try {
CommonUtil.mLock.wait();
} catch (InterruptedException e) {
e.printStackTrace();
}
}
}
}
private void incrementCount(String tName){
System.out.println(tName+": "+(++ThreadCounter.count));
}
public static void main(String[] args) throws InterruptedException {
new ThreadCounter("Thread1");
Thread.sleep(500);
new ThreadCounter("Thread2");
}
}
class CommonUtil{
public static Object mLock = new Object();
}

hi please find answer here...pattern ABABABAB
package com.abhi.ThreadPractice;
public class Test {
public static void main(String[] args) throws InterruptedException {
final Object lock = new Object();
Thread t1 = new Thread(new Runnable() {
#Override
public void run() {
for (int i = 0; i < 10; i++) {
synchronized (lock) {
// count++;
System.out.println("A");
try {
lock.wait();
lock.notify();
} catch (InterruptedException e) {
e.printStackTrace();
}
}
}
}
});
Thread t2 = new Thread(new Runnable() {
#Override
public void run() {
for (int i = 0; i < 10; i++) {
synchronized (lock) {
lock.notify();
//count++;
System.out.println("B");
try {
lock.wait();
} catch (InterruptedException e) {
e.printStackTrace();
}
}
}
}
});
t1.start();
t2.start();
t1.join();
t2.join();
}
}

This is another solution:
Thread t1 = new Thread(new Runnable() {
#Override
public void run() {
synchronized (lock) {
for (int i = 1; i <= 50; i += 2) {
System.out.println("T1=" + i);
t1turn = false;
try {
lock.notifyAll();
lock.wait();
} catch (InterruptedException e) {
}
}
}
}
});
Thread t2 = new Thread(new Runnable() {
#Override
public void run() {
synchronized (lock) {
for (int i = 2; i <= 50; i += 2) {
if (t1turn)
try {
lock.wait();
} catch (InterruptedException e) {
}
System.out.println("T2=" + i);
t1turn = true;
lock.notify();
}
}
}
});
t1.start();
t2.start();

May be this is still relevant:
public class MyRunnable implements Runnable {
public static int counter = 0;
public static int turn = 0;
public static Object lock = new Object();
#Override
public void run() {
while (counter < 50) {
synchronized (lock) {
if (turn == 0) {
System.out.println(counter + " from thread "
+ Thread.currentThread().getName());
turn = 1;
try {
lock.wait();
} catch (InterruptedException e) {
Thread.currentThread().interrupt();
}
} else {
turn = 0;
lock.notify();
}
}
}
}
}
and then the main function
public static void main(String[] args) {
Thread threadA = new Thread(new MyRunnable());
Thread threadB = new Thread(new MyRunnable ());
threadA.start();
threadB.start();
}

public class PingPong extends Thread {
static StringBuilder object = new StringBuilder("");
public static void main(String[] args) throws InterruptedException {
Thread t1 = new PingPong();
Thread t2 = new PingPong();
t1.setName("\nping");
t2.setName(" pong");
t1.start();
t2.start();
}
#Override
public void run() {
working();
}
void working() {
while (true) {
synchronized (object) {
try {
System.out.print(Thread.currentThread().getName());
object.notify();
object.wait();
} catch (InterruptedException e) {
e.printStackTrace();
}
}
}
}
}

This was the simplest solution, I was able to think of. It uses a synchronized method and uses the notify() and the wait() to alternatively print the numbers. Hope it helps. :)
public class program implements Runnable
{
static int count =1;
private static final int MAX_COUNT = 50;
public synchronized void print ()
{
System.out.println(Thread.currentThread().getName() + " is printing " + count);
count++;
notify();
try{
if(count>MAX_COUNT)
return;
wait();
}catch (InterruptedException e){
e.printStackTrace();
}
}
public void run()
{
for(int i=0;i<MAX_COUNT/2;i++)
{
print();
}
}
public static void main(String[] args) {
program x= new program();
Thread t0= new Thread(x);
Thread t1= new Thread(x);
t0.start();
try
{
Thread.sleep(1);
} catch (InterruptedException e){
e.printStackTrace();
}
t1.start();
}
}

//simply use wait and notify and and set a counter and it will do
public class ThreadalternatePrint implements Runnable {
static int counter =0;
#Override
public synchronized void run() {
try {
Thread.sleep(10);
} catch (InterruptedException e1) {
// TODO Auto-generated catch block
e1.printStackTrace();
}
while(counter<51)
{ ++counter;
notify();
System.out.println(Thread.currentThread().getName());
try {
wait();
} catch (InterruptedException e) {
// TODO Auto-generated catch block
e.printStackTrace();
}
}
}
public static void main(String[] args) {
ThreadalternatePrint obj1 = new ThreadalternatePrint();
Thread Th1 = new Thread(obj1);
Thread Th2 = new Thread(obj1);
Th1.setName("Thread1");
Th2.setName("Thread2");
Th1.start();
Th2.start();
}
}

public class Testing implements Runnable {
private static int counter = 1;
private static final Object lock = new Object();
public static void main(String[] args) {
Thread t1 = new Thread(new Testing(), "1");
t1.start();
Thread t2 = new Thread(new Testing(), "2");
t2.start();
}
#Override
public void run() {
while (counter<=100) {
synchronized (lock) {
if (counter % 2 == 0) {
System.out.println(counter +" Written By Thread-"+ Thread.currentThread().getName());
counter++;
try {
lock.notifyAll();
lock.wait();
} catch (InterruptedException e) {
e.printStackTrace();
}
} else if (counter % 2 == 1) {
System.out.println(counter +" Written By Thread-"+ Thread.currentThread().getName());
counter++;
try {
lock.notifyAll();
lock.wait();
} catch (InterruptedException e) {
e.printStackTrace();
}
}
}
}
}
}

