Let's have the following:
Date inDbDate = null;
SimpleDateFormat sdf = new SimpleDateFormat("yyyy-MM-dd HH:mm:ss.SSS");
inDbDate = sdf.parse("2015-09-27 23:24:28.035");
Now, when I output the inDbDate I receive the following:
Sun Sep 27 23:24:28 EEST 2015
So, If I have two dates with millisecond differences, there would be no way to find out or to display it.
How do I compare two Dates with this format - 2015-09-27 23:24:28.035 ?
If you want to compare two Date variables, there are some methods provided after(), before(), equals().
private void someMethod(){
final String dateFormat = "yyyy-MM-dd HH:mm:ss.SSS";
Date firstDate = new Date();
Date secondDate = new Date();
SimpleDateFormat sdf = new SimpleDateFormat(dateFormat);
try {
firstDate = sdf.parse("2015-09-27 23:24:28.035");
secondDate = sdf.parse("2015-09-27 23:24:28.036");
} catch (ParseException pe) {
pe.getMessage();
}
if(firstDate.after(secondDate)) {
System.out.println("The first date is after the second date");
} else{
System.out.println("The first date is before the second date");
}
}
You can copy and paste the above method into your IDE, then try changing the time in the Date variables and see what the outcome is as well as changing the check performed in the if statement.
If you look at the values in one of the Date objects in your debugger you can see the milliseconds are there, just not shown when printed out in a certain format.
1/ you should parse inDbDate with date format ==> inDbDate = sdf.parse("2015-11-11 23:24:28.035");
2/ you can now compare the two dates
if (inDbDate.compareTo(new Date()) > 0) {
System.out.println("inDbDate is after the current date !!");
}
3/ if you want to display, you format it
System.out.println("current time = " + sdf.format(new Date()));
Related
I need to convert a time stamp that currently is in string format "08.00" to a valid time in java so I later can compare time. How do I convert this string to time?
Something like this
DateFormat sdf = new SimpleDateFormat("hh:mm");
Date date = sdf.parse(time);
Instead of using the Date and/or SimpleDateFormat classes, perhaps consider LocalTime
String time = "08:00";
LocalTime lt = LocalTime.parse(time);
System.out.println(lt);
Output:
08:00
And can compare to other times easily with LocalTime::isBefore() or LocalTime::isAfter()
Example
Try below code,
String time = "08.00";
try {
DateFormat sdfInput = new SimpleDateFormat("hh.mm");
Date date = sdfInput.parse(time);
DateFormat sdfOutput = new SimpleDateFormat("hh:mm");
Log.e( "Time: ", sdfOutput.format(date));
} catch (Exception e) {
e.printStackTrace();
}
Output -> Time: 08:00
The easiest way to do so is with a SimplDateFormatter:
DateFormat sdf = new SimpleDateFormat("hh:mm")
Then you can call Date date = sdf.parse(*your time string*)
Now you have your time as a valid Date object.
I have timeformat like this hhmmss="151918"
so you can use any format instead of hhmmss according to your current time format like
"hh.mm" or hh:mm:ss etc
and you can call this method form any where you needed.
fun convertTimeFormat(time:String):String{
var formattedTime=""
try {
val inputFormat: DateFormat = SimpleDateFormat("hhmmss")
val timeObj = inputFormat.parse(time)
Log.d("timeObj",""+timeObj)
formattedTime=SimpleDateFormat("hh:mm aa").format(timeObj)
} catch (e: ParseException) {
e.printStackTrace()
}
return formattedTime
}
I am trying to take date in string and its input format string and converting the date in output format. However after conversion into Date, the java code increases the number of hours by one. I am not able to understand what causes the bug.
My Code:
try {
DateFormat outputFormat = new SimpleDateFormat("dd/MM/yyyy hh:mm:ss");
DateFormat inputFormat = new SimpleDateFormat(format);
Date date = inputFormat.parse(parameterValue);
parameterValue = outputFormat.format(date);
return parameterValue;
} catch (ParseException ex) {
// take action
}
format string: ddMMMyyyy / hh:mm z
Input Date: 07DEC2015 / 10:02 GMT
Output Date: 07/12/2015 11:02:00
outputFormat.setTimeZone(TimeZone.getTimeZone("GMT"));
resolved it.
If you don't want to use timezone, in java 8 you can use LocalDate/LocalTime/LocalDateTime:
LocalDateTime localDateTimeInstance = LocalDateTime.parse(dateToBeConverted, DateTimeFormatter.ofPattern(formatOfDateToBeConverted));
return localDateTimeInstance.format("dd/MM/yyyy hh:mm:ss");
/*
Also check out ZoneDate, ZoneTime (for timezone)
Checkout - LocalDate, LocalTime
*/
I have the input string as 2012-07-27 and I want the output as Date but with the same format like 2012-07-27
Code
DateFormat df = new SimpleDateFormat("yyyy-MM-dd hh:mm:ss");
try {
Date today = df.parse("20-12-2005 23:59:59");
System.out.println("Today = " + df.format(today));
} catch (ParseException e) {
e.printStackTrace();
}
Output
20-12-2005 23:59:59
But it's string object I want the same output (20-12-2005 23:59:59) as date object not as string object.
