I can't make this program show the message "Number out of range" when the user put a number out of (1 - 6). I tried different ways of code, but I don't know what I am doing wrong.
public static void main(String[] args) {
int guess = 0;
int tries = 3;
Scanner input = new Scanner(System.in);
Random ran = new Random();
int diceNumber = ran.nextInt(6)+1;
System.out.println(diceNumber);
System.out.println("Insert a number between 1 and 6 : you have " + tries + " tries.");
guess = input.nextInt();
while((tries >1 && (guess <7 || guess>0))) {
tries--;
System.out.println("Incorrect Number, you have " +tries+ " more tries.");
guess = input.nextInt();
}if(guess >=7 || guess<=0 && (tries >1)){
--tries;
System.out.println("Number out of range, try again; you have " + tries + " more tries.");
guess = input.nextInt();
} if(tries ==0 || guess != diceNumber) {
System.out.println("You Lose!!");
} else if(guess == diceNumber){
System.out.println("You Win!!");
}
}
You need to position the condition to check if the input is a valid input or not at the start of the while loop , currently, it will only be checked after all tries are exhausted as you end the while loop before it.
Also, you should change the while loop condition from (tries >1 && (guess <7 || guess>0)) to (tries > 1 && guess != diceNumber) , since you may not want to exit the loop if the number entered is outside the range.
Code -
public static void main(String[] args) {
int guess = 0;
int tries = 3;
Scanner input = new Scanner(System.in);
Random ran = new Random();
int diceNumber = ran.nextInt(6)+1;
System.out.println(diceNumber);
System.out.println("Insert a number between 1 and 6 : you have " + tries + " tries.");
guess = input.nextInt();
while((tries >1 && guess != diceNumber)) {
if((guess >=7 || guess<=0) && (tries >1)){
--tries;
System.out.println("Number out of range, try again; you have " + tries + " more tries.");
guess = input.nextInt();
}
else {
tries--;
System.out.println("Incorrect Number, you have " +tries+ " more tries.");
guess = input.nextInt();
}
}
if(tries ==0 || guess != diceNumber) {
System.out.println("You Lose!!");
} else if(guess == diceNumber){
System.out.println("You Win!!");
}
}
The below code will fetch you the expected result.
import java.util.Random;
import java.util.Scanner;
public class Dice {
public static void main(String[] args) {
int guess = 0;
int tries = 3;
Scanner input = new Scanner(System.in);
Random ran = new Random();
int diceNumber = ran.nextInt(6) + 1;
System.out.println(diceNumber);
System.out.println("Insert a number between 1 and 6 : you have "
+ tries + " tries.");
guess = input.nextInt();
loop: while ((tries >= 1)) {
--tries;
if ((guess >= 7 || guess <= 0) && (tries >= 1)) {
System.out.println("Number out of range, try again; you have "
+ tries + " more tries.");
guess = input.nextInt();
} else {
if (guess == diceNumber) {
System.out.println("You Win!!");
break loop;
} else if (tries >= 1) {
System.out.println("Incorrect Number, you have " + tries
+ " more tries.");
guess = input.nextInt();
}
}
}
if (tries == 0 && guess != diceNumber) {
System.out.println("You Lose!!");
}
}
}
I think the problem is in your while loop.
I'd say it should be something like this:
while(tries > 0 && guess != diceNumber) {
tries--;
if (guess >= 1 && guess <= 6) {
System.out.println("Incorrect Number, you have " +tries+ " more tries.");
} else if (guess >=7 || guess<=0) {
System.out.println("Number out of range, try again; you have " + tries + " more tries.");
}
if (tries > 0) {
guess = input.nextInt();
}
}
if(tries == 0 || guess != diceNumber) {
System.out.println("You Lose!!");
} else if(guess == diceNumber){
System.out.println("You Win!!");
}
I think this should do what you want.
As you can see, I changed the while condition:
You want the user to be able to enter another number while he has at least 1 try left, so tries>0.
You want the user to enter another number only if guess != diceNumber.
The if conditions inside also change:
You only say it's an incorrect number if the entered number is between 1 and 6: guess >= 1 && guess <= 6.
You only say it's out of range if the number is not between 1 and 6: guess >= 7 || guess <= 0.
You don't need to check the number of tries, the while loop does that already.
You only want to get a new input number if the user as a try left: tries > 0.
