Is there any Java syntax to access new methods defined within anonymous inner classes from outer class? I know there can be various workarounds, but I wonder if a special syntax exist?
For example
class Outer {
ActionListener listener = new ActionListener() {
#Override
void actionPerformed(ActionEvent e) {
// do something
}
// method is public so can be accessible
public void MyGloriousMethod() {
// viva!
}
};
public void Caller() {
listener.MyGloriousMethod(); // does not work!
}
}
MY OWN SOLUTION
I just moved all methods and members up to outer class.
Once the anonymous class instance has been implicitly cast into the named type it can't be cast back because there is no name for the anonymous type. You can access the additional members of the anonymous inner class through this within the class, in the expression immediate after the expression and the type can be inferred and returned through a method call.
Object obj = new Object() {
void fn() {
System.err.println("fn");
}
#Override public String toString() {
fn();
return "";
}
};
obj.toString();
new Object() {
void fn() {
System.err.println("fn");
}
}.fn();
identity(new Object() {
void fn() {
System.err.println("fn");
}
}).fn();
...
private static <T> T identity(T value) {
return value;
}
A student in my class asked our professor if this could be done the other day. Here is what I wrote as a cool proof of concept that it CAN be done, although not worth it, it is actually possible and here is how:
public static void main(String[] args){
//anonymous inner class with method defined inside which
//does not override anything
Object o = new Object()
{
public int test = 5;
public void sayHello()
{
System.out.println("Hello World");
}
};
//o.sayHello();//Does not work
try
{
Method m = o.getClass().getMethod("sayHello");
Field f = o.getClass().getField("test");
System.out.println(f.getInt(o));
m.invoke(o);
} catch (Exception e)
{
e.printStackTrace();
}
}
By making use of Java's Method class we can invoke a method by passing in the string value and parameters of the method. Same thing can be done with fields.
Just thought it would be cool to share this!
Your caller knows listener as an ActionListener and therefore it doesn't know anything about that new method. I think the only way to do this (other than doing reflection gymnastics, which really would defeat the purpose of using an anonymous class, i.e. shortcut/simplicity) is to simply subclass ActionListener and not use an anonymous class.
Funny enough, this is now allowed with var construct (Java 10 or newer). Example:
var calculator = new Object() {
BigDecimal intermediateSum = BigDecimal.ZERO;
void calculate(Item item) {
intermediateSum = Numbers.add(intermediateSum, item.value);
item.sum= intermediateSum;
}
};
items.forEach(calculator::calculate);
Here with method reference, but works with dot method call as well, of course. It works with fields as well. Enjoy new Java. :-)
I found more tricks with var and anonymous classes here: https://blog.codefx.org/java/tricks-var-anonymous-classes/
No, it's imposible. You would need to cast the ActionListener to its real subclass name, but since it's anonymous, it doesn't have a name.
The right way to do it is using reflection:
import java.lang.reflect.InvocationTargetException;
public class MethodByReflectionTest {
public static void main(String[] args) throws IllegalAccessException, IllegalArgumentException, InvocationTargetException, NoSuchMethodException, SecurityException {
Object obj = new Object(){
public void print(){
System.out.println("Print executed.");
}
};
obj.getClass().getMethod("print", null).invoke(obj, null);
}
}
You can check here: How do I invoke a Java method when given the method name as a string?
Yes you can access the method see the example below if any doubt please comment
package com;
interface A
{
public void display();
}
public class Outer {
public static void main(String []args)
{
A a=new A() {
#Override
public void display() {
System.out.println("Hello");
}
};
a.display();
}
}
I am looking for a way to pass a method by reference. I understand that Java does not pass methods as parameters, however, I would like to get an alternative.
I've been told interfaces are the alternative to passing methods as parameters but I don't understand how an interface can act as a method by reference. If I understand correctly an interface is simply an abstract set of methods that are not defined. I don't want to send an interface that needs to be defined every time because several different methods could call the same method with the same parameters.
