We Keep Coding

How to create a cookie and use it in HttpURLConnection?

I have the following python code which creates a cookie and adds it to the session. What would be the equivalent java code for it using HttpURLConnection? I basically want to do a HTTP POST request using the generated cookie.
session = requests.session()
session.auth = (username, password)
try:
token = session.get(SITEMINDER_URL % server, verify=False)
session.cookies.update(dict(SMSESSION=json.loads(token.content)['SMSESSION']))
except Exception as ex:
raise Exception("Failed in authenticating with siteminder", ex)
response = session.post(api_url, headers=headers, verify=False, json=data)

You would use something like this:
HttpURLConnection httpconn = < some source to get a HttpURLConnection >;
String cookieName = "SMSESSION"; // note this is the default but SM can use other prefixes
String cookieValue = < your token content >;
httpurl.setRequestProperty("Cookie", cookieName + "=" + cookieValue);
Also, from the javadocs: NOTE: HTTP requires all request properties which can legally have multiple instances with the same key to use a comma-separated list syntax which enables multiple properties to be appended into a single property
Which leads me to pointing out that using the HttpUrlConnection directly is really clumsy. I recommend you look at an HTTP client library such as Apache HTTP Client http://hc.apache.org/httpcomponents-client-ga/

In my opinion, you can just create an HttpUrlConnection object assigning a List of Cookies as follows:
List<String> cookies = new ArrayList<>();
//Or using a map With entries: Key and value for each cookie
cookies.add("User-Agent=MyUserAgent"); //etc...
URL site = new URL("https://myurl.com");
HttpsURLConnection conn = (HttpsURLConnection) site.openConnection();
for (String string: cookies) {
conn.setRequestProperty("Cookie", string);
}
However this is the simplest but not the best way to do so.

To get higher abstraction for Cookie use CookieManager and CookieStore classes. Here is an example:
HttpURLConnection connection
CookieManager cookieManager = new CookieManager();
HttpCookie cookie = new HttpCookie("cookieName","cookieValue");
cookieManager.getCookieStore().add(null,cookie);
connection.setRequestProperty("Cookie", String.join( ";", cookieManager.getCookieStore().getCookies()));

Try This:
URL url = new URL("http://www.example.com");
HttpURLConnection conn = (HttpURLConnection)url.openConnection();
conn.setRequestProperty("Cookie", "name1=value1; name2=value2");
conn.connect();

How to fix dialogflow authentication issue

I have a dialogflow project that I'm trying to access from Java with a rest call.
It is giving me an authentication issue.
I have followed all online instructions (and many forum suggestions) to no avail.
I have tried generating the key json, as per the instructions here:
https://dialogflow.com/docs/reference/v2-auth-setup
and setting my environment variable as described, but nothing seems to work.
I have checked my projectID, and am running off the same machine with the environment variable, and have double, triple and quadruple checked it's name and location, but I still get the following error:
java.net.HttpRetryException: cannot retry due to server authentication, in streaming mode
Here is my code (though it's a REST call, so I don't know if it's so relevant):
String url = https://dialogflow.googleapis.com/v2/projects/MYPROJECT/agent/sessions/SESSION_NUM:detectIntent
URL url = new URL(full_url);
String inText = "Hello World";
String outText = "";
HttpURLConnection con = (HttpURLConnection) url.openConnection();
try {
con.setDoOutput(true);
con.setRequestMethod("POST");
// set body of http post
Map<String,String> arguments = new HashMap<>();
JSONObject inTextJsn = new JSONObject();
inTextJsn.append("text",inText);
inTextJsn.append("languageCode","en");
JSONObject fieldJsn = new JSONObject();
fieldJsn.append("text", inTextJsn);
arguments.put("queryInput", fieldJsn.toString());
StringJoiner sj = new StringJoiner("&");
for(Map.Entry<String,String> entry : arguments.entrySet())
sj.add(URLEncoder.encode(entry.getKey(), "UTF-8") + "="
+ URLEncoder.encode(entry.getValue(), "UTF-8"));
// post http post as bytes
byte[] bytes_out = sj.toString().getBytes(StandardCharsets.UTF_8);
con.setFixedLengthStreamingMode(bytes_out.length);
con.connect();
try (OutputStream os = con.getOutputStream()) {
os.write(bytes_out);
}
BufferedReader reader = new BufferedReader(new InputStreamReader(con.getInputStream(),
"UTF-8"));
// read all lines to a string
String line;
String response = "";
while ((line = reader.readLine()) != null) {
response += line;
}
JSONObject responseJsn = new JSONObject(response);
outText = responseJsn.get("fulfillmentText").toString();
} catch (Exception e) {
System.err.println(e);
} finally {
con.disconnect();
}
return restResponse;
The gist of the code is to simply send a message ("Hello World!") to my dialogflow, and get back my agent's response (the code may have bugs - it's a bit hard to test when I can't get passed this authentication issue, so please help with the authentication, not code bugs).
Thanks all!