Related
import java.util.Random;
import java.util.Scanner;
public class Activity3 {
public static void main(String[] args) {
//Variables
Scanner input = new Scanner(System.in);
Random Machine = new Random();
int num = Machine.nextInt(10);
do {
System.out.println("Guess the random generated number of the machine from 1-10");
int guess = input.nextInt();
if (guess == num) {
System.out.println("Correct number= " + num);
System.out.println("You Win!");
} else if (guess <= 0 && guess >= 11) {
System.out.println("Invalid Number!");
}
if (guess > 1 && guess < 10){
System.out.println("You Lose:<");
}
System.out.println("Do you want to try again?");
} while (input.next().equalsIgnoreCase("YES"));
input.close();
}
}
If I guess the correct number it outputs " you win!".
If I guess wrong it outputs "you lose". But If I guess a number that isn't in 1-10 it doesn't output the "Invalid Number" and just proceeds to output the "Do you want to try again?".
Random#nextInt(int) will return a value from 0 to bound - 1, so it's possible that the guess could be 0 in your code. You'd correct this by adding 1 to the guess, for example int num = Machine.nextInt(10) + 1;
Look at your logic...
else if(guess <= 0 && guess >= 11) {
if guess <= 0 AND guess >= 11 ... well, that's impossible.
I would change your logic flow, focusing on "happy paths" first.
That is, is the input within the acceptable range? If so, is guess == num if so, you win, otherwise print error messages.
For example...
Scanner input = new Scanner(System.in);
Random Machine = new Random();
int num = Machine.nextInt(10) + 1;
boolean done = false;
do {
System.out.println("Guess the random generated number of the machine from 1-10");
// Read the WHOLE line of text, removing the new line from the
// buffer which would otherwise be left by Scanner#nextInt
// and would cause no end of issues
String text = input.nextLine();
try {
// Try and parse the text to an int
int guess = Integer.parseInt(text);
if (guess >= 1 && guess <= 10) {
if (guess == num) {
System.out.println("Correct number= " + num);
System.out.println("You Win!");
num = Machine.nextInt(10) + 1;
System.out.println("Would you like to play another game? (Yes/No)");
} else {
System.out.println("Incorrect, guess again");
System.out.println("Do you want to try again? (Yes/No)");
}
// Prompt the user to try again or play another game
text = input.nextLine();
done = !"yes".equals(text.toLowerCase());
} else {
System.out.println("Out of range");
}
} catch (NumberFormatException exp) {
System.out.println("Not a valid number");
}
} while (!done);
I've been trying to get the last else if statement to execute but I've been unsuccessful any input would help
import java.util.Scanner; // Imports the Scanner class for keyboard input.
import java.util.Random; // Imports the Random class to generate a random number.
public class GuessingGameEC {
public static void main(String[] args) {
// TODO Auto-generated method stub
Random ran = new Random();
int randomNum = ran.nextInt(501);
int Guess = 0;
Scanner keyboard = new Scanner(System.in);
for (int numOfTries = 0; numOfTries <10; numOfTries++) {
{
System.out.println(" " );
System.out.println("Guess what number I'm thinking of between 0 and 500.");
Guess = keyboard.nextInt();
if (Guess == randomNum) {
System.out.println("You guessed the correct number, and it only took you " + numOfTries + " tries." );
break;
}
else if (Guess < randomNum && Guess < 500 && Guess >= 0 && numOfTries != 10) {
System.out.println("Your guess is too low, please try again!" );
}
else if (Guess > randomNum && Guess <= 500 && numOfTries != 10) {
System.out.println("Your guess is too high, please try again!" );
}
else if (Guess > 500 || Guess < 0 ) {
System.out.println("Please pick a number between 0 and 500!" );
}
else if (numOfTries == 10) {
System.out.println(" " );
System.out.println("Sorry, you're out of attempts. The correct number was " + randomNum +"!" );
}
}
}
}
}
As your for loop goes from 0 to 9, the case of numOfTries == 10 will never happen.
I would change your code so that you return when sucessful
if (Guess == randomNum) {
System.out.println("You guessed the correct number, and it only took you " + numOfTries + " tries." );
return;
}
and then after your loop have finished, you can unconditionally print that you failed
Your for loop conditional terminates when numOfTries >= 10. You should put your last block of code outside the for loop.
I am writing a simple java guessing game, the game is supposed to randomly pick a number between 1 and 100 and then after you pick the correct number it asks you if you would like to play again. I know i should be able to use a Do while loop to ask if the user would like to play again, but every time I try I cannot make it work. This is my fully functional program without the do while loop. If someone could help me prompt the user if they would like to play again I would be very thankful. I am still very new to programming.
