I am trying to transform the following string:
<img src="image.jpg" ... />
with this one
<img src="cid:image" ... />
the "image" string needs to be maintained but the string itself could be different. In the html document there are different img tags each one with a different image file.
so for instance if I have:
<img src="mylogo.jpg" ... />
it should transform to:
<img src="cid:mylogo" ... />
The images could be jpg or gif.
Thanks for any help,
Note:
Apart from the fact that Regex is not the right tool to parse HTML, as mentioned in comments, because in Java there are many tools for parsing HTML maybe you can take a look at jsoup for example, I will give you a solution that fits your needs of using Regex.
Solution:
You can use the following Regex:
src=\"([\\:\\w\\s\\/]+)\\.\\w{3}\"
This is the code you need:
String html = "<img src=\"folder1/mylogo.jpg\" ... />";
Pattern pattern = Pattern.compile("src=\"([\\:\\w\\s\\/]+)\\.\\w{3}\"");
Matcher matcher = pattern.matcher(html);
while (matcher.find()) {
System.out.println("group 1: " + matcher.group(1));
//This line will give you the wanted output.
System.out.println("src=\"cid:"+matcher.group(1)+"\"");
System.out.println("Final Result: "+html.replaceAll("src=\"([\\:\\w\\s\\/]+)\\.\\w{3}\"", "src=\"cid:$1\""));
}
And this is a Working DEMO.
Explanation:
src= matches the characters src= literally.
\" matches the character " literally.
([\\w\\/]+) is a capturing group to match all the wanted text.
\. matches the character . literally.
\w{3,4} match any word character [a-zA-Z0-9_] between 3 and 4 times for extensions, you can use jpg|gif instead if you are not willing to use any other image extensins.
\" matches the character " literally
EDIT:
Desired output:
And to replace this expression with the wanted result just use this regex on the replaceAll() method with your HTML, as follow:
html.replaceAll("src=\"([\\:\\w\\s\\/]+)\\.\\w{3}\"", "src=\"cid:$1\"");
We use $1 to point to the first capturing group.
Related
I am using this regex ("http:|"https:)\/\/.*\/content\/amc\/tdd\/.*?" to find all the urls which starts with http or https and contains /content/amc/tdd
But for the text
"<a id='cdq_element_175_link' href='http://google.com' data-href='edit' >
<img src=\"http://localhost:8080/content/amc/tdd/abc/download_1.jpeg?
ch_ck=1548843340209\" alt=\"\" id=\"element_175\" style=\"height: 135.575px; width: 135.575px;\" data-href=\"edit\">
<img src=\"http://localhost:8080/content/amc/tdd/abc/download_1.jpeg?ch_ck=1548843340209\" alt=\"\" id=\"element_175\" style=\"height: 135.575px; width: 135.575px;\" data-href=\"edit\">
</a>"
I am not getting two strings which matches the pattern, instead I am getting the complete string starting from first instance to the last.
What am I doing wrong ?
Because inside your regex .* is greedy match, it will eat all your string.
You should change it to .*?
Like this:
("http:|"https:)\/\/.*?\/content\/amc\/tdd\/.*?"
Try this Regex:
"https?:\/\/(?:[^\/]*\/)*?content\/amc\/tdd[^"]*"
Click for Demo
Explanation:
"https?:\/\/ - matches "http:// or "https://
(?:[^\/]*\/)*? - matches 0+ occurrences of any character which is not a / followed by /. This subpattern is repeated 0 or more times, as least as possible.
content\/amc\/tdd - matches content/amc/tdd
[^"]*" - matches 0+ occurrences of any character that is not a " followed by "
I have a XML being parsed as string.. the basic structure is something as below
<envelope>
<body>
<entity1>
<tag1>
.
.
</tag 1>
<tag2>
.
.
</tag2>
</entity1>
<entity 2>
<tag1>
.
.
</tag1>
<tag2>
.
.
</tag2>
</entity2>
I need to remove the tags lets say tag2 i.e. the whole .. block.
