NumberFormat df = NumberFormat.getNumberInstance();
df.setMaximumFractionDigits (2);
df.setMinimumFractionDigits (2);
double[] floatValues = new double[5];
String Input;
Input = stdin.readLine();
String[] floatValue = Input.split("\\s+");
while (letter != 'q' && letter != 'Q'){
for (int i = 0; i < floatValue.length; ++i){
floatValues[i] = Double.parseDouble (floatValue[i]);
System.out.println("LWL:" + df.format((floatValues[1])));
System.out.println("Hull Speed:" + df.format(1.34 * Math.sqrt(floatValues[1])));
This is part of the code, I'm suppose to input 5 numbers like: 34.5 24.0 10.2 11200 483. My program runs perfectly, the only problem is that the output is suppose to be 11200 and I get 11,200. How do I get it to not output the comma. Thank You.
This is the issue:
NumberFormat df = NumberFormat.getNumberInstance();
That's getting the format for your machine's default locale, which presumably uses a comma as the decimal point. Just use the US locale:
NumberFormat df = NumberFormat.getNumberInstance(Locale.US);
That will then use a dot for the decimal point regardless of your machine's locale.
Call df.setGroupingUsed(false).
From java.text.NumberFormat.isGroupingUsed():
Returns true if grouping is used in this format. For example, in the English locale, with grouping on, the number 1234567 might be formatted as "1,234,567". The grouping separator as well as the size of each group is locale dependant and is determined by sub-classes of NumberFormat.
This will result in the output "11200.00". If you really want "11200", i.e. no fraction digits (contrary to your code), call df.setMaximumFractionDigits(0) and discard df.setMinimumFractionDigits(2).
Related
I'm trying to to format a number using the DecimalFormat but the problem that I didn't get the expected result. Here is the problem:
I have this number: 1439131519 and I want to print only the five first digits but with a comma after 4 digits like this: 1439,1. I have tried to use DecimalFormat but it didn't work.
I tried like this but it dosen't work:
public static DecimalFormat format2 = new DecimalFormat("0000.0");
Anyone have an idea?
It is easier to do with maths rather than formatting.
Assuming your number is in a double:
double d = 1439131519;
d = d / 100000; // d = 14391,31519
d = Math.round(d) // d = 14391
d = d / 10; // d = 1439,1
Of course, you can do it in one line of code if you want. In using Math.round I am assuming you want to round to the nearest value. If you want to round down you can use Math.floor.
The comma is the normal decimal separator in much of Europe, so that might work by default in your locale. If not, you can force it by getting the formatter for a locale such as Germany. See: How to change the decimal separator of DecimalFormat from comma to dot/point?.
For example in USA 1000000 represented as 1,000,000 (1 million) but in India it is represented as 10,00,000 (10 lakh). For this I tried some methods
double value = 1000000d;
NumberFormat numberFormatter = NumberFormat.getNumberInstance(new Locale("en", "IN"));
System.out.println(numberFormatter.format(value));
NumberFormat deci = new DecimalFormat("#,##,##,###.##");
System.out.println("Decimal Format "+deci.format(value));
NumberFormat format = NumberFormat.getNumberInstance();
format.setCurrency(Currency.getInstance("INR"));
format.setMaximumFractionDigits(2);
System.out.println(format.format(value));
But all these methods give an output as 1,000,000 but I require format 10,00,000. What do I need to change here?
Java decimal formatter doesn't support groups From Docs :
The grouping separator is commonly used for thousands, but in some
countries it separates ten-thousands. The grouping size is a constant
number of digits between the grouping characters, such as 3 for
100,000,000 or 4 for 1,0000,0000. If you supply a pattern with
multiple grouping characters, the interval between the last one and
the end of the integer is the one that is used. So "#,##,###,####" ==
"######,####" == "##,####,####".
You will need another library for this. Suggest this :
http://site.icu-project.org/
https://mvnrepository.com/artifact/com.ibm.icu/icu4j/69.1
Code
double value = 1000000d;
NumberFormat numberFormatter = NumberFormat.getNumberInstance(new Locale("en", "IN"));
System.out.println(numberFormatter.format(value));
Output :
10,00,000
public static String fmt(String s)
{
String formatted = "";
if(s.length() > 1){
formatted = s.substring(0,1);
s = s.substring(1);
}
while(s.length() > 3){
formatted += "," + s.substring(0,2);
s = s.substring(2);
}
return formatted + "," + s + ".00";
}
I want to make a number format like 000"+"000. The rule will be 3 digits "+" 3 digits. I will give you some examples below.
I have tried some codes before i will show them below. I think i have to use NumberFormat class. My codes are below. by the way my number maximum have 6 digits if number has less digits the missing digits(which will be in left), has to be 0.
