I have source code for QR code generation using Java.
I don't know how to run Java in command prompt.
two jar files
E:\QR Code\lib\core-2.2.jar
E:\QR Code\lib\javase-2.2.jar
Java code path
E:\QR Code\src\com\javapapers\java\QRCode.java
Source code
http://javapapers.com/core-java/java-qr-code
Explain me how to run the java in command prompt
Regards
Karthikeyan K
To make sure that Windows can find the Java compiler and interpreter:
Select Start -> Computer -> System Properties -> Advanced system settings Environment Variables -> System variables -> PATH. ...
Prepend C:\Program Files\Java\jdk1.6.0_27\bin; to the beginning of the PATH variable.
Click OK
Then open command prompt and check if Java path setup done by below command
java -version
If everything ok it will show you which Java version you have installed .
then you can run java program Like below a example
C:\test> javac HelloWorld.java
I have test folder and it have HelloWorld.java file inside it after this
C:\test> java HelloWorld
It will give you output in my file i have added below content
public class HelloWorld{
public static void main(String[] args) {
System.out.println("Hello, World!");
}
}
Related
When you write a simple Java Application in Eclipse in automatically compiles those files and stores them in the bin/ folder of the root folder of the project.
Now if I navigate to the /bin folder and to the folder that contains the .class file I want to run via the java command below I am getting the following error - :
java A
Error: Could not find or load main class A
Class A:
package assurance;
public class A {
public static void main(String[] args) {
System.out.println("Hello World");
}
}
While the class A has a main method and runs fine when I right click on the file and do a Run As Java Application. But it does not run from the command like java command.
Why is this happening ?
Update:
Tried with the following commands-:
java -cp "A.class" assurance.A
java -cp "A" assurance.A
java -cp "*" assurance.A
It works in Eclipse, because Eclipse just runs it with correct -cp and correct command :)
Run your code with the following command:
java -cp "./" assurance.A ("" for some odd cmd interpreters like Windows XP)
it is important that the command is run from the "default package" directory (top-level package directory).
Java interprets package name (assurance) as directory path to the class file. Imagine if it replaces . with / and adds .class extension
(assurance.A => ./assurance/A.class)
More details here: http://docs.oracle.com/javase/7/docs/technotes/tools/windows/classpath.html
I'm trying to execute a Java program from the command line in Windows. Here is my code:
import java.io.File;
import java.io.FileInputStream;
import java.io.FileOutputStream;
import java.io.IOException;
import java.io.InputStream;
import java.io.OutputStream;
public class CopyFile
{
public static void main(String[] args)
{
InputStream inStream = null;
OutputStream outStream = null;
try
{
File afile = new File("input.txt");
File bfile = new File("inputCopy.txt");
inStream = new FileInputStream(afile);
outStream = new FileOutputStream(bfile);
byte[] buffer = new byte[1024];
int length;
// copy the file content in bytes
while ((length = inStream.read(buffer)) > 0)
{
outStream.write(buffer, 0, length);
}
inStream.close();
outStream.close();
System.out.println("File is copied successful!");
}
catch (IOException e)
{
e.printStackTrace();
}
}
}
I'm not sure how to execute the program - any help? Is this possible on Windows? Why is it different than another environment (I thought JVM was write once, run anywhere)?
Source: javaindos.
Let's say your file is in C:\mywork\
Run Command Prompt
C:\> cd \mywork
This makes C:\mywork the current directory.
C:\mywork> dir
This displays the directory contents. You should see
filenamehere.java among the files.
C:\mywork> set path=%path%;C:\Program Files\Java\jdk1.5.0_09\bin
This tells the system where to find JDK programs.
C:\mywork> javac filenamehere.java
This runs javac.exe, the compiler. You should see nothing but the
next system prompt...
C:\mywork> dir
javac has created the filenamehere.class file. You should see
filenamehere.java and filenamehere.class among the files.
