Java: Trouble writing primitive data to a file - java

I'm trying to write primitive data such Int, Float, Double to a file in Java. Whenever I run the program the text file contains some random characters. I am using jdk1.8.0_25 and Npp editor. Here's the sample code I've obtained
import java.io.BufferedOutputStream;
import java.io.DataOutputStream;
import java.io.File;
import java.io.FileOutputStream;
import java.io.IOException;
public class Tad {
public static void main(String[] args) throws IOException {
DataOutputStream dos = new DataOutputStream(new BufferedOutputStream(new FileOutputStream(
new File("E:\\temp.txt"))));
for (int i = 0; i < 10; i++)
dos.writeInt(i);
dos.close();
}
}
The output is not pastable here but it has spaces and some weird symbols which are not a part of the keyboard layout.

You want to "write" contents to a file, you don't want to write its binary representation.
So you have to use "Writer" Implementation's in Java not "OutputStream"
You see strange symbols in your file, because they are the binary representation of your data (ASCII codes).
Following code achieves what you are looking for.
Happy learning!
import java.io.BufferedWriter;
import java.io.File;
import java.io.FileWriter;
import java.io.IOException;
import java.io.Writer;
class Test123 {
public static void main(String[] args) throws IOException {
Writer dos = new BufferedWriter(
new FileWriter(new File("C:\\temp.txt")));
for (int i = 0; i < 10; i++)
dos.write(String.valueOf(i));
dos.close();
}
}

That Random characters are the ASCII representation of the decimal 0, 1, 2, 3 and so on till 127, you can see the ASCII values in the following table where 0 = null, 1 = start of heading and so on.
Here is an example of what you want to achieve in my style.
public class Tad {
public static void main(String[] args) throws IOException {
FileWriter dos = new FileWriter(new File("E:\\temp.txt"));
for (int i = 0; i < 10; i++)
dos.write(i+"");
dos.close();
}
}
and the following is an example in your style with a little change, I have used dos.writeChars(Integer.toString(i)); instead of dos.writeInt(i);.
public class Tad {
public static void main(String[] args) throws IOException {
DataOutputStream dos = new DataOutputStream(new BufferedOutputStream(new FileOutputStream(
new File("E:\\temp.txt"))));
for (int i = 0; i < 10; i++){
dos.writeChars(Integer.toString(i));
}
dos.close();
}
}

Try using FileWRiter. I don't have a compiler at hand, but it should be something like this:
import java.io.*
public static writeString(String text)
{
private static String fileName= "put path and file here";
try{
File file = new File(fileName);
FileWriter writer = new FileWriter(file, true); //true means append to the file instead of purging the file every entry.
writer.write(text);
writer.close(); //close the output
}catch(IOException e){
System.err.println("ioexception: " + e.getMessag());
}
}
I'll check the code when I'm home to see if there are no problem, provided nobody gives better answer until that time, but this should at least put you on the right track.
NOTE - you should handle exceptions in IO

Related

Hex Viewer in Java

I'm a beginner in java programming and i'm trying to create a hex viewer in java, my IDE is Netbeans. Below is the code.
import java.io.File;
import java.io.FileInputStream;
import java.io.IOException;
import java.io.InputStream;
import static java.lang.System.out;
import javax.swing.JFileChooser;
public class hope {
public static void main(String[] args) throws IOException {
JFileChooser open = new JFileChooser();
open.showOpenDialog(null);
File f = open.getSelectedFile();
InputStream is = new FileInputStream(f);
int bytesCounter = 0;
int value = 0;
StringBuilder sbHex = new StringBuilder();
StringBuilder sbResult = new StringBuilder();
while ((value = is.read()) != -1) {
//convert to hex value with "X" formatter
sbHex.append(String.format("%02X ", value));
//if 16 bytes are read, reset the counter,
//clear the StringBuilder for formatting purpose only.
if (bytesCounter == 15) {
sbResult.append(sbHex).append("\n");
sbHex.setLength(0);
bytesCounter = 0;
} else {
bytesCounter++;
}
}
//if still got content
if (bytesCounter != 0) {
//add spaces more formatting purpose only
for (; bytesCounter < 16; bytesCounter++) {
//1 character 3 spaces
sbHex.append(" ");
}
sbResult.append(sbHex).append("\n");
}
out.print(sbResult);
is.close();
}
}
The problem are:
1. It doesn't read the files fast enough"It takes a minute to read a file of 200kb"
2. It gives "Out of Memory" error when I tried a large file e.g. 80mb
What I want it to do:
1. Display all the hex code in seconds "Read and display hex of any size of file"
2. read file of any size without error code.
The Question:
What do I need to change or add in my code to achieve the above "What I want it to do"?
For this simple example, the key is to use "Buffered" input stream.
Change this line of code:
InputStream is = new FileInputStream(f);
to:
InputStream is = new BufferedInputStream( new FileInputStream(f));
You will get a much better result.
(But to fix the Out of Memory error, you have to think about a different approach since currently you are "caching" all the data to one string which will eat all your memory. Maybe print/clear the string builder each time the counter reaches 15 or higher? You can try and let us know. :)