How can I get the Date in the form DD-MM-YYYY HH:MM:SS?
Date today is the date object you get for input String. There are nothing like formatted dates in Java. Date is always just date object. You perform all sorts of operations on that date object and when you want to Store (or) display just apply format()
df.format(today) // is just for formatting and display purpose.
There is difference in your format passed to SimpleDateFormat and way you are passing date string. You should Also use HH
DateFormat df = new SimpleDateFormat("dd-MM-yyyy HH:mm:ss");
try {
Date today = df.parse("20-12-2005 23:59:59");
System.out.println("Today = " + df.format(today));
//To Print Real Today
System.out.println("Real Today = " + df.format(new Date()));
} catch (ParseException e) {
e.printStackTrace();
}
The Date class has many deprecated methods and the only correct way to create it right now is via a long (read doc for details).
You should look into GregorialCalendar where you can pass some constant fields of Calendar as attributes.
If you want to input the date from your String, I would either do a custom parser that creates a calendar or something like this.
Hope I helped :)
I have written a small program in which a user enters minutes and program shows the current Date and Time + minutes entered by the user.
final String DATE_FORMAT_NOW = "MM/dd/yyyy HH:mm:ss";
final DateFormat dateFormat = new SimpleDateFormat("MM/dd/yyyy HH:mm:ss", Locale.US);
Calendar cal = Calendar.getInstance();
cal.add(Calendar.MINUTE, Integer.valueOf(sample.getMinutes()));
SimpleDateFormat sdf = new SimpleDateFormat(DATE_FORMAT_NOW);
String dt = sdf.format(cal.getTime());
System.out.println(" Date and time with added Minutes : " + (dateFormat.parse(dt));
Sample
private String minutes;
//getter and setter
I am getting this exception
java.lang.NumberFormatException: For input string: ""
What I am doing wrong here?
Should I use
Integer.parseInt
or
Integer.valueOf(Integer.parseInt(sample.getMinutes())));?
With current date and time.
public static void main(String[] args)
{
try
{
final String DATE_FORMAT_NOW = "MM/dd/yyyy HH:mm:ss";
final DateFormat dateFormat = new SimpleDateFormat("MM/dd/yyyy HH:mm:ss", Locale.US);
Date sample = new Date();
int iMinutes = 30;//minutes added by the user
Calendar cal = Calendar.getInstance();
cal.add(Calendar.MINUTE, Integer.valueOf(sample.getMinutes()));
SimpleDateFormat sdf = new SimpleDateFormat(DATE_FORMAT_NOW);
String dt = sdf.format(cal.getTime());
System.out.println("Current Date and time:"+sample);
System.out.println("Date and time with added Minutes : " + (dateFormat.parse(dt)));
}
catch (ParseException ex)
{
Logger.getLogger(NewMain.class.getName()).log(Level.SEVERE, null, ex);
}
}
The output will be displays as:
Current Date and time:Tue Jun 12 15:57:55 IST 2012
Date and time with added Minutes : Tue Jun 12 16:54:55 IST 2012
Here the minutes "57" was added to the calendar and the time has moved forward by "30" mins.And that is the your result(Date and time with added Minutes).
With user in input minutes.
public static void main(String[] args)
{
try
{
final String DATE_FORMAT_NOW = "MM/dd/yyyy HH:mm:ss";
final DateFormat dateFormat = new SimpleDateFormat("MM/dd/yyyy HH:mm:ss", Locale.US);
int iMinutes = 30;//minutes added by the user
Calendar cal = Calendar.getInstance();
cal.add(Calendar.MINUTE, iMinutes);
SimpleDateFormat sdf = new SimpleDateFormat(DATE_FORMAT_NOW);
String dt = sdf.format(cal.getTime());
System.out.println("Current Date and time:"+sample);
System.out.println("Date and time with added Minutes : " + (dateFormat.parse(dt)));
}
catch (ParseException ex)
{
Logger.getLogger(NewMain.class.getName()).log(Level.SEVERE, null, ex);
}
}
This will work as per your desire first you take the minutes from the user and assign that minutes to the "iMinutes" variable of the code it will add that much minutes to the calander.
The output will be displayed as:
Current Date and time:Tue Jun 12 16:07:55 IST 2012
Date and time with added Minutes : Tue Jun 12 16:37:55 IST 2012
And if you want to set the minutes then use "set" instead of "add" in the "cal.add".
Hope this will solve your problem.
Regards.
Check if the returned string from sample.getMinutes() is a number or not. It must be a number without any white space to be parsed, otherwise you will get a NumberFormatException.
The problem you're having is that an empty string is not a valid integer. Your application should catch the exception, and set a sensible default instead.
"" is an empty string and it cannot be parsed into a valid integer given any circumstances
java.lang.NumberFormatException: For input string: ""
An empty String cannot be parsed to a number.
