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Need to get Particular word using java Regex

I want to get one particular word using regex in java. thanks
in the below paragraph, I need to find the network interface name
resource "azurerm_network_interface" "nic_LinuxVMCent-nhi" {
name = "nic_LinuxVMCent-nhi"
location = azurerm_resource_group.main.location
resource_group_name = azurerm_resource_group.main.name
ip_configuration {
name = "pubIP_LinuxVMCent-nhi"
subnet_id = azurerm_subnet.sub_wind12VM-PtN.id
private_ip_address_allocation = "Dynamic"
public_ip_address_id = azurerm_public_ip.pubIP_LinuxVMCent-nhi.id
}
}
data "azurerm_snapshot" "snapLinuxVMCent-nhi" {
name = "CentOS76New-0"
resource_group_name = "SaaSworkloadsnaps"
}
Expected Result Ex:
nic_LinuxVMCent-nhi

This is a multi-line bit of text. However, there appears to be a line which you could recognise with a regex:
resource "azurerm_network_interface" "nic_LinuxVMCent-nhi" {
So the regex for that would be ^resource "azurerm_network_interface" "([^"]+)" {$ - see https://regexr.com/67ldb
You can use Matcher.match to see if the any line matches this expression and if it does then matcher.group(1) will be the value you're looking for.

you can use this regex to find the network interface name:
(?<=resource \"azurerm_network_interface\" \").+(?=\" {)
I have used lookahead to find the name.
Also, here's a link to regex101:
Link
I don't know network interfaces so,
This regex solution is specific to "azurerm_network_interface."
If you need any additional help, please comment down below.
Cheers :)

java regular expression partial replace

I am working with some legacy code that has a static method call which we need to remove from our source tree.
The existing code is as follows:
Logger.getInstance(JdkUtil.forceInit(SomeBusiness.class));
What we need to end up with is:
Logger.getInstance(SomeBusiness.class);
I've spent all day today trying to figure out how to do that replacement. Since I have very little experience with regular expressions, I have only been able to come up with a pattern that matches the source string.
The pattern JdkUtil.forceInit([a-zA-Z_0-9]*.class) finds matches on the input string I am providing. I've tested this at https://www.freeformatter.com/java-regex-tester.html
So if anyone can post a Java solution to this, I would really appreciate it.
Below is some Groovy code that I have so far. What I am missing is to how correctly replacement explained above.
String source = 'Logger.getInstance(JdkUtil.forceInit(RtpRuleEngineCompiledImpl.class))'
String regexpPattern = 'JdkUtil.forceInit\\([a-zA-Z_0-9\\)]*.class\\)'
String replaced = source.replaceFirst(regexpPattern, 'hello')
println replaced
When I run the above code I get the following output:
Logger.getInstance(hello)
Obviously 'hello' is just for testing.
Thanks in advance to anyone who can give me some suggestions.

You'll likely want to do something such as:
class StackOverflow {
public static void main(String[] args) {
String source = "Logger.getInstance(JdkUtil.forceInit(RtpRuleEngineCompiledImpl.class))";
String regexpPattern = "JdkUtil.forceInit\\(([a-zA-Z_0-9]*.class)\\)";
String replaced = source.replaceFirst(regexpPattern, "$1");
System.out.println(replaced);
}
}
Result:
Logger.getInstance(RtpRuleEngineCompiledImpl.class)
The capture group ($1) replaces the entire string which was within the parentheses.

Regular Expression - detect Specific Url and replace that string

I wanna detect exact domain url in string and then change that with another string and finally make it clickable in TextView.
What I want:
this is sample text with one type of url mydomain.com/pin/123456. another type of url is mydomain.com/username.
Wel, I wrote this regex:
([Hh][tT][tT][pP][sS]?://)?(?:www\\.)?example\\.com/?.*
([Hh][tT][tT][pP][sS]?://)?(?:www\\.)?example\\.com/pin/?.*
this regex can detect:
http://www.example.com
https://www.example.com
www.example.com
example.com
Hhtp://www.example.com // and all other wrong type in http
with anything after .com
Issues:
1. How detect end of domain ( with space or dot)
2. How detect two type of domain, one with /pin/ and another without?
3. How to replace detected domain like mydomain.com/pin/123 with PostLink and mydomain.com/username with ProfileLink
4. I know how to make them clickable with Linkify but if it possible show me best way to provide content provider for links to open each link with proper activity

You could try:
([\w_-]+(?:(?:\.[\w_-]+)+))([\w.,#?^=%&:/~+#-]*[\w#?^=%&/~+#-])?
which is a regex I found after a quick search here on stackoverflow:
Regular expression to find URLs within a string
I just removed the http:// part of that regex to fit your needs.
Be aware though that because of that it now tracks everything that is connected with a dot and no whitespace. For example: a.a would also be found

With special thanks of Gildraths
Answer to question 1
String urlRegex = "(https?://)?(?:www\\.)?exampl.com+([\\w.,#?^=%&:/~+#-]*[\\w#?^=%&/~+#-])?";
Pattern pattern = Pattern.compile(urlRegex, Pattern.CASE_INSENSITIVE);
Matcher matcher = pattern.matcher(textString);
Answer to question 2, 3
while(matcher.find()){
// Answer to question 2 - If was true, url contain "/pin"
boolean contain = matcher.group().indexOf("/pin/") >= 0;
if(contain){
String profileId = matcher.group().substring(matcher.group().indexOf("/pin/") + 5, matcher.group().length());
}
// Answer to question 3 - replace match group with custom text
textString = textString.replace(matcher.group(), "#" + profileId);
}
Answer to question 4
// Pattern to detect replaced custom text
Pattern profileLink = Pattern.compile("[#]+[A-Za-z0-9-_]+\\b");
// Schema
String Link = "content://"+Context.getString(R.string.profile_authority)+"/";
// Make it linkify ;)
Linkify.addLinks(textView, profileLink, Link);

Regex for a url pattern

I'm developing a dynamic controller which accept this urls:
mock_test5 - mock_test1
reviewer_test5
reviewer_test4
reviewer_test3.1
reviewer_test3.2
reviewer_test1
Note: reviewer_test2 is excluded
I'm having a hard time figuring it out. This is what I don't so far:
^(mock|reviewer)_test[1-5]$
I also don't know how do I interpret 3.1 and 3.2

^(?:mock_test[1-5]|reviewer_test(?:[145]|3[.][12]))$
^(?:mock_test(?:1|2|3|4|5)|reviewer_test(?:(?:1|4|5)|3\.(?:1|2)))$

As you can see at this link: http://regexr.com?37dtn
^(mock_test[1-5])|reviewer_test([145]|3\.1|3\.2)$
^ = start a line with
(mock_test[1-5]) = the string 'mock_test' followed by a number from 1 to 5
I think the '(' and ')' are not necessary
| = OR
reviewer_test = the string 'reviewer_test'
([145]|3\.1|3\.2) = the numbers 1,4,5 OR the number 3.1 OR the number 3.2
$ = end of line
Update:
If it is a limited number I wouldn't use a regex, because it seems to be some kind of write once read never again code.

Java: How to spit the line in between two pattern in Java

I am facing some problem with getting the text matching with the two patterns,Please help me out,Here is my question and my requirement :
Line : selenium.TypeKeys("name=email", "raj#ymail.com");
My requirement is to Get the name=email from the above line,
Thanks

This should give you the value between " and ,.
line.substring(line.indexOf("(\""), line.indexOf(","));