Error on Arithmetic Coding Compression Algorithm

I am trying to implement arithmetic coding which is a compression algorithm. Here is the compression code.When I compiled it
Exception in thread "main" java.lang.RuntimeException: Uncompilable source code - Erroneous tree type: arithmetic.FrequencyTable
at arithmetic.ArithmeticCompress.main(ArithmeticCompress.java:35)
It is giving me this error.
source
package arithmetic;
import java.io.BufferedInputStream;
import java.io.BufferedOutputStream;
import java.io.File;
import java.io.FileInputStream;
import java.io.FileOutputStream;
import java.io.IOException;
import java.io.InputStream;
public class ArithmeticCompress {
public static void main(String[] args) throws IOException {
File inputFile = new File("D:\\5.txt");
File outputFile = new File("D:\\new1.txt");
// Read input file once to compute symbol frequencies
//Line no 35
FrequencyTable freqs = getFrequencies(inputFile);
freqs.increment(256); // EOF symbol gets a frequency of 1
// Read input file again, compress with arithmetic coding, and write output file
try (InputStream in = new BufferedInputStream(new FileInputStream(inputFile))) {
try (BitOutputStream out = new BitOutputStream(new BufferedOutputStream(new FileOutputStream(outputFile)))) {
writeFrequencies(out, freqs);
compress(freqs, in, out);
}
}
}
// Returns a frequency table based on the bytes in the given file.
// Also contains an extra entry for symbol 256, whose frequency is set to 0.
private static FrequencyTable getFrequencies(File file) throws IOException {
FrequencyTable freqs = new SimpleFrequencyTable(new int[257]);
try (InputStream input = new BufferedInputStream(new FileInputStream(file))) {
while (true) {
int b = input.read();
if (b == -1)
break;
freqs.increment(b);
}
}
return freqs;
}
// To allow unit testing, this method is package-private instead of private.
static void writeFrequencies(BitOutputStream out, FrequencyTable freqs) throws IOException {
for (int i = 0; i < 256; i++)
writeInt(out, 32, freqs.get(i));
}
// To allow unit testing, this method is package-private instead of private.
static void compress(FrequencyTable freqs, InputStream in, BitOutputStream out) throws IOException {
ArithmeticEncoder enc = new ArithmeticEncoder(out);
while (true) {
int symbol = in.read();
if (symbol == -1)
break;
enc.write(freqs, symbol);
}
enc.write(freqs, 256); // EOF
enc.finish(); // Flush remaining code bits
}
// Writes an unsigned integer of the given bit width to the given stream.
private static void writeInt(BitOutputStream out, int numBits, int value) throws IOException {
if (numBits < 0 || numBits > 32)
throw new IllegalArgumentException();
for (int i = numBits - 1; i >= 0; i--)
out.write((value >>> i) & 1);
}
}
Well it's a little bit weird because such source code shouldn't even compile (so there shouldn't be any RuntimeException): because your code is referencing class FrequencyTable, but that class is not defined in your code and it's not even imported? Not sure. However normally, this would lead to a compilation error and you shouldn't be able to run such code - here I guess that you are using some IDE (like NetBeans, maybe eclipse) which allows you to run the code even if it doesn't compile -> but it'll fail during rutime.
I advise to fully rebuild (clean and compile) your project in your IDE to show errors you might have in the code...

PrintWriter won't stop writing in Java, stuck in infinite loop [duplicate]

