Is it possible to call a constructor from another (within the same class, not from a subclass)? If yes how? And what could be the best way to call another constructor (if there are several ways to do it)?
Yes, it is possible:
public class Foo {
private int x;
public Foo() {
this(1);
}
public Foo(int x) {
this.x = x;
}
}
To chain to a particular superclass constructor instead of one in the same class, use super instead of this. Note that you can only chain to one constructor, and it has to be the first statement in your constructor body.
See also this related question, which is about C# but where the same principles apply.
Using this(args). The preferred pattern is to work from the smallest constructor to the largest.
public class Cons {
public Cons() {
// A no arguments constructor that sends default values to the largest
this(madeUpArg1Value,madeUpArg2Value,madeUpArg3Value);
}
public Cons(int arg1, int arg2) {
// An example of a partial constructor that uses the passed in arguments
// and sends a hidden default value to the largest
this(arg1,arg2, madeUpArg3Value);
}
// Largest constructor that does the work
public Cons(int arg1, int arg2, int arg3) {
this.arg1 = arg1;
this.arg2 = arg2;
this.arg3 = arg3;
}
}
You can also use a more recently advocated approach of valueOf or just "of":
public class Cons {
public static Cons newCons(int arg1,...) {
// This function is commonly called valueOf, like Integer.valueOf(..)
// More recently called "of", like EnumSet.of(..)
Cons c = new Cons(...);
c.setArg1(....);
return c;
}
}
To call a super class, use super(someValue). The call to super must be the first call in the constructor or you will get a compiler error.
[Note: I just want to add one aspect, which I did not see in the other answers: how to overcome limitations of the requirement that this() has to be on the first line).]
In Java another constructor of the same class can be called from a constructor via this(). Note however that this has to be on the first line.
public class MyClass {
public MyClass(double argument1, double argument2) {
this(argument1, argument2, 0.0);
}
public MyClass(double argument1, double argument2, double argument3) {
this.argument1 = argument1;
this.argument2 = argument2;
this.argument3 = argument3;
}
}
That this has to appear on the first line looks like a big limitation, but you can construct the arguments of other constructors via static methods. For example:
public class MyClass {
public MyClass(double argument1, double argument2) {
this(argument1, argument2, getDefaultArg3(argument1, argument2));
}
public MyClass(double argument1, double argument2, double argument3) {
this.argument1 = argument1;
this.argument2 = argument2;
this.argument3 = argument3;
}
private static double getDefaultArg3(double argument1, double argument2) {
double argument3 = 0;
// Calculate argument3 here if you like.
return argument3;
}
}
When I need to call another constructor from inside the code (not on the first line), I usually use a helper method like this:
class MyClass {
int field;
MyClass() {
init(0);
}
MyClass(int value) {
if (value<0) {
init(0);
}
else {
init(value);
}
}
void init(int x) {
field = x;
}
}
But most often I try to do it the other way around by calling the more complex constructors from the simpler ones on the first line, to the extent possible. For the above example
class MyClass {
int field;
MyClass(int value) {
if (value<0)
field = 0;
else
field = value;
}
MyClass() {
this(0);
}
}
Within a constructor, you can use the this keyword to invoke another constructor in the same class. Doing so is called an explicit constructor invocation.
Here's another Rectangle class, with a different implementation from the one in the Objects section.
public class Rectangle {
private int x, y;
private int width, height;
public Rectangle() {
this(1, 1);
}
public Rectangle(int width, int height) {
this( 0,0,width, height);
}
public Rectangle(int x, int y, int width, int height) {
this.x = x;
this.y = y;
this.width = width;
this.height = height;
}
}
This class contains a set of constructors. Each constructor initializes some or all of the rectangle's member variables.
As everybody already have said, you use this(…), which is called an explicit constructor invocation.
However, keep in mind that within such an explicit constructor invocation statement you may not refer to
any instance variables or
any instance methods or
any inner classes declared in this class or any superclass, or
this or
super.
As stated in JLS (§8.8.7.1).
Yes, any number of constructors can be present in a class and they can be called by another constructor using this() [Please do not confuse this() constructor call with this keyword]. this() or this(args) should be the first line in the constructor.
Example:
Class Test {
Test() {
this(10); // calls the constructor with integer args, Test(int a)
}
Test(int a) {
this(10.5); // call the constructor with double arg, Test(double a)
}
Test(double a) {
System.out.println("I am a double arg constructor");
}
}
This is known as constructor overloading.
