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Threading : Lazy Initialization vs Static Lazy Initialization

I am going through Java Memory Model video presentation and author is saying it is better to use Static Lazy Initialization compared to Lazy Initialization and I do not clear understand what he wants to say.
I wanted to reach to community and would appreciate if someone can explain difference between Static Lazy Initialization and Lazy Initialization with simple java code example.
Reference: Advanced Programming Topics - Java Memory Model

Well both implementations can be static so that is the first misunderstanding. The presenter in this video is explaining how you can exploit the thread-safety of class initialization.
Class initialization is inherently thread-safe and if you can have an object initialized on class initialization the object creation too are thread-safe.
Here is an example of a thread-safe statically initialized object
public class MySingletonClass{
private MySingletonClass(){
}
public static MySingletonClass getInstance(){
return IntiailizationOnDemandClassholder.instance;
}
private static class IntiailizationOnDemandClassHolder{
private static final MySingletonClass instance = new MySingletonClass();
}
}
What is important to know here, MySingletonClass instance variable will never be created and or initialized until getInstance() is invoked. And again since class initialization is thread-safe the instance variable of IntiailizationOnDemandClassholder will be loaded safely, once and is visible to all threads.
To answer your edit depends on your other type of implementation. If you want to do double-checked-locking your instance variable would need to be volatile. If you do not want DCL then you will need to synchronize access each time to your variable. Here are the two examples:
public class DCLLazySingleton{
private static volatile DCLLazySingleton instance;
public static DCLLazySingleton getInstace(){
if(instance == null){
synchronized(DCLLazySingleton.class){
if(instance == null)
instance=new DCLLazySingleton();
}
}
return instance;
}
and
public class ThreadSafeLazySingleton{
private static ThreadSafeLazySingleton instance;
public static ThreadSafeLazySingleton getInstance(){
synchronized(ThreadSafeLazySingleton.class){
if(instance == null){
instance = new ThreadSafeLazySingleton();
}
return instance;
}
}
The last example requires a lock acquisition on every request of the instance. The second example requires a volatile-read on each access (may be cheap or not, depends on the CPU).
The first example will always lock once regardless of the CPU. Not only that but each read will be a normal without any need to worry about thread-safety. I personally like the first example I have listed.

I think the author in the presentation refers to the fact that a static field would be initialized only once in a thread-safe way at the first use of the class which contains that field (this is guaranteed by JMM):
class StaticLazyExample1 {
static Helper helper = new Helper();
static Helper getHelper() {
return helper;
}
}
Here helper field would be initialized upon first usage of StaticLazyExample1 class (i.e. upon constructor or static method call)
There is also Initialization On Demand Holder idiom, which is based on static lazy initialization:
class StaticLazyExample2 {
private static class LazyHolder {
public static Helper instance = new Helper();
}
public static Helper getHelper() {
return LazyHolder.instance;
}
}
Here a Helper instance would be created only upon first call to StaticLazyExample2.getHelper() static method. This code is guaranteed to be thread-safe and correct because of the initialization guarantees for static fields; if a field is set in a static initializer, it is guaranteed to be made visible, correctly, to any thread that accesses that class.
UPDATE
What is the difference between both types of initialization?
The static lazy initialization provides efficient thread safe lazy initialization of the static fields and has zero synchronization overhead.
On the other hand if you would like to lazily initialize a non-static field, you should write something like this:
class LazyInitExample1 {
private Helper instance;
public synchronized Helper getHelper() {
if (instance == null) instance == new Helper();
return instance;
}
}
Or use Double-Cheked Locking idiom:
class LazyInitExample2 {
private volatile Helper helper;
public Helper getHelper() {
if (helper == null) {
synchronized (this) {
if (helper == null) helper = new Helper();
}
}
return helper;
}
}
Should I mention they both require explicit synchronization and carry additional timing overhead comparing to static lazy initialization?

It is worth noting that the simplest thread safe static lazy initialisation is to use an enum This works because initialisation of static fields is thread safe and classes are lazily loaded anyway.
enum ThreadSafeLazyLoadedSingleton {
INSTANCE;
}
A class which uses a lazy loaded value is String. The hashCode is only computed the first time it is used. After that the cached hashCode is used.
I don't think you can say that one is better than the other because they are not really interchangeable.