It seems there are different ways to read and write data of files in Java.
I want to read ASCII data from a file. What are the possible ways and their differences?
My favorite way to read a small file is to use a BufferedReader and a StringBuilder. It is very simple and to the point (though not particularly effective, but good enough for most cases):
BufferedReader br = new BufferedReader(new FileReader("file.txt"));
try {
StringBuilder sb = new StringBuilder();
String line = br.readLine();
while (line != null) {
sb.append(line);
sb.append(System.lineSeparator());
line = br.readLine();
}
String everything = sb.toString();
} finally {
br.close();
}
Some has pointed out that after Java 7 you should use try-with-resources (i.e. auto close) features:
try(BufferedReader br = new BufferedReader(new FileReader("file.txt"))) {
StringBuilder sb = new StringBuilder();
String line = br.readLine();
while (line != null) {
sb.append(line);
sb.append(System.lineSeparator());
line = br.readLine();
}
String everything = sb.toString();
}
When I read strings like this, I usually want to do some string handling per line anyways, so then I go for this implementation.
Though if I want to actually just read a file into a String, I always use Apache Commons IO with the class IOUtils.toString() method. You can have a look at the source here:
http://www.docjar.com/html/api/org/apache/commons/io/IOUtils.java.html
FileInputStream inputStream = new FileInputStream("foo.txt");
try {
String everything = IOUtils.toString(inputStream);
} finally {
inputStream.close();
}
And even simpler with Java 7:
try(FileInputStream inputStream = new FileInputStream("foo.txt")) {
String everything = IOUtils.toString(inputStream);
// do something with everything string
}
ASCII is a TEXT file so you would use Readers for reading. Java also supports reading from a binary file using InputStreams. If the files being read are huge then you would want to use a BufferedReader on top of a FileReader to improve read performance.
Go through this article on how to use a Reader
I'd also recommend you download and read this wonderful (yet free) book called Thinking In Java
In Java 7:
new String(Files.readAllBytes(...))
(docs)
or
Files.readAllLines(...)
(docs)
In Java 8:
Files.lines(..).forEach(...)
(docs)
The easiest way is to use the Scanner class in Java and the FileReader object. Simple example:
Scanner in = new Scanner(new FileReader("filename.txt"));
Scanner has several methods for reading in strings, numbers, etc... You can look for more information on this on the Java documentation page.
For example reading the whole content into a String:
StringBuilder sb = new StringBuilder();
while(in.hasNext()) {
sb.append(in.next());
}
in.close();
outString = sb.toString();
Also if you need a specific encoding you can use this instead of FileReader:
new InputStreamReader(new FileInputStream(fileUtf8), StandardCharsets.UTF_8)
Here is a simple solution:
String content = new String(Files.readAllBytes(Paths.get("sample.txt")));
Or to read as list:
List<String> content = Files.readAllLines(Paths.get("sample.txt"))
Here's another way to do it without using external libraries:
import java.io.File;
import java.io.FileReader;
import java.io.IOException;
public String readFile(String filename)
{
String content = null;
File file = new File(filename); // For example, foo.txt
FileReader reader = null;
try {
reader = new FileReader(file);
char[] chars = new char[(int) file.length()];
reader.read(chars);
content = new String(chars);
reader.close();
} catch (IOException e) {
e.printStackTrace();
} finally {
if(reader != null){
reader.close();
}
}
return content;
}
I had to benchmark the different ways. I shall comment on my findings but, in short, the fastest way is to use a plain old BufferedInputStream over a FileInputStream. If many files must be read then three threads will reduce the total execution time to roughly half, but adding more threads will progressively degrade performance until making it take three times longer to complete with twenty threads than with just one thread.
The assumption is that you must read a file and do something meaningful with its contents. In the examples here is reading lines from a log and count the ones which contain values that exceed a certain threshold. So I am assuming that the one-liner Java 8 Files.lines(Paths.get("/path/to/file.txt")).map(line -> line.split(";")) is not an option.
I tested on Java 1.8, Windows 7 and both SSD and HDD drives.
I wrote six different implementations:
rawParse: Use BufferedInputStream over a FileInputStream and then cut lines reading byte by byte. This outperformed any other single-thread approach, but it may be very inconvenient for non-ASCII files.
lineReaderParse: Use a BufferedReader over a FileReader, read line by line, split lines by calling String.split(). This is approximatedly 20% slower that rawParse.
lineReaderParseParallel: This is the same as lineReaderParse, but it uses several threads. This is the fastest option overall in all cases.
nioFilesParse: Use java.nio.files.Files.lines()
nioAsyncParse: Use an AsynchronousFileChannel with a completion handler and a thread pool.
nioMemoryMappedParse: Use a memory-mapped file. This is really a bad idea yielding execution times at least three times longer than any other implementation.
These are the average times for reading 204 files of 4 MB each on an quad-core i7 and SSD drive. The files are generated on the fly to avoid disk caching.