Please note that for constructor, only overloading concept is applicable and not inheritance or overriding.
Using this keyword we can call one constructor in another constructor within same class.
Example :-
public class Example {
private String name;
public Example() {
this("Mahesh");
}
public Example(String name) {
this.name = name;
}
}
Yes it is possible to call one constructor from another. But there is a rule to it. If a call is made from one constructor to another, then
that new constructor call must be the first statement in the current constructor
public class Product {
private int productId;
private String productName;
private double productPrice;
private String category;
public Product(int id, String name) {
this(id,name,1.0);
}
public Product(int id, String name, double price) {
this(id,name,price,"DEFAULT");
}
public Product(int id,String name,double price, String category){
this.productId=id;
this.productName=name;
this.productPrice=price;
this.category=category;
}
}
So, something like below will not work.
public Product(int id, String name, double price) {
System.out.println("Calling constructor with price");
this(id,name,price,"DEFAULT");
}
Also, in the case of inheritance, when sub-class's object is created, the super class constructor is first called.
public class SuperClass {
public SuperClass() {
System.out.println("Inside super class constructor");
}
}
public class SubClass extends SuperClass {
public SubClass () {
//Even if we do not add, Java adds the call to super class's constructor like
// super();
System.out.println("Inside sub class constructor");
}
}
Thus, in this case also another constructor call is first declared before any other statements.
I will tell you an easy way
There are two types of constructors:
Default constructor
Parameterized constructor
I will explain in one Example
class ConstructorDemo
{
ConstructorDemo()//Default Constructor
{
System.out.println("D.constructor ");
}
ConstructorDemo(int k)//Parameterized constructor
{
this();//-------------(1)
System.out.println("P.Constructor ="+k);
}
public static void main(String[] args)
{
//this(); error because "must be first statement in constructor
new ConstructorDemo();//-------(2)
ConstructorDemo g=new ConstructorDemo(3);---(3)
}
}
In the above example I showed 3 types of calling
this() call to this must be first statement in constructor
This is Name less Object. this automatically calls the default constructor.
3.This calls the Parameterized constructor.
Note:
this must be the first statement in the constructor.
You can a constructor from another constructor of same class by using "this" keyword.
Example -
class This1
{
This1()
{
this("Hello");
System.out.println("Default constructor..");
}
This1(int a)
{
this();
System.out.println("int as arg constructor..");
}
This1(String s)
{
System.out.println("string as arg constructor..");
}
public static void main(String args[])
{
new This1(100);
}
}
Output -
string as arg constructor..
Default constructor..
int as arg constructor..
Calling constructor from another constructor
class MyConstructorDemo extends ConstructorDemo
{
MyConstructorDemo()
{
this("calling another constructor");
}
MyConstructorDemo(String arg)
{
System.out.print("This is passed String by another constructor :"+arg);
}
}
Also you can call parent constructor by using super() call
There are design patterns that cover the need for complex construction - if it can't be done succinctly, create a factory method or a factory class.
With the latest java and the addition of lambdas, it is easy to create a constructor which can accept any initialization code you desire.
class LambdaInitedClass {
public LamdaInitedClass(Consumer<LambdaInitedClass> init) {
init.accept(this);
}
}
Call it with...
new LambdaInitedClass(l -> { // init l any way you want });
Pretty simple
public class SomeClass{
private int number;
private String someString;
public SomeClass(){
number = 0;
someString = new String();
}
public SomeClass(int number){
this(); //set the class to 0
this.setNumber(number);
}
public SomeClass(int number, String someString){
this(number); //call public SomeClass( int number )
this.setString(someString);
}
public void setNumber(int number){
this.number = number;
}
public void setString(String someString){
this.someString = someString;
}
//.... add some accessors
}
now here is some small extra credit:
public SomeOtherClass extends SomeClass {
public SomeOtherClass(int number, String someString){
super(number, someString); //calls public SomeClass(int number, String someString)
}
//.... Some other code.
}
Hope this helps.
Yes it is possible to call one constructor from another with use of this()
class Example{
private int a = 1;
Example(){
this(5); //here another constructor called based on constructor argument
System.out.println("number a is "+a);
}
Example(int b){
System.out.println("number b is "+b);
}
You can call another constructor via the this(...) keyword (when you need to call a constructor from the same class) or the super(...) keyword
(when you need to call a constructor from a superclass).
