Have a class be subclass for several super classes - java

There are several (5+) classes, in code I cannot change, that I need to extend by a few fields. Is there any way to do this without writing (and editing every time I need to change something) the almost exactly same code 5 times? So is there any more elegant way than this:
class Subclass1 extends Superclass1 {
private String newField;
public String getNewField() {
return newField;
}
public void setNewField(String newField) {
this.newField = newField;
}
}
class Subclass2 extends Superclass2 {
private String newField;
public String getNewField() {
return newField;
}
public void setNewField(String newField) {
this.newField = newField;
}
}
//...
I do NOT want multiple inheritance, I want 5 seperate subclasses - just without the duplicate code, because the subclasses all add exactly the same.
The only alternative I can think of is copying the original classes and having the copy extend a Superclass which is probably even worse.

No, you can't do this in Java. You can in certain other JVM-based languages, such as Scala (traits). However, if you must use plain Java, you might consider the following:
Determine the (hopefully single) purpose of the fields you are adding, and the behavior that you want.
Create a new class encompassing all of the fields and the new methods. For example:
public class ExtraFields // Don't use this name!
{
private String myExtraField1;
private String myExtraField2;
// etc.
public void doSomethingWithExtraFields() {
// etc.
}
}
Then, you could take one of the following approaches:
Subclass each of the five classes, and add one field, which is an instance of the class you created above, and delegate behavior accordingly. You will have to use this approach if you must have the extra fields in places where you must pass in one of your five classes. For example:
public class Subclass1 extends Superclass1
{
private ExtraFields extraFields;
public MySubclass()
{
super();
extraFields = new ExtraFields();
}
public void doSomethingWithExtraFields()
{
extraFields.doSomethingWithExtraFields();
}
}
Create a new wrapper class that contains an instance of both your new class created above, and one of those five subclasses. You can make this typesafe using generics. For example:
public class Wrapper<T> // Don't use this name either...
{
private ExtraFields extraFields;
private T myClass;
public Wrapper(T myClass) {
this.myClass = myClass;
this.extraFields = new ExtraFields();
}
}
In this second approach, you don't strictly need the ExtraFields class. But it's still often a good idea to do this so as to encapsulate related functionality.
Hope that helps!

Since you can't change the base classes, it's impossible to eliminate the redundancy. Eric Galluzzo's idea to store the extra fields in a separate class is the best one so far, but I don't know if that's practical in your case. If it isn't, create an interface that defines the extra fields. You'll still have to do a lot of repetitive typing, but at least you'll know immediately when you've made a mistake.

You could use a generic wrapper class, as long as it wouldn't be too tedious to change the rest of the code that works with it.
class Wrapper<E> {
private E obj;
private String newField;
public Wrapper (E obj) {
this.obj = obj;
}
public E get() {
return obj;
}
public String getNewField() {
return newField;
}
public void setNewField(String newField) {
this.newField = newField;
}
}

Related

What pattern should be used, strategy?