rawParse 11.10 sec
lineReaderParse 13.86 sec
lineReaderParseParallel 6.00 sec
nioFilesParse 13.52 sec
nioAsyncParse 16.06 sec
nioMemoryMappedParse 37.68 sec
I found a difference smaller than I expected between running on an SSD or an HDD drive being the SSD approximately 15% faster. This may be because the files are generated on an unfragmented HDD and they are read sequentially, therefore the spinning drive can perform nearly as an SSD.
I was surprised by the low performance of the nioAsyncParse implementation. Either I have implemented something in the wrong way or the multi-thread implementation using NIO and a completion handler performs the same (or even worse) than a single-thread implementation with the java.io API. Moreover the asynchronous parse with a CompletionHandler is much longer in lines of code and tricky to implement correctly than a straight implementation on old streams.
Now the six implementations followed by a class containing them all plus a parametrizable main() method that allows to play with the number of files, file size and concurrency degree. Note that the size of the files varies plus minus 20%. This is to avoid any effect due to all the files being of exactly the same size.
rawParse
public void rawParse(final String targetDir, final int numberOfFiles) throws IOException, ParseException {
overrunCount = 0;
final int dl = (int) ';';
StringBuffer lineBuffer = new StringBuffer(1024);
for (int f=0; f<numberOfFiles; f++) {
File fl = new File(targetDir+filenamePreffix+String.valueOf(f)+".txt");
FileInputStream fin = new FileInputStream(fl);
BufferedInputStream bin = new BufferedInputStream(fin);
int character;
while((character=bin.read())!=-1) {
if (character==dl) {
// Here is where something is done with each line
doSomethingWithRawLine(lineBuffer.toString());
lineBuffer.setLength(0);
}
else {
lineBuffer.append((char) character);
}
}
bin.close();
fin.close();
}
}
public final void doSomethingWithRawLine(String line) throws ParseException {
// What to do for each line
int fieldNumber = 0;
final int len = line.length();
StringBuffer fieldBuffer = new StringBuffer(256);
for (int charPos=0; charPos<len; charPos++) {
char c = line.charAt(charPos);
if (c==DL0) {
String fieldValue = fieldBuffer.toString();
if (fieldValue.length()>0) {
switch (fieldNumber) {
case 0:
Date dt = fmt.parse(fieldValue);
fieldNumber++;
break;
case 1:
double d = Double.parseDouble(fieldValue);
fieldNumber++;
break;
case 2:
int t = Integer.parseInt(fieldValue);
fieldNumber++;
break;
case 3:
if (fieldValue.equals("overrun"))
overrunCount++;
break;
}
}
fieldBuffer.setLength(0);
}
else {
fieldBuffer.append(c);
}
}
}
lineReaderParse
public void lineReaderParse(final String targetDir, final int numberOfFiles) throws IOException, ParseException {
String line;
for (int f=0; f<numberOfFiles; f++) {
File fl = new File(targetDir+filenamePreffix+String.valueOf(f)+".txt");
FileReader frd = new FileReader(fl);
BufferedReader brd = new BufferedReader(frd);
while ((line=brd.readLine())!=null)
doSomethingWithLine(line);
brd.close();
frd.close();
}
}
public final void doSomethingWithLine(String line) throws ParseException {
// Example of what to do for each line
String[] fields = line.split(";");
Date dt = fmt.parse(fields[0]);
double d = Double.parseDouble(fields[1]);
int t = Integer.parseInt(fields[2]);
if (fields[3].equals("overrun"))
overrunCount++;
}
lineReaderParseParallel
public void lineReaderParseParallel(final String targetDir, final int numberOfFiles, final int degreeOfParalelism) throws IOException, ParseException, InterruptedException {
Thread[] pool = new Thread[degreeOfParalelism];
int batchSize = numberOfFiles / degreeOfParalelism;
for (int b=0; b<degreeOfParalelism; b++) {
pool[b] = new LineReaderParseThread(targetDir, b*batchSize, b*batchSize+b*batchSize);
pool[b].start();
}
for (int b=0; b<degreeOfParalelism; b++)
pool[b].join();
}
class LineReaderParseThread extends Thread {
private String targetDir;
private int fileFrom;
private int fileTo;
private DateFormat fmt = new SimpleDateFormat("yyyy-MM-dd HH:mm:ss");
private int overrunCounter = 0;
public LineReaderParseThread(String targetDir, int fileFrom, int fileTo) {
this.targetDir = targetDir;
this.fileFrom = fileFrom;
this.fileTo = fileTo;
}
private void doSomethingWithTheLine(String line) throws ParseException {
String[] fields = line.split(DL);
Date dt = fmt.parse(fields[0]);
double d = Double.parseDouble(fields[1]);
int t = Integer.parseInt(fields[2]);
if (fields[3].equals("overrun"))
overrunCounter++;
}
#Override
public void run() {
String line;
for (int f=fileFrom; f<fileTo; f++) {
File fl = new File(targetDir+filenamePreffix+String.valueOf(f)+".txt");
try {
FileReader frd = new FileReader(fl);
BufferedReader brd = new BufferedReader(frd);
while ((line=brd.readLine())!=null) {
doSomethingWithTheLine(line);
}
brd.close();
frd.close();
} catch (IOException | ParseException ioe) { }
}
}
}
nioFilesParse
public void nioFilesParse(final String targetDir, final int numberOfFiles) throws IOException, ParseException {
for (int f=0; f<numberOfFiles; f++) {
Path ph = Paths.get(targetDir+filenamePreffix+String.valueOf(f)+".txt");
Consumer<String> action = new LineConsumer();
Stream<String> lines = Files.lines(ph);
lines.forEach(action);
lines.close();
}
}
class LineConsumer implements Consumer<String> {
#Override