What I would like to accomplish is something similar to this:
public void setAllComponents(Component[] myComponentArray, Method myMethod) {
for (Component leaf : myComponentArray) {
if (leaf instanceof Container) { //recursive call if Container
Container node = (Container) leaf;
setAllComponents(node.getComponents(), myMethod);
} //end if node
myMethod(leaf);
} //end looping through components
}
invoked such as:
setAllComponents(this.getComponents(), changeColor());
setAllComponents(this.getComponents(), changeSize());
Edit: as of Java 8, lambda expressions are a nice solution as other answers have pointed out. The answer below was written for Java 7 and earlier...
Take a look at the command pattern.
// NOTE: code not tested, but I believe this is valid java...
public class CommandExample
{
public interface Command
{
public void execute(Object data);
}
public class PrintCommand implements Command
{
public void execute(Object data)
{
System.out.println(data.toString());
}
}
public static void callCommand(Command command, Object data)
{
command.execute(data);
}
public static void main(String... args)
{
callCommand(new PrintCommand(), "hello world");
}
}
Edit: as Pete Kirkham points out, there's another way of doing this using a Visitor. The visitor approach is a little more involved - your nodes all need to be visitor-aware with an acceptVisitor() method - but if you need to traverse a more complex object graph then it's worth examining.
In Java 8, you can now pass a method more easily using Lambda Expressions and Method References. First, some background: a functional interface is an interface that has one and only one abstract method, although it can contain any number of default methods (new in Java 8) and static methods. A lambda expression can quickly implement the abstract method, without all the unnecessary syntax needed if you don't use a lambda expression.
Without lambda expressions:
obj.aMethod(new AFunctionalInterface() {
#Override
public boolean anotherMethod(int i)
{
return i == 982
}
});
With lambda expressions:
obj.aMethod(i -> i == 982);
Here is an excerpt from the Java tutorial on Lambda Expressions:
Syntax of Lambda Expressions
A lambda expression consists of the following:
A comma-separated list of formal parameters enclosed in parentheses. The CheckPerson.test method contains one parameter, p,
which represents an instance of the Person class.Note: You
can omit the data type of the parameters in a lambda expression. In
addition, you can omit the parentheses if there is only one parameter.
For example, the following lambda expression is also valid:
p -> p.getGender() == Person.Sex.MALE
&& p.getAge() >= 18
&& p.getAge() <= 25
The arrow token, ->
A body, which consists of a single expression or a statement block. This example uses the following expression:
p.getGender() == Person.Sex.MALE
&& p.getAge() >= 18
&& p.getAge() <= 25
If you specify a single expression, then the Java runtime evaluates the expression and then returns its value. Alternatively,
you can use a return statement:
p -> {
return p.getGender() == Person.Sex.MALE
&& p.getAge() >= 18
&& p.getAge() <= 25;
}
A return statement is not an expression; in a lambda expression, you must enclose statements in braces ({}). However, you do not have
to enclose a void method invocation in braces. For example, the
following is a valid lambda expression:
email -> System.out.println(email)
Note that a lambda expression looks a lot like a method declaration;
you can consider lambda expressions as anonymous methods—methods
without a name.
Here is how you can "pass a method" using a lambda expression:
interface I {
public void myMethod(Component component);
}
class A {
public void changeColor(Component component) {
// code here
}
public void changeSize(Component component) {
// code here
}
}
class B {
public void setAllComponents(Component[] myComponentArray, I myMethodsInterface) {
for(Component leaf : myComponentArray) {
if(leaf instanceof Container) { // recursive call if Container
Container node = (Container)leaf;
setAllComponents(node.getComponents(), myMethodInterface);
} // end if node
myMethodsInterface.myMethod(leaf);
} // end looping through components
}
}
class C {
A a = new A();
B b = new B();
public C() {
b.setAllComponents(this.getComponents(), component -> a.changeColor(component));
b.setAllComponents(this.getComponents(), component -> a.changeSize(component));
}
}
Class C can be shortened even a bit further by the use of method references like so:
class C {
A a = new A();
B b = new B();
public C() {
b.setAllComponents(this.getComponents(), a::changeColor);
b.setAllComponents(this.getComponents(), a::changeSize);
}
}
Since Java 8 there is a Function<T, R> interface (docs), which has method
R apply(T t);
You can use it to pass functions as parameters to other functions. T is the input type of the function, R is the return type.
