The code attached below is suppose to produce this output:
The array is: 4 3 6 9 3 9 5 4 1 9
This array DOES contain 5.
Sorted by Arrays.sort(): 1 3 3 4 4 5 6 9 9 9
Sorted by Sweep Sort: 1 3 3 4 4 5 6 9 9 9
Sorted by Selection Sort: 1 3 3 4 4 5 6 9 9 9
Sorted by Insertion Sort: 1 3 3 4 4 5 6 9 9 9
But it doesn't. I followed the instruction in the book that I am reading and it didn't help. Can I get your opinion on what those errors might be? I'm not asking for solutions, I want to be pointed in the right direction as to where the errors are and what type of errors they are.
import java.util.Arrays;
/**
* This class looks like it's meant to provide a few public static methods
* for searching and sorting arrays. It also has a main method that tests
* the searching and sorting methods.
*
* TODO: The search and sort methods in this class contain bugs that can
* cause incorrect output or infinite loops. Use the Eclipse debugger to
* find the bugs and fix them
*/
public class BuggySearchAndSort {
public static void main(String[] args) {
int[] A = new int[10]; // Create an array and fill it with small random ints.
for (int i = 0; i < 10; i++)
A[i] = 1 + (int)(10 * Math.random());
int[] B = A.clone(); // Make copies of the array.
int[] C = A.clone();
int[] D = A.clone();
System.out.print("The array is:");
printArray(A);
if (contains(A,5))
System.out.println("This array DOES contain 5.");
else
System.out.println("This array DOES NOT contain 5.");
Arrays.sort(A); // Sort using Java's built-in sort method!
System.out.print("Sorted by Arrays.sort(): ");
printArray(A); // (Prints a correctly sorted array.)
bubbleSort(B);
System.out.print("Sorted by Bubble Sort: ");
printArray(B);
selectionSort(C);
System.out.print("Sorted by Selection Sort: ");
printArray(C);
insertionSort(D);
System.out.print("Sorted by Insertion Sort: ");
printArray(D);
}
/**
* Tests whether an array of ints contains a given value.
* #param array a non-null array that is to be searched
* #param val the value for which the method will search
* #return true if val is one of the items in the array, false if not
*/
public static boolean contains(int[] array, int val) {
for (int i = 0; i < array.length; i++) {
if (array[i] == val)
return true;
else
return false;
}
return false;
}
/**
* Sorts an array into non-decreasing order. This inefficient sorting
* method simply sweeps through the array, exchanging neighboring elements
* that are out of order. The number of times that it does this is equal
* to the length of the array.
*/
public static void bubbleSort(int[] array) {
for (int i = 0; i < array.length; i++) {
for (int j = 0; j < array.length-1; i++) {
if (array[j] > array[j+1]) { // swap elements j and j+1
int temp = array[j];
array[j] = array[j+1];
array[j+1] = temp;
}
}
}
}
/**
* Sorts an array into non-decreasing order. This method uses a selection
* sort algorithm, in which the largest item is found and placed at the end of
* the list, then the second-largest in the next to last place, and so on.
*/
public static void selectionSort(int[] array) {
for (int top = array.length - 1; top > 0; top--) {
int positionOfMax = 0;
for (int i = 1; i <= top; i++) {
if (array[1] > array[positionOfMax])
positionOfMax = i;
}
int temp = array[top]; // swap top item with biggest item
array[top] = array[positionOfMax];
array[positionOfMax] = temp;
}
}
/**
* Sorts an array into non-decreasing order. This method uses a standard
* insertion sort algorithm, in which each element in turn is moved downwards
* past any elements that are greater than it.
*/
public static void insertionSort(int[] array) {
for (int top = 1; top < array.length; top++) {
int temp = array[top]; // copy item that into temp variable
int pos = top - 1;
while (pos > 0 && array[pos] > temp) {
// move items that are bigger than temp up one position
array[pos+1] = array[pos];
pos--;
}
array[pos] = temp; // place temp into last vacated position
}
}
/**
* Outputs the ints in an array on one line, separated by spaces,
* with a line feed at the end.
*/
private static void printArray(int[] array) {
for (int i = 0; i < array.length; i++) {
System.out.print(" ");
System.out.print(array[i]);
}
System.out.println();
}
}
public static void bubbleSort(int[] array) {
for (int i = 0; i < array.length; i++) {
for (int j = 0; j < array.length-1; i++) { //<---- wrong increment. it should be j++
if (array[j] > array[j+1]) { // swap elements j and j+1
int temp = array[j];
array[j] = array[j+1];
array[j+1] = temp;
}
}
}
}
in this part is at least one error. You should check your loops if your programm does not determine.
I have finished my project and decided to drop a help
public static void main(String[] args) {
int[] A = new int[10]; // Create an array and fill it with small random ints.
for (int i = 0; i < 10; i++)
A[i] = 1 + (int)(10 * Math.random());
int[] B = A.clone(); // Make copies of the array.
int[] C = A.clone();
int[] D = A.clone();
System.out.print("The array is:");
printArray(A);
if (contains(A,5))
System.out.println("This array DOES contain 5.");
else
System.out.println("This array DOES NOT contain 5.");
Arrays.sort(A); // Sort using Java's built-in sort method!