I do have a service which needs to handle two types of meal.
#Service
class MealService {
private final List<MealStrategy> strategies;
MealService(…) {
this.strategies = strategies;
}
void handle() {
var foo = …;
var bar = …;
strategies.forEach(s -> s.remove(foo, bar));
}
}
There are two strategies, ‘BurgerStrategy’ and ‘PastaStrategy’. Both implements Strategy interface with one method called remove which takes two parameters.
BurgerStrategy class retrieves meals of enum type burger from the database and iterate over them and perform some operations. Similar stuff does the PastaStrategy.
The question is, does it make sense to call it Strategy and implement it this way or not?
Also, how to handle duplications of the code in those two services, let’s say both share the same private methods. Does it make sense to create a Helper class or something?
does it make sense to call it Strategy and implement it this way or not
I think these classes ‘BurgerStrategy’ and ‘PastaStrategy’ have common behaviour. Strategy pattern is used when you want to inject one strategy and use it. However, you are iterating through all behaviors. You did not set behaviour by getting one strategy and stick with it. So, in my honour opinion, I think it is better to avoid Strategy word here.
So strategy pattern would look like this. I am sorry, I am not Java guy. Let me show via C#. But I've provided comments of how code could look in Java.
This is our abstraction of strategy:
public interface ISoundBehaviour
{
void Make();
}
and its concrete implementation:
public class DogSound : ISoundBehaviour // implements in Java
{
public void Make()
{
Console.WriteLine("Woof");
}
}
public class CatSound : ISoundBehaviour
{
public void Make()
{
Console.WriteLine("Meow");
}
}
And then we stick with one behaviour that can also be replaced:
public class Dog
{
ISoundBehaviour _soundBehaviour;
public Dog(ISoundBehaviour soundBehaviour)
{
_soundBehaviour = soundBehaviour;
}
public void Bark()
{
_soundBehaviour.Make();
}
public void SetAnotherSound(ISoundBehaviour anotherSoundBehaviour)
{
_soundBehaviour = anotherSoundBehaviour;
}
}
how to handle duplications of the code in those two services, let’s say both share the same private methods.
You can create one base, abstract class. So basic idea is to put common logic into some base common class. Then we should create abstract method in abstract class. Why? By doing this, subclasses will have particular logic for concrete case. Let me show an example.
An abstract class which has common behaviour:
public abstract class BaseMeal
{
// I am not Java guy, but if I am not mistaken, in Java,
// if you do not want method to be overriden, you shoud use `final` keyword
public void CommonBehaviourHere()
{
// put here code that can be shared among subclasses to avoid code duplication
}
public abstract void UnCommonBehaviourShouldBeImplementedBySubclass();
}
And its concrete implementations:
public class BurgerSubclass : BaseMeal // extends in Java
{
public override void UnCommonBehaviourShouldBeImplementedBySubclass()
{
throw new NotImplementedException();
}
}
public class PastaSubclass : BaseMeal // extends in Java
{
public override void UnCommonBehaviourShouldBeImplementedBySubclass()
{
throw new NotImplementedException();
}
}

How to make two classes which both have method with the same name, signature and return type behave like they would implement the same interface