A reference would be good here, for sure. They both have the same basic idea: Why allocate resources (memory, cpu) if you don't have to? Instead, defer allocation of those resources until they're actually needed. This can be good in intensive environments to avoid waste, but can be very bad if you need the results right now and cannot wait. Adding a "lazy but prudent" system is very difficult (one that detects downtime and runs these lazy calculations when it gets free time.)
Here's an example of lazy initialization.
class Lazy {
String value;
int computed;
Lazy(String s) { this.value = s; }
int compute() {
if(computed == 0) computed = value.length();
return computed;
}
}
Here's static lazy initializtion
class StaticLazy {
private StaticLazy staticLazy;
static StaticLazy getInstance() {
if(staticLazy == null) staticLazy = new StaticLazy();
return staticLazy;
}
}

The distinction is the mechanism you implement the lazy initialization. By Static Lazy Initialization I assume the presenter means this solution which relies on the JVM being compliant with any version of Java (see 12.4 Initialization of Classes and Interfaces, of the Java Language Specification).
Lazy Initialization probably means lazy initialization described in many other answers to this question. Such initialization mechanisms make assumptions about the JVM that are not thread-safe until Java 5 (as Java 5 has a real memory model specification).

Lazy loading is just a fancy name given to the process of initializing a class when it’s actually needed.
In simple words, Lazy loading is a software design pattern where the initialization of an object occurs only when it is actually needed and not before to preserve simplicity of usage and improve performance.
Lazy loading is essential when the cost of object creation is very high and the use of the object is very rare. So this is the scenario where it’s worth implementing lazy loading.The fundamental idea of lazy loading is to load object/data when needed.
Source: https://www.geeksforgeeks.org/lazy-loading-design-pattern/

Java: Lazy Initializing Singleton

The pattern to create singletons seems to be something like:
public class Singleton {
private static final Singleton instance = new Singleton();
private Singleton(){
}
public static Singleton getInstance()
{
return instance;
}
}
However my problem is how do you Unit with a class like this if the Singleton Constructor does something that is not unit test friendly e.g. calls external service , jndi lookup etc.
I would think i could refactor it like:
public class Singleton {
private static Singleton instance;
private Singleton(){
}
public synchronized static Singleton getInstance()
{
if(instance == null)
instance = new Singleton();
return instance;
}
//for the unit tests
public static void setInstance(Singleton s)
{
instancce = s;
}
}
The problem now is that just for unit testability I have forced the getInstance to be synchronized so just for testing aspect it will have a negative impact on the real application. Is there a way around it, it seems any other sort of lazy initialization will not work because of the broken nature of double locking pattern in java.

You can use an enum as a Singleton
enum Singleton {
INSTANCE;
}
Say your singleton does something undesirable in unit tests, you can;
// in the unit test before using the Singleton, or any other global flag.
System.setProperty("unit.testing", "true");
Singleton.INSTANCE.doSomething();
enum Singleton {
INSTANCE;
{
if(Boolean.getBoolean("unit.testing")) {
// is unit testing.
} else {
// normal operation.
}
}
}
Note: there is no synchronised blocks or explicit lock needed. The INSTANCE will not be loaded until the .class is accessed and not initialised until a member is used. provided you only use Singleton.INSTANCE and not Singleton.class there won't be a problem with the value used to initialise changing later.
Edit: if you use just the Singleton.class this might not initialise the class. It doesn't in this example on Java 8 update 112.
public class ClassInitMain {
public static void main(String[] args) {
System.out.println("Printing a class reference");
Class clazz = Singleton.class;
System.out.println("clazz = " + clazz);
System.out.println("\nUsing an enum value");
Singleton instance = Singleton.INSTANCE;
}
static enum Singleton {
INSTANCE;
Singleton() {
System.out.println(getClass() + " initialised");
}
}
}
prints
Printing a class reference
clazz = class ClassInitMain$Singleton
Using an enum value
class ClassInitMain$Singleton initialised

You could use the Factory pattern to create the singleton, and switch implementations depending on evironment.
Or, avoid using the singleton pattern, and use Dependency Injection instead.