System.out.print("Sorted by Arrays.sort(): ");
printArray(A); // (Prints a correctly sorted array.)
sweepSort(B);
System.out.print("Sorted by Sweep Sort: "); //Changed name
printArray(B);
selectionSort(C);
System.out.print("Sorted by Selection Sort: ");
printArray(C);
insertionSort(D);
System.out.print("Sorted by Insertion Sort: ");
printArray(D);
}
public static boolean contains(int[] array, int val) {
for (int i = 0; i < array.length; i++) {
if (array[i] == val)
return true;
//removed else
} //removed return false;
return false;
}
public static void sweepSort(int[] array) {
for (int i = 0; i < array.length; i++) {
for (int j = 0; j < array.length-1; j++) { //'i++' => 'j++'
if (array[j] > array[j+1]) { // swap elements j and j+1
int temp = array[j];
array[j] = array[j+1];
array[j+1] = temp;
}
}
}
}
public static void selectionSort(int[] array) {
for (int top = array.length - 1; top > 0; top--) {
int positionOfMax = 0;
for (int i = 1; i <= top; i++) {
if (array[i] > array[positionOfMax]) //replaced [1]
positionOfMax = i;
}
int temp = array[top]; // swap top item with biggest item
array[top] = array[positionOfMax];
array[positionOfMax] = temp;
}
}
public static void insertionSort(int[] array) {
for (int top = 1; top < array.length; top++) {
int temp = array[top]; // copy item that into temp variable
int pos = top - 1;
while (pos >= 0 && array[pos] >= temp) { // '>' => '>='
// move items that are bigger than temp up one position
array[pos+1] = array[pos];
pos--;
}
array[pos+1] = temp; // place temp into last vacated position //added '+1'
}
}
private static void printArray(int[] array) {
for (int i = 0; i < array.length; i++) {
System.out.print(" ");
System.out.print(array[i]);
}
System.out.println();
}
}
Thank for all your help guys. Using the debugger I found the for main issues
Error 1:
public static void sweepSort(int[] array) {
for (int i = 0; i < array.length; i++) {
for (int j = 0; j < array.length-1; i++) {<------// need change i++ to j++
if (array[j] > array[j+1]) { // swap elements j and j+1
int temp = array[j];
array[j] = array[j+1];
array[j+1] = temp;
}
}
}
}
Error 2 and 3:
public static void insertionSort(int[] array) {
for (int top = 1; top < array.length; top++) {
int temp = array[top]; // copy item that into temp variable
int pos = top - 1;
while (pos > 0 && array[pos] > temp) { //<----- need to change '>' to '>='
// move items that are bigger than temp up one position
array[pos+1] = array[pos];
pos--;
}
array[pos ] = temp; // place temp into last vacated position // <------------------------need to change 'array[pos ]' to 'array[pos + 1]'
}
}
Error 4:
public static boolean contains(int[] array, int val) {
for (int i = 0; i < array.length; i++) {
if (array[i] == val)
return true;
else //<---------- need to remove this
return false; //<---------- need to remove this
}
return false;
}
package sort;
import java.util.Arrays;
/**
* This class looks like it's meant to provide a few public static methods
* for searching and sorting arrays. It also has a main method that tests
* the searching and sorting methods.
*
* TODO: The search and sort methods in this class contain bugs that can
* cause incorrect output or infinite loops. Use the Eclipse debugger to
* find the bugs and fix them
*/
public class BuggySearchAndSort {
public static void main(String[] args) {
int[] A = new int[10]; // Create an array and fill it with small random ints.
for (int i = 0; i < 10; i++)
A[i] = 1 + (int)(10 * Math.random());
int[] B = A.clone(); // Make copies of the array.
int[] C = A.clone();
int[] D = A.clone();
System.out.print("The array is:");
printArray(A);
if (contains(A,5))
System.out.println("This array DOES contain 5.");
else
System.out.println("This array DOES NOT contain 5.");
Arrays.sort(A); // Sort using Java's built-in sort method!
System.out.print("Sorted by Arrays.sort(): ");
printArray(A); // (Prints a correctly sorted array.)
bubbleSort(B);
System.out.print("Sorted by Bubble Sort: ");
printArray(B);
selectionSort(C);
System.out.print("Sorted by Selection Sort: ");
printArray(C);
insertionSort(D);
System.out.print("Sorted by Insertion Sort: ");
printArray(D);
}
/**
* Tests whether an array of ints contains a given value.
* #param array a non-null array that is to be searched
* #param val the value for which the method will search
* #return true if val is one of the items in the array, false if not
*/
public static boolean contains(int[] array, int val) {
for (int i = 0; i < array.length; i++) {
if (array[i] == val)
return true;
}
return false;
}
/**
* Sorts an array into non-decreasing order. This inefficient sorting
* method simply sweeps through the array, exchanging neighboring elements
* that are out of order. The number of times that it does this is equal
* to the length of the array.
*/
public static void bubbleSort(int[] array) {
for (int i = 0; i < array.length; i++) {
for (int j = 0; j < array.length-1; j++) {
if (array[j] > array[j+1]) { // swap elements j and j+1
int temp = array[j];
array[j] = array[j+1];
array[j+1] = temp;
}
}
}
}
/**
* Sorts an array into non-decreasing order. This method uses a selection
* sort algorithm, in which the largest item is found and placed at the end of
* the list, then the second-largest in the next to last place, and so on.