I will explain my question on an example.
I have two classes NumberGeneratorApple and NumberGeneratorOrange. Both of them have method with the same signature and return type public Integer getNumber(). The problem is they do not implement the same interface althought it would be logical. I could make interface with this method and modify these classes to implement it but I don't want to do so. Here is why. These classes are generated automatically from let's say xml. In real example there are dozens of such classes. We have to generate them from time to time and it overwrites the old ones. I don't want to change each class manually to implement interface after each generation. Also it might not be obvious that it should be done for some other person working on the same project and even for me after some time.
Here is the first class:
public class NumberGeneratorApple {
public Integer getNumber(){
return 9;
}
}
and the second one:
public class NumberGeneratorOrange {
public Integer getNumber(){
return 19;
}
}
Althought they don't implement the same interface I need to use them in a generic way. I just want to do something like this:
public class ClassThatOperates<T extends NumberGeneratorInterface> {
T generator;
public ClassThatOperates(T generator) {
this.generator = generator;
}
public void doSomeOperation(){
//Obviously it won't work for NumberGeneratorApple and NumberGeneratorOrange
// because they do not implement NumberGeneratorInterface
//And if I change "<T extends NumberGeneratorInterface>" to "<T>"
// I cannot write method call "generator.getNumber()"
System.out.print("The number with constant is: ");
System.out.println(generator.getNumber() + 5);
}
}
This is the interface (I know public is not necessary there and it is there by default. I just want to emphasize it):
public interface NumberGeneratorInterface {
public Integer getNumber();
}
As you can see it is impossible to do such thing because neither NumberGeneratorApple nor NumberGeneratorOrange implements NumberGeneratorInterface. However I came up with some solution but following my instinct I think it is rather poor. I made wrapper classes:
public class NumberGeneratorAppleWrapper extends NumberGeneratorApple implements NumberGeneratorInterface {
}
and
public class NumberGeneratorOrangeWrapper extends NumberGeneratorOrange implements NumberGeneratorInterface {
}
It is a little bit tricky. It might be not obvious at first but when you call getNumber() on object of one of this classes you call in fact something like this:
#Override
public Integer getNumber() {
return super.getNumber();
}
Now I can call it this way:
public class Main {
public static void main(String[] args) {
ClassThatOperates<NumberGeneratorAppleWrapper> classThatOperatesApple = new ClassThatOperates<>(new NumberGeneratorAppleWrapper());
ClassThatOperates<NumberGeneratorOrangeWrapper> classThatOperatesOrange = new ClassThatOperates<>(new NumberGeneratorOrangeWrapper());
classThatOperatesApple.doSomeOperation();
classThatOperatesOrange.doSomeOperation();
}
}
And I get the following output:
The number with constant is: 14
The number with constant is: 24
The advantage of such approach instead of adding manually implements NumberGeneratorInterface to each generated class is that We don't have to repeat the same work after each generation (which overrides old classes). We only have to add a new wrapper when generation results in some new, additional class.
I know that in such scenario I can get rid of generics in ClassThatOperates and just declare NumberGeneratorInterface generator; without <T extends...> and so on (and I even should) so the code would be simpler, but I want to make this example quite similar to what I found in some real project. I wrote: I have, I made, I came up etc. but in fact it is based on the already existing code that I found in some project.
There are my questions:
1. Is there a better solution?
2. Is this solution a so called "bad taste"?
3. If I have to use such solution maybe my whole approach is wrong?
4. If there is no better solution even if the whole approach is wrong what could be improved in this code (including getting rid of generics)?
Is there a better solution?
Your solution looks good to me. You have used the Adapter Pattern, which uses existing functionality to conform to an otherwise unrelated interface. Without changing NumberGeneratorApple and NumberGeneratorOrange, you have adapted those classes' functionality to NumberGeneratorInterface.
More generally, you can have existing methods with different signatures be adapted to an interface, e.g. if you had
public class NumberGeneratorApple {
public Integer getAppleNumber(){
return 9;
}
}
Then your adapter class would explicitly call getAppleNumber when implementing the interface.
public class NumberGeneratorAppleWrapper extends NumberGeneratorApple implements NumberGeneratorInterface {
#Override
public Integer getNumber() {
return getAppleNumber();
}
}
Is this solution a so called "bad taste"?
This solution leaves no bad taste. The Adapter Pattern is a well established software design pattern.
If I have to use such solution maybe my whole approach is wrong?
If you cannot change existing classes such as NumberGeneratorApple, then the Adapter Pattern is the way to go. If you can change them, then just have the classes implement the necessary interface directly.
public class NumberGeneratorApple implements NumberGeneratorInterface {
#Override
public Integer getNumber() {
return 9;
}
}
Or, if the method signature is different:
public class NumberGeneratorApple implements NumberGeneratorInterface {
public Integer getAppleNumber() {
return 9;
}
#Override
public Integer getNumber() {
return getAppleNumber();
}
}
If there is no better solution even if the whole approach is wrong what could be improved in this code (including getting rid of generics)?
If your classes such as NumberGeneratorApple really have exactly one method, and are not just simplifications of more complex classes with multiple methods for the purposes of this question, then you can use method references as another answer has hinted. Instead of declaring your own interface NumberGeneratorInterface, a method reference can be typed as a Supplier<Integer>.
public class ClassThatOperates {
Supplier<Integer> generator;
public ClassThatOperates(Supplier<Integer> generator) {
this.generator = generator;
}
public void doSomeOperation(){
System.out.print("The number with constant is: ");
System.out.println(generator.get() + 5);
}
}
Then you can use it as:
NumberGeneratorOrange ngo = new NumberGeneratorOrange();
ClassThatOperates cto = new ClassThatOperates(ngo::getNumber);
cto.doSomeOperation();
With java8 you can instantiate one of your custom classes
NumberGeneratorApple apple = new NumberGeneratorApple();
and create a generic supplier from it:
Supplier<Integer> numberGenerator = apple::getNumber;
then you can pass it around or do whatever you need with it:
Integer number = numberGenerator.get();
externalObject.execute(numberGenerator);
How's that sound?
Consider:
class ClassThatOperates
{
final Supplier<Integer> m_generator;
ClassThatOperates(Supplier<Integer> generator)
{
m_generator = generator;
}
void doSomething()
{
...
m_generator.get();
}
}
NumberGeneratorApple nga = new NumberGeneratorApple();
ClassThatOperates cta = new ClassThatOperates(nga::generate);