In your example you need to pass a function that takes Component type as an input and returns nothing - Void. In this case Function<T, R> is not the best choice, since there is no autoboxing of Void type. The interface you are looking for is called Consumer<T> (docs) with method
void accept(T t);
It would look like this:
public void setAllComponents(Component[] myComponentArray, Consumer<Component> myMethod) {
for (Component leaf : myComponentArray) {
if (leaf instanceof Container) {
Container node = (Container) leaf;
setAllComponents(node.getComponents(), myMethod);
}
myMethod.accept(leaf);
}
}
And you would call it using method references:
setAllComponents(this.getComponents(), this::changeColor);
setAllComponents(this.getComponents(), this::changeSize);
Assuming that you have defined changeColor() and changeSize() methods in the same class.
If your method happens to accept more than one parameter, you can use BiFunction<T, U, R> - T and U being types of input parameters and R being return type. There is also BiConsumer<T, U> (two arguments, no return type). Unfortunately for 3 and more input parameters, you have to create an interface by yourself. For example:
public interface Function4<A, B, C, D, R> {
R apply(A a, B b, C c, D d);
}
Use the java.lang.reflect.Method object and call invoke
First define an Interface with the method you want to pass as a parameter
public interface Callable {
public void call(int param);
}
Implement a class with the method
class Test implements Callable {
public void call(int param) {
System.out.println( param );
}
}
// Invoke like that
Callable cmd = new Test();
This allows you to pass cmd as parameter and invoke the method call defined in the interface
public invoke( Callable callable ) {
callable.call( 5 );
}
While this is not yet valid for Java 7 and below, I believe that we should look to the future and at least recognize the changes to come in new versions such as Java 8.
Namely, this new version brings lambdas and method references to Java (along with new APIs, which are another valid solution to this problem. While they still require an interface no new objects are created, and extra classfiles need not pollute output directories due to different handling by the JVM.
Both flavors(lambda and method reference) require an interface available with a single method whose signature is used:
public interface NewVersionTest{
String returnAString(Object oIn, String str);
}
Names of methods will not matter from here on. Where a lambda is accepted, a method reference is as well. For example, to use our signature here:
public static void printOutput(NewVersionTest t, Object o, String s){
System.out.println(t.returnAString(o, s));
}
This is just a simple interface invocation, up until the lambda1 gets passed:
public static void main(String[] args){
printOutput( (Object oIn, String sIn) -> {
System.out.println("Lambda reached!");
return "lambda return";
}
);
}
This will output:
Lambda reached!
lambda return
Method references are similar. Given:
public class HelperClass{
public static String testOtherSig(Object o, String s){
return "real static method";
}
}
and main:
public static void main(String[] args){
printOutput(HelperClass::testOtherSig);
}
the output would be real static method. Method references can be static, instance, non-static with arbitrary instances, and even constructors. For the constructor something akin to ClassName::new would be used.
1 This is not considered a lambda by some, as it has side effects. It does illustrate, however, the use of one in a more straightforward-to-visualize fashion.
Last time I checked, Java is not capable of natively doing what you want; you have to use 'work-arounds' to get around such limitations. As far as I see it, interfaces ARE an alternative, but not a good alternative. Perhaps whoever told you that was meaning something like this:
public interface ComponentMethod {
public abstract void PerfromMethod(Container c);
}
public class ChangeColor implements ComponentMethod {
#Override
public void PerfromMethod(Container c) {
// do color change stuff
}
}
public class ChangeSize implements ComponentMethod {
#Override
public void PerfromMethod(Container c) {
// do color change stuff
}
}
public void setAllComponents(Component[] myComponentArray, ComponentMethod myMethod) {
for (Component leaf : myComponentArray) {
if (leaf instanceof Container) { //recursive call if Container
Container node = (Container) leaf;
setAllComponents(node.getComponents(), myMethod);
} //end if node
myMethod.PerfromMethod(leaf);
} //end looping through components
}
Which you'd then invoke with:
setAllComponents(this.getComponents(), new ChangeColor());
setAllComponents(this.getComponents(), new ChangeSize());
If you don't need these methods to return something, you could make them return Runnable objects.