Also I apologize if the indenting isn't 100% correct.
import java.util.Scanner;
import java.util.Random;
public class GuessingGame
{
public static void main (String [] args)
{
//Variables
Random randomNumber = new Random();
Scanner kbd = new Scanner(System.in);
int computerValue = randomNumber.nextInt(100);
int numberOfTries = 0;
int success = 0;
int guess = 0;
//Logic and While Loop
while (success ==0)
{
System.out.println("please enter an integer betwen 1 and 100 inclusive: ");
guess = kbd.nextInt();
numberOfTries++;
if (guess < 1 || guess > 100){
System.out.println("Invalid input");
}
else if (guess == computerValue){
success++;
System.out.println("Congratulations you won! Your numbers of tries was: " + numberOfTries + " and the number was: " + computerValue);
}
else if (guess < computerValue){
System.out.println("Your guess is too low!");
}
else if (guess > computerValue){
System.out.println("Your guess is too high!");
}
}
}
}
Try this:
while(true) {
computerValue = randomNumber.nextInt(100);
numberOfTries = 0;
while (true) {
System.out.println("please enter an integer betwen 1 and 100 inclusive: ");
guess = kbd.nextInt();
numberOfTries++;
if (guess < 1 || guess > 100) System.out.println("Invalid input");
else if (guess == computerValue) {
System.out.println("Congratulations you won! Your numbers of tries was: " + numberOfTries + " and the number was: " + computerValue);
// leave the first loop
break;
}
else if (guess < computerValue) System.out.println("Your guess is too low!");
else if (guess > computerValue) System.out.println("Your guess is too high!");
}
System.out.println("Do you want to play again? (1:Yes/2:No)");
// if input is not yes leave second loop
if(kbd.nextInt() != 1) break;
}
If you want to use a do while loop this would work.
import java.util.Scanner;
import java.util.Random;
public class GuessingGame {
public static void main(String[] args) {
//Variables
Random randomNumber = new Random();
Scanner kbd = new Scanner(System.in);
int computerValue;
int numberOfTries = 0;
int success = 0;
int guess;
boolean playAgain;
//Logic and While Loop
do {
computerValue = randomNumber.nextInt(100);
guess = 0;
playAgain = false;
while (guess != computerValue) {
System.out.println("Please enter an integer betwen 1 and 100 inclusive: ");
guess = kbd.nextInt();
numberOfTries++;
if (guess < 1 || guess > 100) {
System.out.println("Invalid input");
} else if (guess < computerValue) {
System.out.println("Your guess is too low!");
} else if (guess > computerValue) {
System.out.println("Your guess is too high!");
}
}
success++;
System.out.println("Congratulations you won! Your numbers of tries was: " + numberOfTries + " and the number was: " + computerValue);
System.out.println("Would you like to play again?");
switch (kbd.next()) {
case "yes":
playAgain = true;
break;
default:
break;
}
} while (playAgain);
System.out.println("Goodbye");
}
}
Prompt the user if he wants to play again at
else if (guess == computerValue) {
success++;
System.out.println("Congratulations you won! Your numbers of tries was: " + numberOfTries + " and the number was: " + computerValue);
}
If the user inputs yes success--;
I'm kinda new to java and I was wondering how to loop this code until someone enters -1 and how to add "out of bounds" if the user enters number not between 0-100?
here's my code so far:
import java.util.Scanner;
public class Question2 {
public static void main(String args[]) {
Scanner keyboard = new Scanner(System.in);
int count = 0;
int a = 1 + (int) (Math.random() * 99);
int guess = 0;
System.out.println("Welcome to the Number Guessing Game");
System.out.print("Guess a number between 0 and 100 or enter -1 to end: ");
while (guess != a) {
guess = keyboard.nextInt();
count++;
if (guess > a) {
System.out.print("The number is lower. Try again: ");
}
else if (guess < a) {
System.out.print("The number is higher. Try again: ");
}
else if (guess == a) {
System.out.println("Congratulations. You guessed the number in "
+ count + " tries!");
}
}
}
}
You can check for the bounds within the for loop. In order to stop further checks, you can iterate to the next loop through the continue call. Otherwise, if you actually want to break out of the loop, use the break call (for the -1 case).
while (guess != a) {
guess = keyboard.nextInt();
count++;
if (guess < 0 || guess > 100){
if(guess == -1)
break;
System.out.println("Out of bounds");
continue;
}
if (guess > a) {
System.out.print("The number is lower. Try again: ");
}
else if (guess < a) {
System.out.print("The number is higher. Try again: ");
}
else if (guess == a) {
System.out.println("Congratulations. You guessed the number in "
+ count + " tries!");
}
System.out.println("Thank-you for playing the game!!");
You want to do some code while something is not = to -1. In java, we use
!=
to represent not equal. So, try this code with the do while in mind:
do{
guess = keyboard.nextInt();
count++;
if (guess > a) {
System.out.print("The number is lower. Try again: ");
}
else if (guess < a) {
System.out.print("The number is higher. Try again: ");
}
else if (guess == a) {
System.out.println("Congratulations. You guessed the number in "
+ count + " tries!");
}
}
}
\\Here comes the **while**
} while (guess != a && keyboard.in != -1)
The while states that when guess is not a AND the user has not entered -1. This is the only way that the do can be executed.