I have created a pretty basic Solution for it using the Reentrant Lock.
package com.multithreding.trylock;
import java.util.concurrent.locks.ReentrantLock;
public class TryLock extends Thread {
static int intitialCount = 50; //Value till which you want to print
int valueToSubtract = 0; //Value by which difference you want to print the series like 1,2,3
static ReentrantLock alternate = new ReentrantLock();
public TryLock(String name) {
this.setName(name);
}
public void run() {
while (intitialCount > 1) {
if (valueToSubtract > 0) {
alternate.lock();
intitialCount = intitialCount - valueToSubtract;
valueToSubtract = 0;
try {
Thread.sleep(200);
} catch (InterruptedException e) {
// TODO Auto-generated catch block
e.printStackTrace();
}
System.out.println("value Subtracted " + intitialCount + " by the Thread" + this.getName());
alternate.unlock();
} else {
try {
Thread.sleep(100);
} catch (InterruptedException e) {
// TODO Auto-generated catch block
e.printStackTrace();
}
valueToSubtract++;
}
}
}
}
package com.multithreding.trylock;
public class AlternatePrint {
public static void main(String[] args) throws InterruptedException{
//You can add as many thread to print then in different number of series
TryLock t1 = new TryLock("Odd One");
TryLock t2 = new TryLock("Even Value");
t1.start();
t2.start();
}
}
This solution is modular as well,
You can add 'n' number of Threads to print the alternate series. i.e Using 3 thread at once
You can also print the series with more than Difference of more than 1. i.e 1,3,5 etc

package thread;
public class Pingpong extends Thread {
static StringBuilder object = new StringBuilder("");
static int i=1;
#Override
public void run() {
working();
}
void working() {
while (i<=10) {
synchronized (object) {
try {
System.out.println(Thread.currentThread().getName() +" "+ i);
i++;
object.notify();
object.wait();
} catch (InterruptedException e) {
e.printStackTrace();
}
}
}
}
public static void main(String[] args) throws InterruptedException {
Thread t1 = new Pingpong();
Thread t2 = new Pingpong();
t1.setName("Thread1");
t2.setName("Thread2");
t1.start();
t2.start();
}
}
Thread1 1
Thread2 2
Thread1 3
Thread2 4
Thread1 5
Thread2 6
Thread1 7
Thread2 8
Thread1 9
Thread2 10

This answer is generic i.e. not only to print numbers alternately from 2 threads but to execute 2 threads alternately.
The above approaches are commendable but this one doesn't need any lock but instead it uses an AtomicInteger variable alongwith 2 AtomicBooleans to indicate when one thread has finished executing so that the other can finish executing the rest of its remaining execution.
This will work in all 3 cases:
When number of executions of both threads are same.
When first thread finishes before second thread and second thread has more number of executions than first thread.
When second thread finishes before first thread and first thread has more number of executions than second thread.
public class TestAlternateExecutionOfTwoThreads
{
private static final AtomicInteger count = new AtomicInteger(0);
private static final AtomicBoolean firstIsDone = new AtomicBoolean(false);
private static final AtomicBoolean secondIsDone = new AtomicBoolean(false);
// change the below values to change the number of iterations each thread should
// run. In this example, the initial value are hard-coded but you can change
// them as well.
private static final int finalOfFirstThread = 10;
private static final int finalOfSecondThread = 109;
public static void main(String[] args)
{
Runnable r1 = () -> {
int i = 1;
for(; i <= finalOfFirstThread; )
{
while(count.get() == 0)
{
System.out.println(i);
count.incrementAndGet();
i++;
}
if(count.get() == 1 && secondIsDone.get() && i != (finalOfFirstThread + 1))
{
System.out.println(i);
i++;
}
}
firstIsDone.set(true);
};
Runnable r2 = () -> {
int j = 100;
for (; j <= finalOfSecondThread; )
{
while(count.get() == 1)
{
System.out.println(j);
count.decrementAndGet();
j++;
}
if(count.get() == 0 && firstIsDone.get() && j != (finalOfSecondThread + 1))
{
System.out.println(j);
j++;
}
}
secondIsDone.set(true);
};
Thread t1 = new Thread(r1);
Thread t2 = new Thread(r2);
t1.start();
t2.start();
}
}

I guess this might help.
Although it is not standard but i hope it provides a simpler approach.
public class ThreadDemo
{
public static void main (String [] args)
{
PrintDemo pd=new PrintDemo();
MyThread1 mt1 = new MyThread1 ("T1",pd);
MyThread2 mt2 = new MyThread2 ("T2",pd);
mt1.start ();
mt2.start();
}
}
class PrintDemo {
private boolean oddFlag=true;
public synchronized void printOdd(int i,String tName){
if(oddFlag==false){
try {
wait();
} catch (InterruptedException e) {
e.printStackTrace();
}
}else{
System.out.println("\nThread "+tName+" count:"+i);
oddFlag=false;
notify();
}
}
public synchronized void printEven(int i,String tName){
if(oddFlag==true){
try {
wait();
} catch (InterruptedException e) {
e.printStackTrace();
}
}else{
System.out.println("\nThread "+tName+" count:"+i);
oddFlag=true;
notify();
}
}
}
class MyThread1 extends Thread
{
private PrintDemo pd;
private String name;
MyThread1(String threadName,PrintDemo pd){
this.name=threadName;
this.pd=pd;
}
public void run ()
{
for(int i=1;i<=50;i+=2){
pd.printOdd(i,name);
}
}
}
class MyThread2 extends Thread
{
private PrintDemo pd;
private String name;
MyThread2(String threadName,PrintDemo pd){
this.name=threadName;
this.pd=pd;
}
public void run ()
{
for(int i=2;i<=50;i+=2){
pd.printEven(i,name);
}
}
}