Lazy initialization of subclass

In an effort to reduce my NCSS count of a class (~850), I have split all of the methods into their own classes and to make things easier, I extend an abstract class that holds all the helper functions.
AbstractMethod.class
public class AbstractMethod {
protected String requestWebPage(URL url) {
// download a webpage as a string
}
}
Example "account" subclass
public class AccountData extends AbstractMethod {
public String getAccount(String sessionId){
String webPage = requestWebPage("http://google.com/"+sessionId);
system.out.println(webPage);
return webPage;
}
}
I have approx 10 of these method classes and would like to only initialize them when one of the methods in the main/base class is called:
public class MyBaseClass() {
private static AccountData ad;
public MyBaseClass() {
ad = new AccountData(); // Is there a better way?
}
public String getAccount(String sessionId) {
return ad.getAccount(String sessionId);
}
}
I have tried to create an initialise function in the MyBaseClass class that accepts the subtype as a parameter and create an object based on it's class:
private void initAccount() {
if (ad == null) {
ad = new AccountData();
}
}
but it's ugly and I have to have one per sub-class.
So, what's the "correct" way to do this? Sometimes when the class is called, we will only use 1 or 2 of the methods, so I don't want to have to initialise all the sub-classes each time.
It would seem to me that what you really want is to use static methods rather than abstract helper classes, perhaps along with import static.
That way, the class(es) defining those methods would, as you wish, only be initialized once the methods are actually called.
You would also not limit your inheritence structure in general to where the methods happen to be defined.
That's assuming you don't use any instance data for those methods, of course; but from the looks of your sample code, it doesn't seem that way.
Instantiating classes in Java is cheap. If the classes are not doing anything substantial in their contructors then just do
public String getAccount(String sessionId) {
AccountData ad = new AccountData();
return ad.getAccount(String sessionId);
}
Don't optimize where it's not nessesary. Profile your code before. You might be suprised how wrong your assumtions are (I know I was many times).

remove duplicate code in java

class A extends ApiClass
{
public void duplicateMethod()
{
}
}
class B extends AnotherApiClass
{
public void duplicateMethod()
{
}
}
I have two classes which extend different api classes. The two class has some duplicate
methods(same method repeated in both class) and how to remove this duplication?
Edit
Both ApiClass and AnotherApiClass are not under my control
Depending on what the code is you could do something like:
public class Util
{
public static void duplicateMethod()
{
// code goes here
}
}
and then just have the other two duplicateMethods call that one. So the code would not be duplicated, but the method name and the call to the Util.duplicateMethod would be.
If the code in the Util.duplicateMethod needed to access instance/class variables of the A and B class it wouldn't work out so nicely, but it could potentially be done (let me know if you need that).
EDIT (based on comment):
With instance variables it gets less pretty... but can be done. Something like:
interface X
{
int getVar();
void setVar(A a);
}
class A
extends ApiClass
implements X
{
}
class B
extends AnotherApiClass
implements X
{
}
class Util
{
public static void duplicateMethod(X x)
{
int val = x.getVal();
x.setVal(val + 1);
}
}
So, for each variable you need to access you would make a method for get (and set if needed). I don't like this way since it make the get/set methods public which may mean you are making things available that you don't want to be available. An alternative would be to do something with reflection, but I'd like that even less :-)
Sounds like a case for the "Strategy Pattern".
class A extends ApiClass {
private ClassContainingDupMethod strategy;
}
class N extends AnotherApiClass {
private ClassContainingDupMethod strategy;
public methodCallingDupMethod(){
strategy.dupMethod();
}
}
class ClassContainingDupMethod{
public dupMethod(){;}
}
Or is the dupMethod inherted from the Api classes?
Duplicate methods that rely on member variables imply duplicate member variables, too - and that starts to smell like too-large classes. What would those specific member variables, with the method(s), look like, if you were to extract them into their own class, and then compose that class into your other classes? Prefer composition over inheritance.
class BaseApiClass
{
public void duplicateMethod()
{
}
}
class ApiClass extends BaseApiClass
{
}
class AnotherApiClass extends BaseApiClass
{
}
class A extends ApiClass
{
}
class B extends AnotherApiClass
{
}
You need to combine the classes into one object and then all classes using th other two classes, modify their code to use the single class.