*/
public static void selectionSort(int[] array) {
for (int top = array.length - 1; top > 0; top--) {
int positionOfMax = 0;
for (int i = 0; i <= top; i++) {
if (array[i] > array[positionOfMax])
positionOfMax = i;
}
int temp = array[top]; // swap top item with biggest item
array[top] = array[positionOfMax];
array[positionOfMax] = temp;
}
}
/**
* Sorts an array into non-decreasing order. This method uses a standard
* insertion sort algorithm, in which each element in turn is moved downwards
* past any elements that are greater than it.
*/
public static void insertionSort(int[] array) {
for (int top = 1; top < array.length; top++) {
int temp = array[top]; // copy item that into temp variable
int pos = top ;
while (pos > 0 && array[pos-1] >= temp) {
// move items that are bigger than temp up one position
array[pos] = array[pos-1];
pos--;
}
array[pos] = temp; // place temp into last vacated position
}
}
/**
* Outputs the ints in an array on one line, separated by spaces,
* with a line feed at the end.
*/
private static void printArray(int[] array) {
for (int i = 0; i < array.length; i++) {
System.out.print(" ");
System.out.print(array[i]);
}
System.out.println();
}
}
Related
I'm trying to make a selection sort algorithm in java that finds the smallest element of an unsorted array and puts it on the end of a new array. But my program only copies the first element twice, gets the next one, and then the rest is all zeroes:
public static int find_min(int[] a){
int m = a[0];
for (int i = 0; i < a.length; i++){
if (m > a[i])
m = a[i];
}
return m;
}
public static int[] selectionSort(int[] unsorted){
int[] c = new int[unsorted.length];
for(int i = 0; i < unsorted.length; i++){
int smallest = find_min(unsorted);
c[i] = smallest;
unsorted = Arrays.copyOfRange(unsorted, i+1, unsorted.length );
}
return c;
}
When I put in something like:
public static void main(String[] args){
int a[] = {1,-24,4,-4,6,3};
System.out.println(Arrays.toString(selectionSort(a)));
}
I get:
[-24, -24, -4, 0, 0, 0]
where is this going wrong? Is this a bad algorithm?
Ok, let's revisit the selection sort algorithm.
public static void selectionSort(int[] a) {
final int n = a.length; // to save some typing.
for (int i = 0; i < n - 1; i++) {
// i is the position where the next smallest element should go.
// Everything before i is sorted, and smaller than any element in a[i:n).
// Now you find the smallest element in subarray a[i:n).
// Actually, you need the index
// of that element, because you will swap it with a[i] later.
// Otherwise we lose a[i], which is bad.
int m = i;
for (int j = m + 1; j < n; j++) {
if (a[j] < a[m]) m = j;
}
if (m != i) {
// Only swap if a[i] is not already the smallest.
int t = a[i];
a[i] = a[m];
a[m] = t;
}
}
}
In conclusion
You don't need extra space to do selection sort
Swap elements, otherwise you lose them
Remembering the loop invariant is helpful
I need to implement the following in java.
Input: an array of integers
Output: Rearrange the array to have the following:
Suppose the first element in the original array has the value x
In the new array, suppose that x is in position I, that is data[I] = x. Then, data[j] <= x for all x and for all j > I. This means that all the values to the "left" of x are less than or equal to x and all the values to the "right" are larger than x.
An example is as follows: Suppose the array has the elements in this initial order: 4,3,9,2,7,6,5. After applying your algorithm, you should get: 3,2,4,5,9,7,6. That is, the leftmost element, 4, is positioned in the resulting array so that all elements less than 4 (2 and 3) are to its left (in no particular order), and all elements larger than 4 are to its right (in no particular order).
There is no space requirement for the algorithm, only that the problem is solved in O(n) time.
I have implemented a bucket sort, but am having some difficulties with the code.
public class Problem4
{
public static void partition(int[] A)
{
int x = A[0];
int l = A.length;
int[] bucket = int [];
for(int i=0; i<bucket.length; i++){
bucket[i]=0;
}
for (int i=0; i<l; i++){
bucket[x[i]]++;
}
int outPos=0;
for(int i=0; i<bucket.length; i++){
for(int j=0; j<bucket[i]; j++){
x[outPos++]=i;
}
}
}
public static void main(String[] args) {
// TODO Auto-generated method stub
int[] A = {4,3,9,2,7,6,5};
System.out.println("Before partition:");
for(int i = 0; i < A.length; i++)
{
System.out.print(A[i] + " ");
}
partition(A);
System.out.println("After partition:");
System.out.println("Before partition:");
for(int i = 0; i < A.length; i++)
{
System.out.print(A[i] + " ");
}
}
}
The lines:
int[] bucket = int[],
bucket[x[i]]++;, and
x[outpost++] = i;
are causing me troubles. I am getting the error
The type of expression must be an array type but is resolved to an int.
The problem stems from that first line where I am trying to create a new array called bucket. I would appreciate any suggestions! Thanks!
I don't think you need to resort to a bucket sort. Instead you can simply walk through the array, placing elements that are less than the split value at the front and elements that are greater at the back. We can use two variables, front and back to keep track of the insert position at the front and back of the array. Starting at position 1 in the array, if the value is less than the split value we place at front and increment front and the current index. If the value is greater we swap it with the value at back and decrement back, but we keep the current index.