However, such a call must be the first statement of your constructor. To overcome this limitation, use this answer.
The keyword this can be used to call a constructor from a constructor, when writing several constructor for a class, there are times when you'd like to call one constructor from another to avoid duplicate code.
Bellow is a link that I explain other topic about constructor and getters() and setters() and I used a class with two constructors. I hope the explanations and examples help you.
Setter methods or constructors
I know there are so many examples of this question but what I found I am putting here to share my Idea. there are two ways to chain constructor. In Same class you can use this keyword. in Inheritance, you need to use super keyword.
import java.util.*;
import java.lang.*;
class Test
{
public static void main(String args[])
{
Dog d = new Dog(); // Both Calling Same Constructor of Parent Class i.e. 0 args Constructor.
Dog cs = new Dog("Bite"); // Both Calling Same Constructor of Parent Class i.e. 0 args Constructor.
// You need to Explicitly tell the java compiler to use Argument constructor so you need to use "super" key word
System.out.println("------------------------------");
Cat c = new Cat();
Cat caty = new Cat("10");
System.out.println("------------------------------");
// Self s = new Self();
Self ss = new Self("self");
}
}
class Animal
{
String i;
public Animal()
{
i = "10";
System.out.println("Animal Constructor :" +i);
}
public Animal(String h)
{
i = "20";
System.out.println("Animal Constructor Habit :"+ i);
}
}
class Dog extends Animal
{
public Dog()
{
System.out.println("Dog Constructor");
}
public Dog(String h)
{
System.out.println("Dog Constructor with habit");
}
}
class Cat extends Animal
{
public Cat()
{
System.out.println("Cat Constructor");
}
public Cat(String i)
{
super(i); // Calling Super Class Paremetrize Constructor.
System.out.println("Cat Constructor with habit");
}
}
class Self
{
public Self()
{
System.out.println("Self Constructor");
}
public Self(String h)
{
this(); // Explicitly calling 0 args constructor.
System.out.println("Slef Constructor with value");
}
}
It is called Telescoping Constructor anti-pattern or constructor chaining. Yes, you can definitely do. I see many examples above and I want to add by saying that if you know that you need only two or three constructor, it might be ok. But if you need more, please try to use different design pattern like Builder pattern. As for example:
public Omar(){};
public Omar(a){};
public Omar(a,b){};
public Omar(a,b,c){};
public Omar(a,b,c,d){};
...
You may need more. Builder pattern would be a great solution in this case. Here is an article, it might be helpful
https://medium.com/#modestofiguereo/design-patterns-2-the-builder-pattern-and-the-telescoping-constructor-anti-pattern-60a33de7522e
Yes, you can call constructors from another constructor. For example:
public class Animal {
private int animalType;
public Animal() {
this(1); //here this(1) internally make call to Animal(1);
}
public Animal(int animalType) {
this.animalType = animalType;
}
}
you can also read in details from
Constructor Chaining in Java
Originally from an anser by Mirko Klemm, slightly modified to address the question:
Just for completeness: There is also the Instance initialization block that gets executed always and before any other constructor is called. It consists simply of a block of statements "{ ... }" somewhere in the body of your class definition. You can even have more than one. You can't call them, but they're like "shared constructor" code if you want to reuse some code across constructors, similar to calling methods.
So in your case
{
System.out.println("this is shared constructor code executed before the constructor");
field1 = 3;
}
There is also a "static" version of this to initialize static members: "static { ... }"
I prefer this way:
class User {
private long id;
private String username;
private int imageRes;
public User() {
init(defaultID,defaultUsername,defaultRes);
}
public User(String username) {
init(defaultID,username, defaultRes());
}
public User(String username, int imageRes) {
init(defaultID,username, imageRes);
}
public User(long id, String username, int imageRes) {
init(id,username, imageRes);
}
private void init(long id, String username, int imageRes) {
this.id=id;
this.username = username;
this.imageRes = imageRes;
}
}
Related
This is the main demo class
public class Ongoing{
public static void main(String[] args){
ExtendsAbstract josh = new ExtendsAbstract(5, "donkey");
System.out.println(josh.toString());
}
}
this is the class extended from the abstract class, the one who's tostring method won't work.
