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I have text data and I want to split into String and int arrays Java
String text = "one1two20three300four4000";
Desired output:
String str[] = "one","two","three","four";
int num[] = 1,20,300,4000;
This one will work for you in Java :
public static void main(String[] args) {
String text = "one1two20three300four4000";
String arr1[] = text.replaceFirst("^\\d+", "").split("\\d+");
String arr2[] = text.replaceFirst("^\\D+", "").split("\\D+");
System.out.println(Arrays.toString(arr1));
System.out.println(Arrays.toString(arr2)); // parse each value as an in using Streams (preferably) or a loop.
}
O/P :
[one, two, three, four] [1, 20, 300, 4000]
PS : In java 8 Use int[] arr2Int = Arrays.stream(arr2).mapToInt(Integer::parseInt).toArray(); to convert your String array to int array.
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this is my array:
[UserID|Name|Password|IC or Passport Number|Gender|Phone, 01234567|Bob|abcderf|MALE|01234567]
and I want to convert into:
[UserID|Name|Password|IC or Passport Number]
[01234567|Bob|abcderf|MALE|01234567]
this is my code: (but it doesn't work]
String[] arr = userList.toArray(new String[userList.size()]);
String[] arrr = arr[0].split(",");
for ( int i=0; i<arr.length;i++)
{
System.out.println(arr[i]);
}
You can simply use method from Arrays if lenght of array is always the same
String[] array1 = Arrays.copyOfRange(array, 0, 4);
String[] array2 = Arrays.copyOfRange(array, 4, 9);
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I have dates like this in string that need leading zero's removed.
Here is what I need:
Remove leading zero's in between [- and :
Below are some of the examples and expected results
20200831000000.000[-05:EST] -> 20200831000000.000[-5:EST]
20200831000000.000[-08:30:EST] -> 20200831000000.000[-8:30:EST]
20200831000000.000[-10:EST] -> 20200831000000.000[-10:EST]
I can't figure this out as I'm new to regular expressions. I have tried the below but not working
"0+(?!$)"
this will work like you went :
public static void main(String[] args) {
String arr[] = {"20200831000000.000[-05:EST]","20200831000000.000[-08:30:EST]","20200831000000.000[-10:EST]"};
for(int i=0; i < arr.length ; i++){
arr[i] = arr[i].replaceAll("(?<=\\[-?)(0*)(?=.*\\])", "");
}
for(String s : arr){
System.out.println(s);
}
}
output :
20200831000000.000[-5:EST]
20200831000000.000[-8:30:EST]
20200831000000.000[-10:EST]
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How to convert Stream<Character> into a String in Java 8? Collectors.joining() expects CharSequence hence it is giving compilation error.
Refer to #jubobs solution link. That is, you could do it this way in your case:
Stream<Character> testStream = Stream.of('a', 'b', 'c');
String result = testStream.collect(Collector.of(
StringBuilder::new,
StringBuilder::append,
StringBuilder::append,
StringBuilder::toString));
This is more performant then map/castping each character to a String first and then joining, as StringBuilder#append(char c) will cut out that intermediate step.
Convert Character to String
Stream<Character> st = Stream.of('C','h','t');
String result = st.map(c->c.toString()).collect(Collectors.joining());
System.out.println(result); //Cht
Or by using method reference
st.map(Object::toString).collect(Collectors.joining())
And Collectors.joining internally uses StringBuilder here
Or just by using forEach
StringBuilder builder = new StringBuilder();
Stream<Character> st = Stream.of('C','h','t');
st.forEach(ch->builder.append(ch));
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How can I remove multiple characters by their index from a string. I thought to use StringBuilder's deleteCharAt function. But if I delete char one by one, I will not keep track the right index.
For example :
String test = "0123456789"
int[] removingIndice = int[] {2, 4, 0};
// remove character from string
// result = "1356789"
Create a new string builder,
iterate on string, add elements to builder if its index not in the array
StringBuilder sb = new StringBuilder("");
for(int i = 0; i< test.length; i++){
if( !ArrayUtils.contains(removingIndice, i))
{
sb.append(test.charAt(i));
}
}
test = sb.toString();
String is immutable in Java, so you will need to create a new String with characters at positions 0,2,4 removed. As one option, you may use StringBuilder for that, as answered here: How to remove single character from a String
I think, you need to redesign the task:
"new string must contains all characters except ..."
Now, seems weak initial data structure and the goal.
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How can I generate a String and an image array in NetBeans? I try to make the arrays like
string{"lion","cat","dog","bird"};
How can I use the Random class to get s[i] where i is random?
String [] animals = {"lion","cat","dog","bird"};
int rndindex = (int)(Math.random()*number_of_element);
String rndAnimal = animals[rndIndex];
Make the array, get a random number between 0 and n inclusively where n is the number of elements in the array. Then retrieve that element.
java.util.Random rand = new java.util.Random();
int index = rand.nextInt(4);
System.out.println(string[index]);
If I understand your question, one solution is to use Collections.shuffle(List). I know, you wanted to do it with a String[] bute we can use Arrays.asList(T...) and use the fact that this List<String> is backed by a String[] like so,
public static void main(String[] args) {
String[] animals = { "lion", "cat", "dog", "bird" };
System.out.println(Arrays.toString(animals));
Collections.shuffle(Arrays.asList(animals));
System.out.println(Arrays.toString(animals));
}
Output is
[lion, cat, dog, bird]
[cat, lion, dog, bird]
Edit
If you just want one element at a random position in the array, that would be
String[] animals = { "lion", "cat", "dog", "bird" };
System.out.println(animals[rand.nextInt(animals.length)]);