private Runnable methodName (final int arg) {
return (new Runnable() {
public void run() {
// do stuff with arg
}
});
}
Then use it like:
private void otherMethodName (Runnable arg){
arg.run();
}
Java-8 onwards
Java 8 onwards, you can provide the implementation of the abstract method of a functional interface (an interface that has only one abstract method) using a lambda expression and pass the same to a method as a parameter.
#FunctionalInterface
interface ArithmeticFunction {
public int calcualate(int a, int b);
}
public class Main {
public static void main(String args[]) {
ArithmeticFunction addition = (a, b) -> a + b;
ArithmeticFunction subtraction = (a, b) -> a - b;
int a = 20, b = 5;
System.out.println(perform(addition, a, b));
// or
System.out.println(perform((x, y) -> x + y, a, b));
System.out.println(perform(subtraction, a, b));
// or
System.out.println(perform((x, y) -> x - y, a, b));
}
static int perform(ArithmeticFunction function, int a, int b) {
return function.calcualate(a, b);
}
}
Output:
25
25
15
15
ONLINE DEMO
Learn more about it from Method References.
I didn't find any example explicit enough for me on how to use java.util.function.Function for simple method as parameter function. Here is a simple example:
import java.util.function.Function;
public class Foo {
private Foo(String parameter) {
System.out.println("I'm a Foo " + parameter);
}
public static Foo method(final String parameter) {
return new Foo(parameter);
}
private static Function parametrisedMethod(Function<String, Foo> function) {
return function;
}
public static void main(String[] args) {
parametrisedMethod(Foo::method).apply("from a method");
}
}
Basically you have a Foo object with a default constructor. A method that will be called as a parameter from the parametrisedMethod which is of type Function<String, Foo>.
Function<String, Foo> means that the function takes a String as parameter and return a Foo.
The Foo::Method correspond to a lambda like x -> Foo.method(x);
parametrisedMethod(Foo::method) could be seen as x -> parametrisedMethod(Foo.method(x))
The .apply("from a method") is basically to do parametrisedMethod(Foo.method("from a method"))
Which will then return in the output:
>> I'm a Foo from a method
The example should be running as is, you can then try more complicated stuff from the above answers with different classes and interfaces.
Java do have a mechanism to pass name and call it. It is part of the reflection mechanism.
Your function should take additional parameter of class Method.
public void YouMethod(..... Method methodToCall, Object objWithAllMethodsToBeCalled)
{
...
Object retobj = methodToCall.invoke(objWithAllMethodsToBeCalled, arglist);
...
}
I did not found any solution here that show how to pass method with parameters bound to it as a parameter of a method. Bellow is example of how you can pass a method with parameter values already bound to it.
Step 1: Create two interfaces one with return type, another without. Java has similar interfaces but they are of little practical use because they do not support Exception throwing.
public interface Do {
void run() throws Exception;
}
public interface Return {
R run() throws Exception;
}
Example of how we use both interfaces to wrap method call in transaction. Note that we pass method with actual parameters.
