This question already has answers here:
camel case method names
(12 answers)
Closed 7 years ago.
I do not understand what the difference between
int Hello ;
and
int hello ;
is .
Does it make a big difference if i use upper case Characters ?
That's because of Java Convention!
Actually, you can write a program like the way you're imagining but, you won't be following any pattern.......If you become a real programmer someday, you'll understand that patterns exist to make things better and easier.....
Related
This question already has answers here:
What is the convention for word separator in Java package names?
(6 answers)
Closed 6 years ago.
For example:
Which of the following package names is correct?
com.google.payrolldivision;
or
com.google.payrollDivision;
Please just answer the question without beating around the bush?
Please just answer the question
OK, then taking your question as a "a xor b", the answer is
com.google.payrolldivision;
as per https://docs.oracle.com/javase/tutorial/java/package/namingpkgs.html.
However, your title and post ask two very different questions, so it's hard to "just answer the question".
According to the Oracle webpage, you should write your package name in lowercase.
Package names are written in all lower case to avoid conflict with the names of classes or interfaces.
This question already has answers here:
How do I compare strings in Java?
(23 answers)
Closed 8 years ago.
I'm trying to do a comparison in Java with 2 strings containing a extended ASCII character.
boolean result = "éasdfasdf".substring(0,1).equals("é");
Can somebody explain why this results false? I think it has something to do with character encoding, but I can't figure out what exactly the problem is here...
Update: ideone.com does successfully run these 2 lines, so the problem is locally in my box. I think I found some more proof of that:
System.out.println("éb".charAt(1) == 'b');
Does also fails... Can it be the problem of 2 different character encodings?
Use
boolean result = "éasdfasdf".substring(0,1).equals("é")
And it will give expected result!The reason is simple - using '==' you compare objects by reference, not by value. So equals() solves this problem
This question already has answers here:
What is the role of the data types inside of < > in Java? [duplicate]
(5 answers)
Closed 8 years ago.
I am familiar with using parentheses, as in myMethod(myParameter), in Java and other programming languages, but what do the lesser than < and greater than > signs mean when they are used together in a array name? Is there a special name for them?
Sorry if this is a duplicate, but I don't know how to search for this.
Clarification: I wasn't referring to the role of any specific type inside the symbols, but rather the usage of the <> symbols themselves.
it is java generics, for type safe, and always.using with collections.
i suggest you read the SCJP book, it has a chapter called Generics and Collections, it provides all details you will need, it really helpful. hope it helps.
This question already has answers here:
How to convert number to words in java
(31 answers)
Closed 9 years ago.
I'm having a list of Integer from 1 to 100. If I loop through the list, I wanted to make the output as,
"One"
"Two" .....
"Hundred"
Is there any direct method in Java to obtain the above output?
No such method or class has been provided by JDK.
You can use the code mentioned here or here for reference purpose.
switch case are used to meet that requirement: Here
is source code.
Answer of this question described here: How to convert number to words in java
Officially this is not possible or no standard library available by native Java.
Don't duplicate.
There is none in the official Java libraries. However, the International Components for Unicode project has a RuleBasedNumberFormat with those capabilities. It even has a SPELLOUT constant.
This question already has answers here:
Closed 10 years ago.
Possible Duplicate:
Is java case sensitive ? If so Why?
In Java, are user defined symbols case sensitive?
Everything is case-sensitive in Java.