C:\mywork> java filenamehere
This runs the Java interpreter. You should then see your program
output.
If the system cannot find javac, check the set path command. If javac
runs but you get errors, check your Java text. If the program
compiles but you get an exception, check the spelling and
capitalization in the file name and the class name and the java
HelloWorld command. Java is case-sensitive!
To complete the answer :
The Java File
TheJavaFile.java
Compile the Java File to a *.class file
javac TheJavaFile.java
This will create a TheJavaFile.class file
Execution of the Java File
java TheJavaFile
Creation of an executable *.jar file
You've got two options here -
With an external manifest file :
Create the manifest file say - MANIFEST.mf
The MANIFEST file is nothing but an explicit entry of the Main Class
jar -cvfm TheJavaFile.jar MANIFEST.mf TheJavaFile.class
Executable by Entry Point:
jar -cvfe TheJavaFile.jar <MainClass> TheJavaFile.class
To run the Jar File
java -jar TheJavaFile.jar
Complile a Java file to generate a class:
javac filename.java
Execute the generated class:
java filename
In case your Java class is in some package. Suppose your Java class named ABC.java is present in com.hello.programs, then you need to run it with the package name.
Compile it in the usual way:
C:\SimpleJavaProject\src\com\hello\programs > javac ABC.java
But to run it, you need to give the package name and then your java class name:
C:\SimpleJavaProject\src > java com.hello.programs.ABC
Since Java 11, java command line tool has been able to run a single-file source-code directly. e.g.
java HelloWorld.java
This was an enhancement with JEP 330: https://openjdk.java.net/jeps/330
For the details of the usage and the limitations, see the manual of your Java implementation such as one provided by Oracle: https://docs.oracle.com/en/java/javase/11/tools/java.html
Assuming the file is called "CopyFile.java", do the following:
javac CopyFile.java
java -cp . CopyFile
The first line compiles the source code into executable byte code. The second line executes it, first adding the current directory to the class path (just in case).
It is easy. If you have saved your file as A.text first thing you should do is save it as A.java. Now it is a Java file.
Now you need to open cmd and set path to you A.java file before compile it. you can refer this for that.
Then you can compile your file using command
javac A.java
Then run it using
java A
So that is how you compile and run a java program in cmd.
You can also go through these material that is Java in depth lessons. Lot of things you need to understand in Java is covered there for beginners.
You can compile any java source using javac in command line ; eg, javac CopyFile.java.
To run : java CopyFile.
You can also compile all java files using javac *.java as long as they're in the same directory
If you're having an issue resulting with "could not find or load main class" you may not have
jre in your path. Have a look at this question:
Could not find or load main class
On Windows 7 I had to do the following:
quick way
Install JDK http://www.oracle.com/technetwork/java/javase/downloads
in windows, browse into "C:\Program Files\Java\jdk1.8.0_91\bin" (or wherever the latest version of JDK is installed), hold down shift and right click on a blank area within the window and do "open command window here" and this will give you a command line and access to all the BIN tools. "javac" is not by default in the windows system PATH environment variable.
Follow comments above about how to compile the file ("javac MyFile.java" then "java MyFile") https://stackoverflow.com/a/33149828/194872
long way
Install JDK http://www.oracle.com/technetwork/java/javase/downloads/index.html
After installing, in edits the Windows PATH environment variable and adds the following to the path C:\ProgramData\Oracle\Java\javapath. Within this folder are symbolic links to a handful of java executables but "javac" is NOT one of them so when trying to run "javac" from Windows command line it throws an error.
I edited the path: Control Panel -> System -> Advanced tab -> "Environment Variables..." button -> scroll down to "Path", highlight and edit -> replaced the "C:\ProgramData\Oracle\Java\javapath" with a direct path to the java BIN folder "C:\Program Files\Java\jdk1.8.0_91\bin".
This likely breaks when you upgrade your JDK installation but you have access to all the command line tools now.
