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Create copy an existing Excel file within Java

how can I copy an existing excel macro file "test.xlsm" to a new Excel file in the same directory ("test copy.xlsm")?
I have used this approach:
private static void copyFileUsingJava7Files(File source, File dest)
throws IOException {
Files.copy(source.toPath(), dest.toPath());
}
However, I cannot specify the filename of the copied file here and get a handle to use it afterwards. How can I achieve that?
cheers

As written in the documentation the action will fail if the destination already exists. You should only give a path instead of the file as second parameter. If you want to overwrite the destination you should add the specific option.
More information: http://docs.oracle.com/javase/7/docs/api/java/nio/file/Files.html
To get the destination file you can simply return it afterwards.

'File dest' is a file object that contains the destenation file name.
you create it like:
new File("/data/home/test copy.xlsm")

How to copy files from one folder to another using Java?

How can I copy a file from one folder to another using java? I have tried to use
org.apache.commons.io.FileUtils.copyFileToDirectory(pasteItem, destinationPath);
This works if the destination folder does not contain a file with same name. It throws an IOException if I try to paste the file into the folder. However, is there any way to handle this? May be I want to just paste the file with name renamed automatically to pasteItem(1) or something like that. Please suggest.
In fact, I'm getting a new name for the file if the file with same name already exists. I'm not able to figure how to copy the file and then rename. If I rename first and then copy, I'll lose the original file. If I try to copy the file first, then it is giving an exception saying File with same name already exists!

You can use the Java.io.File class.
It has a method that checks if a fill exists.
Example:
//create files
File original =new File("C:\\test\\testfile.txt");
File destination =new File("D:\\test\\file.txt");
//check if file exists.
for(int x=0;destination.exists()==true;x++){
//if file exists then add 1 to file name and check if exists again.
destination=new File("D\\test\\file"+x+".txt");
}
//copy file.
Files.copy(origional, destination, StandardCopyOption.REPLACE_EXISTING);

There is an overloaded version of this method using a boolean flag which will overwrite the destination file if true.
public static void copyFileToDirectory(File srcFile,
File destDir,
boolean preserveFileDate)
throws IOException
http://commons.apache.org/proper/commons-io/apidocs/org/apache/commons/io/FileUtils.html#copyFileToDirectory(java.io.File, java.io.File, boolean)

Please refer this site to copy a file from one folder to another.
http://www.mkyong.com/java/how-to-move-file-to-another-directory-in-java/
I am not sure about rename the file automatically

how to save file path after move it from a directory to another in java

I copy a file from a directory for another but I have a difficulty to find the new file path !
I used FileUtils class from apache commons-io library to do that..... please is that there a function can save the last file path ?

Since FileUtils.moveFile accepts two arguments -- source file and destination file, all you need to do is to use second arg:
File myFile = new File("file");
File newLocation = new File("funky_file");
FileUtils.copyFile(myFile, newLocation);
myFile = newLocation;
You cannot retrive new location basing only on myFile without reassigning: File class is designed to be a immutable path rather that hard link to the file.

Java: File output help

Fixed: Instead of calling isFile() I used exists() and it seems to be working fine. If possible could someone explain why this change worked?
I'm attempting to write out to an excel file but am having a problem when trying to create that file if the name already exists.
Basically I am taking a file that is uploaded to a server, reading it, and then outputting a report file in a new location with the same filename. I tried to do this by simply checking if the file already existed and then adding a number onto the filename. My code works if the file doesn't exist or if it exists without a number (e.g. filename.xls). If a file exists with the name "filename1.xls" the server just seems to hang when trying to write the file. What can do to fix this?
Here is my code:
String destination = "c:/apache-tomcat-7.0.8/webapps/reports/" + fileName.substring( fileName.lastIndexOf("\\")+1, fileName.lastIndexOf(".")) + ".xls";
int filenum = 1;
while (new File(destination).isFile()) {
destination = "c:/apache-tomcat-7.0.8/webapps/reports/" + fileName.substring( fileName.lastIndexOf("\\")+1, fileName.lastIndexOf(".")) + filenum + ".xls";
filenum++;
}
WritableWorkbook workbook = Workbook.createWorkbook(new File(destination));

That will happen if some process is still keeping the file open. E.g. you've created a FileInputStream on the file to read it, but are never calling close() on it after reading.
Unrelated to the problem, the expanded WAR folder is not the best place to use as a permanent storage. All those files in the expanded WAR folder will get lost whenever you redeploy the WAR. Also hardcoding a servletcontainer-specific path in the code makes it totally unportable.
If your actual intent is to return the Excel file on a per-request basis to the client using a servlet, then you should be using
WritableWorkbook workBook = Workbook.createWorkbook(response.getOutputStream());
// ...
This way it writes to the response immediately without the need for an intermediate file.

Use the File.createTempFile(prefix, suffix, directory) API:
String localName = new File(fileName).getName();
String nameNoExt = localName.substring(0, fileName.lastIndexOf("."));
String extension = localName.substring(fileName.lastIndexOf(".")); // need to include the .
File directory = new File("c:/apache-tomcat-7.0.8/webapps/reports/");
File destFile = File.createTempFile(nameNoExt, extension, directory)

get File from JAR

I'm using Spring's Resource abstraction to work with resources (files) in the filesystem. One of the resources is a file inside a JAR file. According to the following code, it appears the reference is valid
ResourcePatternResolver resourceResolver = new PathMatchingResourcePatternResolver();
// The path to the resource from the root of the JAR file
Resource fileInJar = resourcePatternResolver.getResources("/META-INF/foo/file.txt");
templateResource.exists(); // returns true
templateResource.isReadable(); // returns true
At this point, all is well, but then when I try to convert the Resource to a File
templateResource.getFile();
I get the exception
java.io.FileNotFoundException: class path resource [META-INF/foo/file.txt] cannot be resolved to absolute file path because it does not reside in the file system: jar:file:/D:/m2repo/uic-3.2.6-0.jar!/META-INF/foo/file.txt
at org.springframework.util.ResourceUtils.getFile(ResourceUtils.java:198)
at org.springframework.core.io.ClassPathResource.getFile(ClassPathResource.java:174)
What is the correct way to get a File reference to a Resource that exists inside a JAR file?

What is the correct way to get a File
reference to a Resource that exists
inside a JAR file?
The correct way is not doing that at all because it's impossible. A File represents an actual file on a file system, which a JAR entry is not, unless you have a special file system for that.
If you just need the data, use getInputStream(). If you have to satisfy an API that demands a File object, then I'm afraid the only thing you can do is to create a temp file and copy the data from the input stream to it.

If you want to read it, just call resource.getInputStream()
The exception message is pretty clear - the file does not reside on the file-system, so you can't have a File instance. Besides - what will do do with that File, apart from reading its content?

A quick look at the link you provided for Resource documentation, says the following:
Throws: IOException if the resource cannot be resolved as absolute file path,
i.e. if the resource is not available in a file system
Maybe the text file is inside a jar? In that case you will have to use getInputStream() to read its contents.

Just adding an example to the answers here. If you need a File (and not just the contents of it) from within your JAR, you need to create a temporary file from the resource first. (The below is written in Groovy):
InputStream inputStream = resourceLoader.getResource('/META-INF/foo/file.txt').inputStream
File tempFile = new File('file.txt')
OutputStream outputStream = new FileOutputStream(tempFile)
try {
IOUtils.copy(inputStream, outputStream)
} catch (IOException e) {
// Handle exception
} finally {
outputStream.close()
}