public void accept(String line) {
// What to do for each line
String[] fields = line.split(DL);
if (fields.length>1) {
try {
Date dt = fmt.parse(fields[0]);
}
catch (ParseException e) {
}
double d = Double.parseDouble(fields[1]);
int t = Integer.parseInt(fields[2]);
if (fields[3].equals("overrun"))
overrunCount++;
}
}
}
nioAsyncParse
public void nioAsyncParse(final String targetDir, final int numberOfFiles, final int numberOfThreads, final int bufferSize) throws IOException, ParseException, InterruptedException {
ScheduledThreadPoolExecutor pool = new ScheduledThreadPoolExecutor(numberOfThreads);
ConcurrentLinkedQueue<ByteBuffer> byteBuffers = new ConcurrentLinkedQueue<ByteBuffer>();
for (int b=0; b<numberOfThreads; b++)
byteBuffers.add(ByteBuffer.allocate(bufferSize));
for (int f=0; f<numberOfFiles; f++) {
consumerThreads.acquire();
String fileName = targetDir+filenamePreffix+String.valueOf(f)+".txt";
AsynchronousFileChannel channel = AsynchronousFileChannel.open(Paths.get(fileName), EnumSet.of(StandardOpenOption.READ), pool);
BufferConsumer consumer = new BufferConsumer(byteBuffers, fileName, bufferSize);
channel.read(consumer.buffer(), 0l, channel, consumer);
}
consumerThreads.acquire(numberOfThreads);
}
class BufferConsumer implements CompletionHandler<Integer, AsynchronousFileChannel> {
private ConcurrentLinkedQueue<ByteBuffer> buffers;
private ByteBuffer bytes;
private String file;
private StringBuffer chars;
private int limit;
private long position;
private DateFormat frmt = new SimpleDateFormat("yyyy-MM-dd HH:mm:ss");
public BufferConsumer(ConcurrentLinkedQueue<ByteBuffer> byteBuffers, String fileName, int bufferSize) {
buffers = byteBuffers;
bytes = buffers.poll();
if (bytes==null)
bytes = ByteBuffer.allocate(bufferSize);
file = fileName;
chars = new StringBuffer(bufferSize);
frmt = new SimpleDateFormat("yyyy-MM-dd HH:mm:ss");
limit = bufferSize;
position = 0l;
}
public ByteBuffer buffer() {
return bytes;
}
#Override
public synchronized void completed(Integer result, AsynchronousFileChannel channel) {
if (result!=-1) {
bytes.flip();
final int len = bytes.limit();
int i = 0;
try {
for (i = 0; i < len; i++) {
byte by = bytes.get();
if (by=='\n') {
// ***
// The code used to process the line goes here
chars.setLength(0);
}
else {
chars.append((char) by);
}
}
}
catch (Exception x) {
System.out.println(
"Caught exception " + x.getClass().getName() + " " + x.getMessage() +
" i=" + String.valueOf(i) + ", limit=" + String.valueOf(len) +
", position="+String.valueOf(position));
}
if (len==limit) {
bytes.clear();
position += len;
channel.read(bytes, position, channel, this);
}
else {
try {
channel.close();
}
catch (IOException e) {
}
consumerThreads.release();
bytes.clear();
buffers.add(bytes);
}
}
else {
try {
channel.close();
}
catch (IOException e) {
}
consumerThreads.release();
bytes.clear();
buffers.add(bytes);
}
}
#Override
public void failed(Throwable e, AsynchronousFileChannel channel) {
}
};
FULL RUNNABLE IMPLEMENTATION OF ALL CASES
https://github.com/sergiomt/javaiobenchmark/blob/master/FileReadBenchmark.java
Here are the three working and tested methods:
Using BufferedReader
package io;
import java.io.*;
public class ReadFromFile2 {
public static void main(String[] args)throws Exception {
File file = new File("C:\\Users\\pankaj\\Desktop\\test.java");
BufferedReader br = new BufferedReader(new FileReader(file));
String st;
while((st=br.readLine()) != null){
System.out.println(st);
}
}
}
Using Scanner
package io;
import java.io.File;
import java.util.Scanner;
public class ReadFromFileUsingScanner {
public static void main(String[] args) throws Exception {
File file = new File("C:\\Users\\pankaj\\Desktop\\test.java");
Scanner sc = new Scanner(file);
while(sc.hasNextLine()){
System.out.println(sc.nextLine());
}
}
}
Using FileReader
package io;
import java.io.*;
public class ReadingFromFile {
public static void main(String[] args) throws Exception {
FileReader fr = new FileReader("C:\\Users\\pankaj\\Desktop\\test.java");
int i;
while ((i=fr.read()) != -1){
System.out.print((char) i);
}
}
}
Read the entire file without a loop using the Scanner class
package io;
import java.io.File;
import java.io.FileNotFoundException;
import java.util.Scanner;
public class ReadingEntireFileWithoutLoop {
public static void main(String[] args) throws FileNotFoundException {
File file = new File("C:\\Users\\pankaj\\Desktop\\test.java");
Scanner sc = new Scanner(file);
sc.useDelimiter("\\Z");
System.out.println(sc.next());
}
}
The methods within org.apache.commons.io.FileUtils may also be very handy, e.g.:
/**
* Reads the contents of a file line by line to a List
* of Strings using the default encoding for the VM.
*/
static List readLines(File file)
I documented 15 ways to read a file in Java and then tested them for speed with various file sizes - from 1 KB to 1 GB and here are the top three ways to do this:
java.nio.file.Files.readAllBytes()
Tested to work in Java 7, 8, and 9.
import java.io.File;
import java.io.IOException;
import java.nio.file.Files;
public class ReadFile_Files_ReadAllBytes {
public static void main(String [] pArgs) throws IOException {
String fileName = "c:\\temp\\sample-10KB.txt";
File file = new File(fileName);
byte [] fileBytes = Files.readAllBytes(file.toPath());
char singleChar;
for(byte b : fileBytes) {
singleChar = (char) b;
System.out.print(singleChar);
}
}
}
java.io.BufferedReader.readLine()
Tested to work in Java 7, 8, 9.