The directions at that page assume you're going to use the gcloud program to generate a currently valid bearer token, which is then sent along with the HTTP headers. That page illustrates
Your code doesn't seem to be generating an Authorization HTTP header at all, which is why you're getting the error you do.
Since you're using Java, you should look at the google-auth-library-java library, which will give you the tools to generate the token you need to provide in the Authorization header.
You may also wish to check out the google-cloud-java library. This contains Java classes to directly perform operations against Dialogflow instead of coding the REST/HTTP calls yourself. (However, it is still at an Alpha level for Dialogflow, so may not be stable or forwards compatible.)

Http POST in android app without data

I'm trying to send a video url in a http POST request but it's not working for me, I think I've (almost?) the necessary code to make it work, or else I'm missing something very simple?
public void postVideoURL() throws IOException {
String encodedUrl = URLEncoder.encode("http://video.ted.com/talks/podcast/DavidBrooks_2011.mp4", "UTF-8");
URL obj = new URL("http://10.50.0.105:8060/launch/dev?url="+encodedUrl);
HttpURLConnection con = (HttpURLConnection) obj.openConnection();
//add request header
con.setRequestMethod("POST");
// Send post request
con.setDoOutput(true);
OutputStreamWriter wr = new OutputStreamWriter(con.getOutputStream());
System.out.println(con.getResponseCode());
System.out.println(con.getResponseMessage());
wr.flush();
wr.close();
wr.write("");
}
Any tips to lead me to the right direction?
Here is what I'm trying to do but in C#
using System.Net;
using System.Web;
class Program
{
static void Main()
{
string rokuIp = "192.168.0.6";
string channelId = "dev";
string videoUrl = "http://video.ted.com/talks/podcast/DavidBrooks_2011.mp4";
// Note that the query string parameters should be url-encoded
string requestUrl = $"http://{rokuIp}:8060/launch/{channelId}?url={HttpUtility.UrlEncode(videoUrl)}";
using (var wc = new WebClient())
{
// POST the query string with no data
wc.UploadString(requestUrl, "");
}
}
}
The following Post command to use in terminal works, this is essentially what I want to do, but in Java:
curl -d "" "http://10.50.0.46:8060/launch/12?url=http%3A%2F%2Fvideo.ted.com%2Ftalks%2Fpodcast%2FDavidBrooks_2011.mp4"

You are never writing anything to the output stream. You have to call wr.write() to write your data to the stream.
Also, you can't encode the URL like that inside the String. You need to concatenate the two Strings together after you've encoded the url separately. Like this:
String encodedUrl = URLEncoder.encode("http://video.ted.com/talks/podcast/DavidBrooks_2011.mp4");
URL obj = new URL("http://10.50.0.105:8060/launch/dev?url="+encodedUrl);

how to form URL to make HTTP request in android?

I want to make a HTTP request to the url below.
http://192.168.1.60/api/check/merge?nodeid=2&tickets=2-0011,2-0010&saleId=140708120131003102,140708115753005302&firsttableid=1&layoutid=1&userid=1
I stored the tickets details and sales id details in the string array.
String tickets has {2-0011,2-0010} and String saleid has {140708120131003102, 140708115753005302}
How to form the URL like this by using that string array?
String mergeurl1 = "http://192.168.1.60/api/check/merge?nodeid=2&tickets=";
try
{
for(int i=0;i<tablenameurl.length;i++)
{
//System.out.println(ticketidurl[i]+"**"+salesidurl[i]);
if(tablenameurl.length==i && tablenameurl != null)
{
mergeurl1=mergeurl1+ticketidurl[i]+"&";
}
else
{
mergeurl1=mergeurl1+ticketidurl[i]+",";
}
}
mergeurl1=mergeurl1+"saleId=";
for(int i=0;i<tablenameurl.length;i++)
{
//System.out.println(ticketidurl[i]+"**"+salesidurl[i]);
if(tablenameurl.length==i)
{
mergeurl1=mergeurl1+salesidurl[i]+"&";
}
else
{
mergeurl1=mergeurl1+salesidurl[i]+",";
}
}
mergeurl1=mergeurl1+"&firsttableid=1&layoutid=1&userid=1";
System.out.println("URL");
System.out.println(mergeurl1);
}
catch(Exception e)
{
}