I am doing this using a while loop, something like
while(str.indexOf("<tag2>")>=0)
{
strRepl=str.substring(str.indexOf("<tag2>"),str.indexOf("</tag2>")+7);
str=xmlString.replaceFirst(strRepl,"");
}
This is working but i wanted to understand if there is a better way to implement this using strings?
Please suggest.
You could use Regex for that. Java provides Pattern and Matcher class that could do the job for you.
String yourString = "<envelope><body><entity1></entity1></body></envelope>";
String REGULAR_EXPRESSION= "(\\<body>.+?\\</body>)";
Pattern pattern = Pattern.compile(REGULAR_EXPRESSION, Pattern.DOTALL | Pattern.MULTILINE);
Matcher matcher = pattern.matcher(hello);
if (matcher.find()) {
System.out.println(yourString.replaceAll(matcher.group(1), ""));
}
Here (\\<body>.+?\\</body>) represents all the content enclosed inside <body> tag inclusive of tag.
The line matcher.group(1)represent the position of the matched string.
if you want to replace all the occurrence simply use
yourString = matcher.replaceAll("");
And to replace first occurrence only use :
yourString = matcher.replaceFirst("");
And i am not sure whether it will work for the new line "\n" content in the string, if the string is of single line , you can use :
System.out.println(yourString.replaceAll(REGULAR_EXPRESSION, ""));
I have below content in text file
some texting content <img src="cid:part123" alt=""> <b> Test</b>
I read it from file and store it in String i.e inputString
expectedString = inputString.replaceAll("\\<img.*?cid:part123.*?>",
"NewContent");
I get expected output i.e
some texting content NewContent <b> Test</b>
Basically if there is end of line character in between img and src like below, it does not work for example below
<img
src="cid:part123" alt="">
Is there a way regex ignore end of line character in between while matching?
If you want your dot (.) to match newline also, you can use Pattern.DOTALL flag. Alternativey, in case of String.replaceAll(), you can add a (?s) at the start of the pattern, which is equivalent to this flag.
From the Pattern.DOTALL - JavaDoc : -
Dotall mode can also be enabled via the embedded flag expression (?s).
(The s is a mnemonic for "single-line" mode, which is what this is
called in Perl.)
So, you can modify your pattern like this: -
expectedStr = inputString.replaceAll("(?s)<img.*?cid:part123.*?>", "Content");
NOTE: - You don't need to escape your angular bracket(<).
By default, the . character will not match newline characters. You can enable this behavior by specifying the Pattern.DOTALL flag. In String.replaceAll(), you do this by attaching a (?s) to the front of your pattern:
expectedString = inputString.replaceAll("(?s)\\<img.*?cid:part123.*?>",
"NewContent");
See also Pattern.DOTALL with String.replaceAll
You need to use Pattern.DOTALL mode.
replaceAll() doesn't take mode flags as a separate argument, but you can enable them in the expression as follows:
expectedString = inputString.replaceAll("(?s)\\<img.*?cid:part123.*?>", ...);
Note, however, that it's not a good idea to parse HTML with regular expressions. It would be better to use HTML parser instead.
I have a string which contains multiple occurrences of the "<p class=a> ... </p>" where ... is different text.
I am using "<p class=a>(.*)</p>" regex pattern to split the text into chunks. but this is not working. what would be the correct regex for this?
P.S. the same regex pattern is working in iOS using NSRegularExpression but not working in android using Pattern.
To explain my problem more : i am doing the following
Pattern regex3 = Pattern.compile("(?s)<P Class=ENCC>(.*?)</P>", CASE_INSENSITIVE);
String[] result = p.split(str);
result array contains only 1 item and it is the whole string
and the following is a portion of the file that i am reading :
<BODY>
<SYNC Start=200>
<P Class=ENCC><i>Cerita, Watak, Adegan dalam</i><br/><i>Drama Ini Rekaan Semata-Mata.</i></P>
</SYNC>
<SYNC Start=2440>
<P Class=ENCC> </P>
</SYNC>
<SYNC Start=2560>
<P Class=ENCC><i>Kami Tidak Berniat</i><br/><i>Melukakan Hati Sesiapa.</i></P>
</SYNC>
<SYNC Start=4560>
<P Class=ENCC> </P>
</SYNC>
<SYNC Start=66160>
<P Class=ENCC>Hai kawan-kawan.<br/>Inilah bandaraya Banting.</P>
</SYNC>
UPDATE ::::
hi everybody, I have got the problem. the problem was actually with the encoding of the file that i was reading. the file was UTF-16 (Little Endian) encoded. that was causing the all problem of regex not working. i changed it to UTF-8 and everything started working .. thanx everybody for your support.