I tried
NumberFormat numberFormat = new DecimalFormat("000'+'000");
but it gave error which is
Unquoted special character '0' in pattern "000'+'000"
but it was worked when i make
NumberFormat numberFormat = new DecimalFormat("'+'000");
or
NumberFormat numberFormat = new DecimalFormat("000'+'");
So simply i can make number-plus or plus-number but i can't make number(3 digit)-plus-number(3 digit)
I expect to get these outputs for these inputs:
input: 4032
output: 004+032
input : 5
output: 000+005
input: 123450
output: 123+450
input: 10450
output: 010+450
With a trick: change the grouping separator symbol to +:
DecimalFormatSymbols symbols = new DecimalFormatSymbols(Locale.getDefault());
symbols.setGroupingSeparator('+');
NumberFormat nf = new DecimalFormat("000,000", symbols);
int x = 3250;
System.out.println(nf.format(x));
Result:
003+250
Or use a method like this:
public static String specialFormat(int number) {
NumberFormat nf = new DecimalFormat("000");
return nf.format(number / 1000) + "+" + nf.format(number % 1000);
}
it formats separately the 3 first digits and the 3 last digits and concatenates with a + in the middle.
Use it:
int x = 5023;
System.out.println(specialFormat(x));
Result:
005+023
What you want is not a decimal syntax. Therefor, you cannot use the DecimalFormat, because it handles all kinds of localized numbers but not arbitrary ones like yours. However, you might want to implement your own java.text.Format.
What about using this kind of method and later convert it to the format you want
generateNumbers(String val) {
int len = val.length();
String finalValue;
StringBuffer sb = new StringBuffer();
if (len < 6) {
for (int i = 6; i > len; i--) {
sb.append("0");
}
finalValue = sb.append(val).toString();
} else {
finalValue = val;
}
System.out.println(finalValue.substring(0, 3) + "+" + finalValue.substring(3));
}
for testing you can call this
generateNumbers("4032");
generateNumbers("5");
generateNumbers("123450");
generateNumbers("10450");
Output is
004+032
000+005
123+450
010+450
Let me know if it's useful.
What is the best way to format the following number that is given to me as a String?
String number = "1000500000.574" //assume my value will always be a String
I want this to be a String with the value: 1,000,500,000.57
How can I format it as such?
You might want to look at the DecimalFormat class; it supports different locales (eg: in some countries that would get formatted as 1.000.500.000,57 instead).
You also need to convert that string into a number, this can be done with:
double amount = Double.parseDouble(number);
Code sample:
String number = "1000500000.574";
double amount = Double.parseDouble(number);
DecimalFormat formatter = new DecimalFormat("#,###.00");
System.out.println(formatter.format(amount));
This can also be accomplished using String.format(), which may be easier and/or more flexible if you are formatting multiple numbers in one string.
String number = "1000500000.574";
Double numParsed = Double.parseDouble(number);
System.out.println(String.format("The input number is: %,.2f", numParsed));
// Or
String numString = String.format("%,.2f", numParsed);
For the format string "%,.2f" - "," means separate digit groups with commas, and ".2" means round to two places after the decimal.
For reference on other formatting options, see https://docs.oracle.com/javase/tutorial/java/data/numberformat.html
Given this is the number one Google result for format number commas java, here's an answer that works for people who are working with whole numbers and don't care about decimals.
String.format("%,d", 2000000)
outputs:
2,000,000
Once you've converted your String to a number, you can use
// format the number for the default locale
NumberFormat.getInstance().format(num)
or
// format the number for a particular locale
NumberFormat.getInstance(locale).format(num)
I've created my own formatting utility. Which is extremely fast at processing the formatting along with giving you many features :)
It supports:
Comma Formatting E.g. 1234567 becomes 1,234,567.
Prefixing with "Thousand(K),Million(M),Billion(B),Trillion(T)".
Precision of 0 through 15.
Precision re-sizing (Means if you want 6 digit precision, but only have 3 available digits it forces it to 3).
Prefix lowering (Means if the prefix you choose is too large it lowers it to a more suitable prefix).
The code can be found here. You call it like this:
public static void main(String[])
{
int settings = ValueFormat.COMMAS | ValueFormat.PRECISION(2) | ValueFormat.MILLIONS;
String formatted = ValueFormat.format(1234567, settings);
}
I should also point out this doesn't handle decimal support, but is very useful for integer values. The above example would show "1.23M" as the output. I could probably add decimal support maybe, but didn't see too much use for it since then I might as well merge this into a BigInteger type of class that handles compressed char[] arrays for math computations.
you can also use the below solution
public static String getRoundOffValue(double value){
DecimalFormat df = new DecimalFormat("##,##,##,##,##,##,##0.00");
return df.format(value);
}
public void convert(int s)
{
System.out.println(NumberFormat.getNumberInstance(Locale.US).format(s));
}
public static void main(String args[])
{
LocalEx n=new LocalEx();
n.convert(10000);
}
You can do the entire conversion in one line, using the following code:
String number = "1000500000.574";
String convertedString = new DecimalFormat("#,###.##").format(Double.parseDouble(number));
The last two # signs in the DecimalFormat constructor can also be 0s. Either way works.