Is there a way to simulate the C++ 'friend' concept in Java?

I would like to be able to write a Java class in one package which can access non-public methods of a class in another package without having to make it a subclass of the other class. Is this possible?
Here is a small trick that I use in JAVA to replicate C++ friend mechanism.
Lets say I have a class Romeo and another class Juliet. They are in different packages (family) for hatred reasons.
Romeo wants to cuddle Juliet and Juliet wants to only let Romeo cuddle her.
In C++, Juliet would declare Romeo as a (lover) friend but there are no such things in java.
Here are the classes and the trick :
Ladies first :
package capulet;
import montague.Romeo;
public class Juliet {
public static void cuddle(Romeo.Love love) {
Objects.requireNonNull(love);
System.out.println("O Romeo, Romeo, wherefore art thou Romeo?");
}
}
So the method Juliet.cuddle is public but you need a Romeo.Love to call it. It uses this Romeo.Love as a "signature security" to ensure that only Romeo can call this method and checks that the love is real so that the runtime will throw a NullPointerException if it is null.
Now boys :
package montague;
import capulet.Juliet;
public class Romeo {
public static final class Love { private Love() {} }
private static final Love love = new Love();
public static void cuddleJuliet() {
Juliet.cuddle(love);
}
}
The class Romeo.Love is public, but its constructor is private. Therefore anyone can see it, but only Romeo can construct it. I use a static reference so the Romeo.Love that is never used is only constructed once and does not impact optimization.
Therefore, Romeo can cuddle Juliet and only he can because only he can construct and access a Romeo.Love instance, which is required by Juliet to cuddle her (or else she'll slap you with a NullPointerException).
The designers of Java explicitly rejected the idea of friend as it works in C++. You put your "friends" in the same package. Private, protected, and packaged security is enforced as part of the language design.
James Gosling wanted Java to be C++ without the mistakes. I believe he felt that friend was a mistake because it violates OOP principles. Packages provide a reasonable way to organize components without being too purist about OOP.
NR pointed out that you could cheat using reflection, but even that only works if you aren't using the SecurityManager. If you turn on Java standard security, you won't be able to cheat with reflection unless you write security policy to specifically allow it.
The 'friend' concept is useful in Java, for example, to separate an API from its implementation. It is common for implementation classes to need access to API class internals but these should not be exposed to API clients. This can be achieved using the 'Friend Accessor' pattern as detailed below:
The class exposed through the API:
package api;
public final class Exposed {
static {
// Declare classes in the implementation package as 'friends'
Accessor.setInstance(new AccessorImpl());
}
// Only accessible by 'friend' classes.
Exposed() {
}
// Only accessible by 'friend' classes.
void sayHello() {
System.out.println("Hello");
}
static final class AccessorImpl extends Accessor {
protected Exposed createExposed() {
return new Exposed();
}
protected void sayHello(Exposed exposed) {
exposed.sayHello();
}
}
}
The class providing the 'friend' functionality:
package impl;
public abstract class Accessor {
private static Accessor instance;
static Accessor getInstance() {
Accessor a = instance;
if (a != null) {
return a;
}
return createInstance();
}
private static Accessor createInstance() {
try {
Class.forName(Exposed.class.getName(), true,
Exposed.class.getClassLoader());
} catch (ClassNotFoundException e) {
throw new IllegalStateException(e);
}
return instance;
}
public static void setInstance(Accessor accessor) {
if (instance != null) {
throw new IllegalStateException(
"Accessor instance already set");
}
instance = accessor;
}
protected abstract Exposed createExposed();
protected abstract void sayHello(Exposed exposed);
}
Example access from a class in the 'friend' implementation package:
package impl;
public final class FriendlyAccessExample {
public static void main(String[] args) {
Accessor accessor = Accessor.getInstance();
Exposed exposed = accessor.createExposed();
accessor.sayHello(exposed);
}
}
There are two solutions to your question that don't involve keeping all classes in the same package.
The first is to use the Friend Accessor/Friend Package pattern described in (Practical API Design, Tulach 2008).
The second is to use OSGi. There is an article here explaining how OSGi accomplishes this.
Related Questions: 1, 2, and 3.
As far as I know, it is not possible.