Here's some code to illustrate:
public static void main(String[] args)
{
int[] A = {4,3,9,2,7,6,5};
sort(A);
System.out.println(Arrays.toString(A));
}
public static void sort(int[] arr)
{
int split = arr[0];
int front = 0;
int back = arr.length-1;
for(int i=1; front != back; )
{
if(arr[i] <= split)
{
arr[front] = arr[i];
front += 1;
i++;
}
else
{
swap(arr, i, back);
back -= 1;
}
}
arr[front] = split;
}
public static void swap(int[] arr, int i, int j)
{
int t = arr[i];
arr[i] = arr[j];
arr[j] = t;
}
Output:
[3, 2, 4, 7, 6, 5, 9]
Another approach you can use is to use the standard partition algorithm of QuickSort.
I have modified your code and the following code
public class Problem4
{
/* This function takes last element as pivot,
places the pivot element at its correct
position in sorted array, and places all
smaller (smaller than pivot) to left of
pivot and all greater elements to right
of pivot */
public static int partition(int arr[], int low, int high)
{
int pivot = arr[high];
int i = (low-1); // index of smaller element
for (int j=low; j<high; j++)
{
// If current element is smaller than or
// equal to pivot
if (arr[j] <= pivot)
{
i++;
// swap arr[i] and arr[j]
int temp = arr[i];
arr[i] = arr[j];
arr[j] = temp;
}
}
// swap arr[i+1] and arr[high] (or pivot)
int temp = arr[i+1];
arr[i+1] = arr[high];
arr[high] = temp;
return i+1;
}
public static void main(String[] args) {
// TODO Auto-generated method stub
int[] A = {4,3,9,2,7,6,5};
System.out.println("Before partition:");
for(int i = 0; i < A.length; i++)
{
System.out.print(A[i] + " ");
}
// swap and call the standard partition algo of QuickSort
// on last element pivot. swap arr[low] and arr[high]
int low = 0;
int high = A.length-1;
int temp = A[low];
A[low] = A[high];
A[high] = temp;
partition(A, low, high);
System.out.println("\nAfter partition:");
for(int i = 0; i < A.length; i++)
{
System.out.print(A[i] + " ");
}
}
}
Outputs
Before partition:
4 3 9 2 7 6 5
After partition:
3 2 4 5 7 6 9
Hope it helps!
I have this code that sorts an array that is filled with random numbers and counts the number comparisons that it takes to complete the sort. I'm using the sort methods selection bubble and merge sort. I have the counter for the selection and the bubble but not the merge I have no clue where to put it. It might be a simple answer but I just can't get it to work.
Code:
/***********************************************************************
*
* Selection Sort:
* Reads in the array and then searches for the largest number.
* After it finds the largest number, it then swaps that number with the
* last number of the array
* Precondition: takes in an array of "n" items, which in this particular
* case is 2000, 4000, 6000, 8000, and 10000 random items in an array
* Postcondition: all numbers are sorted in ascending order
*
**********************************************************************/
public static int SelectionSort (int[] intArray) {
//Set initial count of comparisons at 0
comparisons= 0; //Number of swaps made
for(int last = intArray.length - 1; last > 0; last--) {
int largestIndex = last; //Int which places the largest number at the end of the array
// Find largest number
for(int i = 0; i < last; i++) {
//if i > the last number
if (intArray[i] > intArray[largestIndex]){
largestIndex = i; //switch the last number and i
} // end if
//Comparison+1
comparisons++;
} // end for
// Swap last element with largest element
int largest = intArray[last];
intArray[last] = intArray[largestIndex];
intArray[largestIndex] = largest;
}
//Return comparison counter
return comparisons;
}
/***********************************************************************
*
* Bubble Sort:
* Takes an array of random integers and sorts them by comparing adjacent
* numbers to one another. Whichever the larger adjacent number, Bubble
* Sort switches it towards the back end of the adjacent numbers. It does
* this until the list is fully sorted.
* Precondition: takes in a random array of integers
* Postcondition: array is sorted from smallest to largest
*
**********************************************************************/
public static int BubbleSort (int[] intArray) {
//Instance Variables
int n = intArray.length;
//boolean swap;
comparisons = 0;
//swap = false;
//for i starts at 0, when i is less than array length, i++ until reach array length
for(int i=0; i < n; i++) {
for(int j=1; j < (n-i); j++) {
if(intArray[j-1] > intArray[j]) {
//Swap the elements
int temp = intArray[j];
intArray[j] = intArray[j+1];
intArray[j+1] = temp;
//swap = true;
}
//comparisons get +1 until the for loop is done sorting
comparisons++;
} //End for loop
}
//Return the comparison counter
return comparisons;
}
/************************************************************************************
*
* Merge Sort:
* This method takes a random array and splits it in half. Once the array is
* split in half, it creates a temp0rary array. This temporary array is built by
* the method searching the two halves of the original array and puts the information
* in order stored in the temporary array. Once all the numbers are in order, the
* temporary array is then copied back to the original array.