public class ExtendsAbstract extends Abstract{
private String t;
public ExtendsAbstract(int y, String t){
super(y);
this.t = t;
}
public String getString(){
return this.t;
}
public int getInt(){
return super.getInt();
}
public String toString(int y){
return(/*super.toString(y)+*/"The integer is "+ y) ;
}
}
This is the abstract class
public abstract class Abstract{
private int y;
public Abstract(int y){
this.y = y;
}
public int getInt(){
return y;
}
public String toString(int y){
return("The integer is :"+y);
}
}
Every time i try and access the toString method from the extended class it just prints out what i think is a memory address. I even didn't mess with the abstract class and it still did that, does anyone know why? Also another question about abstract classes, what advantages do they bring, is it just memory? Because you can't access private members from it so isn't it the same as a normal class, just more restrictions?
Say that you have classes Dad and Son which are defined like this
public class OverLoadedToString {
public static void main(String[] args) {
Son son = new Son();
son.test();
son.test(90);
}
}
class Dad {
void test() {
System.out.println("Dad - test");
}
}
class Son extends Dad {
void test(int testTime) {
System.out.println("Son - test1" + testTime);
}
}
The Son class is extending Dad so the test() with no arguments is inheriting to Son, just like your ExtendsAbstract class is having toString() with no arguments inheriting from Object class (every class in Java inherits Object class).
Then in Son class I added new method test(int testTime), which has got an argument, that makes test() and test(int testTime) different which is called method overloading. In you ExtendsAbstract class there are two toString methods one is the no-arg inherited and the other you defined.
Now let me show you the inheritance flow
Object--->Abstract--->ExtendsAbstract
Object class toString() methods prints the memory address, we can override it in our classes to change its definition, you can return any string that you want. But you haven't overridden it anywhere in either Abstract class or ExtendsAbstract class, so in both classes it will print the memory address.
Now in your Ongoing class you are calling that Object class toString() method which always prints memory address. Your confusion is that you think you have overridden the toString() method but actually you have just overloaded it and you are calling the wrong method for your expected output.
Reference : Java overloading and overriding
Currently, what happens is toString() of object is getting called which goes like this: ClassName#HashCode.
You can do this to print: (Add an #Override at toString()). Also, no need to call josh.toString(). You can simply call System.out.println(josh); (magic will happen and it will call toString)..
public class ExtendsAbstract extends Abstract{
private String t;
public ExtendsAbstract(int y, String t){
super(y);
this.t = t;
}
public String getString(){
return this.t;
}
public int getInt(){
return super.getInt();
}
#Override
public String toString(int y){
return(/*super.toString(y)+*/"The integer is "+ y) ;
}
}
The "toString()" method must be like this:
#Override
public String toString(){
return("The integer is "+ y) ;
}
The "#Override" annotations is used for compiler checking, is not mandatory.
More info about the annotation here: https://docs.oracle.com/javase/7/docs/api/java/lang/Override.html
I am a little confused on how to set up the TestHomework method so that it prints properly when using the toString() method. Right now when I run the main method it prints "null - 0" but what I would like it to say is "Math - 6". This program is supposed to extend an abstract class. It is supposed to say how many pages there are for homework and for what subject.
public abstract class Homework {
private int pagesToRead;
private String typeHomework;
{
// initialise instance variables
pagesToRead = 0;
typeHomework = "none";
}
public Homework(int pages, String hw) {
this.pagesToRead = pages;
this.typeHomework = hw;
}
public abstract void createAssignment(int p);
public int getPages() {
return pagesToRead;
}
public void setPagesToRead(int p) {
pagesToRead = p;
}
public String getTypeHomework() {
return typeHomework;
}
public void setTypeHomework(String hw) {
typeHomework = hw;
}
}
public class MyMath extends Homework {
private int pagesRead;
private String typeHomework;
public MyMath(int pages, String hw) {
super(pages,hw);
}
public void createAssignment(int p) {
setTypeHomework("Math");
setPagesToRead(p);
}
public String toString() {
return typeHomework + " - " + pagesRead;
}
}
public class TestHomework {
public static void main(String[] args) {
MyMath one = new MyMath(6, "Math");
one.createAssignment(6);
System.out.println(one);
}
}
That's because you are defining the 2 properties (that one of them happen to have the same name as one of the abstract class's) but you are not initializing them, you are initializing those of the abstract class. (So their values is always set to their type's default)
You need to drop those from the MyMath class, & define the toString method in your abstract class: it's the one to be used by default by its inheriting classes.