Maybe, You could give us some more details about Your design. Questions like these are likely the result of design flaws.
Just consider
Why are those classes in different packages, if they are so closely related?
Has A to access private members of B or should the operation be moved to class B and triggered by A?
Is this really calling or is event-handling better?
eirikma's answer is easy and excellent. I might add one more thing: instead of having a publicly accessible method, getFriend() to get a friend which cannot be used, you could go one step further and disallow getting the friend without a token: getFriend(Service.FriendToken). This FriendToken would be an inner public class with a private constructor, so that only Service could instantiate one.
Here's a clear use-case example with a reusable Friend class. The benefit of this mechanism is simplicity of use. Maybe good for giving unit test classes more access than the rest of the application.
To begin, here is an example of how to use the Friend class.
public class Owner {
private final String member = "value";
public String getMember(final Friend friend) {
// Make sure only a friend is accepted.
friend.is(Other.class);
return member;
}
}
Then in another package you can do this:
public class Other {
private final Friend friend = new Friend(this);
public void test() {
String s = new Owner().getMember(friend);
System.out.println(s);
}
}
The Friend class is as follows.
public final class Friend {
private final Class as;
public Friend(final Object is) {
as = is.getClass();
}
public void is(final Class c) {
if (c == as)
return;
throw new ClassCastException(String.format("%s is not an expected friend.", as.getName()));
}
public void is(final Class... classes) {
for (final Class c : classes)
if (c == as)
return;
is((Class)null);
}
}
However, the problem is that it can be abused like so:
public class Abuser {
public void doBadThings() {
Friend badFriend = new Friend(new Other());
String s = new Owner().getMember(badFriend);
System.out.println(s);
}
}
Now, it may be true that the Other class doesn't have any public constructors, therefore making the above Abuser code impossible. However, if your class does have a public constructor then it is probably advisable to duplicate the Friend class as an inner class. Take this Other2 class as an example:
public class Other2 {
private final Friend friend = new Friend();
public final class Friend {
private Friend() {}
public void check() {}
}
public void test() {
String s = new Owner2().getMember(friend);
System.out.println(s);
}
}
And then the Owner2 class would be like this:
public class Owner2 {
private final String member = "value";
public String getMember(final Other2.Friend friend) {
friend.check();
return member;
}
}
Notice that the Other2.Friend class has a private constructor, thus making this a much more secure way of doing it.
The provided solution was perhaps not the simplest. Another approach is based on the same idea as in C++: private members are not accessible outside the package/private scope, except for a specific class that the owner makes a friend of itself.
The class that needs friend access to a member should create a inner public abstract "friend class" that the class owning the hidden properties can export access to, by returning a subclass that implement the access-implementing methods. The "API" method of the friend class can be private so it is not accessible outside the class that needs friend access. Its only statement is a call to an abstract protected member that the exporting class implements.
Here's the code:
First the test that verifies that this actually works:
package application;
import application.entity.Entity;
import application.service.Service;
import junit.framework.TestCase;
public class EntityFriendTest extends TestCase {
public void testFriendsAreOkay() {
Entity entity = new Entity();
Service service = new Service();
assertNull("entity should not be processed yet", entity.getPublicData());
service.processEntity(entity);
assertNotNull("entity should be processed now", entity.getPublicData());
}
}
Then the Service that needs friend access to a package private member of Entity:
package application.service;
import application.entity.Entity;
public class Service {
public void processEntity(Entity entity) {
String value = entity.getFriend().getEntityPackagePrivateData();
entity.setPublicData(value);
}
/**
* Class that Entity explicitly can expose private aspects to subclasses of.
* Public, so the class itself is visible in Entity's package.
*/
public static abstract class EntityFriend {
/**
* Access method: private not visible (a.k.a 'friendly') outside enclosing class.
*/
private String getEntityPackagePrivateData() {
return getEntityPackagePrivateDataImpl();
}