* Precondition: take in an array of random integers
* Postcondition: return the random array sorted in ascending order
*
**********************************************************************************/
public static int mergeSort(int[] intArray) {
if(intArray.length >= 2) {
int mid = intArray.length / 2;
//Create 2 arrays to store half of the data in each
int[] first = new int[mid]; //holds first half of array
int[] second = new int[intArray.length - mid]; //holds second half of array
for(int i = 0; i < first.length; i++) {
first[i] = intArray[i];
}
for(int i = 0; i < second.length; i++) {
second[i] = intArray[mid+i];
}
mergeSort(first);
mergeSort(second);
merge(first, second, intArray); //Merge all together
}
return comparisons;
}
//merging first and second halves of mergeSort array
public static int merge(int[] first, int[] second, int[] intArray) {
int iFirst = 0;
int iSecond = 0;
int i = 0;
//moving the smaller element into intArray
while(iFirst < first.length && iSecond < second.length) {
comparisons++;
if(first[iFirst] < second[iSecond]) {
intArray[i] = first[iFirst];
iFirst++;
}
else {
intArray[i] = second[iSecond];
iSecond++;
}
i++;
}
//copying the remaining of first array
while(iFirst < first.length) {
intArray[i] = first[iFirst];
iFirst++; i++;
}
//copying the remaining of second array
while(iSecond < second.length)
{
intArray[i] = second[iSecond];
iSecond++; i++;
}
return comparisons;
}
/**************************************************************************************
* Instance methods:
* These methods perform actions to the array.
*
* copyArray()--makes a copy of the array to be used in the main class
* so that each method is able to create the same array
*
* printArray()--prints out the array for display
*
* randomArray()--creates a random integer array used by all three sorting methods
*
**************************************************************************************/
public static int[] copyArray(int[] intArray) {
//Constructor that creates copyArray
int[] copyArray = new int[intArray.length]; //siz equal to the length of the array
for(int i = 0; i < intArray.length; i++){
copyArray[i] = intArray[i];
} // end for
return copyArray;
} // end copyArray
//Prints out array
public static void printArray(int[] intArray){
//Preconditions
// Input: unsorted integer array
// Assumptions: array is full
//Postconditions
// Output: none
// Actions: array is displayed on screen
System.out.print("Array==> ");
for(int i = 0; i < intArray.length; i++){
System.out.print(intArray[i] + " ");
} // end for
System.out.println(" ");
} // end printArray
//Creates a random array that is used for each sorting method
public static int[] randomArray(int array, double range){
//Preconditions
// Input: size of array(n), range of integers (0 to range)
// Assumptions: none
//Postconditions
// Output: array of random integers 0 to floor(range)
// Actions: none
int[] intArray = new int[array];
for(int i = 0; i < array; i++){
intArray[i] = (int)(Math.random() * range);
} // end for
return intArray;
} // end randomIntArray
}
When (or just prior to) the following lines are executed:
if (intArray[i] > intArray[largestIndex]){
if(intArray[j-1] > intArray[j]) {
if(first[iFirst] < second[iSecond]) {
Your mergeSort method uses recursion. As such, it needs to take a comparisons parameter, and pass that down to each subsequent method call and receive the resulting value back again.
public static int mergeSort(int[] intArray, int comparisons) {
if(intArray.length >= 2) {
int mid = intArray.length / 2;
//Create 2 arrays to store half of the data in each
int[] first = new int[mid]; //holds first half of array
int[] second = new int[intArray.length - mid]; //holds second half of array
for(int i = 0; i < first.length; i++) {
first[i] = intArray[i];
}
for(int i = 0; i < second.length; i++) {
second[i] = intArray[mid+i];
}
comparisons = mergeSort(first, comparisons);
comparisons = mergeSort(second, comparisons);
comparisons = merge(first, second, intArray, comparisons); //Merge all together
}
return comparisons;
}
//merging first and second halves of mergeSort array
public static int merge(int[] first, int[] second, int[] intArray, int comparisons) {
int iFirst = 0;
int iSecond = 0;
int i = 0;
//moving the smaller element into intArray
while(iFirst < first.length && iSecond < second.length) {
comparisons++;
if(first[iFirst] < second[iSecond]) {
intArray[i] = first[iFirst];
iFirst++;
}
else {
intArray[i] = second[iSecond];
iSecond++;
}
i++;
}
//copying the remaining of first array
while(iFirst < first.length) {
intArray[i] = first[iFirst];
iFirst++; i++;
}
//copying the remaining of second array
while(iSecond < second.length)
{
intArray[i] = second[iSecond];
iSecond++; i++;
}
return comparisons;
}
I tried to make an implementation of bubble sort, but I am not sure whether it is correct or not. If you can give it a look and if it is a bubble sort and can be done in better way please don't be shy. Here is the code:
package Exercises;
import java.util.*;
public class BubbleSort_6_18
{
public static void main(String[] args)
{
Random generator = new Random();
int[] list = new int[11];
for(int i=0; i<list.length; i++)
{
list[i] = generator.nextInt(10);
}
System.out.println("Original Random array: ");
printArray(list);
bubbleSort(list);
System.out.println("\nAfter bubble sort: ");
printArray(list);
}
public static void bubbleSort(int[] list)
{
for(int i=0; i<list.length; i++)
{
for(int j=i + 1; j<list.length; j++)
{
if(list[i] > list[j])
{
int temp = list[i];
list[i] = list[j];
list[j] = temp;
}
}
}
}
public static void printArray(int[] list)
{
for(int i=0; i<list.length; i++)
{
System.out.print(list[i] + ", ");
}
}
}
private static int [] bublesort (int[] list , int length) {
boolean swap = true;
int temp;
while(swap){
swap = false;
for(int i = 0;i < list.length-1; i++){
if(list[i] > list[i+1]){
temp = list[i];
list[i] = list[i+1];
list[i+1] = temp;
swap = true;
}
}
}
return list;
}
Mohammod Hossain implementation is quite good but he does alot of unecessary iterations, sadly he didnt accept my edit and i can't comment due to reputations points so here is how it should look like:
public void sort(int[] array) {
int temp = 0;
boolean swap = true;
int range = array.length - 1;
while (swap) {
swap = false;
for (int i = 0; i < range; i++) {
if (array[i] > array[i + 1]) {
temp = array[i];
array[i] = array[i + 1];
array[i + 1] = temp;
swap = true;
}
}
range--;
}
}
This is the calssical implementation for bubble sort and it seems to be OK. There are several optimizations that can be done, but the overall idea is the same. Here are some ideas:
If there is an iteration of the outer cycle when no swap is performed in the inner cycle, then break, no use to continue
On each iteration of the outer cycle swap the direction of the inner one - do it once left to right and then do it once right to left(this helps avoid elements moving slowly towards the right end).