//example - when passed method does not return any value
public void tx(final Do func) throws Exception {
connectionScope.beginTransaction();
try {
func.run();
connectionScope.commit();
} catch (Exception e) {
connectionScope.rollback();
throw e;
} finally {
connectionScope.close();
}
}
//Invoke code above by
tx(() -> api.delete(6));
Another example shows how to pass a method that actually returns something
public R tx(final Return func) throws Exception {
R r=null;
connectionScope.beginTransaction();
try {
r=func.run();
connectionScope.commit();
} catch (Exception e) {
connectionScope.rollback();
throw e;
} finally {
connectionScope.close();
}
return r;
}
//Invoke code above by
Object x= tx(() -> api.get(id));
Example of solution with reflection, passed method must be public
import java.lang.reflect.Method;
import java.lang.reflect.InvocationTargetException;
public class Program {
int i;
public static void main(String[] args) {
Program obj = new Program(); //some object
try {
Method method = obj.getClass().getMethod("target");
repeatMethod( 5, obj, method );
}
catch ( NoSuchMethodException | IllegalAccessException | InvocationTargetException e) {
System.out.println( e );
}
}
static void repeatMethod (int times, Object object, Method method)
throws IllegalAccessException, InvocationTargetException {
for (int i=0; i<times; i++)
method.invoke(object);
}
public void target() { //public is necessary
System.out.println("target(): "+ ++i);
}
}
Use the Observer pattern (sometimes also called Listener pattern):
interface ComponentDelegate {
void doSomething(Component component);
}
public void setAllComponents(Component[] myComponentArray, ComponentDelegate delegate) {
// ...
delegate.doSomething(leaf);
}
setAllComponents(this.getComponents(), new ComponentDelegate() {
void doSomething(Component component) {
changeColor(component); // or do directly what you want
}
});
new ComponentDelegate()... declares an anonymous type implementing the interface.
Here is a basic example:
public class TestMethodPassing
{
private static void println()
{
System.out.println("Do println");
}
private static void print()
{
System.out.print("Do print");
}
private static void performTask(BasicFunctionalInterface functionalInterface)
{
functionalInterface.performTask();
}
#FunctionalInterface
interface BasicFunctionalInterface
{
void performTask();
}
public static void main(String[] arguments)
{
performTask(TestMethodPassing::println);
performTask(TestMethodPassing::print);
}
}
Output:
Do println
Do print
I'm not a java expert but I solve your problem like this:
#FunctionalInterface
public interface AutoCompleteCallable<T> {
String call(T model) throws Exception;
}
I define the parameter in my special Interface
public <T> void initialize(List<T> entries, AutoCompleteCallable getSearchText) {.......
//call here
String value = getSearchText.call(item);
...
}
Finally, I implement getSearchText method while calling initialize method.
initialize(getMessageContactModelList(), new AutoCompleteCallable() {
#Override
public String call(Object model) throws Exception {
return "custom string" + ((xxxModel)model.getTitle());
}
})
I appreciate the answers above but I was able to achieve the same behavior using the method below; an idea borrowed from Javascript callbacks. I'm open to correction though so far so good (in production).
The idea is to use the return type of the function in the signature, meaning that the yield has to be static.
Below is a function that runs a process with a timeout.
public static void timeoutFunction(String fnReturnVal) {
Object p = null; // whatever object you need here
String threadSleeptime = null;
Config config;
try {
config = ConfigReader.getConfigProperties();
threadSleeptime = config.getThreadSleepTime();
} catch (Exception e) {
log.error(e);
log.error("");
log.error("Defaulting thread sleep time to 105000 miliseconds.");
log.error("");
threadSleeptime = "100000";
}
ExecutorService executor = Executors.newCachedThreadPool();
Callable<Object> task = new Callable<Object>() {
public Object call() {
// Do job here using --- fnReturnVal --- and return appropriate value
return null;
}
};
Future<Object> future = executor.submit(task);
try {
p = future.get(Integer.parseInt(threadSleeptime), TimeUnit.MILLISECONDS);
} catch (Exception e) {
log.error(e + ". The function timed out after [" + threadSleeptime
+ "] miliseconds before a response was received.");
} finally {
// if task has started then don't stop it
future.cancel(false);
}
}
private static String returnString() {
return "hello";
}
public static void main(String[] args) {
timeoutFunction(returnString());
}
I am a beginner and i try to teach myself clean coding. I want to pass a function as a parameter that I can reuse a method without to repeat code. As an example I have this:
public class Dog {
private String name;
private int id;
private List<String> characteristic;
public List<String> getCharacteristic() {
return characteristic;
}
public void setCharacteristic(List<String> characteristic) {
this.characteristic = characteristic;
}
}
public class Check{
private List<Dog> dogs = new ArrayList();
public void iterate() {
while (dogs.size() > 0) {
for (Dog dog : dogs) {
List<String> restChara = new ArrayList<>();
restChara= checkChara(dog, restChara);
if (restChara.size()>0) {
dog.setCharacteristic(restChara);
} else {
dogs.remove(dog);
}
}
}
}
private List<String> checkChara(Dog dog, List<String> restChara) {
for (String chara : dog.getCharacteristic()) {
boolean charaChecked = doSomething(chara);
if (!charaChecked) {
restChara.add(chara);
} else {
dog.getCharacteristic().remove(chara);
}
}
return restChara;
}
private boolean doSomething(String chara){
//do sth.
