I have a program that saves on a file. The current code is set for the file to save on a specific path, but when I run the program from a different computer the program doesn't work and I need to change the path everytime.
public CreateCustomer() {
initComponents();
ArrayList<String> ConsIDList = new ArrayList<String>();
String csvFileToRead = "E:\\ryan_assignment_sit2\\ConsID\\consID.csv"; // Reads the CSV File.
BufferedReader br = null; // Creates a buffer reader.
String line = "";
String splitBy = ","; // Reader Delimiter
try {
br = new BufferedReader(new FileReader(csvFileToRead)); // Buffer Reader with file name to read.
Scanner reader = new Scanner(System.in);
while ((line = br.readLine()) != null) { //While there is a line to read.
reader = new Scanner(line);
reader.useDelimiter(splitBy);
while (reader.hasNext()) { // While there is a next value (token).
ConsIDList.add(reader.next());
}
}
} catch (FileNotFoundException exception) { // Exception Handler if the File is not Found.
exception.printStackTrace();
} catch (IOException exception) { // Input/Output exception
exception.printStackTrace();
} finally {
if (br != null) {
try {
br.close(); // Close the Scanner.
} catch (IOException exception) {
exception.printStackTrace();
}
}
I placed the file in the a subfolder in the program with the name ConsID and I tried changing the path file to
String csvFileToRead = "..\\ConsID\\consID.csv";
But the file can't be read from the program.
String csvFileToRead = "E:\ryan_assignment_sit2\ConsID\consID.csv";
The above path will only be applicable to windows. If you execute the program in linux environment you will get an Filenotfoundexception. Eventhough you change the file, again you are hardcoding the file path.
Better you can get it as runtime parameters so that the program will be executed irrespective of OS.
If you are running you program from command line then you can place the csv file in your classpath (root folder where the class files are generated) and refer to it as below:
BufferedReader br = new BufferedReader(ClassLoader.getResourceAsStream("consID.csv"));
Related
How do you read and display data from .txt files?
BufferedReader in = new BufferedReader(new FileReader("<Filename>"));
Then, you can use in.readLine(); to read a single line at a time. To read until the end, write a while loop as such:
String line;
while((line = in.readLine()) != null)
{
System.out.println(line);
}
in.close();
If your file is strictly text, I prefer to use the java.util.Scanner class.
You can create a Scanner out of a file by:
Scanner fileIn = new Scanner(new File(thePathToYourFile));
Then, you can read text from the file using the methods:
fileIn.nextLine(); // Reads one line from the file
fileIn.next(); // Reads one word from the file
And, you can check if there is any more text left with:
fileIn.hasNext(); // Returns true if there is another word in the file
fileIn.hasNextLine(); // Returns true if there is another line to read from the file
Once you have read the text, and saved it into a String, you can print the string to the command line with:
System.out.print(aString);
System.out.println(aString);
The posted link contains the full specification for the Scanner class. It will be helpful to assist you with what ever else you may want to do.
In general:
Create a FileInputStream for the file.
Create an InputStreamReader wrapping the input stream, specifying the correct encoding
Optionally create a BufferedReader around the InputStreamReader, which makes it simpler to read a line at a time.
Read until there's no more data (e.g. readLine returns null)
Display data as you go or buffer it up for later.
If you need more help than that, please be more specific in your question.
I love this piece of code, use it to load a file into one String:
File file = new File("/my/location");
String contents = new Scanner(file).useDelimiter("\\Z").next();
Below is the code that you may try to read a file and display in java using scanner class. Code will read the file name from user and print the data(Notepad VIM files).