How to execute four threads consecutively one by one in java? [duplicate]

I have 3 threads
1st printing A
2nd printing B
3rd printing C
I want to print in sequence A B C A B C A B C and so on.....
So I wrote the program below, but I am not able to achieve the same.
I am aware of the problem that when status=1 at that time say for example B1 and C1 thread are waiting and when I do notifyAll() both waiting thread wake up and depending on CPU allocation it might print B or C.
in this case I want only B to be printed after A.
what modification I need to do.
public class NotifyAllExample {
int status=1;
public static void main(String[] args) {
NotifyAllExample notifyAllExample = new NotifyAllExample();
A1 a=new A1(notifyAllExample);
B1 b=new B1(notifyAllExample);
C1 c=new C1(notifyAllExample);
a.start();
b.start();
c.start();
}
}
class A1 extends Thread{
NotifyAllExample notifyAllExample;
A1(NotifyAllExample notifyAllExample){
this.notifyAllExample = notifyAllExample;
}
#Override
public void run() {
try{
synchronized (notifyAllExample) {
for (int i = 0; i < 100; i++) {
if(notifyAllExample.status!=1){
notifyAllExample.wait();
}
System.out.print("A ");
notifyAllExample.status = 2;
notifyAllExample.notifyAll();
}
}
}catch (Exception e) {
System.out.println("Exception 1 :"+e.getMessage());
}
}
}
class B1 extends Thread{
NotifyAllExample notifyAllExample;
B1(NotifyAllExample notifyAllExample){
this.notifyAllExample = notifyAllExample;
}
#Override
public void run() {
try{
synchronized (notifyAllExample) {
for (int i = 0; i < 100; i++) {
if(notifyAllExample.status!=2){
notifyAllExample.wait();
}
System.out.print("B ");
notifyAllExample.status = 3;
notifyAllExample.notifyAll();
}
}
}catch (Exception e) {
System.out.println("Exception 2 :"+e.getMessage());
}
}
}
class C1 extends Thread{
NotifyAllExample notifyAllExample;
C1(NotifyAllExample notifyAllExample){
this.notifyAllExample = notifyAllExample;
}
#Override
public void run() {
try{
synchronized (notifyAllExample) {
for (int i = 0; i < 100; i++) {
if(notifyAllExample.status!=3){
notifyAllExample.wait();
}
System.out.print("C ");
notifyAllExample.status = 1;
notifyAllExample.notifyAll();
}
}
}catch (Exception e) {
System.out.println("Exception 3 :"+e.getMessage());
}
}
}

Convert those IF statements to WHILE statements to get the desired behavior:
if (notifyAllExample.status != 2){
notifyAllExample.wait();
}
to
while (notifyAllExample.status != 2){
notifyAllExample.wait();
}
This will ensure that if a thread is notified, it won't go out of the while loop until the status value is what it expects.
Also, mark status as volatile so that the threads won't have a local copy.

public class RunThreadsInOrder implements Runnable {
static int numThread = 1;
static int threadAllowedToRun = 1;
int myThreadID;
private static Object myLock = new Object();
public RunThreadsInOrder() {
this.myThreadID = numThread++;
System.out.println("Thread ID:" + myThreadID);
}
#Override
public void run() {
synchronized (myLock) {
while (myThreadID != threadAllowedToRun) {
try {
myLock.wait();
} catch (InterruptedException e) {
} catch (Exception e) {}
}
try {
Thread.sleep(2000);
} catch (InterruptedException e) {
}
System.out.println("myThreadID is running: " + myThreadID);
myLock.notifyAll();
threadAllowedToRun++;
}
}
public static void main(String[] args) {
// TODO Auto-generated method stub
Thread t1 = new Thread(new RunThreadsInOrder());
Thread t2 = new Thread(new RunThreadsInOrder());
Thread t3 = new Thread(new RunThreadsInOrder());
Thread t4 = new Thread(new RunThreadsInOrder());
Thread t5 = new Thread(new RunThreadsInOrder());
Thread t6 = new Thread(new RunThreadsInOrder());
Thread t7 = new Thread(new RunThreadsInOrder());
t7.start();
t6.start();
t5.start();
t4.start();
t3.start();
t2.start();
t1.start();
}
}