Double-checked locking is broken in every language, not just Java.
I tend to eschew singletons, but you can use the holder pattern just fine if you need them, as recommended in Josh Bloch's Effective Java:
public class Foo
{
static class Holder
{
static final Foo instance = new Foo();
}
public static Foo getInstance()
{
return Holder.instance;
}
private Foo()
{
}
// ...
}
EDIT: Repaired the reference.

You can dependency inject the singleton instance, override the getInstance() from the unit test code, use aspect oriented programming to intercept the method call and return a different object, or use a tool like jmockit which lets you mock pretty much anything, including statics, final classes, constructors, and all the stuff people normally say is "untestable."
One approach I've taken in legacy systems (where I wanted to make something testable with a minimal impact on the system's architecture) was to modify the factory methods (getInstance) to check a system property for an alternate implementation that I would instantiate instead. This was set to an alternate, mock object in the unit test suite.
As for the "double checked locking is broken" statement, that's not really true anymore, if you use the volatile keyword, and Java >= 1.5. It was broken (even with volatile) with 1.4 and earlier, but if you know your code will be run on only recent JVMs, I wouldn't worry about it. But I also wouldn't use a singleton anyway: having a DI/IOC container manage the lifecycle of the object would solve both of your problems (testability and synchronized accessor bottleneck) much more elegantly.

How about you lazy initialize in the build phase where you execute the unit tests. Then you change the code back to inline initialize before it's compiled for distribution.
Your production code is inline initialized, except during your tests. Perhaps this discrepancy btw production and testing code could introdude bugs, but which?
(Of course if this is a solution, we let a build phase + tool do the work. I see this facilitated with maven and dp4j).

Thread Safe Efficient way to implement singleton pattern in Java? [duplicate]

This question already has answers here:
Closed 12 years ago.
Possible Duplicate:
Efficient way to implement singleton pattern in Java
I was reading this Best Singleton Implementation In Java, but its not thread safe.
As per wiki :
if(singleton==null) {
synchronized(Singleton.class) { //
this is needed if two threads are
waiting at the monitor at the // time
when singleton was getting
instantiated if(singleton==null)
singleton= new Singleton(); }
}
But Find Bugs utility gives two errors in this :
1. Double null check.
2. Incorrect lazy initialization of static field.
What is the best way,
Is it Correct :
synchronized (Singleton.class) {
if (singleton== null) {
singleton= new Singleton();
}
}

The most efficient/simplest way to make a lazy loading Singleton is just
enum Singleton {
INSTANCE
}
Note: there is no need for locking as class loading is thread safe. The class is final by default and the constructor cannot be called via reflection. The INSTANCE will not be created until the INSTANCE, or the class is used. If you are worried the class might be accidentally used you can wrap the singleton in an inner class.
final class Singleton {
private Singleton() { }
static class SingletonHolder {
static final Singleton INSTANCE = new Singleton();
}
public static Singleton getInstance() {
return SingletonHolder.INSTANCE;
}
}
IMHO, you have to be pretty paranoid to consider this a better solution.

A lot has been written about this issue. Yes, the simple double-check-locking pattern is not safe. But you can make it safe by declaring the static instance as volatile. The new Java Memory Model specification adds some code-reordering restrictions for compilers when dealing with volatile, therefore the original risks are gone.
Anyway, I rarely really need this kind of lazyness when creating the instance, so I usually simply create it statically at class-loading time:
private static MyClass instance = new MyClass();
This is short and clear. As an alternative, if you really want to make it lazy, you can take advantage of the class loading characteristics and do this:
public class MyClass {
private static class MyClassInit {
public static final MyClass instance = new MyClass();
}
public static MyClass getInstance() {
return MyClassInit.instance;
}
...
}
The nested class will not be loaded until the first time you call getInstance().

The first code sample in the accepted answer for Efficient way to implement singleton pattern in Java is thread safe. The creation of the INSTANCE is performed by the class loader the first time the class is loaded; it's performed exactly once, and in a thread-safe way:
public final class Foo {
private static final Foo INSTANCE = new Foo();
private Foo() {
if (INSTANCE != null) {
throw new IllegalStateException("Already instantiated");
}
}
public static Foo getInstance() {
return INSTANCE;
}
}
(copied from What is an efficient way to implement a singleton pattern in Java?)
The 2nd code sample in the question is correct and thread-safe, but it causes synchronization on each call to getInstance(), which affects performance.

