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Getting " when trying to replace a character in string [duplicate]

This question already has answers here:
What special characters must be escaped in regular expressions?
(13 answers)
How do you match a caret (^) symbol in regex?
(2 answers)
Carets in Regular Expressions
(2 answers)
Closed 4 years ago.
I want to replace " from a string with ^.
String str = "hello \"there";
System.out.println(str);
String str1 = str.replaceAll("\"", "^");
System.out.println(str1);
String str2= str1.replaceAll("^", "\"");
System.out.println(str2);
and the output is :
hello "there
hello ^there
"hello ^there
why I am getting extra " in start of string and ^ in between string
I am expecting:
hello "there

the replaceAll() method consume a regex for the 1st argument.
the ^ in String str2= str1.replaceAll("^", "\""); will match the starting position within the string.
So if you want the ^ char, write \^
Hope this code can help:
String str2= str1.replaceAll("\\^", "\"");

Try using replace which doesnt use regex
String str2 = str1.replace("^", "\"");

^ means start of a line in regex, you can add two \ before it:
String str2= str1.replaceAll("\\^", "\"");
The first is used to escape for compiling, the second is used to escape for regex.

Since String::replaceAll consumes regular expression you need to convert your search and replacement strings into regular expressions first:
str.replaceAll(Pattern.quote("\""), Matcher.quoteReplacement("^"));

Why do you want to use replaceAll. Is there any specific reason ?
If you can use replace function then try below
String str2= str1.replace("^", "\"");

Replace String ignoring case in Java [duplicate]

This question already has answers here:
How to replace case-insensitive literal substrings in Java
(10 answers)
Closed 7 years ago.
String Checkout = D:\ifs\APP\Checkout
String DeleteLine = D:\IFS\APP\Checkout\trvexp\client\Ifs.App\text.txt
Note the ifs and IFS in both Strings.
I want to replace the Checkout String in the Deleted Line
So the final String would look like this:
\trvexp\client\Ifs.App\text.txt
Following is what I have tried, but obviously due to Case Sensitivity, the string won't get replaced. Any Solution or a work around for this?
String final = DeleteLine.replace(Checkout, "");

String.replace() doesn't support regex. You need String.replaceAll().
DeleteLine.replaceAll("(?i)" + Pattern.quote(Checkout), "");

Put (?i) in the replaceAll method's regular expression:
String finalString = DeleteLine.replaceAll("(?i)" + Checkout, "");

You can do this:
String Checkout = "D:\\\\ifs\\\\APP\\\\Checkout";
String DeleteLine = "D:\\IFS\\APP\\Checkout\\trvexp\\client\\Ifs.App\\text.txt";
String f = DeleteLine.replaceFirst("(?i)"+Checkout, "");

Alternatively, if youi want the pattern on a specific portion you can do it manually. You can declare the checkout Sting as:
String Checkout= \Q(?i)D:\ifs\APP\Checkout\E
as
\Q means "start of literal text"
\E means"end of literal text"
and then do the replace
String final = DeleteLine.replace(Checkout, "");

JAVA string split with regex ("||") cannot be used? [duplicate]

This question already has answers here:
Splitting a Java String by the pipe symbol using split("|")
(7 answers)
Closed 7 years ago.
I have a string like |serialNo|checkDelta?|checkFuture?|checkThis?|.
Now I am using the following code to split the string.
String[] splitString = str.split("|");
but when I use this I get array of string that contains each and every character, whereas I need string which contains letter like serialNo, checkDelta?, checkFuture?, checkthis?.
How to get these? Am I missing something?

You'll have to escape your pipe character (split takes a regular expression as argument and therefore "|" is a control character):
str.split("\\|");
Please note: the resulting array contains an empty string at the beginning since you have "|" at start of your string.

