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how to read string upto certain comma with java

i need to read a file upto certain comma,for example;
String s=hii,lol,wow,and,finally
need output as hii,lol,wow,and
Dont want last comma followed with characters
As my code is reading last comma string
Example:iam getting my code out put as: finally
Below is my code
please guide me
File file =new File("C:/Users/xyz.txt");
FileInputStream inputStream = new FileInputStream(file);
String filke = IOUtils.toString(inputStream);
String[] pieces = filke.split("(?=,)");
String answer = Arrays.stream(pieces).skip(pieces.length - 1).collect(Collectors.joining());
String www=answer.substring(1);
System.out.format("Answer = \"%s\"%n", www);

You don't necessarily need to use regex for this. Just get the index of the last ',' and get the substring from 0 to that index:
String answer = "hii,lol,wow,and,finally";
String www = answer.substring(0, answer.lastIndexOf(','));
System.out.println(www); // prints hii,lol,wow,and

String in Java has a method called lastIndexOf(String str). That might come in handy for you.
Say your input is String s = "hii,lol,wow,and,finally";
You can do a String operation like:
String s = "hii,lol,wow,and,finally";
s = s.substring(0, s.lastIndexOf(","));
This gives you the output: hii,lol,wow,and

If you want to use java 8 stream to do it for you maybe try filter ?
String answer = Arrays.stream(pieces).filter(p -> !Objects.equals(p, pieces[pieces.length-1])).collect(Collectors.joining());
this will print Answer = "hii,lol,wow,and"

To have stricly regex you can use the Pattern.compile and Matcher
Pattern.compile("\w+(?=,)");
Matcher matcher = pattern.matcher(filke);
while (matcher.find()) {
System.out.println(matcher.group(1) + ","); // regex not good enough, maybe someone can edit it to include , (comma)
}
Will match hii, lol, wow, and,
See the regex example here https://regex101.com/r/1iZDjg/1

How to get multi sub strings from String, Android/Java

I know there are similar questions regarding to this. However, I tried many solutions and it just does not work for me.
I need help to extract multiple substrings from a string:
String content = "Ben Conan General Manager 90010021 benconan#gmail.com";
Note: The content in the String may not be always in this format, it may be all jumbled up.
I want to extract the phone number and email like below:
1. 90010021
2. benconan#gmail.com
In my project, I was trying to get this result and then display it into 2 different EditText.
I have tried using pattern and matcher class but it did not work.
I can provide my codes here if requested, please help me ~
--------------------EDIT---------------------
Below is my current method which only take out the email address:
private static final String EMAIL_PATTERN =
"[a-zA-Z0-9\\+\\.\\_\\%\\-\\+]{1,256}" +
"\\#" +
"[a-zA-Z0-9][a-zA-Z0-9\\-]{0,64}" +
"(" +
"\\." +
"[a-zA-Z0-9][a-zA-Z0-9\\-]{0,25}" +
")+";
public String EmailValidator(String email) {
Pattern pattern = Pattern.compile(EMAIL_PATTERN);
Matcher matcher = pattern.matcher(email);
if (matcher.find()) {
return email.substring(matcher.start(), matcher.end());
} else {
// TODO handle condition when input doesn't have an email address
}
return email;
}

You can separate your string into arraylist like this
String str = "Ben Conan, General Manager, 90010021, benconan#gmail.com";
List<String> List = Arrays.asList(str.split(" "));

maybe you should do this instead of yours :
String[] Stringnames = new String[5]
Stringnames [0] = "your phonenumber"
Stringnames[1] = "your email"
System.out.println(stringnames)
Or :
String[] Stringnames = new String[2]
String[] Stringnames = {"yournumber","your phonenumber"};
System.out.println(stringnames [1]);

String.split(...) is a java method for that.
EXAMPLE:
String content = "Ben Conan, General Manager, 90010021, benconan#gmail.com";
String[] selection = content.split(",");
System.out.println(selection[0]);
System.out.println(selection[3]);
BUT if you want to do a Regex then take a look at this:
https://stackoverflow.com/a/16053961/982161

Try this regex for phone number
[\d+]{8} ---> 8 represents number of digits in phone number
You can use
[\d+]{8,} ---> if you want the number of more than 8 digits
Use appropriate JAVA functions for matching. You can try the results here
http://regexr.com/
For email, it depends whether the format is simple or complicated. There is a good explanation here
http://www.regular-expressions.info/index.html

Showing email address as hint

I have seen Mail services displays the email id's as e*****e#gmail.com , mostly in their recovery page.
So i am trying to replace the example#gmail.com as e*****e#gmail.com .
Is it possible to achieve it using String#replace(String) alone ? or should i use some REGEX to achieve it .
Thanks for your valuable suggestions in adavance