import java.io.BufferedReader;
import java.io.FileReader;
import java.io.IOException;
public class ReadFile_BufferedReader_ReadLine {
public static void main(String [] args) throws IOException {
String fileName = "c:\\temp\\sample-10KB.txt";
FileReader fileReader = new FileReader(fileName);
try (BufferedReader bufferedReader = new BufferedReader(fileReader)) {
String line;
while((line = bufferedReader.readLine()) != null) {
System.out.println(line);
}
}
}
}
java.nio.file.Files.lines()
This was tested to work in Java 8 and 9 but won't work in Java 7 because of the lambda expression requirement.
import java.io.File;
import java.io.IOException;
import java.nio.file.Files;
import java.util.stream.Stream;
public class ReadFile_Files_Lines {
public static void main(String[] pArgs) throws IOException {
String fileName = "c:\\temp\\sample-10KB.txt";
File file = new File(fileName);
try (Stream linesStream = Files.lines(file.toPath())) {
linesStream.forEach(line -> {
System.out.println(line);
});
}
}
}
What do you want to do with the text? Is the file small enough to fit into memory? I would try to find the simplest way to handle the file for your needs. The FileUtils library is very handle for this.
for(String line: FileUtils.readLines("my-text-file"))
System.out.println(line);
Below is a one-liner of doing it in the Java 8 way. Assuming text.txt file is in the root of the project directory of the Eclipse.
Files.lines(Paths.get("text.txt")).collect(Collectors.toList());
The most intuitive method is introduced in Java 11 Files.readString
import java.io.*;
import java.nio.file.Files;
import java.nio.file.Paths;
public class App {
public static void main(String args[]) throws IOException {
String content = Files.readString(Paths.get("D:\\sandbox\\mvn\\my-app\\my-app.iml"));
System.out.print(content);
}
}
PHP has this luxury for decades! ☺
The buffered stream classes are much more performant in practice, so much so that the NIO.2 API includes methods that specifically return these stream classes, in part to encourage you always to use buffered streams in your application.
Here is an example:
Path path = Paths.get("/myfolder/myfile.ext");
try (BufferedReader reader = Files.newBufferedReader(path)) {
// Read from the stream
String currentLine = null;
while ((currentLine = reader.readLine()) != null)
//do your code here
} catch (IOException e) {
// Handle file I/O exception...
}
You can replace this code
BufferedReader reader = Files.newBufferedReader(path);
with
BufferedReader br = new BufferedReader(new FileReader("/myfolder/myfile.ext"));
I recommend this article to learn the main uses of Java NIO and IO.
Using BufferedReader:
import java.io.BufferedReader;
import java.io.FileNotFoundException;
import java.io.FileReader;
import java.io.IOException;
BufferedReader br;
try {
br = new BufferedReader(new FileReader("/fileToRead.txt"));
try {
String x;
while ( (x = br.readLine()) != null ) {
// Printing out each line in the file
System.out.println(x);
}
}
catch (IOException e) {
e.printStackTrace();
}
}
catch (FileNotFoundException e) {
System.out.println(e);
e.printStackTrace();
}
This is basically the exact same as Jesus Ramos' answer, except with File instead of FileReader plus iteration to step through the contents of the file.
Scanner in = new Scanner(new File("filename.txt"));
while (in.hasNext()) { // Iterates each line in the file
String line = in.nextLine();
// Do something with line
}
in.close(); // Don't forget to close resource leaks
... throws FileNotFoundException
Probably not as fast as with buffered I/O, but quite terse:
String content;
try (Scanner scanner = new Scanner(textFile).useDelimiter("\\Z")) {
content = scanner.next();
}
The \Z pattern tells the Scanner that the delimiter is EOF.
The most simple way to read data from a file in Java is making use of the File class to read the file and the Scanner class to read the content of the file.
public static void main(String args[])throws Exception
{
File f = new File("input.txt");
takeInputIn2DArray(f);
}
public static void takeInputIn2DArray(File f) throws Exception
{
Scanner s = new Scanner(f);
int a[][] = new int[20][20];
for(int i=0; i<20; i++)
{
for(int j=0; j<20; j++)
{
a[i][j] = s.nextInt();
}
}
}
PS: Don't forget to import java.util.*; for Scanner to work.
You can use readAllLines and the join method to get whole file content in one line:
String str = String.join("\n",Files.readAllLines(Paths.get("e:\\text.txt")));
It uses UTF-8 encoding by default, which reads ASCII data correctly.
Also you can use readAllBytes:
String str = new String(Files.readAllBytes(Paths.get("e:\\text.txt")), StandardCharsets.UTF_8);
I think readAllBytes is faster and more precise, because it does not replace new line with \n and also new line may be \r\n. It is depending on your needs which one is suitable.
I don't see it mentioned yet in the other answers so far. But if "Best" means speed, then the new Java I/O (NIO) might provide the fastest preformance, but not always the easiest to figure out for someone learning.
http://download.oracle.com/javase/tutorial/essential/io/file.html
Guava provides a one-liner for this:
import com.google.common.base.Charsets;
import com.google.common.io.Files;
String contents = Files.toString(filePath, Charsets.UTF_8);
Cactoos give you a declarative one-liner:
new TextOf(new File("a.txt")).asString();