Thread safety in Singleton

I understand that double locking in Java is broken, so what are the best ways to make Singletons Thread Safe in Java? The first thing that springs to my mind is:
class Singleton{
private static Singleton instance;
private Singleton(){}
public static synchronized Singleton getInstance(){
if(instance == null) instance = new Singleton();
return instance;
}
}
Does this work? if so, is it the best way (I guess that depends on circumstances, so stating when a particular technique is best, would be useful)

Josh Bloch recommends using a single-element enum type to implement singletons (see Effective Java 2nd Edition, Item 3: Enforce the singleton property with a private constructor or an enum type).
Some people think this is a hack, since it doesn't clearly convey intent, but it does work.
The following example is taken straight from the book.
public enum Elvis {
INSTANCE;
public void leaveTheBuilding() { ... }
}
Here is his closing arguments:
This approach [...] is more concise, provides the serialization machinery for free, and provides an ironclad guarantee against multiple instantiations, even in the face of sophisticated serialization or reflection attacks. While this approach has yet to be widely adopted, a single-element enum type is the best way to implement a singleton.
On enum constant singleton guarantee
JLS 8.9. Enums
An enum type has no instances other than those defined by its enum constants. It is a compile-time error to attempt to explicitly instantiate an enum type (§15.9.1).
The final clone method in Enum ensures that enum constants can never be cloned, and the special treatment by the serialization mechanism ensures that duplicate instances are never created as a result of deserialization. Reflective instantiation of enum types is prohibited. Together, these four things ensure that no instances of an enum type exist beyond those defined by the enum constants.
On lazy initialization
The following snippet:
public class LazyElvis {
enum Elvis {
THE_ONE;
Elvis() {
System.out.println("I'M STILL ALIVE!!!");
}
}
public static void main(String[] args) {
System.out.println("La-dee-daaa...");
System.out.println(Elvis.THE_ONE);
}
}
Produces the following output:
La-dee-daaa...
I'M STILL ALIVE!!!
THE_ONE
As you can see, THE_ONE constant is not instantiated through the constructor until the first time it's accessed.

I see no problem with your implementation (other than the fact that the lock for the singleton-monitor may be used by other methods, for other reasons, and thus, unnecessarily, prevent some other thread from getting the instance). This could be avoided by introducing an extra Object lock to lock on.
This Wikipedia article suggests another method:
public class Something {
private Something() {
}
private static class LazyHolder {
private static final Something INSTANCE = new Something();
}
public static Something getInstance() {
return LazyHolder.INSTANCE;
}
}
From the article:
This implementation is a well-performing and concurrent implementation valid in all versions of Java.
...
The implementation relies on the well-specified initialization phase of execution within the Java Virtual Machine (JVM); see section 12.4 of Java Language Specification (JLS) for details.

My preference is to just do:
class Singleton {
private static final INSTANCE = new Singleton();
private Singleton(){}
public Singleton instance(){
return INSTANCE;
}
}
It is rare that you need lazy initialization. You should always start with eager initialization and only change to lazy initialization if you see problems. Unless you have measured and pinpointed Singleton instantiation as the culprit of performance problem, just use eager initialization. It's simpler and more performant.
You could use enum for sure, but personally I don't bother because the benefit over normal eager instantiation is security (against reflection attack), and most of the time my code is vulnerable to such attacks anyways :p

Josh Bloch recommends 2 solutions:
1) worser:
class Singleton {
public static Singleton instance = new Singleton();
...
}
2) better:
public enum Singleton {
INSTANCE;
...
}

You can use this snippet of code from wiki
public class Singleton {
// Private constructor prevents instantiation from other classes
private Singleton() {}
/**
* SingletonHolder is loaded on the first execution of Singleton.getInstance()
* or the first access to SingletonHolder.INSTANCE, not before.
*/
private static class SingletonHolder {
private static final Singleton INSTANCE = new Singleton();
}
public static Singleton getInstance() {
return SingletonHolder.INSTANCE;
}
}

