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How to get restaurant name in jbeil only using xml DOM parser , please help :
And this is my XML file
<city>
<beirut>
<restaurant>
<name>sada</name>
</restaurant>
</beirut>
<jbeil>
<restaurant>
<name>sada</name>
</restaurant>
</jbeil>
<sour>
<restaurant>
<name>sada</name>
</restaurant>
</sour>
</city>
I want to get the name of restaurant in Jbeil using dom parser and this code give me restaurants name in all city's:
try {
File inputFile = new File("src/josephXml.xml");
DocumentBuilderFactory dbFactory
= DocumentBuilderFactory.newInstance();
DocumentBuilder dBuilder = dbFactory.newDocumentBuilder();
Document doc = dBuilder.parse(inputFile);
doc.getDocumentElement().normalize();
NodeList nList = doc.getElementsByTagName("Restaurant");
for (int temp = 0; temp < nList.getLength(); temp++) {
Node nNode = nList.item(temp);
if (nNode.getNodeType() == Node.ELEMENT_NODE) {
Element eElement = (Element) nNode;
jTextArea1.append( "\n"+"Name : "+ eElement
.getElementsByTagName("name")
.item(0)
.getTextContent()+"\n "
use XPath
many resources: http://viralpatel.net/blogs/java-xml-xpath-tutorial-parse-xml/
something like that (not tested)
import javax.xml.xpath.XPath;
import javax.xml.xpath.XPathFactory;
XPath xPath = XPathFactory.newInstance().newXPath();
String expression = "/city/jbeil/restaurant/name";
//read a string value
String thename= xPath.compile(expression).evaluate(xmlDocument);
Using the same code style as you and "only using xml DOM parser" get the jbeil and then the restaurant...
NodeList nList = doc.getElementsByTagName("jbeil");
for (int i = 0; i < nList.getLength(); i++) {
Node nNode = nList.item(i);
if (nNode.getNodeType() == Node.ELEMENT_NODE) {
Element eElement = (Element) nNode;
NodeList nList2 = eElement.getElementsByTagName("restaurant");
for (int n = 0; n < nList.getLength(); n++) {
Node nNode2 = nList2.item(n);
if (nNode2.getNodeType() == Node.ELEMENT_NODE) {
Element eElement2 = (Element) nNode;
System.out.println(eElement2.getElementsByTagName("name").item(0).getTextContent());
}
}
}
}
But I would go for the XPath answer...
Related
I have xml as follows,
<students>
<Student><age>23</age><id>2000</id><name>PP2000</name></Student>
<Student><age>23</age><id>1000</id><name>PP1000</name></Student>
</students>
I have 2 xpaths Template XPATH = students/Student will be the template nodes, but I cannot hard code this xpath, because it will change for other XMLs, and XML is pretty dynamic, can expand (but with the same base XPATHs) So if I evaluate one more XPATH using the template node, I'm using the following code,
XPath xpathResource = XPathFactory.newInstance().newXPath();
Document xmlDocument = //creating document;
NodeList nodeList = (NodeList)xpathResource.compile("//students/Student").evaluate(xmlDocument, XPathConstants.NODESET);
for (int nodeIndex = 0; nodeIndex < nodeList.getLength(); nodeIndex++) {
Node currentNode = nodeList.item(nodeIndex);
String xpathID = "//students/Student/id";
String xpathName = "//students/Student/name";
NodeList childID = (NodeList)xpathResource.compile(xpathID).evaluate(currentNode, XPathConstants.NODESET);
NodeList childName = (NodeList)xpathResource.compile(xpathName).evaluate(currentNode, XPathConstants.NODESET);
System.out.println("node ID " +childID.item(0).getTextContent());
System.out.println("node Name " +childName.item(0).getTextContent());
}
Now the problem is, this for loop will execute for 2 times, but both time I'm getting 2000 , PP2000 as ID value. Is there any way to iterate to the child node with generic XPATH against a node. I cannot go generic XPATH against the whole XMLDocument, I have some validation to do. I want to use XML nodelist as result set rows, so that I can validate the XML value and do my stuff.