Parsing HTML with regular expressions is not really a good idea (reason here). What you should use in an HTML parser such as this.
That being said, your issue is most likely the fact that the * operator is greedy. In your question you just say that it is not working, so I think that your problem is because it is matching the first <p class=a> and the very last </p>. Making the regular expression non greedy, like so: <p class=a>(.*?)</p> (notice the extra ? to make the * operator non greedy) should solve the problem (assuming that your problem is the one I have stated earlier).
That being said, I would really recommend you ditch the regular expression approach and use appropriate HTML Parsers.
EDIT:
Now that you've posted the code and the text you're matching against, one thing immediately leaps to mind:
You're matching <p class..., but your string contains <P Class.... Regexes are case-sensitive.
Then, . does not match newlines. And it's quite likely that your paragraphs do contain newlines.
Therefore, try "(?si)<p class=a>(.*?)</p>". The (?s) modifier allows the dot to match newlines, too, and the (?i) modifier makes the regex case-insensitive.
The .* may match <. You can try :
<p class=a>([^<]*)</p>
I guess the problem is that your pattern is greedy. You should use this instead.
"<p class=a>(.*?)</p>"
If you have this string:
"<p class=a>fist</p><p class=a>second</p>"
Your pattern ("<p class=a>(.*)</p>") will match this
"<p class=a>fist</p><p class=a>second</p>"
While "<p class=a>(.*?)</p>" only matches
"<p class=a>fist</p>"
I have a large number (>1500) of JSP files that I am trying to convert to JSPX. I am using a tool that will parse well-formed JSPs and convert to JSPX, however, my JSPs are not all well-formed :)
My solution is to pre-process the JSPs and convert untidy code so the tool will parse them correctly. The main problem I am trying to resolve is that of unquoted attribute values. Examples:
<INPUT id="foo" size=1>
<input id=body size="2">
My current regex for finding these is (in Java string format):
"(\\w+)=([^\"' >]+)"
And my replacement string is (in Java string format):
"$1=\"$2\""
This works well, EXCEPT for a few patterns, both of which involve inline scriptlets. For example:
<INPUT id=foo value="<%= someBean.method("a=b") %>">
In this case, my pattern matches the string literal "a=b", which I don't want to do. What I'd like to have happen is that the regex would IGNORE anything between <% and %>. Is there a regular expression that will do what I am trying to do?
EDIT:
Changed to title to clarify that I am NOT trying to parse HTML / JSP with regexes... I am doing a simple syntactic transformation to prepare the input for parsing.
If a sentence contains an arbitrary number of matching tokens such as double quotes, then this sentence belongs to a context-free language, which simply cannot be parsed with Regex designed to handle regular languages.
Either there could be some simplification assumptions (e.g. there are no unmatched double quotes and there is only a certain number of those etc.) that would permit the use of Regex, or your need to think about using (creating) a lexer/parser for a case of context-free language. ANTLR is a good tool for this.
Based on the assumption that there are NO unquoted attribute values inside the scriptlets, the following construct might work for you:
Note: this approach is fragile. Just for your reference.
import java.util.regex.*;
public class test{
public static void main(String args[]){
String s = "<INPUT id=foo abbr='ip ' name = bar color =\"blue\" value=\" <%= someBean.method(\" a = b \") %>\" nickname =box >";
Pattern p = Pattern.compile("(\\w+)\\s*=\\s*(\\w+[^\"'\\s])");
Matcher m = p.matcher(s);
while (m.find())
{
System.out.println("Return Value :"+m.group(1)+"="+m.group(2));
}
}
}
Output:
Return Value:id=foo
Return Value:name=bar
Return Value:nickname=box