This might not be the exact answer to the question. It's just another way of reading a file where you do not explicitly specify the path to your file in your Java code and instead, you read it as a command-line argument.
With the following code,
import java.io.BufferedReader;
import java.io.InputStreamReader;
import java.io.IOException;
public class InputReader{
public static void main(String[] args)throws IOException{
BufferedReader br = new BufferedReader(new InputStreamReader(System.in));
String s="";
while((s=br.readLine())!=null){
System.out.println(s);
}
}
}
just go ahead and run it with:
java InputReader < input.txt
This would read the contents of the input.txt and print it to the your console.
You can also make your System.out.println() to write to a specific file through the command line as follows:
java InputReader < input.txt > output.txt
This would read from input.txt and write to output.txt.
For JSF-based Maven web applications, just use ClassLoader and the Resources folder to read in any file you want:
Put any file you want to read in the Resources folder.
Put the Apache Commons IO dependency into your POM:
<dependency>
<groupId>org.apache.commons</groupId>
<artifactId>commons-io</artifactId>
<version>1.3.2</version>
</dependency>
Use the code below to read it (e.g. below is reading in a .json file):
String metadata = null;
FileInputStream inputStream;
try {
ClassLoader loader = Thread.currentThread().getContextClassLoader();
inputStream = (FileInputStream) loader
.getResourceAsStream("/metadata.json");
metadata = IOUtils.toString(inputStream);
inputStream.close();
}
catch (FileNotFoundException e) {
// TODO Auto-generated catch block
e.printStackTrace();
}
catch (IOException e) {
// TODO Auto-generated catch block
e.printStackTrace();
}
return metadata;
You can do the same for text files, .properties files, XSD schemas, etc.
try {
File f = new File("filename.txt");
Scanner r = new Scanner(f);
while (r.hasNextLine()) {
String data = r.nextLine();
JOptionPane.showMessageDialog(data);
}
r.close();
} catch (FileNotFoundException ex) {
JOptionPane.showMessageDialog("Error occurred");
ex.printStackTrace();
}
Use Java kiss if this is about simplicity of structure:
import static kiss.API.*;
class App {
void run() {
String line;
try (Close in = inOpen("file.dat")) {
while ((line = readLine()) != null) {
println(line);
}
}
}
}
import java.util.stream.Stream;
import java.nio.file.*;
import java.io.*;
class ReadFile {
public static void main(String[] args) {
String filename = "Test.txt";
try(Stream<String> stream = Files.lines(Paths.get(filename))) {
stream.forEach(System.out:: println);
} catch (IOException e) {
e.printStackTrace();
}
}
}
Just use java 8 Stream.
In case you have a large file you can use Apache Commons IO to process the file iteratively without exhausting the available memory.
try (LineIterator it = FileUtils.lineIterator(theFile, "UTF-8")) {
while (it.hasNext()) {
String line = it.nextLine();
// do something with line
}
}
try (Stream<String> stream = Files.lines(Paths.get(String.valueOf(new File("yourFile.txt"))))) {
stream.forEach(System.out::println);
} catch (IOException e) {
e.printStackTrace();
}
new File(<path_name>)
Creates a new File instance by converting the given pathname string into an abstract pathname. If the given string is the empty string, then the result is the empty abstract pathname.
Params:
pathname – A pathname string
Throws:
NullPointerException – If the pathname argument is null
Files.lines returns a stream of String
Stream<String> stream = Files.lines(Paths.get(String.valueOf(new File("yourFile.txt"))))
can throw nullPointerExcetion , FileNotFoundException so, keepint it inside try will take care of Exception in runtime
stream.forEach(System.out::println);
This is used to iterate over the stream and print in console
If you have different use case you can provide your custome function to manipulate the stream of lines
My new favorite approach to simply read a whole text file from a BufferedReader input goes:
String text = input.lines().collect(Collectors.joining(System.lineSeparator())));
This will read the whole file by adding new line (lineSeparator) behind each line. Without the separator it would join all lines together as one.
This appears to have existed since Java 8.
For Android developers ending up here (who use Kotlin):
val myFileUrl = object{}.javaClass.getResource("/vegetables.txt")
val text = myFileUrl.readText() // Not recommended for huge files
println(text)
Other solution:
val myFileUrl = object{}.javaClass.getResource("/vegetables.txt")
val file = File(myFileUrl.toURI())
val lines = file.readLines() // Not recommended for huge files
lines.forEach(::println)
Another good solution which can be used for huge files as well:
val myFileUrl = object{}.javaClass.getResource("/vegetables.txt")
val file = File(myFileUrl.toURI())
file
.bufferedReader()
.lineSequence()
.forEach(::println)
Or:
val myFileUrl = object{}.javaClass.getResource("/vegetables.txt")
val file = File(myFileUrl.toURI())
file.useLines { lines ->
lines.forEach(::println)
}
Notes:
The vegetables.txt file should be in your classpath (for example, in src/main/resources directory)
The above solutions all treat the file encodings as UTF-8 by default. You can specify your desired encoding as the argument for the functions.
The above solutions do not need any further action like closing the files or readers. They are automatically taken care of by the Kotlin standard library.