You are using a special character and will have to escape it: str.split("\\|");

Use StringTokenizer..
String str="|serialNo|checkDelta?|checkFuture?|checkThis?|"
StringTokenizer st=new StringTokenizer(str,"|",false);
String s1 = st.nextToken();
String s2 = st.nextToken();
String s3 = st.nextToken();
String s4 = st.nextToken();
s1=serialNo
s2=checkDelta?
s3=checkFuture?
s4=checkThis?
Refer to javadocs for reading about StringTokenizer
http://download.oracle.com/javase/1.4.2/docs/api/java/util/StringTokenizer.html

How to replace all numbers in java string

I have string like this String s="ram123",d="ram varma656887"
I want string like ram and ram varma so how to seperate string from combined string
I am trying using regex but it is not working
PersonName.setText(cursor.getString(cursor.getColumnIndex(cursor
.getColumnName(1))).replaceAll("[^0-9]+"));

The correct RegEx for selecting all numbers would be just [0-9], you can skip the +, since you use replaceAll.
However, your usage of replaceAll is wrong, it's defined as follows: replaceAll(String regex, String replacement). The correct code in your example would be: replaceAll("[0-9]", "").

You can use the following regex: \d for representing numbers. In the regex that you use, you have a ^ which will check for any characters other than the charset 0-9
String s="ram123";
System.out.println(s);
/* You don't need the + because you are using the replaceAll method */
s = s.replaceAll("\\d", ""); // or you can also use [0-9]
System.out.println(s);

To remove the numbers, following code will do the trick.
stringname.replaceAll("[0-9]","");

Please do as follows
String name = "ram varma656887";
name = name.replaceAll("[0-9]","");
System.out.println(name);//ram varma
alternatively you can do as
String name = "ram varma656887";
name = name.replaceAll("\\d","");
System.out.println(name);//ram varma
also something like given will work for you
String given = "ram varma656887";
String[] arr = given.split("\\d");
String data = new String();
for(String x : arr){
data = data+x;
}
System.out.println(data);//ram varma

i think you missed the second argument of replace all. You need to put a empty string as argument 2 instead of actually leaving it empty.
try
replaceAll(<your regexp>,"")

you can use Java - String replaceAll() Method.
This method replaces each substring of this string that matches the given regular expression with the given replacement.
Here is the syntax of this method:
public String replaceAll(String regex, String replacement)
Here is the detail of parameters:
regex -- the regular expression to which this string is to be matched.
replacement -- the string which would replace found expression.
Return Value:
This method returns the resulting String.
for your question use this
String s = "ram123", d = "ram varma656887";
System.out.println("s" + s.replaceAll("[0-9]", ""));
System.out.println("d" + d.replaceAll("[0-9]", ""));

How to split a string on | (pipe) in Java [duplicate]

This question already has answers here:
Splitting a Java String by the pipe symbol using split("|")
(7 answers)
Closed 7 years ago.
I have a string like |serialNo|checkDelta?|checkFuture?|checkThis?|.
Now I am using the following code to split the string.
String[] splitString = str.split("|");
but when I use this I get array of string that contains each and every character, whereas I need string which contains letter like serialNo, checkDelta?, checkFuture?, checkthis?.
How to get these? Am I missing something?

You'll have to escape your pipe character (split takes a regular expression as argument and therefore "|" is a control character):
str.split("\\|");
Please note: the resulting array contains an empty string at the beginning since you have "|" at start of your string.

You are using a special character and will have to escape it: str.split("\\|");

Use StringTokenizer..
String str="|serialNo|checkDelta?|checkFuture?|checkThis?|"
StringTokenizer st=new StringTokenizer(str,"|",false);
String s1 = st.nextToken();
String s2 = st.nextToken();
String s3 = st.nextToken();
String s4 = st.nextToken();
s1=serialNo
s2=checkDelta?
s3=checkFuture?
s4=checkThis?
Refer to javadocs for reading about StringTokenizer
http://download.oracle.com/javase/1.4.2/docs/api/java/util/StringTokenizer.html