public class Main {
public static void main(String[] args) throws IOException{
Thread t1 = new Thread(new A(), "1");
Thread t2 = new Thread(new A(), "2");
Thread t3 = new Thread(new A(), "3");
t1.start();
try{
t1.join();
}catch (Exception e){
}
t2.start();
try{
t2.join();
}catch (Exception e){
}
t3.start();
try{
t3.join();
}catch (Exception e){
}
}
}
class A implements Runnable{
public void run(){
System.out.println(Thread.currentThread().getName());
}
}
or you can use Executor Framework
public class Sequence {
int valve = 1;
public static void main(String[] args){
Sequence s = new Sequence();
ExecutorService es = Executors.newFixedThreadPool(3);
List<Runnable> rList = new ArrayList<>();
rList.add(new A(s));
rList.add(new B(s));
rList.add(new C(s));
for(int i = 0; i < rList.size(); i++){
es.submit(rList.get(i));
}
es.shutdown();
}
}
class A implements Runnable{
Sequence s;
A(Sequence s){
this.s = s;
}
public void run(){
synchronized (s) {
for (int i = 0; i < 10; i++) {
while (s.valve != 1) {
try {
s.wait();
} catch (InterruptedException e) {
e.printStackTrace();
}
}
System.out.println("A");
s.valve = 2;
s.notifyAll();
}
}
}
}
class B implements Runnable{
Sequence s;
B(Sequence s){
this.s = s;
}
public void run() {
synchronized (s) {
for (int i = 0; i < 10; i++) {
while (s.valve != 2) {
try {
s.wait();
} catch (InterruptedException e) {
e.printStackTrace();
}
}
System.out.println("B");
s.valve = 3;
s.notifyAll();
}
}
}
}
class C implements Runnable{
Sequence s;
C(Sequence s){
this.s = s;
}
public void run() {
synchronized (s) {
for(int i = 0; i < 10; i++) {
while (s.valve != 3) {
try {
s.wait();
} catch (InterruptedException e) {
e.printStackTrace();
}
}
System.out.println("C");
s.valve = 1;
s.notifyAll();
}
}
}
}
In the first case the join for each thread causes the threads to wait for one another. In the second case a list stores the threads and executor executes them one after another creating 3 threads
Another way to do this is where only one runnable class is present and communication between thread is done via static variable in the main class and a variable in the runnable class
import java.util.ArrayList;
import java.util.List;
import java.util.concurrent.Executor;
import java.util.concurrent.ExecutorService;
import java.util.concurrent.Executors;
public class Seq {
int i = 1;
public static void main(String[] args){
Seq s = new Seq();
Common c1 = new Common(s, 1);
Common c2 = new Common(s, 2);
Common c3 = new Common(s, 3);
List<Runnable> l = new ArrayList<>();
l.add(c1);
l.add(c2);
l.add(c3);
ExecutorService es = Executors.newFixedThreadPool(3);
for(int i = 0; i < 3; i++){
es.submit(l.get(i));
}
es.shutdown();
}
}
class Common implements Runnable{
Seq s;
int o;
Common(Seq s, int o){
this.s = s;
this.o = o;
}
public void run(){
synchronized (s) {
for (int z = 0; z < 100; z++) {
if(s.i > 3)
s.i = 1;
while (s.i != o) {
try {
s.wait();
} catch (InterruptedException e) {
e.printStackTrace();
}
}
System.out.println(o);
s.i++;
s.notifyAll();
}
}
}
}

I was asked to write a similar program in an interview with the added condition that it should be extensible in a way that we can provide our own count of threads and they should print characters with the first thread printing 'A' and then the subsequent threads printing B, C, D and so on. Here's how I did it.
public class AlternateCharPrinter {
public static char ch = 65;
private static void createAndStartThreads(int count) {
Object lock = new Object();
for (int i = 0; i < count; i++) {
new Thread(new AlternateCharRunner((char) (65 + i), lock)).start();
}
}
public static void main(String[] args) {
createAndStartThreads(4);
}
}
class AlternateCharRunner implements Runnable {
private char ch;
private Object lock;
private static int runnerCount;
public AlternateCharRunner(char ch, Object lock) {
this.ch = ch;
this.lock = lock;
runnerCount++;
}
#Override
public void run() {
while (true) {
synchronized (lock) {
while (ch != AlternateCharPrinter.ch) {
try {
lock.wait();
} catch (InterruptedException e) {
e.printStackTrace();
}
}
System.out.println(AlternateCharPrinter.ch++);
if (AlternateCharPrinter.ch == (65 + runnerCount)) {
AlternateCharPrinter.ch = 65;
}
lock.notifyAll();
}
}
}
}

You need to replace
if (notifyAllExample.status!=1)
with
while (notifyAllExample.status!=1)
and same thing in the other 2 classes. If not, then as soon as the wait exits the thread continues without knowing if it is its turn.

Replace:
if(notifyAllExample.status!=1){
notifyAllExample.wait();
}
with:
while(notifyAllExample.status!=1){
notifyAllExample.wait();
}
in all classes accordingly.

The simplest solution to solve this can be following way:
public class PrintInOrder implements Runnable {
private int valueToPrint;
private int id;
private static int turn = 1;
private static int RESET_TURN_THRESHOLD = 3;
public PrintInOrder() {
this.valueToPrint = -1;
}
public PrintInOrder(int id, int val) {
this.id = id;
this.valueToPrint = val;
}
#Override
public void run() {
while(true) {
if (turn == this.id) {
System.out.println(Thread.currentThread().getName() + "::::" + valueToPrint);
turn++;
}
if (turn > RESET_TURN_THRESHOLD) {
turn = 1;
}
}
}
public static void main(String []args) {
Thread t1 = new Thread(new PrintInOrder(1, 1));
t1.setName("THREAD-1");
t1.start();
Thread t2 = new Thread(new PrintInOrder(2, 2));
t2.setName("THREAD-2");
t2.start();
Thread t3 = new Thread(new PrintInOrder(3, 3));
t3.setName("THREAD-3");
t3.start();
}
}
/*
OUTPUT::::
THREAD-1::::1
THREAD-2::::2
THREAD-3::::3
THREAD-1::::1
THREAD-2::::2
THREAD-3::::3
THREAD-1::::1
THREAD-2::::2
THREAD-3::::3
THREAD-1::::1
THREAD-2::::2
THREAD-3::::3
THREAD-1::::1
THREAD-2::::2
THREAD-3::::3
THREAD-1::::1
THREAD-2::::2
THREAD-3::::3
...
*/