public abstract class Homework {
private int pagesToRead;
private String typeHomework;
// Same code
// Define the toString here
#Override
public String toString() {
return typeHomework + " - " + pagesToRead;
}
}
public class MyMath extends Homework {
// You don't need to define any extra attributes
public MyMath(int pages, String hw) {
super(pages,hw);
}
public void createAssignment(int p) {
setTypeHomework("Math");
setPagesToRead(p);
}
}
public static void main(String[] args) {
// Calls the constructor of the MyMath class, which in turn
// invokes the constructor of its superclass, the 'Homework' class
MyMath one = new MyMath(6, "Math");
one.createAssignment(6);
// Invokes the toString of the MyMath class. Since it does not have one,
// The toString method of its superclass (Homework) is called.
System.out.println(one);
}
Your derived class has its own typeHomework and pagesRead fields, which are never set (even though the base class happens to have fields with the same names). Therefore, they stay null and 0.
You should delete those fields and use the data from the base class, via the public getter methods.
Why it doesn't work:
Be careful you redeclared the attribute typeHomework of you parent class. Attributes are automatically added to your extending class so you don't have to write them again.
By redeclaring it you confused the compiler, viewing your code in debug shows, that your one object contains your typeHomework twice:
typeHomework = null // The one from the super class
typeHomework = "Math" // The one from your child class
Your method now uses the typeHomework from your super-class therefor the output is null!
pagesRead is 0 because you are setting the pagesToRead of your super-class to 6(not pagesRead!) when calling setPagesToRead(p);.
Some style tips
Use the #Override annotation when overriding methods like this:
#Override
public void createAssignment(int p) {
setTypeHomework("Math");
setPagesToRead(p);
}
It's not really needed but it's good practice (readers of your code know that it overrides something).
When referring to attributes of your class it's also good practice to use the this statement so it's clear, that you're referring to an attribute and not a local variable:
#Override
public String toString() {
return this.typeHomework + " - " + this.pagesRead;
}
I was wondering if it was possible to do the following with a Class, that extends another class in Java, if so. How?:
public class HelloWorld {
public HelloWorld() {
A aClass = new A(22);
}
}
public class A extends B {
public A() {
System.out.println(number);
}
}
public class B {
public int number;
public B(int number) {
this.number = number;
}
}
Your A constructor needs to chain to a B constructor using super. At the moment the only constructor in B takes an int parameters, so you need to specify one, e.g.
public A(int x) {
super(x); // Calls the B(number) constructor
System.out.println(number);
}
Note that I've added the x parameter into A, because of the way you're calling it in HelloWorld. You don't have to have the same parameters though. For example:
public A() {
super(10);
System.out.println(number); // Will print 10
}
Then call it with:
A a = new A();
Every subclass constructor either chains to another constructor within the same class (using this) or to a constructor in the superclass (using super or implicitly) as the first statement in the constructor body. If the chaining is implicit, it's always equivalent to specifying super();, i.e. invoking a parameterless superclass constructor.
See section 8.8.7 of the JLS for more details.
I work primarily with dynamic languages - I've just started playing with Java, and I'm struggling with a static pattern.
From what I understand, the first call in the constructor of a child class has to be to its parent. That's fine, but I need to set instance variables in the child that are referenced in the constructor of the parent...which, of course, creates a catch-22. (Need to set variables in child before calling parent, but need to call parent before setting variables in child).
I'm sure I'm breaking some sort of static language pattern or law...I'm just not sure which one, or how to redesign it. Any help appreciated. Stripped down example below:
Class Race {
public Race(Venue event_venue) {
greeting();
}
public void greeting() {
String event_greeting = String.format("The next event is: %s", getName());
System.out.println(event_greeting);
}
public String getName() {
return getClass().getSimpleName();
}
}
Class Sprint extends Race {
private int event_distance;
public Sprint(Venue event_venue, int distance) {
// super has to be the first call
super(event_venue);
// but I need to set event_distance to reference getName() in parent constructor
setDistance(distance);
}
public String getName() {
String sprint_name = String.format("%s meter sprint", Integer.toString(getDistance());
return sprint_name;
}
public int getDistance() {
return distance;
}
public void setDistance(int distance) {
event_distance = distance;
}
}
You have side-effects in your constructor, which is frowned upon. For best results, put the side-effects in an other method. You have this already, so just specify in the javadoc that greeting() should be called after construction (or, it could be called by the subclass constructors, but then sub-subclasses will have the same problem).