return true;
}
private boolean doSomething2(String chara){
//do sth.
return true;
}
}
How would you define the method checkChara in order to use different functions within it?
My first thought was to pass the function as a parameter (i think it would be in C# delegates)
Thank you very much!
EDIT:
I think I found another pattern strategy design pattern
https://www.freecodecamp.org/news/the-strategy-pattern-explained-using-java-bc30542204e0/
Java does not support “directly” nested methods. Many functional programming languages support method within method. But you can achieve nested method functionality in Java 7 or older version by define local classes, class within method so this does compile. And in java 8 and newer version you achieve it by lambda expression.
Method 1 (Using anonymous subclasses)
It is an inner class without a name and for which only a single object is created. An anonymous inner class can be useful when making an instance of an object with certain “extras” such as overloading methods of a class or interface, without having to actually subclass a class.
//Java program implements method inside method
public class GFG {
// create a local interface with one abstract
// method run()
interface myInterface {
void run();
}
// function have implements another function run()
static void Foo()
{
// implement run method inside Foo() function
myInterface r = new myInterface() {
public void run()
{
System.out.println("geeksforgeeks");
};
};
r.run();
}
public static void main(String[] args)
{
Foo();
}
}
Method 2 (Using local classes)
You can also implement a method inside a local class. A class created inside a method is called local inner class. If you want to invoke the methods of local inner class, you must instantiate this class inside method.
// Java program implements method inside method
public class GFG {
// function have implementation of another
// function inside local class
static void Foo()
{
// local class
class Local {
void fun()
{
System.out.println("geeksforgeeks");
}
}
new Local().fun();
}
public static void main(String[] args)
{
Foo();
}
}
Method 3 (Using a lambda expression)
Lambda expressions basically express instances of functional interfaces (An interface with single abstract method is called functional interface. An example is java.lang.Runnable). lambda expressions implement the only abstract function and therefore implement functional interfaces.
// Java program implements method inside method
public class GFG {
interface myInterface {
void run();
}
// function have implements another function
// run() using Lambda expression
static void Foo()
{
// Lambda expression
myInterface r = () ->
{
System.out.println("geeksforgeeks");
};
r.run();
}
public static void main(String[] args)
{
Foo();
}
}
I don't exaclty know what you mean, but i figure out it could be something like that:
List<Runnable> runMyStuff = new ArrayList<Runnable>();
String variable= "Hallo"; //needs to be effectively final
runMyStuff.add(() -> {
System.out.println(variable);
doSomething(variable);
});
runMyStuff.add(() ->{
System.out.println("This is a test");
});
runMyStuff.add(() ->{
System.out.println("2 + 2 = " + (2+2) );
});
runMyStuff.get(0).run();
runMyStuff.get(2).run();
runMyStuff.get(0).run();
runMyStuff.get(1).run();
runMyStuff.get(2).run();
will result in :
Hallo
2 + 2 = 4
Hallo
This is a test
2 + 2 = 4
When you put variables or Passing Parameters in those runnable methods, they need to be effectively final or you pass them in a container.