XPath xpathResource = XPathFactory.newInstance().newXPath();
Document xmlDocument = //creating document;
NodeList nodeList = (NodeList)xpathResource.compile("//students/Student/id").evaluate(xmlDocument, XPathConstants.NODESET);
for (int nodeIndex = 0; nodeIndex < nodeList.getLength(); nodeIndex++) {
Node currentNode = nodeList.item(nodeIndex);
System.out.println("node " +currentNode.getTextContent());
}
I want to only get restaurants in beirut with dom parser please help
this is a part from my xml file :
city -> beirut->restaurants->restaurant->name->
tyr->restaurants->restaurant->name->
jbeil->restaurants->restaurant->name->
<restaurants>
<restaurant>
<name>
...
</restaurant>
</restaurants>
<restaurants>
<restaurant>
<name>
...
</restaurant>
</restaurants>
<restaurants>
<restaurant>
<name>
...
</restaurant>
</restaurants>
because this code give me all restaurants in all city's :
try {
File inputFile = new File("src/josephXml.xml");
DocumentBuilderFactory dbFactory
= DocumentBuilderFactory.newInstance();
DocumentBuilder dBuilder = dbFactory.newDocumentBuilder();
Document doc = dBuilder.parse(inputFile);
doc.getDocumentElement().normalize();
NodeList nList = doc.getElementsByTagName("Restaurant");
for (int temp = 0; temp < nList.getLength(); temp++) {
Node nNode = nList.item(temp);
if (nNode.getNodeType() == Node.ELEMENT_NODE) {
Element eElement = (Element) nNode;
jTextArea1.append( "\n"+"Name : "+ eElement
.getElementsByTagName("name")
.item(0)
.getTextContent()+"\n "
, i only want restaurants in beirut please help
You use Restaurant, but your file uses restaurant. It's not OK, because case sensitive.
use XPath: you can select many things, it is very readable.
Replace this in your code:
XPath xPath = XPathFactory.newInstance().newXPath();
String expression="/city/beirut/restaurants/restaurant";
NodeList nList = (NodeList) xPath.compile(expression).evaluate(document, XPathConstants.NODESET);
Hello this is my xml document :
<city>
<beirut>
<restaurant>
<name>sada</name>
</restaurant>
</beirut>
<jbeil>
<restaurant>
<name>toto</name>
<rating>4.3/5</rating>
</restaurant>
<restaurant>
<name>jojo</name>
<rating>4.3/5</rating>
</restaurant>
</jbeil>
<sour>
<restaurant>
<name>sada</name>
</restaurant>
</sour>
</city>
I want to update the rating of "jojo" restaurant in jbeil from 4.3/5 to 4.5/5 using xpath and netbeans please help ,
this code give the rating ,
try {
File inputFile = new File("src/xpath/josephXml.xml");
DocumentBuilderFactory dbFactory
= DocumentBuilderFactory.newInstance();
DocumentBuilder dBuilder;
dBuilder = dbFactory.newDocumentBuilder();
Document doc = dBuilder.parse(inputFile);
doc.getDocumentElement().normalize();
XPath xPath = XPathFactory.newInstance().newXPath();
String expression = "/City/Jbeil/Restaurant";
NodeList nodeList = (NodeList) xPath.compile(expression).evaluate(doc, XPathConstants.NODESET);
for (int i = 0; i < nodeList.getLength(); i++) {
Node nNode = nodeList.item(i);
System.out.println("\nCurrent Element :"
+ nNode.getNodeName());
if (nNode.getNodeType() == Node.ELEMENT_NODE) {
Element eElement = (Element) nNode;
System.out.println("rating : "
+ eElement
.getElementsByTagName("rating")
.item(0)
.getTextContent());
and i want only to update the rating of restaurant in jbeil where name is "jojo" , please help
This is one possible XPath to find such restaurant named jojo in the city of jbeil and then return the corresponding rating element :
/city/jbeil/restaurant[name='jojo']/rating
Notice that XML & XPath are case-sensitive, so I used all lower-case characters in the above XPath to match the XML posted in this question.