Here is my solution -
I have created three threads each thread knows what it needs to print and what comes after it.
I have also created a Class NLock which holds the next word which needs to be printed.
Whenever a thread is able to acquire NLock lock then it checks
if it's his turn if yes then it prints the word and set the next value to be printed in NLock or else it waits till it's his turn
public class SynchronizeThreeThreads {
public static void main(String args[]) throws InterruptedException {
NLock lock=new NLock("A");
Thread a =new Thread(new PrintInOrder("A","B",lock));
Thread b =new Thread(new PrintInOrder("B","C",lock));
Thread c =new Thread(new PrintInOrder("C","A",lock));
a.start();
b.start();
c.start();
c.join(); // Once all is done main thread will exit
System.out.println("Done");
}
}
class NLock{
private String value;
public NLock(String value) {
this.value=value;
}
public String getValue() {
return value;
}
public void setValue(String next) {
this.value=next;
}
}
class PrintInOrder implements Runnable{
private String word;
private String next;
private NLock lock;
public PrintInOrder(String word, String next,NLock lock){
this.word=word;
this.next=next;
this.lock=lock;
}
#Override
public void run() {
int i=0;
while(i<3) {
synchronized (lock) {
try {
//Check if it's my turn
if(lock.getValue().equals(word)) {
System.out.println(this.word);
//Set what next needs to be printed
//So that when that thread wakes up it knows that it's his turn
lock.setValue(next);
i++;
lock.notifyAll();
Thread.sleep(100);
}
else //Nope not my turn wait
lock.wait();
} catch (InterruptedException e) {
e.printStackTrace();
}
}
}
}
}
Below is the output
A
B
C
A
B
C
A
B
C
Done

This is my attempt to solve the same. Any suggestions are welcome. This is the complete running code.
import lombok.SneakyThrows;
import lombok.extern.slf4j.Slf4j;
import java.util.List;
import java.util.concurrent.atomic.AtomicInteger;
#Slf4j
public class SeqExecution {
static class SeqThread extends Thread {
private static final Object lock = new Object();
private static final AtomicInteger AUTO_COUNTER = new AtomicInteger();
private static final TrackExecution trackExecution = new TrackExecution();
private final int seqNo;
SeqThread(Runnable runnable) {
super(runnable);
this.seqNo = AUTO_COUNTER.getAndIncrement();
}
#SneakyThrows
#Override
public void run() {
while (true) {
synchronized (lock) {
while (trackExecution.CUR_EXECUTION.get() != this.seqNo) {
try {
lock.wait(100);
} catch (Exception e) {}
}
//log.info("Thread: {} is running", this.seqNo);
super.run();
sleep(1000);
trackExecution.increment();
lock.notifyAll();
}
}
}
static class TrackExecution {
private final AtomicInteger CUR_EXECUTION = new AtomicInteger();
int get() {
return CUR_EXECUTION.get();
}
synchronized void increment() {
var val = CUR_EXECUTION.incrementAndGet();
if (val >= SeqThread.AUTO_COUNTER.get()) {
CUR_EXECUTION.set(0);
}
}
}
}
public static void main(String[] args) {
final var seqThreads = List.of(new SeqThread(() -> System.out.print("A ")),
new SeqThread(() -> System.out.print("B ")),
new SeqThread(() -> System.out.print("C ")));
seqThreads.forEach(Thread::start);
seqThreads.forEach(t -> {
try {
t.join();
} catch (Exception e) {
log.warn(e.getMessage(), e);
}
});
}
}

I think it's simpler to achieve this using join.
Example:
public static void main(String[] args) {
final Thread t1 = new Thread("t1") {
#Override
public void run() {
System.out.println("i am thread: " + Thread.currentThread().getName());
}
};
final Thread t2 = new Thread(t1, "t2") {
#Override
public void run() {
t1.start();
try {
t1.join();
} catch ( InterruptedException e ) {
// TODO Auto-generated catch block
e.printStackTrace();
}
System.out.println("i am thread: " + Thread.currentThread().getName());
}
};
Thread t3 = new Thread(t2, "t3") {
#Override
public void run() {
t2.start();
try {
t2.join();
} catch ( InterruptedException e ) {
// TODO Auto-generated catch block
e.printStackTrace();
}
System.out.println("i am thread: " + Thread.currentThread().getName());
}
};
t3.start();
}