I assume each race will have a distance, so why not make this field part of the supertype. This field can then be set via an argument provided to the constructor.
Class Race {
private int event_distance;
public Race(Venue event_venue, int distance) {
this.distance = distance;
greeting();
}
public void greeting() {
String event_greeting = String.format("The next event is: %s", getName());
System.out.println(event_greeting);
}
public String getName() {
return getClass().getSimpleName();
}
public int getDistance() {
return distance;
}
public void setDistance(int distance) {
event_distance = distance;
}
}
Providing distance as argument to super constructor:
Class Sprint extends Race {
private int event_distance;
public Child(Venue event_venue, int distance) {
super(event_venue, distance);
}
/* omitted rest of class */
}
Yes, that does not work.
You need to refactor your code in ways that make it possible to execute the constructors in their proper order. Usually this is not a problem if the constructors do not have side-effects and do not call methods that can be overridden in subclasses (both of which are discouraged patterns).
public Race(Venue event_venue) {
greeting(); // constructor should not call non-final method
}
// method called by a constructor should not print anything
public void greeting() {
String event_greeting = String.format("The next event is: %s", getName());
System.out.println(event_greeting);
}
I ran into this block of code, and there is this one line I don't quit understand the meaning or what it is doing.
public Digraph(In in) {
this(in.readInt());
int E = in.readInt();
for (int i = 0; i < E; i++) {
int v = in.readInt();
int w = in.readInt();
addEdge(v, w);
}
}
I understand what this.method() or this.variable are, but what is this()?
This is constructor overloading:
public class Diagraph {
public Diagraph(int n) {
// Constructor code
}
public Digraph(In in) {
this(in.readInt()); // Calls the constructor above.
int E = in.readInt();
for (int i = 0; i < E; i++) {
int v = in.readInt();
int w = in.readInt();
addEdge(v, w);
}
}
}
You can tell this code is a constructor and not a method by the lack of a return type.
This is pretty similar to calling super() in the first line of the constructor in order to initialize the extended class. You should call this() (or any other overloading of this()) in the first line of your constructor and thus avoid constructor code duplications.
You can also have a look at this post: Constructor overloading in Java - best practice
Using this() as a function like that, essentially calls the Constructor of the class. This allows you to all the generic initializations in one constructor and have specializations in others. So in this piece of code for example, the call to this(in.readInt()) is calling the Digraph constructor that has one int argument.
This code snippet is a constructor.
This call to this calls another constructor of the same class
public App(int input) {
}
public App(String input) {
this(Integer.parseInt(input));
}
In the above example we have a constructor that takes an int and one that takes a String. The constructor that takes a String converts the String to an int and then delegates to the int constructor.
Note that a call to another constructor or a superclass constructor (super()) must be the first line in a constructor.
Maybe take a look at this for a more detailed explanation of constructor overloading.
It's nearly the same
public class Test {
public Test(int i) { /*construct*/ }
public Test(int i, String s){ this(i); /*construct*/ }
}
Calling this essentially calls the class Constructor.
For example, if you're extending something, than along with add(JComponent), you could do: this.add(JComponent).
An other constructor of the class Digraph with an int parameter.
Digraph(int param) { /* */ }
Constructor Overloading:
ex:
public class Test{
Test(){
this(10); // calling constructor with one parameter
System.out.println("This is Default Constructor");
}
Test(int number1){
this(10,20); // calling constructor with two parameter
System.out.println("This is Parametrized Constructor with one argument "+number1);
}
Test(int number1,int number2){
System.out.println("This is Parametrized Constructor with two argument"+number1+" , "+number2);
}
public static void main(String args[]){
Test t = new Test();
// first default constructor,then constructor with 1 parameter , then constructor with 2 parameters will be called
}
}
this(); is constructor which is used to call another constructor in a class,
for example:-
class A{
public A(int,int)
{ this(1.3,2.7);-->this will call default constructor
//code
}
public A()
{
//code
}
public A(float,float)
{ this();-->this will call default type constructor
//code
}
}
Note:
i did not use this() constructor in default constructor because it will lead to deadlock state.
Hope this will help you:)