Follow comments above about how to compile the file ("javac MyFile.java" then "java MyFile") https://stackoverflow.com/a/33149828/194872
STEP 1: FIRST OPEN THE COMMAND PROMPT WHERE YOUR FILE IS LOCATED. (right click while pressing shift)
STEP 2: THEN USE THE FOLLOWING COMMANDS TO EXECUTE.
(lets say the file and class name to be executed is named as Student.java)The example program is in the picture background.
javac Student.java
java Student
As of Java 9, the JDK includes jshell, a Java REPL.
Assuming the JDK 9+ bin directory is correctly added to your path, you will be able to simply:
Run jshell File.java — File.java being your file of course.
A prompt will open, allowing you to call the main method: jshell> File.main(null).
To close the prompt and end the JVM session, use /exit
Full documentation for JShell can be found here.
Now (with JDK 9 onwards), you can just use java to get that executed.
In order to execute "Hello.java" containing the main, one can use:
java Hello.java
You do not need to compile using separately using javac anymore.
You can actually run Java program as you would shell or python scripts without manually compile the Java file, as described in
JEP 330. That is available since JDK 11.
If you create a file testing, and put the following you should be able to run it as command testing. You need to make it executable in Linux and Mac OSX with chmod +x testing.
#!/usr/bin/env java --source 11
public class Test {
public static void main(String [] args) {
System.out.println("Hello world!");
System.exit(0);
}
}
You are not allowed to use the file extension .java in the previous example.
$ chmod +x testing
$ ./testing
Hello world!
$
But you can still execute if it is was name Test.java without the shebang "#!" prefix like this:
public class Test {
public static void main(String [] args) {
System.out.println("Hello again!");
System.exit(0);
}
}
Then execute the file Test.java with following command:
$ java Test.java
Hello again!
$
So this works as long as you have a new enough Java compiler in the path, check with java -version. More information in this blog.
Thank you for your replays.
I'm writing this code using eclipse on ububntu OS.
this is my code:
public class test{
public static void main (String[] args){
System.out.print("Hello world");
}
}
Then make it by using eclipse export JAR Executable file.
I run the code under ubuntu terminal like this:
java -jar test.jar
so I got the Hello world string, and this is the result:
Screen shot on ubuntu
And running the same command on the command prompt of windwos 8.1 x86.
java -jar test.jar
And the result is this: Result on windows
Thank you again for helping.
This might be the classpath issue , use below code to run. -verbose will print you the execution details.
set classpath=.;
java -verbose -jar helloworld.jar
Please show us your code and the way you run it.
First idea: make sure you run your code on the command line:
open DOS box
cd to the directory where your .jar file is
java -jar helloworld.jar
You might not see any console output if you double-click the .jar file
I'm trying to execute a Java program from the command line in Windows. Here is my code:
import java.io.File;
import java.io.FileInputStream;
import java.io.FileOutputStream;
import java.io.IOException;
import java.io.InputStream;
import java.io.OutputStream;
public class CopyFile
{
public static void main(String[] args)
{
InputStream inStream = null;
OutputStream outStream = null;
try
{
File afile = new File("input.txt");
File bfile = new File("inputCopy.txt");
inStream = new FileInputStream(afile);
outStream = new FileOutputStream(bfile);
byte[] buffer = new byte[1024];
int length;
// copy the file content in bytes
while ((length = inStream.read(buffer)) > 0)
{
outStream.write(buffer, 0, length);
}
inStream.close();
outStream.close();
System.out.println("File is copied successful!");
}
catch (IOException e)
{
e.printStackTrace();
}
}
}
I'm not sure how to execute the program - any help? Is this possible on Windows? Why is it different than another environment (I thought JVM was write once, run anywhere)?
Source: javaindos.
Let's say your file is in C:\mywork\
Run Command Prompt
C:\> cd \mywork
This makes C:\mywork the current directory.