Here is my solution please try and let me know
package thread;
class SyncPrinter {
public static void main(String[] args) {
SyncPrinterAction printAction1 = new SyncPrinterAction(new int[]{1,5,9,13}, true);
SyncPrinterAction printAction2 = new SyncPrinterAction(new int[]{2,6,10,14}, true);
SyncPrinterAction printAction3 = new SyncPrinterAction(new int[]{3,7,11,15}, true);
SyncPrinterAction printAction4 = new SyncPrinterAction(new int[]{4,8,12,16}, false);
printAction1.setDependentAction(printAction4);
printAction2.setDependentAction(printAction1);
printAction3.setDependentAction(printAction2);
printAction4.setDependentAction(printAction3);
new Thread(printAction1, "T1").start();;
new Thread(printAction2, "T2").start();
new Thread(printAction3, "T3").start();
new Thread(printAction4, "T4").start();
}
}
class SyncPrinterAction implements Runnable {
private volatile boolean dependent;
private SyncPrinterAction dependentAction;
int[] data;
public void setDependentAction(SyncPrinterAction dependentAction){
this.dependentAction = dependentAction;
}
public SyncPrinterAction( int[] data, boolean dependent) {
this.data = data;
this.dependent = dependent;
}
public SyncPrinterAction( int[] data, SyncPrinterAction dependentAction, boolean dependent) {
this.dependentAction = dependentAction;
this.data = data;
this.dependent = dependent;
}
#Override
public void run() {
synchronized (this) {
for (int value : data) {
try {
while(dependentAction.isDependent())
//System.out.println("\t\t"+Thread.currentThread().getName() + " :: Waithing for dependent action to complete");
wait(100);
} catch (InterruptedException e) {
e.printStackTrace();
}
dependentAction.setDependent(true);
System.out.println(Thread.currentThread().getName() + " :: " +value);
dependent = false;
}
}
}
private void setDependent(boolean dependent) {
this.dependent = dependent;
}
private boolean isDependent() {
return dependent;
}
}

Writing a program with 2 threads which prints alternatively

I got asked this question recently in an interview.
Write a program with two threads (A and B), where A prints 1 , B prints 2 and so on until 50 is reached.
How do we go about doing that ?

The essence of the assignment is to demonstrate how a thread can signal another one. Most common way is to use blocking queues, but here a signal does not carry any information, so a Semaphore is sufficient.
Create thread class which is parameterized with 2 Semaphores: input and output:
class ThreadPrinter implements Runnable {
int counter;
Semaphore ins, outs;
ThreadPrinter(int counter, Semaphore ins, Semaphore outs) {
this.counter = counter;
this.ins = ins;
this.outs = outs;
}
#Override
public void run() {
for (int i = 0; i < 25; i++) {
ins.aquire(); // wait for permission to run
System.out.println("" + counter);
outs.release(); // allow another thread to run
counter += 2;
}
}
Create 2 Semaphores and pass them to 2 threads:
Semaphore a = new Semaphore(1); // first thread is allowed to run immediately
Semaphore b = new Semaphore(0); // second thread has to wait
ThreadPrinter tp1 = new ThreadPrinter(1, a, b);
ThreadPrinter tp2 = new ThreadPrinter(2, b, a);
Note semaphores a and b are passed in different order.

public class Test {
private static int count = 0;
public static void main(String[] args) throws InterruptedException {
Thread t1 = new Thread(new Runnable() {
#Override
public void run() {
for (int i = 0; i < 25; i++) {
synchronized (CommonUtil.mLock) {
incrementCount();
CommonUtil.mLock.notify();
try {
CommonUtil.mLock.wait();
} catch (InterruptedException e) {
// TODO Auto-generated catch block
e.printStackTrace();
}
}
}
}
});
Thread t2 = new Thread(new Runnable() {
#Override
public void run() {
for (int i = 0; i < 25; i++) {
synchronized (CommonUtil.mLock) {
incrementCount();
CommonUtil.mLock.notify();
try {
CommonUtil.mLock.wait();
} catch (InterruptedException e) {
// TODO Auto-generated catch block
e.printStackTrace();
}
}
}
}
});
t1.start();
Thread.sleep(400);
t2.start();
t1.join();
t2.join();
}
private static void incrementCount() {
count++;
System.out.println("Count: " + count + " icnremented by: " + Thread.currentThread().getName());
}
}
class CommonUtil {
static final Object mLock = new Object();
}

I encountered the same problem and was expected to use only basics so I choose wait notify on shared object between threads
public class Message implements Runnable {
private static final int N = 10;
private Thread thread;
private static Object object = new Object();
public Message(String name){
thread = new Thread(this, name);
thread.start();
}
public void run(){
for(int i=0; i<N; i++){
synchronized (object) {
System.out.println(i + "--" + thread.getName());
object.notify();
try {
object.wait();
} catch (InterruptedException e) {
e.printStackTrace();
}
}
}
}
}
In main method :
Message message1 = new Message("Ping");
Message message2 = new Message("Pong");

public class ThreadCounter implements Runnable {
private static int count = 0;
private Thread t;
public ThreadCounter(String tName){
t= new Thread(this, tName);
t.start();
}
#Override
public void run() {
for(int i=1; i<=5; i++){
synchronized (CommonUtil.mLock) {
incrementCount(t.getName());
CommonUtil.mLock.notify();
try {
CommonUtil.mLock.wait();
} catch (InterruptedException e) {
e.printStackTrace();
}
}
}
}
private void incrementCount(String tName){
System.out.println(tName+": "+(++ThreadCounter.count));
}
public static void main(String[] args) throws InterruptedException {
new ThreadCounter("Thread1");
Thread.sleep(500);
new ThreadCounter("Thread2");
}
}
class CommonUtil{
public static Object mLock = new Object();
}

hi please find answer here...pattern ABABABAB
package com.abhi.ThreadPractice;
public class Test {
public static void main(String[] args) throws InterruptedException {
final Object lock = new Object();
Thread t1 = new Thread(new Runnable() {
#Override
public void run() {
for (int i = 0; i < 10; i++) {
synchronized (lock) {
// count++;
System.out.println("A");
try {
lock.wait();
lock.notify();
} catch (InterruptedException e) {
e.printStackTrace();
}
}
}
}
});
Thread t2 = new Thread(new Runnable() {
#Override
public void run() {
for (int i = 0; i < 10; i++) {
synchronized (lock) {
lock.notify();
//count++;
System.out.println("B");
try {
lock.wait();
} catch (InterruptedException e) {
e.printStackTrace();
}
}
}
}
});
t1.start();
t2.start();
t1.join();
t2.join();
}
}