Search regex:
\b(\w)\S*?(\S)(?=#)(\S+)\b
Replacement Pattern:
$1****$2$3****$4
RegEx Demo
Code:
String email = "anexample#gmail.com";
String repl = email.replaceFirst("\\b(\\w)\\S*?(\\S#)(\\S)\\S*(\\S\\.\\S*)\\b",
"$1****$2$3****$4");
//=> a****e#g****l.com

You can try without regex too
String email = "example#gmail.com";
int start = 1;
int end = email.indexOf("#") - 1;
StringBuilder sb = new StringBuilder(email);
StringBuilder sb1=new StringBuilder();
for(int i=start;i<end;i++){
sb1.append("*");
}
sb.replace(start, end, sb1.toString());
System.out.println(sb.toString());
Out put:
e*****e#gmail.com

It could be possible through replaceAll function.
(?<!^).(?=.*?.#)
Use the above regex and replace the matched characters with *
DEMO
String s = "example#gmail.com";
System.out.println(s.replaceAll("(?<!^).(?=.*?.#)", "*"));
Output:
e*****e#gmail.com
Update:
Use the below regex to get the output like e*****e#g***l.com
String s = "example#gmail.com";
System.out.println(s.replaceAll("\\B.\\B(?=.*?\\.)", "*"));
Output:
e*****e#g***l.com

I sugges to use indexOf and substring. With replace you can run into tuble with emails like gmail#gmail.com

I want to check if a word or a set of words exists in a String

My requirement is to check if a group of words or a single word is present in a larger string. I tried using String.contains() method but this fails in case the larger string has new line character. Currently I am using a regex mentioned below. But this works for only one word. The searched text is a user entered value and can contain more than one word. This is an android application.
String regex = ".*.{0}" + searchText + ".{0}.*";
Pattern pattern = Pattern.compile(regex);
pattern.matcher(largerString).find();
Sample String
String largerString ="John writes about this, and John writes about that," +
" and John writes about everything. ";
String searchText = "about this";

Why not just replace line breaks with spaces, and on top of that, convert it all to lower case?
String s = "hello";
String originalString = "Does this contain \n Hello?";
String formattedString = originalString.toLowerCase().replace("\n", " ");
System.out.println(formattedString.contains(s));
Edit: Thinking about it, I don't really understand how line breaks make a difference...
Edit 2: I was right. Line breaks don't matter.
String s = "hello";
String originalString = "Does this contain \nHello?";
String formattedString = originalString.toLowerCase();
System.out.println(formattedString.contains(s));

here is code not using regex.
String largerString = "John writes about this, and John writes about that," +" and John writes about everything. ";
String searchText = "about this";
Pattern pattern = Pattern.compile(searchText);
Matcher m = pattern.matcher(largerString);
if(m.find()){
System.out.println(m.group().toString());
}
Result:
about this
I hope it will help you.

How to remove " " from java string

I have a java string with " " from a text file the program accesses with a Buffered Reader object. I have tried string.replaceAll(" ","") and it doesn't seem to work.
Any ideas?
cleaned = cleaned.replace(" "," ");

cleaned = cleaned.replace("\u00a0","")

This is a two step process:
strLineApp = strLineApp.replaceAll("&"+"nbsp;", " ");
strLineApp = strLineApp.replaceAll(String.valueOf((char) 160), " ");
This worked for me. Hope it helps you too!

The same way you mentioned:
String cleaned = s.replace(" "," ");
It works for me.

There's a ready solution to unescape HTML from Apache commons:
StringEscapeUtils.unescapeHtml("")
You can also escape HTML if you want:
StringEscapeUtils.escapeHtml("")

Strings are immutable so You need to do
string = string.replaceAll(" ","")

You can use JSoup library:
String date = doc.body().getElementsByClass("Datum").html().toString().replaceAll(" ","").trim();

String.replace(char, char) takes char inputs (or CharSequence inputs)
String.replaceAll(String, String) takes String inputs and matches by regular expression.
For example:
String origStr = "bat";
String newStr = str.replace('a', 'i');
// Now:
// origStr = "bat"
// newStr = "bit"
The key point is that the return value contains the new edited String. The original String variable that invokes replace()/replaceAll() doesn't have its contents changed.
For example:
String origStr = "how are you?";
String newStr = origStr.replaceAll(" "," ");
String anotherStr = origStr.replaceAll(" ","");
// origStr = "how are you?"
// newStr = "how are you?"
// anotherStr = howareyou?"

We can have a regular expression check and replace HTML nbsp;
input.replaceAll("[\\s\\u00A0]+$", "") + "");
It removes non breaking spaces in the input string.

My solution is the following, and only this worked for me:
String string = stringWithNbsp.replaceAll("NNBSP", "");

Strings in Java are immutable. You have to do:
String newStr = cleaned.replaceAll(" ", "");

I encountered the same problem: The inner HTML of the element I needed had "&nbsp" and my assertion failed.
Since the question has not accepted any answer,yet I would suggest the following, which worked for me
String string = stringwithNbsp.replaceAll("\n", "");
P.S : Happy testing :)