C:\mywork> dir
This displays the directory contents. You should see
filenamehere.java among the files.
C:\mywork> set path=%path%;C:\Program Files\Java\jdk1.5.0_09\bin
This tells the system where to find JDK programs.
C:\mywork> javac filenamehere.java
This runs javac.exe, the compiler. You should see nothing but the
next system prompt...
C:\mywork> dir
javac has created the filenamehere.class file. You should see
filenamehere.java and filenamehere.class among the files.
C:\mywork> java filenamehere
This runs the Java interpreter. You should then see your program
output.
If the system cannot find javac, check the set path command. If javac
runs but you get errors, check your Java text. If the program
compiles but you get an exception, check the spelling and
capitalization in the file name and the class name and the java
HelloWorld command. Java is case-sensitive!
To complete the answer :
The Java File
TheJavaFile.java
Compile the Java File to a *.class file
javac TheJavaFile.java
This will create a TheJavaFile.class file
Execution of the Java File
java TheJavaFile
Creation of an executable *.jar file
You've got two options here -
With an external manifest file :
Create the manifest file say - MANIFEST.mf
The MANIFEST file is nothing but an explicit entry of the Main Class
jar -cvfm TheJavaFile.jar MANIFEST.mf TheJavaFile.class
Executable by Entry Point:
jar -cvfe TheJavaFile.jar <MainClass> TheJavaFile.class
To run the Jar File
java -jar TheJavaFile.jar
Complile a Java file to generate a class:
javac filename.java
Execute the generated class:
java filename
In case your Java class is in some package. Suppose your Java class named ABC.java is present in com.hello.programs, then you need to run it with the package name.
Compile it in the usual way:
C:\SimpleJavaProject\src\com\hello\programs > javac ABC.java
But to run it, you need to give the package name and then your java class name:
C:\SimpleJavaProject\src > java com.hello.programs.ABC
Since Java 11, java command line tool has been able to run a single-file source-code directly. e.g.
java HelloWorld.java
This was an enhancement with JEP 330: https://openjdk.java.net/jeps/330
For the details of the usage and the limitations, see the manual of your Java implementation such as one provided by Oracle: https://docs.oracle.com/en/java/javase/11/tools/java.html
Assuming the file is called "CopyFile.java", do the following:
javac CopyFile.java
java -cp . CopyFile
The first line compiles the source code into executable byte code. The second line executes it, first adding the current directory to the class path (just in case).
It is easy. If you have saved your file as A.text first thing you should do is save it as A.java. Now it is a Java file.
Now you need to open cmd and set path to you A.java file before compile it. you can refer this for that.
Then you can compile your file using command
javac A.java
Then run it using
java A
So that is how you compile and run a java program in cmd.
You can also go through these material that is Java in depth lessons. Lot of things you need to understand in Java is covered there for beginners.
You can compile any java source using javac in command line ; eg, javac CopyFile.java.
To run : java CopyFile.
You can also compile all java files using javac *.java as long as they're in the same directory
If you're having an issue resulting with "could not find or load main class" you may not have
jre in your path. Have a look at this question:
Could not find or load main class
On Windows 7 I had to do the following:
quick way
Install JDK http://www.oracle.com/technetwork/java/javase/downloads
in windows, browse into "C:\Program Files\Java\jdk1.8.0_91\bin" (or wherever the latest version of JDK is installed), hold down shift and right click on a blank area within the window and do "open command window here" and this will give you a command line and access to all the BIN tools. "javac" is not by default in the windows system PATH environment variable.
Follow comments above about how to compile the file ("javac MyFile.java" then "java MyFile") https://stackoverflow.com/a/33149828/194872
long way
Install JDK http://www.oracle.com/technetwork/java/javase/downloads/index.html
After installing, in edits the Windows PATH environment variable and adds the following to the path C:\ProgramData\Oracle\Java\javapath. Within this folder are symbolic links to a handful of java executables but "javac" is NOT one of them so when trying to run "javac" from Windows command line it throws an error.