You can re-run each method.
And within those Methods you can execute other methods.
NOTE:
If you want to have return Parameters you could do the same with Callable and than ".call()" instead of run.
EDIT:
Under the assumption you mean character Check or something like that
Example for charaCheck passable Method With Interface:
public interface CharacterChecker{
//is a template returns boolean, need a String param
public boolean call(String chara);
}
A method that executes a passes method of the type of "CHaracterChecker"
public static void excecutePassedMethod(CharacterChecker checker, String chara) {
System.out.println(chara + ": " + checker.call(chara));
}
Two different implementations of a "Character Checker"
CharacterChecker goodChecker = new CharacterChecker() {
#Override
public boolean call(String chara) {
return "good".equals(chara);
}
};
CharacterChecker lazyCheker = new CharacterChecker() {
#Override
public boolean call(String chara) {
return "lazy".equals(chara);
}
};
The Methods that are Passed the "method" (More like anonymos class object with the method)
excecutePassedMethod(goodChecker, "bad");
excecutePassedMethod(goodChecker, "good");
excecutePassedMethod(goodChecker, "jolly");
excecutePassedMethod(lazyCheker, "frisky");
excecutePassedMethod(lazyCheker, "lazy");
result will be:
bad: false
good: true
jolly: false
frisky: false
lazy: true
I got a problem..I recieve mainly 3 types of inputs from command line arguments in java..say A,B,C.Based on these three inputs I need to invoke respective method (I have 3 methods defined one for each input).
condition is : we should not use if,switch,conditional operator,while statement,reflection
any one please share your thoughts
You can use a Map in order to map the 3 possible inputs to the 3 corresponding methods.
For example, suppose the input is a String and the logic to be performed is a method that accepts a String:
Map<String,Consumer<String>> methods = new LinkedHashMap<>();
methods.put("A",a->methodA(a));
methods.put("B",a->methodB(a));
methods.put("C",a->methodC(a));
Now, given input x, you invoke the required method with
methods.get(x).accept(input);
You can use getOrDefault instead of get if you want to have a default method invoked when the input x is not found in the Map:
methods.getOfDefault(x, a -> System.out.println("cannot process input " + a)).accept(input);
You can use an interface with a common method
import java.util.*;
interface A{
public void run();
}
public class MyClass implements A{
public static void method1() { System.out.println("method1"); }
public static void method2() { System.out.println("method2"); }
public static void method3() { System.out.println("method3"); }
public void run(){}
public static void main(String [] args){
A method1 = new A() {
public void run() { method1(); }
};
A method2 = new A() {
public void run() { method2(); }
};
A method3 = new A() {
public void run() { method3(); }
};
Map<String, A> methodMap = new HashMap<String, A>();
methodMap.put(args[0], method1);
methodMap.put(args[1], method2);
methodMap.put(args[2], method3);
A a = methodMap.get(args[0]);
a.run();
}
}
In Java, can a method/constructor declaration appear inside another method/constructor declaration? Example:
void A() {
int B() { }
}
I think not, but I'd love to be reassured.
No. it is not compilable.
No this is not possible.
For reference: http://download.oracle.com/javase/tutorial/java/javaOO/methods.html
Not directly, but you can have a method in a class in a method:
class A {
void b() {
class C {
void d() {
}
}
}
}
This is not possible in java. However this can achieved by interface though the code becomes complex.
interface Block<T> {
void invoke(T arg);
}
class Utils {
public static <T> void forEach(Iterable<T> seq, Block<T> fct) {
for (T elm : seq)
fct.invoke(elm);
}
}
public class MyExample {
public static void main(String[] args) {
List<Integer> nums = Arrays.asList(1,2,3);
Block<Integer> print = new Block<Integer>() {
private String foo() { // foo is declared inside main method and within the block
return "foo";
}
public void invoke(Integer arg) {
print(foo() + "-" + arg);
}
};
Utils.forEach(nums,print);
}
}
No, Java only allows a method to be defined within a class, not within another method.