import java.io.*;
import java.util.Scanner;
import java.io.*;
public class TestRead
{
public static void main(String[] input)
{
String fname;
Scanner scan = new Scanner(System.in);
/* enter filename with extension to open and read its content */
System.out.print("Enter File Name to Open (with extension like file.txt) : ");
fname = scan.nextLine();
/* this will reference only one line at a time */
String line = null;
try
{
/* FileReader reads text files in the default encoding */
FileReader fileReader = new FileReader(fname);
/* always wrap the FileReader in BufferedReader */
BufferedReader bufferedReader = new BufferedReader(fileReader);
while((line = bufferedReader.readLine()) != null)
{
System.out.println(line);
}
/* always close the file after use */
bufferedReader.close();
}
catch(IOException ex)
{
System.out.println("Error reading file named '" + fname + "'");
}
}
}
If you want to take some shortcuts you can use Apache Commons IO:
import org.apache.commons.io.FileUtils;
String data = FileUtils.readFileToString(new File("..."), "UTF-8");
System.out.println(data);
:-)
public class PassdataintoFile {
public static void main(String[] args) throws IOException {
try {
PrintWriter pw = new PrintWriter("C:/new/hello.txt", "UTF-8");
PrintWriter pw1 = new PrintWriter("C:/new/hello.txt");
pw1.println("Hi chinni");
pw1.print("your succesfully entered text into file");
pw1.close();
} catch (FileNotFoundException e) {
// TODO Auto-generated catch block
e.printStackTrace();
} catch (UnsupportedEncodingException e) {
// TODO Auto-generated catch block
e.printStackTrace();
}
BufferedReader br = new BufferedReader(new FileReader("C:/new/hello.txt"));
String line;
while((line = br.readLine())!= null)
{
System.out.println(line);
}
br.close();
}
}
In Java 8, you can read a whole file, simply with:
public String read(String file) throws IOException {
return new String(Files.readAllBytes(Paths.get(file)));
}
or if its a Resource:
public String read(String file) throws IOException {
URL url = Resources.getResource(file);
return Resources.toString(url, Charsets.UTF_8);
}
You most likely will want to use the FileInputStream class:
int character;
StringBuffer buffer = new StringBuffer("");
FileInputStream inputStream = new FileInputStream(new File("/home/jessy/file.txt"));
while( (character = inputStream.read()) != -1)
buffer.append((char) character);
inputStream.close();
System.out.println(buffer);
You will also want to catch some of the exceptions thrown by the read() method and FileInputStream constructor, but those are implementation details specific to your project.
Im having a problem in checking if a file exists in Java. However the IF block seems to work , but the ELSE seems dont. see, when a file exist, it will prompt a box that says, 'File found.' which happens in my program whenever a file do exist, the problem is errors flood in my console when a file dont exist. Can somebody tell me what's the easier and shorter way of coding my problem? thanks ! here's my code
public void actionPerformed(ActionEvent e) {
BufferedReader br = null;
File f = new File(textField.getText());
String path = new String("C:\\Users\\theBeard\\workspace\\LeapYear\\");
try {
String sCurrentLine;
br = new BufferedReader(new FileReader(path+f));
if (f.exists())
{
JOptionPane.showMessageDialog(null, textField.getText()+" found" );
while ((sCurrentLine = br.readLine()) != null) {
textArea.append(sCurrentLine);
textArea.append(System.lineSeparator());
}
}
else
{
JOptionPane.showMessageDialog(null, textField.getText()+" not found" );
}
} catch (IOException ex) {
ex.printStackTrace();
} finally {
try {
if (br != null)
{
br.close();
}
} catch (IOException ex) {
ex.printStackTrace();
}
}
}
});
The problem is with this line:
br = new BufferedReader(new FileReader(path+f));
You're appending a File to a String, which doesn't make sense. You should append a String to a String, in this case textField.getText()) appended to path.
This line will throw an exception if the file doesn't exist as per the documentation of FileReader:
Throws:
FileNotFoundException - if the named file does not exist, is a directory rather than a regular file, or for some other reason cannot be opened for reading.
This causes your program to reach the catch clause and print an exception stack trace. You should only call this line when f.exists() returns true:
if (f.exists())
{
br = new BufferedReader(new FileReader(path + textField.getText()));
...
}
Look at these lines of your code:
br = new BufferedReader(new FileReader(path+f));
if (f.exists())
You are trying to open the file before checking whether it exists. So if the attempt to open it fails with a FileNotFoundException, the test is never reached.
String path = "C:\\Path\\To\File\\Directory\\";
String fileName = "NameOfFile.ext";
File f = new File(path, fileName);
if(f.exists()) {
//<code for file existing>
} else {
//<code for file not existing>
}
You have to instantiate the BufferedReader after checking the existence of the file.
String path = new String("C:\\Users\\theBeard\\workspace\\LeapYear\\");
File f = new File(path + textField.getText());
...
if (f.exists())
{
br = new BufferedReader(new FileReader(f.getAbsolutePath())); // or br = new BufferedReader(f);
...
I am trying to open a file in JAVA using BufferedReader but it cannot open the file. Here is my code
public static void main(String[] args) {
try
{
BufferedReader reader = new BufferedReader(new FileReader("test.txt"));
String line = null;
while ((reader.readLine()!= null))
{
line = reader.readLine();
System.out.println(line);
}
reader.close();
}
catch(Exception ex)
{
System.out.println("Unable to open file ");
}
}
It goes to the exception and prints Unable to open file. Any suggestions why I cannot able to read it.
If you want to be more nearly modern, try the Java 7 solution, taken from the Paths Javadoc:
final Path path = FileSystems.getDefault().getPath("test.txt"); // working directory
try (final Reader r = Files.newBufferedReader(path, StandardCharsets.UTF_8)) {
String line = null;
while ((line = r.readLine()) != null) {
System.out.println(line);
}
} // No need for catch; let IOExceptions bubble up.