I edited the path: Control Panel -> System -> Advanced tab -> "Environment Variables..." button -> scroll down to "Path", highlight and edit -> replaced the "C:\ProgramData\Oracle\Java\javapath" with a direct path to the java BIN folder "C:\Program Files\Java\jdk1.8.0_91\bin".
This likely breaks when you upgrade your JDK installation but you have access to all the command line tools now.
Follow comments above about how to compile the file ("javac MyFile.java" then "java MyFile") https://stackoverflow.com/a/33149828/194872
STEP 1: FIRST OPEN THE COMMAND PROMPT WHERE YOUR FILE IS LOCATED. (right click while pressing shift)
STEP 2: THEN USE THE FOLLOWING COMMANDS TO EXECUTE.
(lets say the file and class name to be executed is named as Student.java)The example program is in the picture background.
javac Student.java
java Student
As of Java 9, the JDK includes jshell, a Java REPL.
Assuming the JDK 9+ bin directory is correctly added to your path, you will be able to simply:
Run jshell File.java — File.java being your file of course.
A prompt will open, allowing you to call the main method: jshell> File.main(null).
To close the prompt and end the JVM session, use /exit
Full documentation for JShell can be found here.
Now (with JDK 9 onwards), you can just use java to get that executed.
In order to execute "Hello.java" containing the main, one can use:
java Hello.java
You do not need to compile using separately using javac anymore.
You can actually run Java program as you would shell or python scripts without manually compile the Java file, as described in
JEP 330. That is available since JDK 11.
If you create a file testing, and put the following you should be able to run it as command testing. You need to make it executable in Linux and Mac OSX with chmod +x testing.
#!/usr/bin/env java --source 11
public class Test {
public static void main(String [] args) {
System.out.println("Hello world!");
System.exit(0);
}
}
You are not allowed to use the file extension .java in the previous example.
$ chmod +x testing
$ ./testing
Hello world!
$
But you can still execute if it is was name Test.java without the shebang "#!" prefix like this:
public class Test {
public static void main(String [] args) {
System.out.println("Hello again!");
System.exit(0);
}
}
Then execute the file Test.java with following command:
$ java Test.java
Hello again!
$
So this works as long as you have a new enough Java compiler in the path, check with java -version. More information in this blog.
I have done a lot of researching on this concept but I can't seem to run a java program on the command prompt. Let's say we had a simple program like this:
public class Hello_World {
public static void main(String[] args) {
System.out.println("Hello World!");
}
}
On the command prompt I tried:
javac Hello_World.java
But I get:
'javac' is not recognized as an internal or external command, operable program or batch file
So I compiled it on BlueJ and then did this:
java Hello_World.java
But it said "cannot load or find main class Hello_World"!
I am currently using Windows 7, and made the programs on Notepad++ and BlueJ (to compile).
Any suggestions? Thanks!
This explains in detail what you have to do to set class path. Primarily you need to set your environment variables so that your shell finds the right directory containing javac to compile your program
javac' is not recognized ..
comes when you haven't point your java bin directory to your path environment variable. Because bin directory is the place where javac.exe exist.
To do it.
1) right click on mycomputer property
2) go to Advance system settings.
3) go to environment variable.
4) In system variable click on path
5) go to edit mode and provide your path to java bin directory.
in my case it is C:\Program Files\Java\jdk1.7.0_01\bin;
'javac' is not recognized as an internal...
means OS does not know where javac program is located. Either add it to PATH or run explicitly
my\path\to\file\javac Hello_World.java
Compiling will convert *.java to *.class
Hello_World.class file should be located according to it's package directive. Since you have no one, in your case it should be located in the same directory you will run java.
To run your class specify it's name not file name
java Hello_world
looking for the class is essential part of launching and occurs by rules.