{
System.out.println("The Elments Before Sorting:");
for(i=0;i<a.length;i++)
{
System.out.print(a[i]+"\t");
}
for(i=1;i<=a.length-1;i++)
{
for(j=0;j<=a.length-i-1;j++)
{
if((a[j])>(a[j+1]))
{
temp=a[j];
a[j]=a[j+1];
a[j+1]=temp;
}
}
System.out.println("The Elements After Sorting:");
for(i=0;i<a.length;i++)
{
System.out.println(a[i]+"\t");
}
}
}
Short Answer: This is definitely NOT Bubble sort. It is a variant of Selection sort (a less efficient variant than the commonly known one).
It might be helpful to see a visualization of how they work on VisuAlgo
Why this is not bubble sort?
Because you loop over the array and compare each element to each other element on its right. if the right element is smaller you swap. Thus, at the end of the first outer loop iteration you will have the smallest element on the left most position and you have done N swaps in the worst case (think of a reverse-ordered array).
If you think about it, you did not really need to do all these swaps, you could have searched for the minimum value on the right then after you find it you swap. This is simply the idea of Selection sort, you select the min of remaining unsorted elements and put it in its correct position.
How does bubble sort look like then?
In bubble sort you always compare two adjacent elements and bubble the larger one to the right. At the end of the first iteration of the outer loop, you would have the largest element on the right-most position. The swap flag stops the outer loop when the array is already sorted.
void bubbleSort(int[] arr) {
boolean swap = true;
for(int i = arr.length - 1; i > 0 && swap; i--) {
swap = false;
// for the unsorted part of the array, bubble the largest element to the right.
for (int j = 0; j < i; j++) {
if (arr[j] > arr[j+1]) {
// swap
int temp = arr[j];
arr[j] = arr[j+1];
arr[j+1] = temp;
swap = true;
}
}
}
}
Yes it seems to be Bubble sort swapping the elements
Bubble sort
void bubbleSort(int arr[])
{
int n = arr.length;
for (int i = 0; i < n-1; i++)
for (int j = 0; j < n-i-1; j++)
if (arr[j] > arr[j+1])
{
// swap temp and arr[i]
int temp = arr[j];
arr[j] = arr[j+1];
arr[j+1] = temp;
}
}
It will give in worst case O(n^2) and even if array is sorted.
I think you got the idea of bubble sort by looking at your code:
Bubble sort usually works like the following:
Assume aNumber is some random number:
for (int i = 0; i < aNumber; i++)
{
for(int j = 0; j < aNumber; j++)
//Doing something with i and j, usually running it as a loop for 2D array
//array[i][j] will give you a complete sort.
}
How bubble sort works is it iterates through every single possible spot of the array. i x j times
The down side to this is, it will take square the number of times to sort something. Not very efficient, but it does get the work done in the easiest way.
You can loop over the array until no more elements are swapped
When you put the element at the last position you know it's the largest, so you can recuce the inner loop by 1
A bubblesort version with while loops from my first undergraduate year ("the BlueJ era").
public static void bubbleSort()
{
int[] r = randomArrayDisplayer();
int i = r.length;
while(i!=0){
int j = 0;
while(j!=i-1){
if(r[j+1]<r[j]){
swap(r,j,j+1);
}
j++;
}
i--;
}
}
private static void swap(int[] r, int u, int v)
{
int value = r[u];
r[u] = r[v];
r[v] = value;
arrayDisplayer(r);
}
My advice is to display every step in order to be sure of the correct behaviour.
public class BubbleSort {
public static void main(String[] args) {
int arr[] = {64, 34, 25, 12, 22, 11, 90};
BubbleSort client=new BubbleSort();
int[] result=client.bubbleSort(arr);
for(int i:result)
{
System.out.println(i);
}
}
public int[] bubbleSort(int[] arr)
{
int n=arr.length;
for(int i=0;i<n;i++)
{
for(int j=0;j<n-i-1;j++)
if(arr[j]>arr[j+1])
swap(arr,j,j+1);
}
return arr;
}
private int[] swap(int[] arr, int i, int j) {
int temp=arr[i];
arr[i]=arr[j];
arr[j]=temp;
return arr;
}
}
Above code is looks like implementation Selection sort , it's not a bubble sort.
Please find below code for bubble sort.