// No need for finally; try-with-resources auto-closes.
You'll need to declare main as throwing IOException, but that's okay. You have no coherent way of handling IOException anyway. Just read the stack trace if an exception is triggered.
I don't know why this happened, but the problem seemed that I did not enter the complete path for the file even though the file was in the same folder. Ideally if the file is in the same folder then I wouldn't need to enter the entire pathname.
Try doing a check if it exists first:
File file = new File("test.txt");
if (!file.exists()) {
System.err.println(file.getName() + " not found. Full path: " + file.getAbsolutePath());
/* Handling code, or */
return;
}
BufferedReader reader = new BufferedReader(new FileReader(file));
/* other code... */
Goal: to read contents of a file that is in my root directory. Eventually I want to be able to read a .conf file, but right now I am testing with a .txt file since it seems easier to begin with..
I am using the open source Shell file from an XDA video to navigate to my root directory. For reference, the file is located at: "/data/misc/joke.txt"
This is the code in my main method:
String command[]={"su","-c","ls /data/misc"};
Shell shell = new Shell();
String output = shell.sendShellCommand(command);
try {
read(output);
} catch (Exception e) {
// TODO Auto-generated catch block
e.printStackTrace();
}
So basically all that is doing is granting SU permission, and then navigating to the /data/misc folder. Then in the Shell() class, I scan through each file and search for the text file I want. This might be redundant since I expect the text file to be "joke.txt" EVERYTIME. Anyways, I am having an issue with this block of code, the read() method:
public void read(String out) throws Exception{
File yourFile = new File("/data/misc", out);
FileReader file = new FileReader(yourFile);
BufferedReader reader = new BufferedReader(file);
String line;
String text = "";
line = reader.readLine();
while (line != null) {
text += (line);
line = reader.readLine();
}
setNewTextInTextView(text);
}
It crashes at this line:
FileReader file = new FileReader(yourFile);
Any tips?
I have this method that gets the last line of a .txt file and creates a new temp file without that line. But when I try to delete the .txt that has the line I want to delete (so then I can rename the temp file) for some reason I can't. This is the code:
void removeFromLocal() throws IOException {
String lineToRemove = getLastLine();
File inputFile = new File("nexLog.txt");
File tempFile = new File("TempnexLog.txt");
BufferedReader reader = null;
BufferedWriter writer = null;
try {
reader = new BufferedReader(new FileReader(inputFile));
writer = new BufferedWriter(new FileWriter(tempFile));
String currentLine;
int i = 0;
while ((currentLine = reader.readLine()) != null) {
i++;
String trimmedLine = currentLine.trim();
if (!trimmedLine.equals(lineToRemove)) {
if (i != 1) {
writer.newLine();
}
writer.write(currentLine);
}
}
reader.close();
reader = null;
writer.flush();
writer.close();
writer = null;
System.gc();
inputFile.setWritable(true);
if (!inputFile.delete()) {
System.out.println("Could not delete file");
return;
}
if (!tempFile.renameTo(inputFile)) {
System.out.println("Could not rename file");
}
//boolean successful = tempFile.renameTo(inputFile);
} catch (IOException ex) {
Logger.getLogger(dropLog.class.getName()).log(Level.SEVERE, null, ex);
}
}
Whats funny is that when I press the button that calls the method once, nothing happens ("Could not delete file"), the second time it works fine and the 3rd I get "Could not rename file".
The file cannot be deleted when it's been opened by another process. E.g. in notepad or so or maybe even another FileReader/FileWriter on the file somewhere else in your code. Also, when you're executing this inside an IDE, you'll risk that the IDE will touch the file during the background scan for modifications in the project's folder. Rather store the files in an absolute path outside the IDE's project.
Also, the code flow of opening and closing the files has to be modified so that the close is performed in the finally block. The idiom is like this:
Reader reader = null;
try {
reader = new SomeReader(file);
// ...
} finally {
if (reader != null) try { reader.close(); } catch (IOException logOrIgnore) {}
}
Or, if you're already on Java 7, use the automatic resource management instead.
try (Reader reader = new SomeReader(file)) {
// ...
}
Further I recommend to use File#createTempFile() instead to create temp files. This way an unique temp filename will be generated and thus you prevent the very same temp file being written and renamed by multiple processes.
File tempFile = File.createTempFile("nexLog", ".txt");
Does BufferedReader close the nested reader (not mentioned in the doc)? You have to make sure, by checking if setWritable was successful.Otherwise you need to close FileReader too, and I would recommend because in case you close it twice there is no harm... by the way GC call is more harmful than useful.