I don't know much about Java, but quick searching over the internet* suggest something like this :
XPath xpath = XPathFactory.newInstance().newXPath();
String expression = "/city/jbeil/restaurant[name='jojo']/rating";
Element e = (Element)xpath.evaluate(expression, doc, XPathConstant.NODE);
if (e != null)
e.setTextContent("4.5/5");
*) how to modify xml tag specific value in java?
This question already has answers here:
Get element name from XML in Java DOM
(3 answers)
Closed 8 years ago.
I never really know how to work with XML tags.How do I traverse the node and print particular node in the XML tag.Below is the XML file.
<Employees>
<Employee>
<Gender></Gender>
<Name>
<Firstname></Firstname>
<Lastname></Lastname>
</Name>
<Email></Email>
<Projects>
<Project></Project>
</Projects>
<PhoneNumbers>
<Home></Home>
<Office></Office>
</PhoneNumbers>
</Employee>
There is no data but this is the structure.I am using the following code to parse it partially.
DocumentBuilderFactory factory = DocumentBuilderFactory.newInstance();
factory.setValidating(false);
DocumentBuilder builder = factory.newDocumentBuilder();
Document xmlDocument = builder.parse("employees.xml");
System.out.println(xmlDocument.getDocumentElement().getNodeName());
I would like to print the gender and lastname values.How do I parse the tag which is inside the Name tag which in turn the Name is inside the Employee tag.
Regards.
You should use XPATH. There is a good explanation in this post.
DocumentBuilderFactory factory = DocumentBuilderFactory.newInstance();
DocumentBuilder builder = factory.newDocumentBuilder();
Document doc = builder.parse(<uri_as_string>);
XPathFactory xPathfactory = XPathFactory.newInstance();
XPath xpath = xPathfactory.newXPath();
XPathExpression expr = xpath.compile(<xpath_expression>);
Try this.
String expression = "/Employees/Employee/Gender"; //read Gender value
NodeList nList = (NodeList) xPath.compile(expression).evaluate(document, XPathConstants.NODESET);
for (int j = 0; nList != null && j < nList.getLength(); j++) {
Node node = nList.item(j);
System.out.println("" + node.getFirstChild().getNodeValue());
}
expression = "/Employees/Employee/Name/Lastname"; //read Lastname value
nList = (NodeList) xPath.compile(expression).evaluate(document, XPathConstants.NODESET);
for (int j = 0; nList != null && j < nList.getLength(); j++) {
Node node = nList.item(j);
System.out.println("" + node.getFirstChild().getNodeValue());
}
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can any one share good document for dom parser in java.
thanks
Following are tutorial for using DOM in java:
xml dom
DOM-Parser
java-xml-dom
dom example
Hope this helps.
Check this Simple Parser XML with DOM Example and this Sax Example:
public class ReadXMLFile {
public static void main(String argv[]) {
try {
File fXmlFile = new File("/Users/mkyong/staff.xml");
DocumentBuilderFactory dbFactory = DocumentBuilderFactory.newInstance();
DocumentBuilder dBuilder = dbFactory.newDocumentBuilder();
Document doc = dBuilder.parse(fXmlFile);
//optional, but recommended
//read this - http://stackoverflow.com/questions/13786607/normalization-in-dom-parsing-with-java-how-does-it-work
doc.getDocumentElement().normalize();
System.out.println("Root element :" + doc.getDocumentElement().getNodeName());
NodeList nList = doc.getElementsByTagName("staff");
System.out.println("----------------------------");
for (int temp = 0; temp < nList.getLength(); temp++) {
Node nNode = nList.item(temp);
System.out.println("\nCurrent Element :" + nNode.getNodeName());
if (nNode.getNodeType() == Node.ELEMENT_NODE) {
Element eElement = (Element) nNode;
System.out.println("Staff id : " + eElement.getAttribute("id"));
System.out.println("First Name : " + eElement.getElementsByTagName("firstname").item(0).getTextContent());
System.out.println("Last Name : " + eElement.getElementsByTagName("lastname").item(0).getTextContent());
System.out.println("Nick Name : " + eElement.getElementsByTagName("nickname").item(0).getTextContent());
System.out.println("Salary : " + eElement.getElementsByTagName("salary").item(0).getTextContent());
}
}
} catch (Exception e) {
e.printStackTrace();
}
}
}