Class BubbleSort {
public static void main(String []args) {
int n, c, d, swap;
Scanner in = new Scanner(System.in);
System.out.println("Input number of integers to sort");
n = in.nextInt();
int array[] = new int[n];
System.out.println("Enter " + n + " integers");
for (c = 0; c < n; c++)
array[c] = in.nextInt();
for (c = 0; c < ( n - 1 ); c++) {
for (d = 0; d < n - c - 1; d++) {
if (array[d] > array[d+1]) /* For descending order use < */
{
swap = array[d];
array[d] = array[d+1];
array[d+1] = swap;
}
}
}
System.out.println("Sorted list of numbers");
for (c = 0; c < n; c++)
System.out.println(array[c]);
}
}
/*
Implementation of Bubble sort using Java
*/
import java.util.Arrays;
import java.util.Scanner;
public class BubbleSort {
/**
* #param args
*/
public static void main(String[] args) {
// TODO Auto-generated method stub
Scanner in = new Scanner(System.in);
System.out.println("Enter the number of elements of array");
int n = in.nextInt();
int []a = new int[n];
System.out.println("Enter the integer array");
for(int i=0; i<a.length; i++)
{
a[i]=in.nextInt();
}
System.out.println("UnSorted array: "+ Arrays.toString(a));
for(int i=0; i<n; i++)
{
for(int j=1; j<n; j++)
{
if(a[j-1]>a[j])
{
int temp = a[j-1];
a[j-1]=a[j];
a[j]=temp;
}
}
}
System.out.println("Sorted array: "+ Arrays.toString(a));
}
}
/*
****************************************
Time Complexity: O(n*n)
Space Complexity: O(1)
****************************************
*/
class BubbleSort {
public static void main(String[] args) {
int a[] = {5,4,3,2,1};
int length = a.length - 1;
for (int i = 0 ; i < length ; i++) {
for (int j = 0 ; j < length-i ; j++) {
if (a[j] > a[j+1]) {
int swap = a[j];
a[j] = a[j+1];
a[j+1] = swap;
}
}
}
for (int x : a) {
System.out.println(x);
}
}
}
int[] nums = new int[] { 6, 3, 2, 1, 7, 10, 9 };
for(int i = nums.Length-1; i>=0; i--)
for(int j = 0; j<i; j++)
{
int temp = 0;
if( nums[j] < nums[j + 1])
{
temp = nums[j];
nums[j] = nums[j + 1];
nums[j + 1] = temp;
}
}
package com.examplehub.sorts;
public class BubbleSort implements Sort {
/**
* BubbleSort algorithm implements.
*
* #param numbers the numbers to be sorted.
*/
public void sort(int[] numbers) {
for (int i = 0; i < numbers.length - 1; ++i) {
boolean swapped = false;
for (int j = 0; j < numbers.length - 1 - i; ++j) {
if (numbers[j] > numbers[j + 1]) {
int temp = numbers[j];
numbers[j] = numbers[j + 1];
numbers[j + 1] = temp;
swapped = true;
}
}
if (!swapped) {
break;
}
}
}
/**
* Generic BubbleSort algorithm implements.
*
* #param array the array to be sorted.
* #param <T> the class of the objects in the array.
*/
public <T extends Comparable<T>> void sort(T[] array) {
for (int i = 0; i < array.length - 1; ++i) {
boolean swapped = false;
for (int j = 0; j < array.length - 1 - i; ++j) {
if (array[j].compareTo(array[j + 1]) > 0) {
T temp = array[j];
array[j] = array[j + 1];
array[j + 1] = temp;
swapped = true;
}
}
if (!swapped) {
break;
}
}
}
}
source from
function bubbleSort(arr,n) {
if (n == 1) // Base case
return;
// One pass of bubble sort. After
// this pass, the largest element
// is moved (or bubbled) to end. and count++
for (let i = 0; i <n-1; i++){
if (arr[i] > arr[i + 1])
{
let temp = arr[i];
arr[i] = arr[i + 1];
arr[i + 1] = temp;
}
}
// Largest element is fixed,
// recur for remaining array
console.log("Bubble sort Steps ", arr, " Bubble sort array length reduce every recusrion ", n);
bubbleSort(arr, n - 1);
}
let arr1 = [64, 3400, 251, 12, 220, 11, 125]
bubbleSort(arr1, arr1.length);
console.log("Sorted array : ", arr1);
Here's an implementation for the bubble sort algorithm using Stack:
static void bubbleSort(int[] elements) {
Stack<Integer> primaryStack = new Stack<>();
Stack<Integer> secondaryStack = new Stack<>();
int lastIndex = elements.length - 1;
for (int element : elements) {
primaryStack.push(element);
} // Now all the input elements are in primaryStack
// Do the bubble sorting
for (int i = 0; i < elements.length; i++) {
if (i % 2 == 0) sort(elements, i, primaryStack, secondaryStack, lastIndex);
else sort(elements, i, secondaryStack, primaryStack, lastIndex);
}
}
private static void sort(int[] elements, int i, Stack<Integer> stackA, Stack<Integer> stackB, int lastIndex) {
while (!stackA.isEmpty()) { // Move an element from stack A to stack B
int element = stackA.pop();
if (stackB.isEmpty() || element >= stackB.peek()) { // Don't swap, just push
stackB.push(element);
} else { // Swap, then push
int temp = stackB.pop();
stackB.push(element);
stackB.push(temp);
}
}
elements[lastIndex - i] = stackB.pop();
}
I'm trying to make an implementation of 'adding' the elements of two arrays in Java.
I have two arrays which contain integers and i wanna add them. I dont want to use immutable variables. I prefer do sth like that : a.plus(b);
The problem is when i add 2 arrays with different length.It tries to add the elements of b to a, but if b has a bigger length it flags an error "ArrayIndexOutOfBoundsException".