Here is the simplest way to get there:
String number = "10987655.876";
double result = Double.parseDouble(number);
System.out.println(String.format("%,.2f",result));
output:
10,987,655.88
The first answer works very well, but for ZERO / 0 it will format as .00
Hence the format #,##0.00 is working well for me.
Always test different numbers such as 0 / 100 / 2334.30 and negative numbers before deploying to production system.
According to chartGPT
Using DecimalFormat:
DecimalFormat df = new DecimalFormat("#,###.00");
String formattedNumber = df.format(yourNumber);
Using NumberFormat:
NumberFormat nf = NumberFormat.getNumberInstance();
nf.setGroupingUsed(true);
String formattedNumber = nf.format(yourNumber);
Using String.format():
String formattedNumber = String.format("%,.2f", yourNumber);
Note: In all the above examples, "yourNumber" is the double value that you want to format with a comma. The ".2f" in the format string indicates that the decimal places should be rounded to 2 decimal places. You can adjust this value as needed.
My percentages get truncated by the default java.text.MessageFormat function, how do you format a percentage without losing precision?
Example:
String expectedResult = "12.5%";
double fraction = 0.125;
String actualResult = MessageFormat.format("{0,number,percent}", fraction);
assert expectedResult.equals(actualResult) : actualResult +" should be formatted as "+expectedResult;
I think the proper way to do it is the following:
NumberFormat percentFormat = NumberFormat.getPercentInstance();
percentFormat.setMaximumFractionDigits(1);
String result = percentFormat.format(0.125);
It also takes internalization into account. For example on my machine with hungarian locale I got "12,5%" as expected. Initializing percentFormat as NumberFormat.getPercentInstance(Locale.US) gives "12.5%" of course.
Looks like this:
String actualResult = MessageFormat.format("{0,number,#.##%}", fraction);
... is working.
EDIT: To see how are the #'s and %'s interpreted, see the javadoc of java.text.DecimalFormat.
EDIT 2: And, yes, it is safe for internationalization. The dot in format string is interpreted as a decimal separator, not as a hardcoded dot. :-)
How about
DecimalFormat f = new DecimalFormat( "###.#" );
System.out.println( f.format( 12.5 ) );
The format char '#' does not print a 0 as absent. So 12.5 ->"12.5", 12.0 -> "12", not "12.0". You could of course set up your formatter with e.g. "###,###.##", the hundreths place will only show up if you need the precision.
You do realize that "expectedResult == actualResult" will always be false, right?
Anyway, the best solution I can find is to set the formatter explicitly. This is the code I tested:
String expectedResult = "12.5%";
double fraction = 0.125;
MessageFormat fmt = new MessageFormat("{0,number,percent}");
NumberFormat nbFmt = NumberFormat.getPercentInstance();
nbFmt.setMaximumFractionDigits(1); // or 2, or however many you need
fmt.setFormatByArgumentIndex(0, nbFmt);
String actualResult = fmt.format(new Object[] {fraction});
assert expectedResult.equals(actualResult) : actualResult +" is getting rounded off";
If internationalization is a concern:
// get locale from somewhere. default is usually a bad idea, especially
// if running in a app server
Locale locale = Locale.getDefault();
NumberFormat fmt = NumberFormat.getPercentInstance(locale);
// the question requires 1 digit for fractional part
// therefore set both, minimum and maximum digit count
fmt.setMinimumFractionDigits(1);
fmt.setMaximumFractionDigits(1);
// set grouping, if you expect large values
// notabene: not all languages use 3 digits per group
fmt.setGroupingUsed(true);
// output the example of the original question
System.out.println(fmt.format(0.125));
The percent number formatter appends a space and the percent sign to the output in the locales I know. I don't know, whether the position of the percent sign is before the digits in other locales (right-to-left locales for instance).
My solution renders as many fractional digits as scale was set on given Number. Unit tested with many primitive and Number types.
/**
* Formats the given Number as percentage with necessary precision.
* This serves as a workaround for {#link NumberFormat#getPercentInstance()} which does not renders fractional
* digits.
*
* #param number
* #param locale
*
* #return
*/
public static String formatPercentFraction(final Number number, final Locale locale)
{
if (number == null)
return null;
// get string representation with dot
final String strNumber = NumberFormat.getNumberInstance(Locale.US).format(number.doubleValue());
// create exact BigDecimal and convert to get scale
final BigDecimal dNumber = new BigDecimal(strNumber).multiply(new BigDecimal(100));
final NumberFormat percentScaleFormat = NumberFormat.getPercentInstance(locale);
percentScaleFormat.setMaximumFractionDigits(Math.max(0, dNumber.scale()));
// convert back for locale percent formatter
return percentScaleFormat.format(dNumber.multiply(new BigDecimal(0.01)));
}