Simplified Singleton pattern in Java

The default way to implement singleton pattern is:
class MyClass {
private static MyClass instance;
public static MyClass getInstance() {
if (instance == null) {
instance = new MyClass();
}
return instance;
}
}
In an old project, I've tried to simplify the things writing:
class MyClass {
private static final MyClass instance = new MyClass();
public static MyClass getInstance() {
return instance;
}
}
But it sometimes fail. I just never knew why, and I did the default way.
Making a SSCCE to post here today, I've realized the code works.
So, I would like to know opinions..
Is this a aleatory fail code?
Is there any chance of the second approach return null?
Am I going crazy?
--
Although I don't know if is the right answer for every case, it's a really interesting answer by #Alfred:
I also would like to point out that singletons are testing nightmare and that according to the big guys you should use google's dependency injection framework.

The recommended (by Effective Java 2nd ed) way is to do the "enum singleton pattern":
enum MyClass {
INSTANCE;
// rest of singleton goes here
}
The key insight here is that enum values are single-instance, just like singleton. So, by making a one-value enum, you have just made yourself a singleton. The beauty of this approach is that it's completely thread-safe, and it's also safe against any kinds of loopholes that would allow people to create other instances.

The first solution is (I believe) not thread-safe.
The second solution is (I believe) thread-safe, but might not work if you have complicated initialization dependencies in which MyClass.getInstance() is called before the MyClass static initializations are completed. That's probably the problem you were seeing.
Both solutions allow someone to create another instance of your (notionally) singleton class.
A more robust solution is:
class MyClass {
private static MyClass instance;
private MyClass() { }
public synchronized static MyClass getInstance() {
if (instance == null) {
instance = new MyClass();
}
return instance;
}
}
In a modern JVM, the cost of acquiring a lock is miniscule, provided that there is no contention over the lock.
EDIT #Nate questions my statement about static initialization order possibly causing problems. Consider the following (pathological) example:
public ClassA {
public static ClassB myB = ClassB.getInstance();
public static ClassA me = new ClassA();
public static ClassA getInstance() {
return me;
}
}
public ClassB {
public static ClassA myA = ClassA.getInstance();
public static ClassB me = new ClassB();
public static ClassB getInstance() {
return me;
}
}
There are two possible initialization orders for these two classes. Both result in a static method being called before the method's classes static initialization has been performed. This will result in either ClassA.myB or ClassB.myA being initialized to null.
In practice, cyclic dependencies between statics are less obvious than this. But the fact remains that if there is a cyclic dependency: 1) the Java compiler won't be able to tell you about it, 2) the JVM will not tell you about it. Rather, the JVM will silently pick an initialization order without "understanding" the semantics of what you are trying to do ... possibly resulting in something unexpected / wrong.
EDIT 2 - This is described in the JLS 12.4.1 as follows:
As shown in an example in §8.3.2.3, the fact that initialization code is unrestricted allows examples to be constructed where the value of a class variable can be observed when it still has its initial default value, before its initializing expression is evaluated, but such examples are rare in practice. (Such examples can be also constructed for instance variable initialization; see the example at the end of §12.5). The full power of the language is available in these initializers; programmers must exercise some care. ...

The second example is preferable, since the first isn't thread safe (as pointed out in the comments). The first example uses a technique called lazy instantiation (or lazy initialization), which ensures that the Singleton instance isn't created unless it's actually needed. This isn't really necessary in Java because of the way Java handles class loading and static instance variable initialization.

I also would like to point out that singletons are testing nightmare and that according to the big guys you should use google's dependency injection framework.

Remember, you need to declare a private constructor to ensure the singleton property.
The second case could be even simpler with just
class MyClass {
public static final MyClass instance = new MyClass();
private MyClass() {
super()
}
}
`

As others have noted, the first is not thread-safe. Don't bother with it as the second is perfectly fine, and will instantiate the object only when MyClass is referenced. Further it makes the reference final which expresses the intent better.
Just make sure that the declaration
private static final MyClass INSTANCE = new MyClass();
is the first static declaration in your class to avoid risk of calls to getInstance() or INSTANCE before it is initialized.

Don't forget the SingletonHolder pattern. See this SO question.

I don't know the answers to your questions, but here is how I might structure the same thing.
class MyClass {
private static MyClass instance;
static {
instance = new MyClass();
}
private MyClass() { }
public static MyClass getInstance() {
return instance;
}
}