This is another solution:
Thread t1 = new Thread(new Runnable() {
#Override
public void run() {
synchronized (lock) {
for (int i = 1; i <= 50; i += 2) {
System.out.println("T1=" + i);
t1turn = false;
try {
lock.notifyAll();
lock.wait();
} catch (InterruptedException e) {
}
}
}
}
});
Thread t2 = new Thread(new Runnable() {
#Override
public void run() {
synchronized (lock) {
for (int i = 2; i <= 50; i += 2) {
if (t1turn)
try {
lock.wait();
} catch (InterruptedException e) {
}
System.out.println("T2=" + i);
t1turn = true;
lock.notify();
}
}
}
});
t1.start();
t2.start();

May be this is still relevant:
public class MyRunnable implements Runnable {
public static int counter = 0;
public static int turn = 0;
public static Object lock = new Object();
#Override
public void run() {
while (counter < 50) {
synchronized (lock) {
if (turn == 0) {
System.out.println(counter + " from thread "
+ Thread.currentThread().getName());
turn = 1;
try {
lock.wait();
} catch (InterruptedException e) {
Thread.currentThread().interrupt();
}
} else {
turn = 0;
lock.notify();
}
}
}
}
}
and then the main function
public static void main(String[] args) {
Thread threadA = new Thread(new MyRunnable());
Thread threadB = new Thread(new MyRunnable ());
threadA.start();
threadB.start();
}

public class PingPong extends Thread {
static StringBuilder object = new StringBuilder("");
public static void main(String[] args) throws InterruptedException {
Thread t1 = new PingPong();
Thread t2 = new PingPong();
t1.setName("\nping");
t2.setName(" pong");
t1.start();
t2.start();
}
#Override
public void run() {
working();
}
void working() {
while (true) {
synchronized (object) {
try {
System.out.print(Thread.currentThread().getName());
object.notify();
object.wait();
} catch (InterruptedException e) {
e.printStackTrace();
}
}
}
}
}

This was the simplest solution, I was able to think of. It uses a synchronized method and uses the notify() and the wait() to alternatively print the numbers. Hope it helps. :)
public class program implements Runnable
{
static int count =1;
private static final int MAX_COUNT = 50;
public synchronized void print ()
{
System.out.println(Thread.currentThread().getName() + " is printing " + count);
count++;
notify();
try{
if(count>MAX_COUNT)
return;
wait();
}catch (InterruptedException e){
e.printStackTrace();
}
}
public void run()
{
for(int i=0;i<MAX_COUNT/2;i++)
{
print();
}
}
public static void main(String[] args) {
program x= new program();
Thread t0= new Thread(x);
Thread t1= new Thread(x);
t0.start();
try
{
Thread.sleep(1);
} catch (InterruptedException e){
e.printStackTrace();
}
t1.start();
}
}

//simply use wait and notify and and set a counter and it will do
public class ThreadalternatePrint implements Runnable {
static int counter =0;
#Override
public synchronized void run() {
try {
Thread.sleep(10);
} catch (InterruptedException e1) {
// TODO Auto-generated catch block
e1.printStackTrace();
}
while(counter<51)
{ ++counter;
notify();
System.out.println(Thread.currentThread().getName());
try {
wait();
} catch (InterruptedException e) {
// TODO Auto-generated catch block
e.printStackTrace();
}
}
}
public static void main(String[] args) {
ThreadalternatePrint obj1 = new ThreadalternatePrint();
Thread Th1 = new Thread(obj1);
Thread Th2 = new Thread(obj1);
Th1.setName("Thread1");
Th2.setName("Thread2");
Th1.start();
Th2.start();
}
}

public class Testing implements Runnable {
private static int counter = 1;
private static final Object lock = new Object();
public static void main(String[] args) {
Thread t1 = new Thread(new Testing(), "1");
t1.start();
Thread t2 = new Thread(new Testing(), "2");
t2.start();
}
#Override
public void run() {
while (counter<=100) {
synchronized (lock) {
if (counter % 2 == 0) {
System.out.println(counter +" Written By Thread-"+ Thread.currentThread().getName());
counter++;
try {
lock.notifyAll();
lock.wait();
} catch (InterruptedException e) {
e.printStackTrace();
}
} else if (counter % 2 == 1) {
System.out.println(counter +" Written By Thread-"+ Thread.currentThread().getName());
counter++;
try {
lock.notifyAll();
lock.wait();
} catch (InterruptedException e) {
e.printStackTrace();
}
}
}
}
}
}