You need to check it first (using something like String#length() or StringUtils#isBlank()) and decide what to do with this case (for example treat it as zero).
java.lang.NumberFormatException: For input string: ""
Seems like you never set the minutes String
java.lang.NumberFormatException: For input string: ""
input String "" can not be converted into valid Integer.
before using Integer.parseInt, you ensure you are getting an integer by the following ways.
1.provide javascript validation for checking int
or/and
2.provide a server side validation for checking non-integer Strings
also see how to avoid NumberFormatException
Add some sort of checking:
final String DATE_FORMAT_NOW = "MM/dd/yyyy HH:mm:ss";
final DateFormat dateFormat = new SimpleDateFormat("MM/dd/yyyy HH:mm:ss", Locale.US);
Calendar cal = Calendar.getInstance();
final String minutes = sample.getMinutes()
cal.add(Calendar.MINUTE, Integer.valueOf((minutes != null && !minutes.isEmpty()) ? minutes : 0);
SimpleDateFormat sdf = new SimpleDateFormat(DATE_FORMAT_NOW);
String dt = sdf.format(cal.getTime());
System.out.println(" Date and time with added Minutes : " + (dateFormat.parse(dt));
There is nothing unusal here. Read the java docs for parseInt() and valueOf which clearly states that a NumberFormatException is thrown if the String does not contain a parsable integer. And an empty string "" is not a parsable int.
It is up to you how you handle such cases for which a NumberFormatException is thrown.
I'm having a hard time Parsing/Formatting a Date string received back from a web service. I've attempted multiple approaches, but with no luck.
Sample Date String:
2011-10-05T03:00:00Z
Exception:
W/System.err(10072): java.text.ParseException: Unparseable date: "2011-10-05T05:00:00Z" (at offset 10)
W/System.err(10072): at java.text.DateFormat.parse(DateFormat.java:626)
Sample Code:
SimpleDateFormat formatter = new SimpleDateFormat("yyyy-MM-dd HH:mm:SSSS");
Date date = formatter.parse(info.AiringTime);
I've found that if I remove the "T" between the date and the time and replace it with a space, it will format just fine. Anybody have any suggestions?
--UPDATE--
After looking deeper into the API documentation, I found this:
All response DateTime values are in UTC format. You need to apply the UTC offset to calculate the local time for display.
DateTime is a date-and-time value specified in one of the following formats:
UTC format: YYYY-MM-DDThh:mm:ssZ. For example: 2011-03-15T02:00:00Z.
Local time with an offset: YYYY-MM-DDThh:mm:ss + or - hh:mm (positive or negative offset). For example, for US Pacific time: 2011-03-14T06:00:00 -08:00.
Any suggestions on the UTC format approach?
You could try:
DateFormat dateFormat = new SimpleDateFormat("yyyy-MM-dd'T'HH:mm:ssZ");
String dateString = dateString.replace("Z", "GMT+00:00");
Date date = dateFormat.parse(dateString);
The above code should correctly handle the case where a timezone is specified in the date. As Z represents the UTC/GMT timezone it is replaced by GMT so the SimpleDateFormat can interpret it correctly (i would love to know a cleaner way of handling this bit if anyone knows one).
Try,
SimpleDateFormat formatter = new SimpleDateFormat("yyyy-MM-dd'T'HH:mm:ss'Z'");
This pattern should parse the date you provide: "yyyy-MM-dd'T'HH:mm:ss'Z'".
If you want to use SimpleDateFormat and you have a limited number of variations, you can create separate formatters for each pattern and chain them:
Date date = formatter1.parse(info.AiringTime);
if (date == null)
{
date = formatter2.parse(info.AiringTime);
if (date == null)
{
date = formatter2.parse(info.AiringTime);
if (date == null)
{
date = formatter3.parse(info.AiringTime);
}
}
}
or put them in a list and iterate until non-null or no more formatters.
If you have too many patterns for this to be practical, you can parse it yourself or try one of these libraries.
This worked for me
SimpleDateFormat isoDateFormat = new SimpleDateFormat("yyyy-mm-dd'T'hh:mm:ss'Z'");
SimpleDateFormat viewFriendlyDateFormat = new SimpleDateFormat("dd/MMM/yyyy hh:mm:ss aaa");
String viewFriendlyDate = "";
try {
Date date = isoDateFormat.parse(timestamp);
viewFriendlyDate = viewFriendlyDateFormat.format(date);
} catch (ParseException e) {
e.printStackTrace();
}
SimpleDateFormat isoDateFormat = new SimpleDateFormat("yyyy-mm-dd'T'hh:mm:ss'Z'");
SimpleDateFormat viewFriendlyDateFormat = new SimpleDateFormat("dd/MMM/yyyy hh:mm:ss aaa");
String viewFriendlyDate = "";
try {
Date date = isoDateFormat.parse(timestamp);
viewFriendlyDate = viewFriendlyDateFormat.format(date);
} catch (ParseException e) {
e.printStackTrace();
}