/** contribute access to private member by implementing this */
protected abstract String getEntityPackagePrivateDataImpl();
}
}
Finally: the Entity class that provides friendly access to a package private member only to the class application.service.Service.
package application.entity;
import application.service.Service;
public class Entity {
private String publicData;
private String packagePrivateData = "secret";
public String getPublicData() {
return publicData;
}
public void setPublicData(String publicData) {
this.publicData = publicData;
}
String getPackagePrivateData() {
return packagePrivateData;
}
/** provide access to proteced method for Service'e helper class */
public Service.EntityFriend getFriend() {
return new Service.EntityFriend() {
protected String getEntityPackagePrivateDataImpl() {
return getPackagePrivateData();
}
};
}
}
Okay, I must admit it is a bit longer than "friend service::Service;" but it might be possible to shorten it while retaining compile-time checking by using annotations.
In Java it is possible to have a "package-related friendness".
This can be userful for unit testing.
If you do not specify private/public/protected in front of a method, it will be "friend in the package".
A class in the same package will be able to access it, but it will be private outside the class.
This rule is not always known, and it is a good approximation of a C++ "friend" keyword.
I find it a good replacement.
I think that friend classes in C++ are like inner-class concept in Java. Using inner-classes
you can actually define an enclosing class and an enclosed one. Enclosed class has full access to the public and private members of it's enclosing class.
see the following link:
http://docs.oracle.com/javase/tutorial/java/javaOO/nested.html
Not using a keyword or so.
You could "cheat" using reflection etc., but I wouldn't recommend "cheating".
I think, the approach of using the friend accessor pattern is way too complicated. I had to face the same problem and I solved using the good, old copy constructor, known from C++, in Java:
public class ProtectedContainer {
protected String iwantAccess;
protected ProtectedContainer() {
super();
iwantAccess = "Default string";
}
protected ProtectedContainer(ProtectedContainer other) {
super();
this.iwantAccess = other.iwantAccess;
}
public int calcSquare(int x) {
iwantAccess = "calculated square";
return x * x;
}
}
In your application you could write the following code:
public class MyApp {
private static class ProtectedAccessor extends ProtectedContainer {
protected ProtectedAccessor() {
super();
}
protected PrivateAccessor(ProtectedContainer prot) {
super(prot);
}
public String exposeProtected() {
return iwantAccess;
}
}
}
The advantage of this method is that only your application has access to the protected data. It's not exactly a substitution of the friend keyword. But I think it's quite suitable when you write custom libraries and you need to access protected data.
Whenever you have to deal with instances of ProtectedContainer you can wrap your ProtectedAccessor around it and you gain access.
It also works with protected methods. You define them protected in your API. Later in your application you write a private wrapper class and expose the protected method as public. That's it.
If you want to access protected methods you could create a subclass of the class you want to use that exposes the methods you want to use as public (or internal to the namespace to be safer), and have an instance of that class in your class (use it as a proxy).
As far as private methods are concerned (I think) you are out of luck.
I agree that in most cases the friend keyword is unnecessary.
Package-private (aka. default) is sufficient in most cases where you have a group of heavily intertwined classes
For debug classes that want access to internals, I usually make the method private and access it via reflection. Speed usually isn't important here
Sometimes, you implement a method that is a "hack" or otherwise which is subject to change. I make it public, but use #Deprecated to indicate that you shouldn't rely on this method existing.
And finally, if it really is necessary, there is the friend accessor pattern mentioned in the other answers.
A method I've found for solving this problem is to create an accessor object, like so:
class Foo {
private String locked;
/* Anyone can get locked. */
public String getLocked() { return locked; }
/* This is the accessor. Anyone with a reference to this has special access. */
public class FooAccessor {
private FooAccessor (){};
public void setLocked(String locked) { Foo.this.locked = locked; }
}
private FooAccessor accessor;
/** You get an accessor by calling this method. This method can only