Reading contents of excel file

I am looking for some help with reading contents from a excel file.
Here is the code, I want it to read from the .csv file and
generate the result for the same.
My error shows
java.lang.NumberFormatException: For input string: "companycode"
at sun.misc.FloatingDecimal.readJavaFormatString(FloatingDecimal.java:2043)
at sun.misc.FloatingDecimal.parseDouble(FloatingDecimal.java:110)
at java.lang.Double.parseDouble(Double.java:538)
at java.lang.Double.valueOf(Double.java:502)
at testgbt.TestGBT.main(TestGBT.java:40)
Please help and thanks in advance!!
package testgbt;
import java.io.BufferedReader;
import java.io.FileInputStream;
import java.io.FileWriter;
import java.io.InputStreamReader;
import java.util.Vector;
import java.io.FileOutputStream;
import testgbt.BoostingTree;
import testgbt.BoostingTree.ResultFunction;
public class TestGBT {
public static void main(String[] args) {
String data_name = "C:\\Mihir\\NetBeans\\TestGBT\\data.csv";
Vector<Vector<Double>> x = new Vector<Vector<Double>>();
Vector<Double> y = new Vector<Double>();
try {
FileInputStream fis = new FileInputStream("C:\\Mihir\\NetBeans\\TestGBT\\data.csv");
// -------- load data from the file -------------
// get object of data input stream
BufferedReader b_reader = new BufferedReader(new
InputStreamReader(new FileInputStream(data_name))); // buffer
String read_line;
while ((read_line = b_reader.readLine()) != null) {
String[] str_list = read_line.trim().split(",");
Vector<Double> buffer_x = new Vector<Double>();
buffer_x.add(Double.valueOf(str_list[0]));
x.add(buffer_x);
y.add(Double.valueOf(str_list[1]));
}
b_reader.close();
// --------- learn a function of y=f(x) -------
BoostingTree gbt_ranker = new BoostingTree();
ResultFunction res_fun = gbt_ranker.gradient_boosting_tree(x, y);
// --------- save the curve fitting result y=f(x) ------
FileWriter file_writer = new FileWriter("C:\\Mihir\\NetBeans\\TestGBT\\result.txt");
FileOutputStream fos=new FileOutputStream("C:\\Mihir\\NetBeans\\TestGBT\\result.csv");
for (int i = 0; i < x.size(); i ++) {
file_writer.append(String.format("%f,%f,%f\n",
x.get(i).get(0),
res_fun.get_value(x.get(i)),
y.get(i)));
}
file_writer.close();
} catch (Exception err) {
err.printStackTrace();
System.exit(0);
}
}
}
Does your input CSV have a header row? Remove the header row from your input data or change your code to skip the first line.
You can skip the first row easily by changing this line:
String read_line;
to this:
String read_line = b_reader.readLine();
Looks like str_list[1] isn't the data you're looking for. In fact, it looks like you're trying to convert one of your column headers into a double. You probably just need to skip past the headers.

Java File .write() a stream of integers

I run this code, I get "File written !" and when I open the file to see it, every thing that is written is not making any sense. You can understand that I want to write 012345678910 in the file. Is there any other way to write in file than buffW.write(k);. Are there any other mistakes I made?
package thema4_create_write_read_file;
import java.io.BufferedWriter;
import java.io.File;
import java.io.FileWriter;
public class FW {
public static void main(String[] args) {
File newFile = new File("newFile.txt");
if (newFile.exists()) {
System.out.println("The file already exists");
} else {
try {
newFile.createNewFile();
} catch (Exception e) {
e.printStackTrace();
}
try {
FileWriter fileW = new FileWriter(newFile);
BufferedWriter buffW = new BufferedWriter(fileW);
for (int k = 0; k <= 10; k++) {
buffW.write(k); // This is where the problem occurs
}
buffW.close();
System.out.print("File written !");
} catch (Exception e) {
e.printStackTrace();
}
}
}
}
Is there any way of writing (k) as integer and not as string ,in order to read it as int then?
Bufferedwriter#write(int c):
Writes a single character.
Parameters:
c - int specifying a character to be written
Use Writer#write(String)
writer.write(String.valueOf(integer));
BufferedWriter#write(int i) writes character that corresponds to i in Unicode Table you can take a look what will be written by using
System.out.print((char)k);
Now if you want to write int value of k you should probably use PrintWriter
PrintWriter printW = new PrintWriter(fileW);
printW.print(k);
You can also take a look at PrintStream#print() method (System.out is instance of PrintStream) but Writers are preferred over Streams for character I/O operations.

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