You have to use a URL Encoder for this purpose. The best way to do that would be to URLEncode and encode parts of the url. Dont encode the complete URL, it wont work then. You only have to encode the parts of the url that need to be passed as values. For example in this case encode 2-0011,2-0010

OK, assuming you have the URL String mergeurl1
URL url = new URL(mergeurl1);
HttpURLConnection urlConnection = (HttpURLConnection) url.openConnection();
If you want to obtain the response ...
InputStream in = new BufferedInputStream(urlConnection.getInputStream());
//go ahead to process your information with the inputstream
Finally close the HttpURLConnection by urlConnection.disconnect();
Please note that all the code the above cannot be run in your UI Thread, you may use a AsyncTask to cater that.
Here is the reference for you to learn about that:)
http://developer.android.com/reference/android/os/AsyncTask.html
http://developer.android.com/reference/java/net/HttpURLConnection.html
By the way, as the comment above mentioned, you better use a StringBuffer to append the String

Using a session with php and Java

I'm currently trying to use the current session of a php web page from an applet. I tought it would be straightforward, but it didn't go as smooth as I tough. From the php man:
session_start() creates a session or resumes the current one based on a session
identifier passed via a GET or POST request, or passed via a cookie.
From there I did some php (simplified here):
// PAGE1.PHP
session_start();
$_SESSION['test'] = true;
echo "sid=" . session_id();
// PAGE2.PHP
session_start();
if ($_SESSION['test'])
$echo "success";
else
$echo "fail";
So, from my applet, I do a request to PAGE1.PHP and it returns me the session id. When I do a new request on the page 2, I pass the session id as a parameter and it seems that the session wasn't kept. I use
URL url = new URL("my/url/PAGE2.php?sid=" + session_id);
URLConnection conn = url.openConnection();
conn.setDoOutput(true);
OutputStreamWriter wr = new OutputStreamWriter(conn.getOutputStream());
wr.write(data); // data is the post data created previously
wr.flush();
// Get the response
BufferedReader rd = new BufferedReader(
new InputStreamReader(conn.getInputStream()));
String line;
while ((line = rd.readLine()) != null) {
System.out.println(line);
}
I have tried via POST and GET method and it doesn't seem to work.
So I'm wondering if it's possible, and if yes, what do I miss?
thanks.

Accepting session IDs as part of the GET is bad form, and bad idea security wise. I would suggest that you retrieve the session ID from the PHPSESSION cookie with something like:
Following java snippet was shamelessly copied from here – Have a look at that (although it is java 1.4 specific).
public String getCookie() {
/*
** get all cookies for a document
*/
try {
JSObject myBrowser = (JSObject) JSObject.getWindow(this);
JSObject myDocument = (JSObject) myBrowser.getMember("document");
String myCookie = (String)myDocument.getMember("cookie");
if (myCookie.length() > 0)
return myCookie;
}
catch (Exception e){
e.printStackTrace();
}
return "?";
}
public String getCookie(String name) {
/*
** get a specific cookie by its name, parse the cookie.
** not used in this Applet but can be useful
*/
String myCookie = getCookie();
String search = name + "=";
if (myCookie.length() > 0) {
int offset = myCookie.indexOf(search);
if (offset != -1) {
offset += search.length();
int end = myCookie.indexOf(";", offset);
if (end == -1) end = myCookie.length();
return myCookie.substring(offset,end);
}
else
System.out.println("Did not find cookie: "+name);
}
return "";
}
Elsewhere in your code grab the session id using:
getCookie("PHPSESSION"); // replace this with the cookie name in your /etc/php.ini
and set it in your applet.
conn.setRequestProperty("Cookie", "PHPSESSION=value");
Far more current information is available at the sun java cookie page

Your PAGE2.php is not actually using the sid param you're passing via _GET to initiate the session.
In page2.php, try:
session_id($_GET['sid']);
session_start();
instead of plain-old:
session_start();