* be called once, so calling is like claiming ownership of the accessor. */
public FooAccessor getAccessor() {
if (accessor != null)
throw new IllegalStateException("Cannot return accessor more than once!");
return accessor = new FooAccessor();
}
}
The first code to call getAccessor() "claims ownership" of the accessor. Usually, this is code that creates the object.
Foo bar = new Foo(); //This object is safe to share.
FooAccessor barAccessor = bar.getAccessor(); //This one is not.
This also has an advantage over C++'s friend mechanism, because it allows you to limit access on a per-instance level, as opposed to a per-class level. By controlling the accessor reference, you control access to the object. You can also create multiple accessors, and give different access to each, which allows fine-grained control over what code can access what:
class Foo {
private String secret;
private String locked;
/* Anyone can get locked. */
public String getLocked() { return locked; }
/* Normal accessor. Can write to locked, but not read secret. */
public class FooAccessor {
private FooAccessor (){};
public void setLocked(String locked) { Foo.this.locked = locked; }
}
private FooAccessor accessor;
public FooAccessor getAccessor() {
if (accessor != null)
throw new IllegalStateException("Cannot return accessor more than once!");
return accessor = new FooAccessor();
}
/* Super accessor. Allows access to secret. */
public class FooSuperAccessor {
private FooSuperAccessor (){};
public String getSecret() { return Foo.this.secret; }
}
private FooSuperAccessor superAccessor;
public FooSuperAccessor getAccessor() {
if (superAccessor != null)
throw new IllegalStateException("Cannot return accessor more than once!");
return superAccessor = new FooSuperAccessor();
}
}
Finally, if you'd like things to be a bit more organized, you can create a reference object, which holds everything together. This allows you to claim all accessors with one method call, as well as keep them together with their linked instance. Once you have the reference, you can pass the accessors out to the code that needs it:
class Foo {
private String secret;
private String locked;
public String getLocked() { return locked; }
public class FooAccessor {
private FooAccessor (){};
public void setLocked(String locked) { Foo.this.locked = locked; }
}
public class FooSuperAccessor {
private FooSuperAccessor (){};
public String getSecret() { return Foo.this.secret; }
}
public class FooReference {
public final Foo foo;
public final FooAccessor accessor;
public final FooSuperAccessor superAccessor;
private FooReference() {
this.foo = Foo.this;
this.accessor = new FooAccessor();
this.superAccessor = new FooSuperAccessor();
}
}
private FooReference reference;
/* Beware, anyone with this object has *all* the accessors! */
public FooReference getReference() {
if (reference != null)
throw new IllegalStateException("Cannot return reference more than once!");
return reference = new FooReference();
}
}
After much head-banging (not the good kind), this was my final solution, and I very much like it. It is flexible, simple to use, and allows very good control over class access. (The with reference only access is very useful.) If you use protected instead of private for the accessors/references, sub-classes of Foo can even return extended references from getReference. It also doesn't require any reflection, so it can be used in any environment.
I prefer delegation or composition or factory class (depending upon the issue that results in this problem) to avoid making it a public class.
If it is a "interface/implementation classes in different packages" problem, then I would use a public factory class that would in the same package as the impl package and prevent the exposure of the impl class.
If it is a "I hate to make this class/method public just to provide this functionality for some other class in a different package" problem, then I would use a public delegate class in the same package and expose only that part of the functionality needed by the "outsider" class.
Some of these decisions are driven by the target server classloading architecture (OSGi bundle, WAR/EAR, etc.), deployment and package naming conventions. For example, the above proposed solution, 'Friend Accessor' pattern is clever for normal java applications. I wonder if it gets tricky to implement it in OSGi due to the difference in classloading style.
I once saw a reflection based solution that did "friend checking" at runtime using reflection and checking the call stack to see if the class calling the method was permitted to do so. Being a runtime check, it has the obvious drawback.
As of Java 9, modules can be used to make this a non-issue in many cases.

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