I can understand why that's happening. But how can i solve this?
How can i expand array a? :/
public void plus(int[] b)
{
int maxlength = Math.max( this.length, b.length );
if (maxlength==a.length)
{
for (int i = 0; i <= maxlength; i++)
{
a[i] = a[i] + b[i]; //ArrayIndexOutOfBoundsException error
}
}
}
i <= maxlength replace this with i < maxlength.
Your array index is starting at zero, not at one.
So the length of the array is one less than the end index of the array.
When you use <= you are trying to go one element after the last element in your array, Hence the exception.
Also you got to check the length of array b. If length of array b is smaller than a, you will end up facing the same exception.
int maxlength = Math.min( this.length, b.length ); is more appropriate.
Or incase if you don't want to miss out any elements in either of the arrays while adding, ArrayList is the answer for you. ArrayList is the self expanding array you are looking for.
Here is how you can do that -
// First ArrayList
ArrayList<Integer> a = new ArrayList<Integer>();
a.add(1);
a.add(2);
a.add(3);
// Second ArrayList
ArrayList<Integer> b = new ArrayList<Integer>();
b.add(1);
b.add(2);
b.add(3);
b.add(4);
int maxlength = Math.max(a.size(), b.size());
// Add the elements and put them in the first ArrayList in the corresponding
// position
for (int i = 0; i < maxlength; i++) {
if (i < a.size()) {
if (i < b.size()) {
int j = a.get(i);
a.set(i, j + b.get(i));
}
} else {
a.add(i, b.get(i));
}
}
for (int j : a) {
System.out.println(j);
}
How can i expand array a?
Don't use arrays if you need variable-size data structures. Use Lists.
How about this:
private int[] a;
/**
* Adds the specified array to our array, element by element, i.e.
* for index i, a[i] = a[i] + b[i]. If the incoming array is
* longer, we pad our array with 0's to match the length of b[].
* If our array is longer, then only the first [b.length] values
* of our array have b[] values added to them (which is the same
* as if b[] were padded with 0's to match the length of a[].
*
* #param b the array to add, may not be null
*/
public void plus(final int[] b)
{
assert b != null;
if (a.length < b.length) {
// Expand a to match b
// Have to move a to a larger array, no way to increase its
// length "dynamically", i.e. in place.
final int[] newA = new int[b.length];
System.arraycopy(a, 0, newA, 0, a.length);
// remaining new elements of newA default to 0
a = newA;
}
for (int i = 0; i < b.length; i++)
{
a[i] = a[i] + b[i];
}
}
Another version:
private ArrayList<Integer> aList;
public void plusList(final int[] b)
{
assert b != null;
if (aList.size() < b.length) {
aList.ensureCapacity(b.length);
}
for (int i = 0; i < b.length; i++)
{
if (i < aList.size()) {
aList.set(i, aList.get(i) + b[i]);
} else {
aList.add(b[i]);
}
}
}
Edit: Here's the full class with sample run from data in comments
public class AddableArray {
private int[] a;
public AddableArray(final int... a) {
this.a = a;
}
/**
* Adds the specified array to our array, element by element, i.e.
* for index i, a[i] = a[i] + b[i]. If the incoming array is
* longer, we pad our array with 0's to match the length of b[].
* If our array is longer, then only the first [b.length] values
* of our array have b[] values added to them (which is the same
* as if b[] were padded with 0's to match the length of a[].
*
* #param b the array to add, may not be null
*/
public void plus(final int[] b)
{
assert b != null;
if (a.length < b.length) {
// Expand a to match b
// Have to move a to a larger array, no way to increase its
// length "dynamically", i.e. in place.
final int[] newA = new int[b.length];
System.arraycopy(a, 0, newA, 0, a.length);
// remaining new elements of newA default to 0
a = newA;
}
for (int i = 0; i < b.length; i++)
{
a[i] = a[i] + b[i];
}
}
int[] get() {
return a;
}
#Override
public String toString() {
final StringBuilder sb = new StringBuilder("a[] = [ ");
for (int i = 0; i < a.length; i++) {
if (i > 0) sb.append(", ");
sb.append(a[i]);
}
sb.append(" ]");
return sb.toString();
}
public static void main (final String[] args) {
final AddableArray myAddableArray = new AddableArray(1,2,3);
System.out.println("Elements before plus(): ");
System.out.println(myAddableArray.toString());
final int b[]={1,2,3,4};
myAddableArray.plus(b);
System.out.println("Elements after plus(): ");
System.out.println(myAddableArray.toString());
}
}
Sample run:
Elements before plus():
a[] = [ 1, 2, 3 ]
Elements after plus():
a[] = [ 2, 4, 6, 4 ]
maxlength is the max between the size of a[] and b[], so in a loop from 0 to maxlength, you will get an ArrayIndexOutOfBoundsException when i exceeds the min of the size of a[] and b[].
Try this:
public void plus(int[] b)
{
Polynomial a = this;
int[] c;
int maxlength;
if (a.length>b.length) {
c=a;
maxlength=a.length;
} else {
c=b;
maxlength=b.length;
}
int ca, cb;
for (int i = 0; i < maxlength; i++)
{
if (i<this.length)
ca=a[i];
else
ca=0;
if (i<b.length)
cb=b[i];
else
cb=0;
c[i] = ca + cb;
}
}
Try replacing:
for (int i = 0; i <= maxlength; i++)
with:
for (int i = 0; i < maxlength; i++)