Thats it! I suggest you read more about math operations and loops.
Best of luck,
{Rich}
The program will generate the correct output for the first number guess but after the user inputs the second guess, there is no output at all. Please help! THANKS
final int number = (int)((Math.random()*99)+1);
int counter = 0;
System.out.print("Enter a guess between 1 and 100: ");
while (keyboard.nextInt() > number) {
System.out.println("Your guess was too high. Try again.");
counter++;
System.out.print("Enter a guess between 1 and 100: ");
}
while (keyboard.nextInt() < number) {
System.out.println("Your guess was too low. Try again.");
counter++;
System.out.print("Enter a guess between 1 and 100: ");
}
while (keyboard.nextInt() == number) {
System.out.println("Congratulations! Your guess was correct!");
counter++;
System.out.println("I had chosen " + number + " as the target number.");
System.out.println("You guessed it in " + counter + " tries.");
if (counter == 1) {
System.out.println("That was lucky!");
}
if (counter >= 2 || counter <= 4) {
System.out.println("That was amazing!");
}
if (counter == 5 || counter == 6) {
System.out.println("That was good.");
}
if (counter == 7) {
System.out.println("That was OK.");
}
if (counter == 8 || counter == 9) {
System.out.println("That was not very good.");
}
if (counter >= 10) {
System.out.println("This just isn't your game.");
}
you really need to change your design pattern.
Once you fail to satisfy the conditions in 1 of those while loops, you code will never go back.
you should only have 1 while loop for the guessing phase. you code should look like this
while(someCondition)
{
int num = keyboard.nextInt()
if (num > number) {
...
}
else if (num < number) {
...
}
else if (num == number) {
...
}
}
Your while loops should be if statements.
There should be a while loop around (practically) all your code
You code should roughly look like:
while(true) {
// prompt for input
// read input
// break from loop if input is the exit input, eg -1
// check input - essentially change your whiles to ifs
}
This block doesn't seem to work as intended:
while (keyboard.nextInt() > number) {
System.out.println("Your guess was too high. Try again.");
counter++;
System.out.print("Enter a guess between 1 and 100: ");
}
while (keyboard.nextInt() < number) {
System.out.println("Your guess was too low. Try again.");
counter++;
System.out.print("Enter a guess between 1 and 100: ");
}
Assume the user enters -1 and then 101. You'll end up in the next loop. Thus you might want to change it to something like this:
boolean retry = true;
while ( retry ) {
counter++;
int n = keyboard.nextInt();
if( n > number ) {
System.out.println("Your guess was too high. Try again.");
}
else if( n < number ) {
System.out.println("Your guess was too low. Try again.");
}
else {
//number found
retry = false;
}
if( retry ) {
System.out.prnt("Enter a guess between 1 and 100: ");
}
}
There is some problem in how you use the while statement.
Here you can find the correct version of your code:
public static void main(final String[] args) {
final Scanner keyboard = new Scanner(System.in);
final int number = (int) ((Math.random() * 99) + 1);
int counter = 0;
System.out.print("Enter a guess between 1 and 100: ");
int user_number;
do {
user_number = keyboard.nextInt();
if (user_number > number) {
System.out.println("Your guess was too high. Try again.");
System.out.print("Enter a guess between 1 and 100: ");
counter++;
} else if (user_number < number) {
System.out.println("Your guess was too low. Try again.");
System.out.print("Enter a guess between 1 and 100: ");
counter++;
}
} while (user_number != number);
System.out.println("Congratulations! Your guess was correct!");
counter++;
System.out.println("I had chosen " + number + " as the target number.");
System.out.println("You guessed it in " + counter + " tries.");
if (counter == 1) {
System.out.println("That was lucky!");
}
if ((counter >= 2) || (counter <= 4)) {
System.out.println("That was amazing!");
}
if ((counter == 5) || (counter == 6)) {
System.out.println("That was good.");
}
if (counter == 7) {
System.out.println("That was OK.");
}
if ((counter == 8) || (counter == 9)) {
System.out.println("That was not very good.");
}
if (counter >= 10) {
System.out.println("This just isn't your game.");
}
}
while(someCondition)
{
if (keyboard.nextInt() > number) {
...
} else if(keyboard.nextInt() < number) {
...
} else {
...
}
}