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java program to loop and output 2,5,7,10,12 [closed]

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Loop
how to loop this without using array? I'm clearly confuse in this in java module I don't know the solution ;-; I'm new to java pls helppp mee

Try this.
for (int i = 5; i <= 25; i += 5)
System.out.println(i / 2);
Or
for (int i = 1; i <= 5; i++)
System.out.println(i * 5 / 2);
output:
2
5
7
10
12
Think for yourself why this produces the correct result.

public class Main {
public static void main(String[] args) {
int outputNum = 0;
for(int i = 0; i < 5; i++){
if (i % 2 == 0){
outputNum += 2;
}
else {
outputNum += 3;
}
System.out.print(outputNum + (i == 4 ? "" : " "));
}
}
}
This does exactly what you need.
Explanation:
In the loop if the i variable is even we add 2 to the output number (since you need to add 2 then 3 then 2...) and if i is uneven then we add three. At the end of the for loop we print the number without the newline using System.out.print and we separate them by a space if we aren't printing the last number using a ternary operator (i == 4 ? "" : " ") which returns a space if i is not equal to 4 and an empty string if it is, we do this to avoid having a space on the end of our output, so we get this 2 5 7 10 12 instead of this 2 5 7 10 12

while (1) loop with continue and break statements [closed]

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I need help with a while(1) loop that contains a continue and break statement. It must count from numbers 1 to 20 and for every even number, it must output the values. I have to use a continue after my writeToPage statement and use a break statement when it reaches 20.
This is what I tested out but the file will not even load:
writeToPage("Program 4: Continue and Break");
writeToPage("");
while(1) {
if (i % 2 == 0){
writeToPage(+ i);
continue;
}
if (i >= 20){
break;
}
}
I'm not sure if I'm putting them in the wrong place.

For infinite loop, you need to write while(true) instead of while(1).
If i % 2 != 0 is true, simply increment i by 1 and continue; otherwise, print the value of i and increment i by 1.
Demo:
public class Main {
public static void main(String[] args) {
int i = 1;
while (true) {
if (i % 2 != 0) {
i++;
continue;
} else {
writeToPage(i);
i++;
}
if (i >= 20) {
break;
}
}
}
static void writeToPage(int i) {
System.out.println(i);
}
}
Output:
2
4
6
8
10
12
14
16
18
20

how to stop the code when the code has executed a certain amount of times? [closed]

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Name: runSequence4
Input: Intake feed, int n
Output: none
Action: Takes in an intake object and calls the method give(). It first passes the number 1 into
give and then alternates between -1 and 1. It does this n number of times.
How do I stop the loop when the code executes it "N" times?
This is what i have so far
public void runSequence4(Intake feed, int n){
for(int x = 1; ???? ; x = (x * -1)){
feed.give(x);
}
}

Just add a variable i to store the current iteration and test whether it has exceeded n
public void runSequence4(Intake feed, int n){
for(int x = 1, i = 0; i < n; x = (x * -1), i++){
feed.give(x);
}
}

Finding the sum of the two greatest numbers of 3 [closed]

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With Java, how would one find the greatest two numbers of a set of 3 numbers without using if conditionals.
For example given the 3 numbers {2,3,5}
int a = 2;
int b = 3;
int c = 5;
int total;
total would be replaced with the value of c+b = 8

List<Integer> data = Arrays.asList(23,6,13);
Collections.sort(data);
Collections.reverse(data)
data = data.sublist(0,2);
System.out.println(data);

One line:
int biggest = (a > b ? a : b) > c ? (a > b ? a : b) : c;
Two lines:
int firstStep = (a > b ? a : b);
int biggest = firstStep > c ? firstStep : c;

Java 8:
int max = Arrays.stream(numbers).max().getAsInt();
int sec_max = Arrays.stream(numbers).filter(i -> i != max).max().getAsInt();

Write a program that returns number of decimal digits in the given input string [closed]

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Write a program that returns number of decimal digits in the given input string.
ex :
Input: 2345abc423
output: 7
This is my code:
Scanner input = new Scanner(System.in);
String s = input.nextLine();
int len = s.length();
int numbers = 0 ;
for(int i=0; i < len; i++){
char c = s.charAt(i);
int num = (int) c;
while(num <= 57 && num >= 48){
System.out.println(numbers);
numbers++;
}
}
System.out.print(numbers);
/////
sorry because my question wasn't obvious
my program always return 0 , not the number of decimal digits
thanks #Keppil i tried if and it worked
thanks

Your program will never exit the while loop since the condition never changes. You should just use an if instead:
if (num <= 57 && num >= 48) {
System.out.println(numbers);
numbers++;
}

Solution that abuses regex:
System.out.println(input.replaceAll("\\D", "").length());