I have created a pretty basic Solution for it using the Reentrant Lock.
package com.multithreding.trylock;
import java.util.concurrent.locks.ReentrantLock;
public class TryLock extends Thread {
static int intitialCount = 50; //Value till which you want to print
int valueToSubtract = 0; //Value by which difference you want to print the series like 1,2,3
static ReentrantLock alternate = new ReentrantLock();
public TryLock(String name) {
this.setName(name);
}
public void run() {
while (intitialCount > 1) {
if (valueToSubtract > 0) {
alternate.lock();
intitialCount = intitialCount - valueToSubtract;
valueToSubtract = 0;
try {
Thread.sleep(200);
} catch (InterruptedException e) {
// TODO Auto-generated catch block
e.printStackTrace();
}
System.out.println("value Subtracted " + intitialCount + " by the Thread" + this.getName());
alternate.unlock();
} else {
try {
Thread.sleep(100);
} catch (InterruptedException e) {
// TODO Auto-generated catch block
e.printStackTrace();
}
valueToSubtract++;
}
}
}
}
package com.multithreding.trylock;
public class AlternatePrint {
public static void main(String[] args) throws InterruptedException{
//You can add as many thread to print then in different number of series
TryLock t1 = new TryLock("Odd One");
TryLock t2 = new TryLock("Even Value");
t1.start();
t2.start();
}
}
This solution is modular as well,
You can add 'n' number of Threads to print the alternate series. i.e Using 3 thread at once
You can also print the series with more than Difference of more than 1. i.e 1,3,5 etc

package thread;
public class Pingpong extends Thread {
static StringBuilder object = new StringBuilder("");
static int i=1;
#Override
public void run() {
working();
}
void working() {
while (i<=10) {
synchronized (object) {
try {
System.out.println(Thread.currentThread().getName() +" "+ i);
i++;
object.notify();
object.wait();
} catch (InterruptedException e) {
e.printStackTrace();
}
}
}
}
public static void main(String[] args) throws InterruptedException {
Thread t1 = new Pingpong();
Thread t2 = new Pingpong();
t1.setName("Thread1");
t2.setName("Thread2");
t1.start();
t2.start();
}
}
Thread1 1
Thread2 2
Thread1 3
Thread2 4
Thread1 5
Thread2 6
Thread1 7
Thread2 8
Thread1 9
Thread2 10

This answer is generic i.e. not only to print numbers alternately from 2 threads but to execute 2 threads alternately.
The above approaches are commendable but this one doesn't need any lock but instead it uses an AtomicInteger variable alongwith 2 AtomicBooleans to indicate when one thread has finished executing so that the other can finish executing the rest of its remaining execution.
This will work in all 3 cases:
When number of executions of both threads are same.
When first thread finishes before second thread and second thread has more number of executions than first thread.
When second thread finishes before first thread and first thread has more number of executions than second thread.
public class TestAlternateExecutionOfTwoThreads
{
private static final AtomicInteger count = new AtomicInteger(0);
private static final AtomicBoolean firstIsDone = new AtomicBoolean(false);
private static final AtomicBoolean secondIsDone = new AtomicBoolean(false);
// change the below values to change the number of iterations each thread should
// run. In this example, the initial value are hard-coded but you can change
// them as well.
private static final int finalOfFirstThread = 10;
private static final int finalOfSecondThread = 109;
public static void main(String[] args)
{
Runnable r1 = () -> {
int i = 1;
for(; i <= finalOfFirstThread; )
{
while(count.get() == 0)
{
System.out.println(i);
count.incrementAndGet();
i++;
}
if(count.get() == 1 && secondIsDone.get() && i != (finalOfFirstThread + 1))
{
System.out.println(i);
i++;
}
}
firstIsDone.set(true);
};
Runnable r2 = () -> {
int j = 100;
for (; j <= finalOfSecondThread; )
{
while(count.get() == 1)
{
System.out.println(j);
count.decrementAndGet();
j++;
}
if(count.get() == 0 && firstIsDone.get() && j != (finalOfSecondThread + 1))
{
System.out.println(j);
j++;
}
}
secondIsDone.set(true);
};
Thread t1 = new Thread(r1);
Thread t2 = new Thread(r2);
t1.start();
t2.start();
}
}

I guess this might help.
Although it is not standard but i hope it provides a simpler approach.
public class ThreadDemo
{
public static void main (String [] args)
{
PrintDemo pd=new PrintDemo();
MyThread1 mt1 = new MyThread1 ("T1",pd);
MyThread2 mt2 = new MyThread2 ("T2",pd);
mt1.start ();
mt2.start();
}
}
class PrintDemo {
private boolean oddFlag=true;
public synchronized void printOdd(int i,String tName){
if(oddFlag==false){
try {
wait();
} catch (InterruptedException e) {
e.printStackTrace();
}
}else{
System.out.println("\nThread "+tName+" count:"+i);
oddFlag=false;
notify();
}
}
public synchronized void printEven(int i,String tName){
if(oddFlag==true){
try {
wait();
} catch (InterruptedException e) {
e.printStackTrace();
}
}else{
System.out.println("\nThread "+tName+" count:"+i);
oddFlag=true;
notify();
}
}
}
class MyThread1 extends Thread
{
private PrintDemo pd;
private String name;
MyThread1(String threadName,PrintDemo pd){
this.name=threadName;
this.pd=pd;
}
public void run ()
{
for(int i=1;i<=50;i+=2){
pd.printOdd(i,name);
}
}
}
class MyThread2 extends Thread
{
private PrintDemo pd;
private String name;
MyThread2(String threadName,PrintDemo pd){
this.name=threadName;
this.pd=pd;
}
public void run ()
{
for(int i=2;i<=50;i+=2){
pd.printEven(i,name);
}
}
}